

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
251. |
Nervous system starts from ………. part. A) Brain B) Spinal cord C) A and B D) Heart |
Answer» Answer is (C) A and B |
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252. |
We did not know about the Nervous control system in………. century. A) 16th B) 17thC) 18th D) 19th |
Answer» We did not know about the Nervous control system in 17th century. |
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253. |
The arcs which operate when you put your leg on sharp thing …………. A) Reflex arcs B) Controlled arcs C) Brain D) Involuntary arcs |
Answer» (A) Reflex arcs |
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254. |
Collect information about the major plant hormones from library or internet? |
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Answer» Some major plant hormones and their action are given in the following table. Major plant hormones and their action.
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255. |
Which is not found in non – myelinated neurons ? A) Cyton B) Synapse C) Axon D) Dendrite |
Answer» Answer is (C) Axon |
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256. |
Which structure makes up about 10 percent of the brain’s mass and contains about 50 percent of its neurons ? A) Cerebral cortex B) Cerebellum C) Medulla oblongata D) Pons varoli |
Answer» B) Cerebellum |
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257. |
Cells present in myelin sheath of neuron are ………. A) Nissel’s granules B) Schwann cells C) α – particles D) Globulins |
Answer» (B) Schwann cells |
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258. |
The cells which nourish nutrients to the neurons A) Erythrocytes B) Glial cells C) Monocytes D) Blood platelets |
Answer» (B) Glial cells |
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259. |
1. The largest region of the brain is ———–. 2. A point of contact between two neurons is ———–. 3. ———– phytohormone is responsible for cell elongation and differentiation of shoots and roots. 4. Thyroxine is responsible for ———–. |
Answer» 1. cerebrum 2. synapse 3. Auxin 4. General growth rate and metabolic rate |
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260. |
The cells that give the nutrients to the neurons are ……… A) Red blood cells B) Monocytes C) Blood platelets D) Glial cells |
Answer» (D) Glial cells |
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261. |
What is synapse? |
Answer» Synapse is the functional region of contact between two neurons. |
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262. |
What is a Synapse? How is it useful in transfer information? |
Answer» 1. Definition: Synapse is a functional region between two neurons where information from one neuron is transmitted or relayed to another neuron. 2. Through synaptic region is with minute gaps it does not have any protoplasmic connection between them. 3. Information is passed from one nerve cell to the other through these gaps either in the form of chemical or electrical signals or both. |
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263. |
In a synapse, chemical signal is transmitted from: A) axon to cell body of the same neuron. B) cell body to axon end of the same neuron. C) dendrite end of one neuron to axon end of adjacent neuron. D) axon end of one neuron to dendrite end of adjacent neuron. |
Answer» (C) dendrite end of one neuron to axon end of adjacent neuron. |
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264. |
Observe the following table and answer the questions.HormonesUsesThyroxineNormal growth rate, effect on metabolismAuxinsCell elongation and differentiation of shoots and roots i) Name the phytohormone in the table.ii) Name the hormone which influences growth rate in humans. |
Answer» i) Auxin ii) Thyroxine. |
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265. |
What is true about below given picture?A) Connection between the dendrites of different neurons B) Functional region between two neurons C) Analysis of received information D) Both A and B |
Answer» B) Functional region between two neurons |
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266. |
Look at the picture and answer the questions:a) To which system does the diagram belong ?b) What is the name of A, B parts ?c) What is ‘C’ ? What is its function ?d) Through which horn the sensory nerve enters ? |
Answer» a) The diagram belongs to T.S. of Spinal cord (peripheral). b) A – Dorsal Root, B – Ventral Root c) C – Association neuron It analyse the information – and send the order (function) through motor neuron to muscle. d) Sensory nerve enters through dorsal horn. |
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267. |
Observe the following table and answer the questions.Division -1Division – IIAuxinsAdrenalinGibberellinsTestosteroneEthyleneEstrogenAbscisic AcidThyroxinCytokininsGrowth Hormonea) On what basis the above classification done?b) From which gland is Adrenalin released?c) Which hormone is responsible for closing of stomata?d) What are the functions of Auxins? |
Answer» a) Hormones in animals and hormones in plants. b) Adrenal gland. c) Abscisic Acid (ABA) d) Cell elongation and differentiation of shoots and roots. |
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268. |
Fill in the blanks:In the octahedral complexes, if the (n-l)d orbitals are involved in hybridisation, they are called …….. and ….. complexes. |
Answer» The inner orbital complexes, low spin complexes (or) Spin paired complexes. |
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269. |
The d orbital involved in dsp3 hybridisation of [Fe (CO)5 ] is …………….. (a) dxy (b) dyz (c) dxz (d) dx2y2 |
Answer» The d orbital involved in dsp3 hybridisation of [Fe(CO)5] is dx2y2 . |
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270. |
Find out the correct pair (a) [Cr (H2O)6] Cl3 and [Cr(H2O)4Cl2]. 2H2O (b) [Cr (H2O)5Cl]Cl2 . H2O and [Cr (H2O)6]Cl3(c) [Cr (H2O)4Cl2]Cl . 2H2O and [Cr(H2O)5Cl] Cl2 . H2O (d) [Fe (CO)5] and [Ni (CN)4]2 |
Answer» (d) [Fe (CO)5] and [Ni (CN)4]2- Others are solvate isomersim. |
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271. |
Which of the following will give a pair of enantiomorphs? (a) [Cr (NH3)6 [CO(CN)6] (b) [CO (en)2 Cl2] Cl (c) [Pt (NH3)4 [Pt (Cl)6](d) [CO (NH3)4 Cl2 ] NO2 |
Answer» (b) [CO (en)2 Cl2] Cl |
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272. |
Which one of the following will give a pair of enantiomorphs?(a) [Cr(NH3)6][CO(CN)6] (b) [CO(en)2Cl2]Cl (c) [Pt(NH3)4][PtCl4] (d) [CO(NH3)4Cl2]NO2 |
Answer» (b) [CO(en)2Cl2]Cl |
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273. |
Which of the following complex ion is not expected to absorb visible light? (a) [Ni (H2O)6]3+ (b) [Ni (CN)4]2-(c) [Cr (NH3)6]3+(d) [Fe(H2O)6]2+ |
Answer» (b) [Ni (CN)4]2- |
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274. |
A magnetic moment of 1.73BM will be shown by one among the following …… (a) TiCl4(b) [COCl6]4-(c) [Cu(NH3)4]2+(d) [Ni(CN)4]2- |
Answer» (c) [Cu(NH3)4]2+ |
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275. |
In which of the following coordination entities the magnitude of ∆0 will be maximum?(a) [CO(CN)6]3-(b) [CO(C2O4)3]3-(c) [CO(H2O)6]3+ (d) [CO(NH3)6]3+ |
Answer» (a) [CO(CN)6]3- |
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276. |
Crystal field stabilization energy for high spin d5 octahedral complex is ………(a) – 0.6∆0 (b) 0 (c) 2 (P – ∆0) (d) 2 (P + ∆0) |
Answer» Crystal field stabilization energy for high spin d octahedral complex is 0. |
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277. |
Fill in the blanks :The spin only magnetic moment of tetrachlorido manganate (II) ion is .... |
Answer» The spin only magnetic moment of tetrachlorido manganate (II) ion is 5.9 BM |
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278. |
Gonadotropins are : A) produced by ovaries and testes B) thyroid stimulating hormones C) stimulators of ovaries and testes D) follicle stimulating hormones |
Answer» C) stimulators of ovaries and testes |
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279. |
The part of brain with the greatest influence on the endocrine system is the: A) Hypothalamus B) Medulla oblongata C) Cerebral cortex D) Pituitary |
Answer» (A) Hypothalamus |
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280. |
A farmer arranged support for cucumber plants. So that they creep and grow in normal conditions. What type of tropic movement is shown by cucumber? A) Phototropism B) GeotropismC) Hydrotropism D) Thigmotropism |
Answer» (D) Thigmotropism |
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281. |
Geometrical isomerism is exhibited by ………(a) Tetrahedral complex (b) Linear complex (c) Square planar complex (d) All the above |
Answer» (c) Square planar complex |
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282. |
Define isomerism in coordination compounds. |
Answer» Isomerism is the phenomenon in which more than one coordination compounds having the same molecular formula have different physical and chemical properties due to different arrangement of ligands around the central metal atom. |
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283. |
Using crystal field theory, explain the colour of the coordination compound. |
Answer» 1. The ligand field causes the splitting of d orbitals of the central metal atom into two sets (t2g and eg). 2. When the white light falls on the complex ion, the central metal ion absorbs visible light corresponding to the crystal field splitting energy and transmits rest of the light which is responsible for the colour of the complex. 3. This absorption causes excitation of d – electrons of the central metal ion from the lower energy t2g level to the higher energy eg level which is known as d – d transition |
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284. |
Write the formulae for the following coordination compounds:1. Tetraamminediaquacobalt (III) chloride. 2. Potassium tetracyanonickelate (II).3. Tris ( ethane – 1, 2 – diamine ) chromium (III) chloride.4. Amminebromidochloridonitrito – N – platinate (II).5. Dichlorobis(ethane – 1, 2 – diamine ) platinum (IV) nitrate. 6. Iron (III) hexacyanoferrate (II) |
Answer» 1. [CO(NH3)4(H2O)2]Cl3 2. K2[Ni(CN)4] 3. [Cr(en)3]Cl3 4. [Pt(NH3)BrCl(NO2)]- 5. [PtCl2(en)2](NO3)2 6. Fe4[Fe(CN)6]3 |
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285. |
Bethe and Van vleck proposed a coordination theory named as ………(a) Werner’s theory (b) Valence bond theory (c) Molecular orbital theory (d) Crystal field theory |
Answer» (d) Crystal field theory |
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286. |
[Fe(H2O)6]3+ is strongly paramagnetic whereas [Fe(CN)6]3- is weakly paramagnetic. Explain. |
Answer» In both the complexes, Fe is in +3 oxidation state with the configuration 3d5 . CN- is a strong field ligand. In its presence, 3d electrons pair up leaving only one unpaired electron. The hybridisation is d2 sp3 forming inner orbital complex. H2O is a weak ligand. In its presence 3d electrons do not pair up. The hybridisation is sp3d2 forming an outer orbital complex containing five unpaired electrons, hence it is strongly paramagnetic. |
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287. |
VB theory was proposed by ………(a) Alfred Werner(b) Bethe and Van vleck (c) Linus Pauling (d) Louis de Broglie |
Answer» (c) Linus Pauling |
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288. |
What are the limitations of VB theory? |
Answer» Limitations of VB – Theory: 1. It does not explain the colour of the complex 2. It considers only the spin only magnetic moments and does not consider the other components of magnetic moments. 3. It does not provide a quantitative explanation as to why certain complexes are inner orbital complexes and the others are outer orbital complexes for the same metal. For example, [Fe(CN6)]4- is diamagnetic (low spin) whereas [Fe(CN6)]4- is paramagnetic (high spin). |
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289. |
Describe about the postulate of VB theory (or) Valence bond theory. |
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Answer» 1. The ligand → metal bond in a coordination complex is covalent in nature. It is formed by the sharing of electrons between the central metal atom and electron donor ligand. 2. Each ligand should have atleast one filled orbital containing a lone pair of electrons. 3. In order to accommodate the electron pairs donated by the ligands, the central metal ion present in a complex provides required number of vacant orbitals. 4. These vacant orbitals of central metal atoms undergo hybridisation, the process of mixing of atomic orbitals of comparable energy to form equal number of new orbitals called hybridised orbitals with same energy. 5. The vacant hybridised orbitals of the central metal ion, linearly overlap with filled orbitals of the ligands to form coordinate covalent sigma bonds between the metal and the ligand. 6. The hybridised orbitals are directional and their orientation in space gives a definite geometry to the complex ion.
7. In the octahedral complexes, if the (n-l)d orbitals are involved in hybridisation they are called inner orbital complexes or low spin complexes (or) spin paired complexes. If the nd orbitals are involved in hybridisation, such complexes are called outer orbital complexes (or) high spin (or) spin free complexes. Here “n” represents the principal quantum number of the outermost shell. 8. The complexes containing a central metal atom with unpaired electron (s) are paramagnetic. If all the electrons are paired, then the complexes will be diamagnetic. 9. Ligands such as CO, CN-, en and NH3 present in the complexes cause pairing of electrons present in the central metal atom. Such ligands are called strong field ligands. 10. Greater the overlapping between, the ligand orbitals and the hybridised metal orbital, greater is the bond strength. |
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290. |
Fill in the blanks :…….. is used as a chelating ligand for the separation of lanthanides, in softening of hard water and also in removing poisoning. |
Answer» EDTA, Lead is used as a chelating ligand for the separation of lanthanides, in softening of hard water and also in removing poisoning. |
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291. |
Consider the following statements,.(i) VB theory does not explain the colour of the complex (ii) VB theory does not explain the magnetic properties (iii) VB theory does not provide a quantitative explanation about inner orbital complexes.Which of the above statements is/are not correct? (a) (i) only (b) (i) and (ii)(c) (iii) only (d) (ii) only |
Answer» (c) (iii) only |
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292. |
Which is used for the separation of lanthanides, in softening of hard water and also in removing lead poisoning? (a) [Ni (CO)4] (b) EDTA (c) [Ni(DMG)2] (d) Ti Cl4 + AI (C2H5)3 |
Answer» EDTA is used for the separation of lanthanides, in softening of hard water and also in removing lead poisoning. |
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293. |
Find the Odd one out(a) Vitamin – B12 (b) Haemoglobin (c) Chlorophyll (d) Glycine |
Answer» (d) Glycine is an amino acid whereas others are complex salts. |
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294. |
Assertion (A) – Most of the transition complexes are coloured. Reason (R) – Transition complexes absorbs the light of particular wavelength in the visible light. The transmitted light gives the complementary colour. (a) Both A and R are correct and R is the correct explanation of A. (b) A is correct but R is wrong. (c) A and R are wrong. (d) A is wrong but R is correct |
Answer» (a) Both A and R are correct and R is the correct explanation of A. |
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295. |
Consider the following statements,. (i) Complexes of central metal atom such as of Cu+ , Zn2+ are coloured (ii) Most of the transition metal complexes are colourless (iii) Negative CFSE value indicates that low spin complex is favoured Which of the above statements is/are correct? (a) (i) and (ii) (b) (iii) only (c) (ii) only (d) (i), (ii) only (iii) |
Answer» (b) (iii) only |
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296. |
Assertion (A) – Complexes of central metal atom such as of Cu+ , Zn2+ , SC3+ , Ti4+ are colourless. Reason (R) – Cu+ , Zn2+ , SC3+ , Ti4+are having d0 or d10 configuration and because of it, d – d transition is not possible and so they are colourless. (a) Both A and R are correct and R is the correct explanation of A. (b) Both A and R are correct and R is not correct explanation of A. (c) Both A and R arc wrong. (d) A is correct but R is wrong. |
Answer» (a) Both A and R are correct and R Is the correct explanation of A. |
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297. |
Cu+ , Zn2+ , Sc3+ , Ti4+ are colourless. Prove this statement. |
Answer» Cu+ , Zn2+ have d configuration and Sc3+ , Ti4+ have d10 configuration. 2. d – d transition is not possible in the above complexes. So they are colourless. |
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298. |
[Ti(H2O)6]3+ is coloured, while [Sc(H2O)6]3+ is colourless- explain. |
Answer» Ti in [Ti(H2O)6]3+ is in +3 oxidation state. Sc in [Sc(H2O)6]3+ is in +3 oxidation state. The outer electronic configuration of Sc, Ti and their trivalent ions are, SC: 3d1 4S2 SC3+ : 3d0 Ti: 3d2 4S2 Ti3+ : 3d1 Ti3+ has one unpaired electron in 3d orbital and they undergoes d-d transition. This electron can be promoted to a higher energy level by light absorption. Therefore [Ti(H2O)6]3+ is coloured. In the case of [Sc(H2O)6]3+ there is no electron in 3d orbital of Sc3+ , hence there is no possibility of light absorbance. Therefore [Sc(H2O)6]3+ is colourless. |
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299. |
[CuCl4]2- exists while [CuI4]2- does not exist why? |
Answer» 1. In [CuI4]2- complex, the size of chloride ion is less hence exist. But in [CuI4]2- the bigger iodide ion makes the compound unstable. 2. When copper cation comes in contact with iodide anion, iodide get oxidised to iodine molecule hence the formation of the above complex ion does not take place. Hence [CuI4]2- exists while [CuI4]2- does not exist. |
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300. |
How many division of brain? |
Answer» The brain has three divisions: 1. Forebrain: The forebrain consists of the cerebrum, diencephalon. 2. Midbrain: Midbrain has optic lobes. 3. Hindbrain has cerebellum, medulla oblongata. |
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