Explore topic-wise InterviewSolutions in .

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1.

The points (x, 2) is equidistant from (8, -2) and (2, -2). Find the value of x.

Answer»

Let A = (2, 2) B = (8, -2) C = (2, -2) 

By data AB = AC = AB2 = AC2 

⇒ (8 – x)2 + (-2 -2)2 = (x – 2)2 + (2 + 2)2 

64 + x2 + 16x + 16 = x2 + 4 - 4x + 16

-16x + 4x = 4 -64 ⇒ – 12x = -60 

∴ x = 5

2.

Find the reflection of (-4, 3) through x-axis, y-axis and through the centre.

Answer»

Reflection through x – axis → (-4, – 3) 

Reflection through y – axis → (4,3) 

Reflection through center → (4, -3)

3.

Find ‘a’ if the distance between the points (a, 2) and (3, 4) is V8 units. 

Answer»

Let P = (a, 2) and Q = (3, 4) 

By data |PQ| = √8 

⇒ √8 = √((3 - a)2 + (4 - 2)2)

⇒ 8 = (3 – a)2 + 22 = 8 

⇒ 9 + a2 – 6a + 4 

⇒ a2 – 6a + 5 = 0 

⇒ (a – 5)(a – 1) = 0 

⇒ a = 5 or a = 1