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51.

Identify the incorrect statement regarding VBT.(a) It does not explain the colour of coordination compounds(b) It is unreliable in the prediction of geometries of 4-coordinate complexes(c) It does not explain the kinetic stabilities of coordination compounds(d) It can distinguish between strong and weak ligandsThe question was asked by my school principal while I was bunking the class.The above asked question is from Bonding in Coordination Compounds topic in division Coordination Compounds of Chemistry – Class 12

Answer»

The correct OPTION is (d) It can DISTINGUISH between strong and WEAK LIGANDS

Best explanation: One of the limitations of VBT is that it cannot differentiate between weak and strong ligands. The other OPTIONS are also its limitations.

52.

Predict the geometry of the complex from the electronic configuration shown.(a) Linear(b) Square planar(c) Tetrahedral(d) OctahedralThe question was asked by my school principal while I was bunking the class.Question is taken from Bonding in Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (a) Linear

The explanation is: The hybridisation TYPE is sp which involves only TWO orbitals, so the GEOMETRY has to be linear and the coordination number is 2.

53.

A complex having _________ geometry can have more than one type of hybridisation.(a) tetrahedral(b) square planar(c) trigonal bipyramidal(d) octahedralThe question was posed to me in final exam.The query is from Bonding in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer»

Correct ANSWER is (d) octahedral

The best explanation: Complexes having octahedral GEOMETRY can have either sp^3d^2 or d^2sp^3 HYBRIDISATION depending on WHETHER the outer or inner d orbitals are involved in hybridisation RESPECTIVELY.

54.

How many geometrical isomers are possible in [Al(C2o4)3]^3-?(a) 0(b) 2(c) 3(d) 4I got this question in final exam.Asked question is from Isomerism in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer»

The CORRECT option is (a) 0

Easiest explanation: The entity shown has a CN=6 as oxalate is a bidentate ligand. The structure of the entity will be same no MATTER which POSITIONS in the geometry each of the oxalate ligands occupy because their RELATIVE positions will REMAIN the same in each case.

55.

Which of the following compounds is not a linkage isomer?(a) Hg[Co(SCN)4](b) [Cr(H2O)5(NO2)]Cl2(c) [CoCl2(en)2]Cl(d) K[Cr(NH3)2(ONO)4]I got this question in an interview.The origin of the question is Isomerism in Coordination Compounds in chapter Coordination Compounds of Chemistry – Class 12

Answer»

The correct OPTION is (C) [CoCl2(en)2]Cl

The explanation: The COMPOUNDS Hg[Co(SCN)4], [Cr(H2O)5(NO2)]Cl2 and K[Cr(NH3)2(ONO)4] have ambidentate ligands thiocyanate or nitrate in them and these ligands can bind through DIFFERENT donor atoms to produce different structures or isomers.

56.

Which of the following is not enclosed in parenthesis?(a) Polyatomic ligands in the formula of coordination compounds(b) Ligand abbreviations in the formula of coordination compounds(c) Oxidation number of central metal in the naming of coordination compounds(d) The coordination entity in the formula of coordination compoundsThe question was asked in final exam.I'd like to ask this question from Nomenclature of Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

Correct answer is (d) The coordination entity in the formula of coordination compounds

Best explanation: The coordination entity consisting of the metal atom/ion followed by LIGANDS is enclosed WITHIN square BRACKETS and not in parenthesis.

57.

Which of the following is a complex salt?(a) Potassium aluminium sulphate(b) Ammonium iron(ll) sulphate(c) Carnallite(d) Potassium ferrocyanideThis question was posed to me in semester exam.My doubt stems from Werner’s Theory of Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

Right option is (d) Potassium ferrocyanide

Easiest explanation: Potassium ferrocyanide, K4[FE(CN6)], is a complex salt that does not dissociate into Fe^2+ and CN^– ions when DISSOLVED in WATER. The other THREE, i.e., potash alum, carnallite and MOHR’s salt are double salt that dissociate into simple ions completely when dissolved in water.

58.

[Fe(CN)6]^4- is an example of a _______(a) Coordination compound(b) Complex ion(c) Double salt(d) Complex saltThis question was posed to me in an international level competition.The above asked question is from Werner’s Theory of Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer»

The correct CHOICE is (b) COMPLEX ion

Best explanation: [Fe(CN)6]^4- is the COORDINATION complex ion of the coordination compound K4[Fe(CN6)], or potassium ferrocyanide, which is ALSO a complex SALT. Coordination complexes are also known as coordination entities.

59.

Which of the following terms is used to indicate the number of individual ligands that do not include a numerical prefix, in the name of a coordination compound?(a) tetra(b) bis(c) tris(d) tetrakisI got this question at a job interview.The origin of the question is Nomenclature of Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

The CORRECT choice is (a) tetra

The explanation: The terms bis, TRIS, TETRAKIS are used when the NAMES of the LIGAND include a numerical prefix. Else, the prefixes used are mono, di, tri, tetra, etc.

60.

The compounds [Co(NH3)5Cl]SO4 and [Co(NH3)5(SO4)]Cl are ________ isomers.(a) linkage(b) coordination(c) ionisation(d) solvateThe question was posed to me during a job interview.This is a very interesting question from Isomerism in Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (C) ionisation

Easiest explanation: The SULPHATE counter ion is a potential LIGAND and can displace the Cl atom to MAKE the latter the counter ion.

61.

Which of the following compounds consists of a homoleptic complex?(a) [Co(NH3)6]Cl3(b) [Co(NH3)5Cl]Cl2(c) [Co(NH3)4Cl2]Cl(d) [Co(NH3)5(CO3)]ClI had been asked this question during a job interview.Query is from Definitions topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

Right answer is (a) [Co(NH3)6]Cl3

For explanation I would SAY: [Co(NH3)6]Cl3 consists of only AMMONIA ligands in the complex and is hence homoleptic. The rest of the compounds consists of two kinds of ligates, either NH3 and Cl or NH3 and CO3, and hence they are HETEROLEPTIC.

62.

The central atom/ion of a coordination complex is also referred to as ________(a) Lewis acid(b) Lewis base(c) Bronsted-Lowry acid(d) Bronsted-Lowry baseThis question was posed to me in an online quiz.Asked question is from Definitions in division Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (a) LEWIS acid

Easy explanation: A Lewis acid is a species that can accept an electron pair. All CATIONS are Lewis acids. Since the central atom of a COORDINATION complex is METAL and always accept ELECTRONS, it is a Lewis acid.

63.

What is the colour of the compound CoCl3.5NH3?(a) Yellow(b) Purple(c) Green(d) VioletThe question was posed to me during an online exam.This key question is from Werner’s Theory of Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (b) Purple

To EXPLAIN I would say: The different compounds of COBALT(III) chloride with ammonia show distinct properties, most NOTABLY with respect to colour and conductivity measurements in solution.

64.

Which of the following does not explain the nature of bonding in coordination compounds?(a) Crystal Field Theory(b) Molecular Orbital Theory(c) Valence Bond Theory(d) VSEPR TheoryI had been asked this question in a national level competition.This interesting question is from Bonding in Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

Correct answer is (d) VSEPR THEORY

For explanation I would SAY: The VSEPR Theory explains the structure of individual molecules BASED on the electron PAIRS in their atoms. VBT, CFT, LFT and MOT are theories that explain the nature of bonding in coordination compounds.

65.

Geometrical isomerism can be observed in some homoleptic complexes.(a) True(b) FalseThis question was posed to me in examination.This key question is from Isomerism in Coordination Compounds topic in chapter Coordination Compounds of Chemistry – Class 12

Answer»

Right choice is (b) False

The best EXPLANATION: GEOMETRICAL isomerism takes place only in heteroleptic ligands as there is more than one TYPE of bonding group that can be arranged in different possible MANNERS to GIVE rise to isomers.

66.

A protein can exist in a coordination entity as a ligand.(a) True(b) FalseI have been asked this question in semester exam.Question is from Definitions topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

Correct option is (a) True

The explanation is: A protein is a macromolecule that consists of atoms that may DONATE ELECTRONS to a metal ion to FORM a COORDINATE bond, and hence ACT as a ligand.

67.

The prefixes bis, tris and tetrakis are used to indicate the number of individual ligands in the coordination entity.(a) True(b) FalseThis question was posed to me by my school teacher while I was bunking the class.Question is taken from Nomenclature of Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

Right choice is (a) True

For explanation I would say: Mono, DI, TRI, etc. are used when NAME of ligands don’t have a numerical PREFIX. If not, then bis, tris and tetrakis are used as prefixes.

68.

The correct way of naming Co in [CoCl2(en)2]^+ is ________(a) cobalt(III)(b) cobalt(II)(c) cobaltate(III)(d) cobaltate(II)I have been asked this question during an online exam.Enquiry is from Nomenclature of Coordination Compounds in chapter Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (a) cobalt(III)

Explanation: The complex ion given is cationic and hence the metal is named same as the element. Also, the oxidation NUMBER of cobalt is +3 as (en) is a neutral LIGAND and Cl has -1 charge. THUS, the correct naming for CO is cobalt(III).

69.

What is the primary valence of iron in the coordination entity of compound Fe4[Fe(CN)6]3?(a) 0(b) +2(c) +3(d) +4The question was asked during an interview.My query is from Werner’s Theory of Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

Correct answer is (b) +2

For EXPLANATION: This COMPOUND, also known as PRUSSIAN blue, dissociates into 4 Fe^3+ and 3[Fe(CN)6]^4- ions, of which the latter is the coordination entity having a CHARGE of -4. The Fe atom in question is the one inside the bracket. Since CN has a charge of -1 and there are 6 of them, the primary valence of Fe will be 6 – 4 = +2.

70.

Werner proposed that the primary valences are ionizable and are satisfied only by positive ions.(a) True(b) FalseThe question was asked in an online quiz.My query is from Werner’s Theory of Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

The correct option is (b) False

Best EXPLANATION: According to Werner’s POSTULATES, primary valences are ionizable and are satisfied by NEGATIVE ions. Whereas, secondary valences are non-ionizable, and these are satisfied by NEUTRAL MOLECULES or negative ions.

71.

A tetrahedral compound of type [MP2Q2] has two geometrical isomers.(a) True(b) FalseI got this question in an interview for job.The above asked question is from Isomerism in Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer» RIGHT choice is (b) False

Best explanation: Tetrahedral complexes do not form geometric ISOMERS as the relative positions of all the ligands will always be same because of the geometric PROPERTIES of a tetrahedron.
72.

The compound K4[Mn(CN)6] is diamagnetic.(a) True(b) FalseI had been asked this question at a job interview.Question is from Bonding in Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (b) False

To explain: The atomic number of Mn is 25 and the outer SHELL configuration of Mn^2+ is 3D^5. Four out of these five electrons pair up leaving 1 unpaired electron in 3d orbital and forming d^2sp^3 hybridisation. THUS, it is paramagnetic.

73.

What is the coordination number of chromium in K3[Cr(C2O4)3]?(a) 1(b) 2(c) 3(d) 6I got this question in an interview for job.My doubt is from Definitions topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (d) 6

The explanation: There are three oxalate groups attached to the central ION in the GIVEN compound, but SINCE oxalate is a didentate ligand, there are a total of 6 donor atoms to which the metal is directly bonded. THUS, the CN of Cr in K3[Cr(C2O4)3] is 6.

74.

The optical isomer that rotates the plane of polarised in the clockwise direction is called ______(a) trans(b) dextro(c) mer(d) laevoThis question was posed to me during an interview for a job.My enquiry is from Isomerism in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer»

Correct option is (b) dextro

Explanation: The optical isomers are of two TYPES BASED on the direction they rotate the plane of polarised light in a polarimeter. If it rotates it to the RIGHT, it is called dextro and if it rotates it to the left, it is called LAEVO.

75.

Identify the type of isomerism exhibited by the following structures.(a) Geometric isomerism(b) Optical isomerism(c) Linkage isomerism(d) Coordination isomerismThis question was posed to me during an interview.My question is taken from Isomerism in Coordination Compounds in section Coordination Compounds of Chemistry – Class 12

Answer»

Correct answer is (c) Linkage isomerism

The explanation: GEOMETRIC and optical isomerism are types of STEREOISOMERISM in which the chemical bonds remain same. The two structures shown have different chemical bonds between the central atom (Co) and the ligand GROUP (NO2). Nitrate is an AMBIDENTATE ligand which can result in two forms in the entities it is present in. If it links through N atom, it forms nitrito-N form (NO2) as in FIGURE i), and if it binds through O atom, it forms nitrito-O form (ONO) as in figure ii). This type of isomerism is called linkage isomerism.

76.

Linkage isomerism is seen in compounds having ________ ligand.(a) unidentate(b) polydentate(c) chelate(d) ambidentateI have been asked this question at a job interview.The origin of the question is Isomerism in Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

The CORRECT CHOICE is (d) ambidentate

The best EXPLANATION: Ambidentate ligands can bind through either one of their TWO DONOR atoms and can result in different forms. These forms are called linkage isomers.

77.

The prefix di is used twice in the naming of [NiCl2(PPh3)2].(a) True(b) FalseThis question was posed to me during an internship interview.I want to ask this question from Nomenclature of Coordination Compounds in section Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (b) False

The best I can explain: The prefix DI is used only once for chlorido. For the PPh3 LIGAND, the prefix bis is used instead, as PPh3 (triphenylphosphine) already includes a NUMERICAL prefix in its NAME.

78.

Complexes in which a metal is attached to only one kind of donor group is called _______(a) Unidentate(b) Chelate(c) Homoleptic(d) HeterolepticThis question was posed to me by my college director while I was bunking the class.Origin of the question is Definitions in section Coordination Compounds of Chemistry – Class 12

Answer»

The correct ANSWER is (c) Homoleptic

To elaborate: UNIDENTATE and chelate are words associated with ligands, whereas coordination COMPLEXES can be either homoleptic or heteroleptic depending upon WHETHER only one KIND or different kinds of ligands linked to the metal atom/ion respectively.

79.

Which of the following do not show geometrical isomerism? (Assume all ligands are unidentate)(a) Square planar [MXL3](b) Square planar [MX2L2](c) Octahedral [MX2L4](d) Octahedral [MX3L3]I had been asked this question in examination.The above asked question is from Isomerism in Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (a) Square planar [MXL3]

For explanation: In square planar complexes, the type [MXL3] does not have any isomers as there is no pair of LIGANDS that can be arranged adjacent to or opposite each other to FORM cis or TRANS forms respectively. All possible COMBINATIONS result in the same spatial arrangement.

80.

How many stereoisomers does the following compound have?(a) 0(b) 2(c) 3(d) 4This question was posed to me during an interview.This interesting question is from Isomerism in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (c) 3

For EXPLANATION: Firstly, the COMPOUND can have 2 geometric ISOMERS, cis and TRANS, depending on whether similar ligands are placed adjacent to or opposite each other. Furthermore, one of them, i.e. the cis form is optically active and has two non-superimposable forms. This means that the cis form is both a geometric isomers as well as an optical isomer. Hence, there are 3 stereoisomers (1 geometric, 1 optical, 1 both geometric and optical).

81.

In the coordination entity [Co(NH3)3(NO2)3], if all three N atoms of the amine ligands occupy adjacent positions at the corners of an octahedral face, the geometrical isomer formed is known as _______ isomer.(a) cis(b) trans(c) fac(d) merI had been asked this question by my school principal while I was bunking the class.Asked question is from Isomerism in Coordination Compounds topic in division Coordination Compounds of Chemistry – Class 12

Answer»

The correct choice is (C) fac

Explanation: Octahedral ENTITIES of the type [MA3B3] form two types of ISOMERS based on WHETHER the same ligand groups occupy adjacent positions on the octahedral face (fac) or positions around the meridian of the OCTAHEDRON (mer).

82.

How many geometrical isomers are possible in a complex of type [MA2(D)2], where A is unidentate and D is didentate?(a) 0(b) 2(c) 3(d) 4This question was addressed to me during an interview for a job.My question comes from Isomerism in Coordination Compounds topic in section Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (b) 2

For explanation I would say: In a complex of such TYPE, the two A ligands can be ARRANGED EITHER adjacent to or opposite each other to form cis and trans ISOMERS RESPECTIVELY, making it a total of two possible isomers.

83.

What would be the formula of the hypothetical compound shown in the figure? (Assume all ligands are monoatomic)(a) [M(AB)2C]^+(b) [M(A2B2C)]^+(c) [MA2B2C]^+(d) [M(A)2(B)2C]^+This question was addressed to me at a job interview.The origin of the question is Nomenclature of Coordination Compounds in section Coordination Compounds of Chemistry – Class 12

Answer» CORRECT option is (C) [MA2B2C]^+

To EXPLAIN: A, B and C are distinct monoatomic ligands are simply listed in that order after the METAL M, without the use of any PARENTHESIS, and enclosed within square brackets.
84.

Given that 1 mol of NiCl2.6H2O with excess AgNO3 precipitates 2 mols of AgCl, what is the secondary valence of Ni?(a) 1(b) 2(c) 4(d) 6The question was posed to me during an internship interview.I need to ask this question from Werner’s Theory of Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct CHOICE is (d) 6

To explain: After the reaction, it will form [NI(H2O)6]^2- and 2Cl^– in which the former is the COORDINATION complex. There are six water molecules bound to Ni, which makes the secondary valence of Ni as 6.

85.

What is the shape of the coordination polyhedron of [PtCl4]^2-?(a) Linear(b) Square planar(c) Tetrahedral(d) OctahedralI got this question in an interview.My enquiry is from Definitions topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The CORRECT choice is (b) Square planar

To elaborate: The CN of the metal ion is 4 because Cl^– is a unidentate ligand. The only possibility for the SHAPE of its coordination polyhedra is square planar or TETRAHEDRAL. From crystal FIELD SPLITTING diagram, it is known that [PtCl4]^2- is square planar.

86.

Which of the following compounds has enantiomers?(a) K3[Fe(CN)6](b) K3[Al(C2O4)3](c) K2[Zn(OH)4](d) K2[PdCl4]I have been asked this question by my college director while I was bunking the class.My enquiry is from Isomerism in Coordination Compounds in section Coordination Compounds of Chemistry – Class 12

Answer» RIGHT option is (b) K3[Al(C2O4)3]

To explain: K3[Fe(CN)6], K2[Zn(OH)4] and K2[PdCl4] are compounds with unidentate LIGANDS and CN of 6 (octahedral), 4 and 4 RESPECTIVELY. Whereas, K3[Al(C2O4)3] is an octahedral compound with a didentate ligand OXALATE and shows optical isomerism.
87.

Which type of isomerism exhibits compounds with same chemical formula and bonds but different spatial arrangement?(a) Optical isomerism(b) Linkage isomerism(c) Structural isomerism(d) Solvate isomerismThe question was asked during an online interview.This question is from Isomerism in Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer» CORRECT CHOICE is (a) OPTICAL ISOMERISM

For explanation: Stereoisomers have the same CHEMICAL formula and binds but have different spatial arrangement. Optical isomerism is a type of stereoisomerism.
88.

If the complex ion is cationic, the name of the metal ends with suffix -ate.(a) True(b) FalseThe question was posed to me in homework.The doubt is from Nomenclature of Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct ANSWER is (B) False

The explanation is: In cationic complex ions, the metal is named same as element. On the other hand, in anionic complex ions, the name of the metal is ENDED with -ate.

89.

If the secondary valence in CoCl3.4NH3 is six, the solution conductivity in silver nitrate corresponds to ________ electrolyte.(a) 1:1(b) 1:2(c) 1:3(d) 1:4This question was posed to me by my college professor while I was bunking the class.I need to ask this question from Werner’s Theory of Coordination Compounds topic in chapter Coordination Compounds of Chemistry – Class 12

Answer»

Right choice is (a) 1:1

The explanation: Werner OBSERVED that ‘x’ mol of AgCl was precipitated per mole of CoCl3.4NH3 with excess silver nitrate. Currently, there are SEVEN GROUPS attached to the cobalt atom. For the secondary valence to be six, one of the CHLORIDE (x=1) has to be precipitated as AgCl, therefore 1:1 ELECTROLYTE.

90.

The ferricyanide complex ion is _________(a) paramagnetic(b) outer orbital(c) spin free(d) tetrahedralI have been asked this question in homework.The above asked question is from Bonding in Coordination Compounds in chapter Coordination Compounds of Chemistry – Class 12

Answer»

Right choice is (a) paramagnetic

For explanation I would say: The oxidation state of FE in [Fe(CN)6]^3- ion is +3, which LEAVES it with FIVE unpaired electrons in 3d orbitals. Two of these pair up LEAVING one unpaired electron in 3d and six vacant orbitals to form d^2sp^3 hybridised octahedral inner orbital complex.

91.

The compound [Co(NH3)5(NO2)](NO3)2 does not show _________ isomerism.(a) coordination(b) optical(c) ionisation(d) linkageThis question was addressed to me during an interview.Question is taken from Isomerism in Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

Right CHOICE is (a) coordination

The best explanation: There is only ONE complex ion and there is no possibility of a coordination ISOMER. The ionisation isomer is [CO(NH3)5(NO3)](NO3)(NO2) and the linkage isomer is [Co(NH3)5(ONO)](NO3)2.

92.

[Co(NH3)5Cl]SO4 + Ag^+ = _________(a) AgCl(b) BaSO4(c) white precipitate(d) no reactionI got this question during an interview.This intriguing question comes from Isomerism in Coordination Compounds in section Coordination Compounds of Chemistry – Class 12

Answer»

Correct ANSWER is (d) no reaction

The best I can explain: The compound [Co(NH3)5Cl]SO4 dissociates into a COBALT complex ion and a sulphate ion when dissolved ion water. The sulphate ion does not react with silver ion. On the other hand, the ionisation isomer of [Co(NH3)5Cl]SO4, that is [Co(NH3)5(SO4)]Cl dissociates into cobalt complex ion and Cl ion which reacts with silver ion to precipitate AgCl.

93.

Which of the following compounds does not have a coordination isomer?(a) [Ag(NH3)2][Ag(CN)2](b) [Cr(NH3)6][Co(CN)6](c) [Zn(NH3)4][PtCl4](d) [Cu(NH3)4][FeCl4]The question was asked in homework.This interesting question is from Isomerism in Coordination Compounds in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct choice is (a) [Ag(NH3)2][Ag(CN)2]

Best explanation: Coordination isomerism takes PLACE when exchange of ligands happens between cationic and ANIONIC complex IONS having different metal ions. In the COMPOUND [Ag(NH3)2][Ag(CN)2], both the complexes have the same metal ion Ag^+, and hence does not have a coordination isomer.

94.

Identify the correct naming for [Co(ONO)(NH3)5]^2+.(a) Pentaamminenitritocolbalt(III)(b) Pentaamminenitrito-O-cobalt(III)(c) Pentaamminenitrito-N-cobalt(III)(d) Pentaamminenitrosylcobalt(III)This question was posed to me by my college director while I was bunking the class.My query is from Nomenclature of Coordination Compounds topic in division Coordination Compounds of Chemistry – Class 12

Answer»

Correct ANSWER is (b) Pentaamminenitrito-O-cobalt(III)

The explanation is: Nitrate is an ambidentate ligand and can BIND through either O or N ATOM. In this case, it is written as (ONO) which implies that it binds through O atom, hence giving it the NAME nitrito-O.

95.

When a polydentate ligand uses all its donor atoms simultaneously to bond to a single metal ion, it is said to be a _______ ligand.(a) unidentate(b) didentate(c) chelate(d) ambidentateI got this question during an internship interview.The doubt is from Definitions in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct option is (c) chelate

To explain: Unidentate LIGANDS use only ONE donor atom at a TIME. Didentate are POLYDENTATE ligands that have two donor ATOMS. An ambidentate ligand can bind through different donor atoms.

96.

The compound tetraamminecopper(II) sulphate, or [Cu(NH3)4]SO4.5H2O, a double salt.(a) True(b) FalseI had been asked this question during an interview for a job.This key question is from Werner’s Theory of Coordination Compounds topic in chapter Coordination Compounds of Chemistry – Class 12

Answer»

Correct answer is (b) False

To explain: The given compound is a coordination compound MADE of a COMPLEX ion, i.e., [Cu(NH3)4]^2+ which does not dissociate into its CONSTITUENT ions when dissolved. Hence, it is a complex salt and not a double salt.

97.

What is the number ofwater molecules that are present as ligands in the solvate isomer of hexaaquachromium(III) chloride which is grey-green in colour?(a) 1(b) 4(c) 5(d) 6I have been asked this question by my college professor while I was bunking the class.My question comes from Isomerism in Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct answer is (c) 5

Explanation: The solvate isomer of [Cr(H2O)6]CL3 that is grey-green in colour is [Cr(H2O)5CL]Cl2.H2O. This compound has 5 water molecules directly bonded to metal ion and one water MOLECULE as a free SOLVENT in the crystal lattice.

98.

Linkage isomers exhibit different physical properties.(a) True(b) FalseI have been asked this question in quiz.This interesting question is from Isomerism in Coordination Compounds in division Coordination Compounds of Chemistry – Class 12

Answer» CORRECT option is (a) True

Best explanation: It was observed that [CO(NH3)5(NO2)]CL2 was either RED in colour or yellow depending on whether the nitrite ligand bonded through O atom or N atom respectively, thus showing different physical properties.
99.

What is the denticity of the ligand shown in the figure?(a) 2(b) 4(c) 6(d) 8The question was posed to me during an internship interview.I need to ask this question from Definitions in section Coordination Compounds of Chemistry – Class 12

Answer»

The CORRECT ANSWER is (c) 6

Explanation: The ion shown in the FIGURE is ethylenediaminetetraacetate which is a hexadentate ligand and can bind through its two N atoms or FOUR O atoms. Hence, its denticity is 6.

100.

The oxidation number of the central metal ion in a coordination entity is the charge it would carry if all the _________ are removed along with the electron pairs that are shared with it.(a) lewis acids(b) anions(c) ligands(d) didentate ligandsThe question was asked during an online exam.The doubt is from Definitions topic in chapter Coordination Compounds of Chemistry – Class 12

Answer» CORRECT answer is (c) ligands

For explanation I would say: The OXIDATION number or primary valence of a central atom is its charge if all the ligands and its donor ATOMS are not PRESENT in the coordination entity.