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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
Which of the following species is not expected to be a ligand?A. `NO`B. `NH_(4)^(+)`C. `NH_(2)CH_(2)CH_(2)NH_(2)`D. `CO` |
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Answer» Correct Answer - B Ligand must donate a pair of electron or loosely held electron pair to metal and form a M-L bond. e.g., `:overset(..)(N)=O, overset(..)(N)H_(2)CH_(2)CH_(2) overset(..)(N)H_(2), :CO`, Among `overset(+)(N)H_(4)` does not have any pair of electron. Hence `overset(+)(N)H_(4)` is not a ligand. |
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| 352. |
Which of the following species is not expected to be a ligand `overset(o+)(NO)` `NH_(4)^(o+)` (c ) `NH_(2)-NH_(3)^(o+)` `(CO)` . |
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Answer» Correct Answer - b `NH_(4)^(o+)` cannot act as a ligand as lone pair on n-atoms is already donated to `H^(o+)` ion `(H_(3)N:rarrH^(o+) -=NH_(4)^(o+)` . |
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| 353. |
Match each coordination compound in List-I with an appropriate pair of characteristics from List - II and select the correct answer using the code given below the lists . [en = `H_(2)NCH_(2)CH_(2)NH_(2)` , At Nos : Ti = 22 , Cr = 24 , Co = 27 , Pt = 78] `{:("List- I" ,, "List- II") , ((P) [Cr(NH_(3))_(4) Cl_(2)]Cl ,, 1. "Paramagnetic and exhibits ionisation isomerism"), ((Q) [Ti(H_(2)O)_(5) Cl](NO_(3))_(2) ,, 2 . "Diamagnetic and exhibits cis- trans isomerism"), ((R) [Pt (en) (NH_(3)) Cl]NO_(3) ,, 3. "Paramagnetic and exhibits cis - trans"), ((S) [Co(NH_(3))_(4) (NO_(3))_(2)]NO_(3) ,, 4."Diamagnetic and exhibits ionisation isomerism"):}`A. `{:(P , Q , R , S), (4 , 2 , 3 , 1):}`B. `{:(P , Q , R , S), (3 , 1 , 4 , 2):}`C. `{:(P , Q , R , S), (2 , 1 , 3 , 4):}`D. `{:(P , Q , R , S), (1 , 3 , 4 , 2):}` |
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Answer» Correct Answer - B `P : Cr^(3+)` has `3d^(3)` configuration with 3 unpaired electrons . Hence , it shows paramagnetic behaviour . Complex of the type `Ma_(4)b_(2)` shows cis-trans isomerism . `Q : Ti^(3+)` has `3d^(1)` configuration , hence shows paramagnetic behaviour . complex gives `Cl^(-)` and `NO_(3)^(-)` ions in solution hence , shows ionisation isomerism . R : `Pt^(2+)` has `3d^(8)` configuration but ligands are strong field ligands hence it forms square planar complex . Thus , all electrons are paired and it also exhibits ionisation isomerism . S : `co^(3+)` has `3d^(6)` configuration . But , ligands present are strong enough to cause electron pairing , hence , it shows diamagnetic behaviour and exhibits cis-trans isomerism as it is `Ma_(4) b_2` type complex . |
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| 354. |
Which of the following complexes formed by `Cu^(2+)` ions is most stable ?A. `Cu^(2+) + 4NH_(3) hArr [Cu(NH_(3))_(4)]^(2+) , log K = 11.6`B. `Cu^(2+) + 4 CN^(-) hArr [Cu(CN)_(4)]^(2-) , log K = 27.3`C. `Cu^(2+) + 2 en hArr [Cu(en)_(2) ]^(2+) , log K = 15.4 `D. `Cu^(2+) + 4H_(2)O hArr [Cu(H_(2)O)_(4)]^(2+) , log K = 8.9` |
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Answer» Correct Answer - B Higher the value of stability constant K , greater is the stability . |
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| 355. |
Identify the correct statements for the behaviour of ethane-1, 2-diamine as a ligand.A. It is a neutral ligandB. It is a didentate ligandC. It is a chelating ligandD. It is a unidentate ligand |
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Answer» Correct Answer - A::B::C Molecular formula of ethane-1, 2-diamine is `{:(CH_(2)- overset(..)(N)H_(2)),("|"),(CH_(2)-overset(..)(N)H_(2)):}` (a) Ethane-1, 2-diamine is a neutral ligand due to absence of any charge. (b) It is a didentate ligand due to presence of two donor sites one at each nitrogen atom of amino group. (c) It is a chelating, ligand due to its ability to chelate with the metal. Hence, options (a), (b) and (c) are correct choices. |
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| 356. |
Consider the following isomers of `[Co(NH_(3))_(4)Br_(2)]^(+)` . The black sphere represent Co, grey spheres represent `NH_(3)` and unshaded spheres represent Br. Which of the following are cis-isomers ?A. Isomers (a) and (b)B. Isomers (a) and (c)C. Isomers (b) and (d)D. Isomers (c) and (d) |
| Answer» Correct Answer - B | |
| 357. |
Consider the following isomers of `[Co(NH_(3))_(4)Br_(2)]^(+)` . The black sphere represent Co, grey spheres represent `NH_(3)` and unshaded spheres represent Br. Which of the following are trans-isomers ?A. Isomers (a) and (b)B. Isomers (a) and (c)C. Isomers (b) and (d)D. Isomers (c) and (d) |
| Answer» Correct Answer - C | |
| 358. |
The two isomers X and Y with the formula `Cr(H_(2)O)_(5)ClBr` were taken for experiment on depression in freezing point. It was found that one mole of X gave depression corresponding to 2 moles of particles and one mole of Y gave depression to 3 moles of particles. The structural formulae of X and Y raspectively areA. ` [Cr(H_(2) O)_(5) Cl] Br_(2 ) , [Cr (H_(2) O) _(3) Cl Br_(2) .2H_(2) O]`B. `[Cr (H_(2)O)_(5) ] BrCl ,[Cr(H_(2) O) ClBr]Br.H_(2) O`C. `[Cr(H_(2)O)_(5)Br]BrCl,[Cr(H_(2)O)_(4)ClBr]Br.H_(2)O`D. `[Cr(H_(2)O)_(4)Br_(2)]ClH_(2)O,[Cr(H_(2)O)_(5)Cl]Br_(2)` |
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Answer» Correct Answer - D One mole of X gave depression corresponding to 2 moles of particles i.e., on ionisation X gives 2 moles of ions thus it contains only 1 ion outsaide the coordination sphere and its structural formula is `[Cr (H_(2)O)_(4) Br_(2) ]Cl .H_(2)O` while Y gives 3 moles of ions , thus it contains two ions outside the coordination sphere and its structural formula is ` [Cr (H_(2) O)_(5) ]Br_(2) ` |
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| 359. |
Among the following, which is not the `pi` bonded oraganometallic comound ?A. `k[PtCI_(3)(eta^(2)-C_(2)H_(4))]`B. `Fe(eta^(5)-C_(5)H_(5))_(2)`C. `(CH_(3))_(4) Sn`D. `Cr(eta^(6))-C_(6)` |
| Answer» (c) `(CH_(3))_(4)` Sn is a `sigma` bonded organometallic comound. | |
| 360. |
The value of x in the complex `H_(x) Co(CO)_(4)` is `(Co, Z = 27)`A. 2B. 3C. 1D. 0 |
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Answer» Correct Answer - C We can get the answer by applying the effective atomic number (ENA) rule which says that electron pairs from ligands are needed until the central metal is surrounded by the same number of electrons as the next noble gas. For period 4 elements such as Co, the next noble gasis is `Kr(Z=36)` . Since atomic number of cobalt is 27 and each CO provides 2 electrons, we have `36 = 27 - (0.N.) + 2xx4` or `O.N = - 36 + 27 + 2xx4` `= - 1` For, `H_(x) Co(CO)_(4)`, the sum of oxidation number must be zero. Thus `x + (-1) + 4 (0) = )` `x = 1` |
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| 361. |
Assertion `NO^(o+)` has a lower pi accepting tendency than the `CO` Reason No donates 3 electrons into the vacant orbital of metal cation or atom .A. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .B. If both `(A)` and ` (R )` are correct and `(R )` is the correct explanation of `(A ) ` .C. If`(A)` is correct, but `( R )` is incorrect .D. Both `(A)` and `(R ) ` are incorrect . |
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Answer» Correct Answer - D Due to positive charge, the tendency of pi- accepting property of `NO^(o+)` will be higher than that of `CO` . |
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| 362. |
Which of the following ligands donates three electrons during the formation of compolexes ?A. NOB. COC. `CN^(-)`D. `PR_(3)` |
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Answer» Correct Answer - A NO readily forms coordination complexes with transition metal ions. These complexes are called nitrosyls. Most nitrosyls are coloured. NO often acts as a three electron donor, in contrast to CO, `CN^(-)` and `PR_(3)` which donate two electrons. |
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| 363. |
Which of the following complex ions is not expected to absorve visible light ?A. `[Ni(H_(2)O)_(6)]^(2+)`B. `[Ni(CN)_(4)]^(2-)`C. `[Cr(NH_(3))_(6)]^(3+)`D. `[Fe(H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - B To explain why complexes are coloured, we need to look at the effect of the ligand charges on the energies of the d orbitals. Because the d electrons are negatively charged, they are repelled by negatively charged ligands. Thus, their orbital energies are higher in the complex than in the free metal ion. But not all the d orbitals are raised in energy by the same amount. The `d_(z^(2))` and `d_(x^(2)-y^(2))` orbitals, which point directly at the ligands are raised in energy to a greater extent than the `d_(xy)` , `d_(xz)` and `d_(yz)` orbitals, which point between the ligands. This energy spliting between the two sets of sets of d orbitals is called the rystal field splitting and is represented by the Greek letter `Delta`. In general, the crystal field splitting energy `Delta` corresponds to wavelengths of light in the visible region of the spectrum and the colours of complexes can therefore be attributed to electronic transitions between the lower the lower and higher energy sets of d orbitals. In octahedral complexes (1), (3) and (4), the d-d trandition by absorbing visible light is possible as they all have a vacancy in the higher energy `e_(g)` set. In square planar `[Ni(CN)_(4)]^(2-)` , all the lower energy d orbitals `(d_(xz), d_(yz),d_(z^(2)))` and `d_(xy))` are completely filled and vacant `d_(x^(2)-y^(2)` orbital, is too high in energy to absorb visible light. |
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| 364. |
Coordination number of calcium is six in .A. `[Mg(EDTA)]^(2-)`B. `MgC_(2)O_(4)`C. `Mg[(C_(2)O_(4))_(2)]^(2-)`D. `MgSO_(4).4H_(2)O` |
| Answer» Correct Answer - A | |
| 365. |
Identify the species with an atom in +6 oxidation state present in the folloiwng complexes.A. `CrO_(2)CI_(2)`B. `[Cr(CN)_(6)]^(3-)`C. `[NiF_(6)]^(2-)`D. `MnO_(4)^(-)` |
| Answer» (a) The oxidation state of Cr in `CrO_(2)CI_(2)` is +6. | |
| 366. |
Coordination number of `Cu^(2+)` in `CuSO_(4).5H_(2)O` is .A. 5B. 4C. 3D. 2 |
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Answer» Correct Answer - B Salt is represented as `[Cu(H_(2)O)_(4)]SO_(4).H_(2)O` . Four `H_(2)O` molecules are coordinated to `Cu^(2+)` while remaining one `H_(2)O` molecule is H-bonded to `SO_(4)^(2-)` . |
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| 367. |
The water -soluble complex among the following is (a) `[Ni(HDMG)_(2)]` (b) `[Co(NH_(3))_(3)CI_(3)]` (c ) `Ni(CO)_(4)` `[Ni(HDMG)_(2)]CI_(2)` . |
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Answer» Correct Answer - d The complex which shows ionisation isomerism are soluble in water Hence answer is (d) . |
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| 368. |
When an excess of ammonia solution is added to `CuSO_(4)` which solution is formed (a) `[Cu(NH_(3))_(2)]^(2+)` (b) `[Cu(NH_(3))_(4)]^(o+)` (c ) `[Cu(NH_(3))_(2)]^(o+)` (d) `[Cu(NH_(3))_(4)]^(2+)` . |
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Answer» Correct Answer - d `CuSO_(4)+4NH_(3)("excess")rarr[Cu(NH_(3))_(4)]^(2+)SO_(4)^(2-)` |
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| 369. |
The cordination number of Co in `[(Co(NH_(3))_(5)CI]CI_(2)` isA. 2B. 5C. 6D. 1 |
| Answer» (c) In the complex `[Co(NH_(3))_(5)CI]CI_(2)` , total number of the ligands linked to the central atom, cobalt is 6. "Therefore", the coordination number of Co is 6. | |
| 370. |
The reaction `[Fe(CNS)_6]^(3-)rarr[FeF_6]^(3-)` takes place with:A. (a) decrease in magnetic momentB. (b) increase in coordination numberC. (c) decrease in coordination numberD. (d) increase in magnetic moment |
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Answer» Correct Answer - D `[Fe(CNS)_6]^(3-)` is inner-orbital complex with one electron unpaired while `[FeF_6]^(3-)` is outer-orbital complex with five unpaired electrons. |
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| 371. |
Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite gives dark blue crystals of :A. `[Ni(py)_(4)]SO_(4)`B. `[Ni(py)_(2)(NO_(2))_(2)]`C. `[Ni(py)_(4)](NO_(2))_(2)`D. `[Ni(py)_(3)(NO_(2))]_(2)SO_(4)` |
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Answer» Correct Answer - C `[Ni(H_(2)O)_(4)]SO_(4)`+Pyridine +`NaNO_(2)to [Ni(Py)_(4)](NO_(2))_(2)` Stronger ligand, pyridine displaces weaker ligand, `H_(2)O` in aqueous solution. `[Ni(py)_(4)](NO_(2))_(2)` is formed as dark blue crystals on crystallisation. |
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| 372. |
Oxidation number of Fe in violet coloured complex `Na_(4)[Fe(CN)_(5)(NOS)]` is |
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Answer» Correct Answer - B Let the oxidation state of Fe is x 4+x-5-1=0 so x=2 |
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| 373. |
A complex of certain metal has the magnetic moment of 4.91 BM whereas another complex of the same metal with same oxidation state has zero magnetic moment. The metal ion could be :A. `Co^(2+)`B. `Mn^(2+)`C. `Fe^(2+)`D. `Fe^(3+)` |
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Answer» Correct Answer - C `[overset(II)(Fe)(H_(2)O)_(6)]^(2-) n=4 and mu=4.91` `[overset(II)(Fe)(CN)_(6)]^(4-) n=0 and mu=0` |
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| 374. |
The d- electron configurations of `Mn^(2+),Fe^(2+),Co^(3+)` and `Ni^(2+)` ard `3d^(5),3d^(6),3d^(6),3d^(8)` , respectively Which of the following aqua complexes will exhibit the minimum paramagnetic behviour ? .A. (a) `[Fe(H_2O)_6]^(2+)`B. (b) `[Ni(H_2O)_6]^(2+)`C. (c) `[Cr(H_2O)_6]^(2+)`D. (d) `[Mn(H_2O)_6]^(2+)` |
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Answer» Correct Answer - B `Cr^(2+), Mn^(2+), Fe^(2+)` and `Ni^(2+)` have 4, 5, 4 and 2 unpaired electrons respectively. |
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| 375. |
The hypothetical complex triamminediaquachloridocobalt(III) chloride can be represented as :A. `[CoCl(NH_(3))_(3)(H_(2)O)_(2)]`B. `[Co(NH_(3))_(3)(H_(2)O)Cl_(3)]`C. `[CO(NH_(3))_(3)(H_(2)O)_(2)Cl]Cl_(2)`D. `[Co(NH_(3))_(3)(H_(2)O)_(3)]Cl_(3)` |
| Answer» Correct Answer - C | |
| 376. |
Which of the following gives the maxium number of isomers?A. (a) `[Co(NH_3)_4Cl_2]`B. (b) `[Ni(en)(NH_3)_4]^(2+)`C. (c) `[Ni(C_2O_4)(en)_2]`D. (d) `[Cr(SCN)_2(NH_3)_4]^(+)` |
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Answer» Correct Answer - D `[Cr(SCN)_2(NH_3)_4]^(+)` shows geometrical (or cis-trans) and linkage isomeism. |
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| 377. |
Given the following data about the absorption maxium of several complex ions what is the order of `Delta_(0)` for these ions? . `{:(Compound,,lambda_(max),,),(I.[CrCI_(6)]^(3-),,758,,),(II.[Cr(NH_(3))_(6)]^(3+),,465,,),(III.[Cr(H_(2)O)_(6)]^(3+),,694,,):}` (a) `Delta_(0)ltdelta_(0)(II)ltDelta_(0)(III)` (b) `delta_(0)(II)ltDelta_(0)(III)ltDelta_(0)(III)` (c) `Delta(0)ltdelta_(0)(III)ltDelta_(0)(II)` (d) `Delta_(0)(III)ltDelta_(0)(II)ltDelta_(0)(I)` . |
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Answer» Correct Answer - c The higher is the value of `Delta_(0)` lower is the value of `lambda` max and vice varsa and hence answer is © |
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| 378. |
The hypothetical complex triamminediaquachloridocobalt`(III)` chloride can be represented as `:`A. `[Co(NH_(3))_(3)(H_(2)O)_(2)Cl]Cl_(2)`B. `[Co(NH_(3))_(3)(H_(2)O)Cl_(3)]`C. `[Co(NH_(2))_(3)(H_(2)O)_(2)Cl]`D. `[Co(NH_(3))_(3)(H_(2)O)_(3)]Cl_(3)` |
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Answer» Correct Answer - 1 Triamminediaquachloridocobait`(III)` chloride is `[Co(NH_(3))_(3)(H_(2)O)_(2)Cl]Cl_(2)`. |
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| 379. |
`NH_2*NH_2` serve as:A. (a) monodenate ligandB. (b) both (a) and (c)C. (c) bridging ligandD. (d) chelating ligand |
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Answer» Correct Answer - B `NH_2*NH_2` serve as monodentate as well as bridging ligand because a 3-membered ring will be too strained to be stable. |
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| 380. |
The `0.0001` molal solution of a complex `AB_(10)` has the freezing point of `-0.0015^(@)C` in water. Assuming `100%` dissociation of the complex, find the proper representation of the complex `[K_(f)(H_(2)O=1.86Km^(-1))]` (a) `[AB_(8)]`(b) `[AB_(3)]B_(7)` (c )` [AB_(7)]B_(3)` (d) `[AB_(5)]B_(5)` . |
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Answer» Correct Answer - b At `100%` dissociation van t Hoff vactor if `I = n` (no of ions from the complex Now `deltaT_(f)|=iK_(f)m` `implies i = n= (|DeltaT_(f)|)/(K_(f)m) = (0.0015)/(1.86 xx 0.0001) = 8` implies Thus there should be 8 ions in solution implies The compound should be `[AB_(3)]B_(7))` . |
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| 381. |
An imperfect complex of a complex compund is `100%` ionized, the compound is called:A. (a) acid saltB. (b) complex saltC. (c) double saltD. (d) normal salt |
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Answer» Correct Answer - C It is a differentiating point in between complex and double salt. |
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| 382. |
The EAN of platinum in potassium hexachloroplatinate (IV) is:A. 46B. 86C. 36D. 84 |
| Answer» Correct Answer - B | |
| 383. |
The EAN of platinum in potassium hexachloroplatinate (IV) is:A. (a) `86`B. (b) `46`C. (c) `36`D. (d) `84` |
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Answer» Correct Answer - A Effective atomic no. `(EAN)=78-4+2xx6=86`. |
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| 384. |
The EAN of platinum in potassium hexachloridoplatinate (IV) is (Atomic number of Pt=78)A. 90B. 86C. 76D. 88 |
| Answer» Correct Answer - B | |
| 385. |
When each of the following complex salts is treated with excess of `AgNO_(3)` solution, which will give the maximum amount of AgClA. `[Co(NH_(3))_(6)]Cl_(6)`B. `[Co(NH_(3))_(5)Cl]Cl_(2)`C. `[Co(NH_(3))_(4)Cl_(2)]Cl`D. `[Co(NH_(3))_(3)Cl_(3)]` |
| Answer» Correct Answer - A | |
| 386. |
How many ions are produced from the complex `Co(NH_3)_6Cl_2` in solution? (i). `6` (ii). `4` (iii). `3` (iv). `2` |
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Answer» Coordination number of cabot =6 Hence, the complex is `[Co(NH_(3))_(6)]Cl_(2)` it ionizes in the solution as follows: `[Co(NH_(3))_(6)]Cl_(2)overset(+aq)rarr[Co(NH_(3))_(6)]^(2+)+2Cl^(-)` Thus, three ions are produced Hence the correct option is (III) |
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| 387. |
The correct structure of ethylenediamineteraacetic acid `(EDTA)` is .A. B. C. D. |
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Answer» Correct Answer - C |
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| 388. |
The IUPAC name of `[Ni (NH_(3))_(4)] [NiCl_(4)]` isA. Tetrachloronickel (II) -tetraamminenickel (II)B. Tetraamminenickel (II) -tetrachloronickel (II)C. Tetraamminenickel (II) -tetrachloronickelate (II)D. Tetrachloronickel (II) -tetraamminenickelate (0) |
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Answer» Correct Answer - C |
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| 389. |
Which among the following complexes is diamagnetic?A. (a) `[Cr(NH_3)_6]^(3+)`B. (b) `[CoF_6]^(3-)`C. (c) `Ni(CO)_4`D. (d) `[CuCl_4]^(2-)` |
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Answer» Correct Answer - C In `Ni(CO)_4`, all electrons are paired |
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| 390. |
The EAN of nickel in `Ni(CO)_4` is:A. (a) `38`B. (b) `36`C. (c) `28`D. (d) `54` |
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Answer» Correct Answer - B Effective atominc no. (EAN)=at. of central atom oxidation state +2 x (no. of ligands) `=28-0+2xx4=36`. |
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| 391. |
Given the molecular formula of the hexacoordinated complexes (A) `[CoCl_(3).6NH_3]` (B) `[CoCl_(3).5NH_3]` (C) `CoCl_(3).4NH_3`. If the number of coordinated `NH_3` molecules in A, B and C respectively are 6, 5 and 4, the primary valency in (A), (B) and (C) are:A. (a) 6, 5, 4B. (b) 3, 2, 1C. (c) 0, 1, 2D. (d) 3, 3, 3 |
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Answer» Correct Answer - B The complexes can be written as follows `underset((A))[Co(NH_3)_6]Cl_3underset((B))[Co(NH_3)_5Cl]Cl_2underset((C))[Co(NH_3)_4Cl_4]Cl` Hence, number of primary valencies are 3, 2 and 1 respectively. |
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| 392. |
Which of the following does not have a metal carbon bond?A. `A1(OC_(2)H_(5))_(3)`B. `C_(2)H_(5)Mg Br`C. `K[Pt(C_(2)H_(4))CI_(3)]`D. `[Ni(CO)_(4)]` |
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Answer» Correct Answer - A Aluminium ethoxide, `A1(OC_(2)H_(5))_(3)` , an ionic compound, consists of `A1^(3+)` and `C_(2)H_(5)O^(-)` ions. There is no metal - carbon bond it is not an organometallic compound like the other. |
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| 393. |
Which of the following does not have a metal carbon bond?A. (a) `K[Pt(C_2H_4)Cl_3]`B. (b) `Ni(CO)_4`C. (c) `Al(OC_2H_5)_3`D. (d) `C_2H_5MgBr` |
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Answer» Correct Answer - C `Al(OC_2H_5)_3` contains bonding through O and thus it does not have metal-carbon bond. |
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| 394. |
The primary valence of the metal ion in the coordination compound `K_2[Ni(CN)_4]` isA. (a) FourB. (b) ZeroC. (c) TwoD. (d) Six |
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Answer» Correct Answer - C Primary valencies are also known as oxidation state. `K_2[Ni(CN)_4], 2+x-4=0impliesx=+2` |
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| 395. |
Aqueous solution of which of the following complexes would exchibit the highest molar conductance?A. (a) `K_4[Fe(CN)_6]`B. (b) `K_2[PtCl_4]`C. (c) `[Cr(NH_3)_3Cl_3]`D. (d) `[Co(NH_3)_6]Cl_3` |
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Answer» Correct Answer - D `[Co(NH_3)_6]Cl_3` will give four ions: `[Co(NH_3)_6]^(3+)` and three `Cl` ions. |
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| 396. |
Number of ions produced when `[Cu(NH_3)_4]Cl_2` is dissolved in water is/areA. (a) `3`B. (b) `2`C. (c) `1`D. (d) `5` |
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Answer» Correct Answer - C `[Cu(NH_(3))_4]Cl_2 hArr [Cu(NH_3)_4]^(2+)+2Cl^(-)` |
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| 397. |
Complexes with halide ligands are generally:A. (a) High spin complexesB. (b) Low spin complexesC. (c) BothD. (d) None |
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Answer» Correct Answer - A halide ions with weak ligand generally form high spin complexes |
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| 398. |
Correct formula of tetraamminechloronitroplatinum (IV) sulphate can be written asA. `[Pt(NH_(3))_(4) (ONO)Cl]SO_(4)`B. `[Pt(NH_(3))_(4) Cl_(2)NO_(2)]_(2)SO_(4)`C. `[Pt(NH_(3))_(4) (NO_(2))Cl]SO_(4)`D. `[PtCl(ONO)NH_(3)(SO_(4))]` |
| Answer» Correct Answer - C | |
| 399. |
The name of the compound `[Co(NH_(3))_(5) NO_2]Cl_2` will beA. pentaamminonitrocobalt (II) chlorideB. pentamminenitrochloridecobalt(III) chlorideC. pentanitrosoamminechlorocobaltate(III) .D. |
| Answer» Correct Answer - C | |
| 400. |
The number of unpaired electrons in `d^(6)`, low spin, octahedral complex is :A. 4B. 2C. 1D. 0 |
| Answer» Correct Answer - D | |