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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If Chameli had Rs 600 left after spending 75% of her money, how much did she have in the beginning? |
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Answer» Let the amount of money which Chameli had in the beginning be x. It is given that after spending 75% of Rs x, she was left with Rs 600. Therefore (100 − 75)% of x = Rs 600 Or, 25 % of x = Rs 600 25/100 x X = Rs 600 x = Rs (60 x 100/25 ) = Rs 2400 Thus, she had Rs 2400 in the beginning. |
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| 2. |
72% of 25 students are good in mathematics. How many are not good in mathematics? |
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Answer» It is given that 72% of 25 students are good in mathematics. Therefore, Percentage of students who are not good in mathematics = (100 − 72)% = 28% Number of students who are not good in mathematics = 28/100 x 25 = 7 Thus, 7 students are not good in mathematics. |
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| 3. |
The ratio of Fatima’s income to her savings is 4 : 1. The percentage of money saved by her is :(a) 20% (b) 25% (c) 40% (d) 80% |
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Answer» Correct answer is (a) 20% |
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| 4. |
Gayatri’s income ₹ 1,60,000 per year. She pays 15% of this as house rent and 10% of the remainder on her child’s education. The money left with her is(a) ₹136000 (b) ₹120000 (c) ₹122400 (d) ₹14000 |
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Answer» (c) ₹122400 From the question it is given that, Gayatri’s income ₹ 1,60,000 per year She pays 15% of this as house rent = 15% of ₹ 1,60,000 = (15/100) × 1,60,000 = ₹ 24000 10% of the remainder on her child’s education = 10% of remaining mount of her income Remaining mount of her income = ₹ 1,60,000 – ₹ 24000 = ₹ 136000 Total amount of her child’s education = 10% of ₹ 136000 = (10/100) × 136000 = 1360000/100 = ₹ 13600 Then, money left with Gayatri = ₹ 1,60,000 – (₹ 24000 + ₹ 13600) = ₹ 1, 60, 000 – ₹ 37,600 = ₹ 1,22,400 |
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| 5. |
Gayatri’s income is Rs 1,60,000 per year. She pays 15% of this as house rent and 10% of the remainder on her child’s education. The money left with her is(a) Rs 136000 (b) Rs 120000 (c) Rs 122400 (d) Rs 14000 |
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Answer» Correct answer is (c) Rs 122400 |
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| 6. |
0.07 is equal to(a) 70% (b) 7% (c) 0.7% (d) 0.07% |
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Answer» (b) 7% 0.07 = 7/100 Percentage = (7/100) × 100 = 7% |
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| 7. |
In a scout camp, 40% of the scouts were from Gujarat State and 20% of these were from Ahmedabad. The percentage of scouts in the camp from Ahmedabad is:(a) 25 (b) 32.5 (c) 8 (d) 50 |
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Answer» (c) 8 From the question it is given that, In a scout camp, 40% of the scouts were from Gujarat State So, let us assume number of scout in the camp be 100 Then, scouts from Gujarat = 40% of 100 = (40/100) × 100 = 4000/100 = 40 Now, 20% of scouts were from Ahmedabad = 20% of 40 = (20 /100) × 40 = 800/100 = 8 Therefore, the percentage of scouts in the camp from Ahmedabad is 8. |
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| 8. |
5.2 is equal to(a) 52% (b) 5.2% (c) 520% (d) 0.52% |
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Answer» (c) 520% 5.2 is equal to = (52/10) × 100 = (5200/10) = 520% |
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| 9. |
The count of bacteria in a certain experiment was increasing at the rate of 2% per hour. Find the bacteria at the end of 2 hours if the count was initially 500000. |
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Answer» Count of bacteria, P = 500000 Time, n = 2 hours Increasing rate, R = 2% per hour Now, Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest P = Present value R = Annual interest rate n = Time] ∴ Count of bacteria = P (1 + R/100)n = 500000 (1 + 2/100)2 = 500000 (102/100)2 = 500000 × 102/100 × 102/100 = 50 × 102 × 102 = 520200 ∴ Count of bacteria at the end of 2 hours is 520200. |
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