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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
601. |
Which of the ion is colourless?A. `Gd^(+3)`B. `Pr^(+3)`C. `Sm^(+3)`D. `Tm^(+4)` |
Answer» Correct Answer - A Gold (64) `to [Xe] 4f^7 5d^1 6s^2` `Gd^(3+) to [Xe] 4f^7 5d^0 6s^0` This configuration is extra stable . Since it is half filled f-subshell. Therefore f-f transition does not occur hence colourless. |
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602. |
`La^(+3)` ion gives a colourless compound due toA. completely filled 4f subshellB. empty 4f subshellC. half filled 4f subshellD. unpaired electron |
Answer» Correct Answer - B `La (57) to [Xe] 4f^0 5d^1 6s^2 to La^(3+) to [Xe] 4f^0 5d^0 6s^0` No `e^-` in 4f orbitals . `therefore` colourless |
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603. |
Lanthaide element isA. AcB. AlC. NdD. Pd |
Answer» Correct Answer - C Nd is lanthanoid element, atomic no. 60, 4f series |
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604. |
The most stable state of Ce (Z = 58) isA. 2B. 3C. 4D. 5 |
Answer» Correct Answer - C Ce (58) `to [Xe] 4f^2 5d^0 6s^2 to underset"Stable state "(Ce^(4+) to [Xe]) 4f^0 5d^0 6s^0` |
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605. |
`Ce^(4+)` is stable .This is because ofA. empty orbitalsB. half filled orbitalsC. completely filled orbitalsD. no unpaired electrons |
Answer» Correct Answer - A `Ce(58) to [Xe] 4f^2 5d^10 6s^2 to Ce^(4+) to [Xe] 4f^0 5d^0 6s^0` Empty `4f^0` orbitals in `Ce^(4+)` |
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606. |
Which one of the following transition metal ions is paramagnetic?A. `Ag^+`B. `Cu^(2-)`C. `Zn^(2+)`D. `Cd^(2+)` |
Answer» Correct Answer - B `Cu^(2+)` has `d^9` configuration with one unpaired electron and is paramagnetic whereas `Ag^(+) , Zn^(2+) ` and `Au^+` have `d^10` configuration and are diamagnetic |
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607. |
Which one of the following is an example of non-typical transition elements?A. `Li, K , Na`B. `Be, Al , Pb`C. `Zn, Cd, Hg`D. `Ba, Ca, Sr` |
Answer» Correct Answer - C Zn, Cd and Hg are non typical transition elements because they have complete d-orbitals. |
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608. |
Which one of the following is an example of non-typical transition elements?A. Ag, Au, PtB. Fe, Co, NiC. Zn, Cd, HgD. Sc, Y, Ac |
Answer» Correct Answer - C Non-typical transition element are Zn, Cd, Hg as they have completely filled (n-1) d and ns orbitals. Electronic configuration for them is `{:(Zn,3d^10,4s^2),(Cd,4d^10,5s^2),(Hg, 5d^10,6s^2):}` |
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609. |
The transition metals mostly areA. DiamagneticB. ParamagneticC. neither diamagnetic nor paramagneticD. both diamagnetic and paramagnetic |
Answer» Correct Answer - B Paramagnetic due to presence of unpaired electrons in (n-1)d orbitals |
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610. |
Which one of the following pairs of ions have the same electronic configuration?A. `Cr^(+3), Fe^(+3)`B. `Fe^(+3) , Mn^(+2)`C. `Fe^(+3) , Co^(+2)`D. `Sc^(+3) , Cr^(+3)` |
Answer» Correct Answer - B `Fe^(+3)` configuration is `3d^5 4s^0` and `Mn^(+2)` configuration is `3d^5 4s^0`. Therefore `Fe^(+2), Mn^(+2)` have same electronic configuration |
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611. |
A transition metal exists in its highest oxidation state.It is expected to behave asA. a chelating agentB. a central metal in a coordination compoundC. an oxidizing agentD. a reducing agent. |
Answer» In the highest oxidation state, it can undergo reduction and hence acts as oxidizing agent, e.g., in `KMnO_(4)`, Mnis in `+7` oxidation state. It is one of the strongest oxidizing agent in solution. | |
612. |
Four successive membersof the first series of the transition metals are listed below.For which one of them, the standard potential `E_(M^(2+) //M)^(@)`value has a positive sign ?A. `Cu(Z= 29)`B. `Fe(Z= 26)`C. `Co( Z=27)`D. `Ni(Z= 28)` |
Answer» Copper does not liberate `H_(2)` gas from acids and thus shows positive valueof `E^(@) ( E^(@) ` for `Cu^(2+)//Cu`is `+0.34V)`. For other metals, `E^(@)` value is negative. | |
613. |
Which of the following represents the correct order of the properties inidicated?A. `Ni^(2+)gtCr^(2+)gtFe^(2+)gtMn^(2+)` (size)B. `ScgtTigtCrgtMn` (size)C. `Ni^(2+)ltCo^(2+)ltFe^(2+)ltMn^(2+)` (unpaired electron)D. `Cr^(3+)gtCr^(2+)` (magnetic moment) |
Answer» Correct Answer - b,c | |
614. |
Which of has the highest number of unpaired electrons?A. `Sc^(+2)`B. `Ni^(+2)`C. `Cu^(+2)`D. `Mn^(+2)` |
Answer» Correct Answer - D | |
615. |
Lucas reagent is `,`A. `MnO_2 + HCI`B. `HCI + HNO_3`C. `ZnCl_2` + conc. HCID. HCI + `H_2SO_4` |
Answer» Correct Answer - C Lucas reagent is Anhydrous `ZnCl_2` + conc. HCl |
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616. |
The correct statement for d-block element isA. it shows magnetic propertyB. It has variable valencyC. It has tendency of formation of coloured ions.D. it has complete d-orbitals. |
Answer» Correct Answer - a,b,c | |
617. |
The range of wavelength of the visible light isA. 500 A - 2000 AB. 2000 A - 4000 AC. 4000 A - 8000 AD. gt 8000 A |
Answer» Correct Answer - C | |
618. |
The decrease in the size of innce transition element is qA. moreB. lessC. not regularD. none of these |
Answer» Correct Answer - B We know that from Ce to lu atomic number increaes by 14, the decrease in atomic and ionic size is very small only 10 pm and 18 pm respectively. This is very small in comparison to elements of the other periods. This is due to poor shielding of 4f electrons. |
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619. |
Basic nature of compounds ofA. lanthanide `gt ` actinideB. lanthanide `lt `actinideC. lathanide = actinideD. none is correct |
Answer» Correct Answer - B We know that, basic nature of compound, depends upon degree of dissociation, more the dossociation of compound, more the basicity. Dissociation of compound depends upon bond length between metal and hydroxy group i.e. Dissociation of compound depends upon bond length betwen metal and hydroxy group i.e. M-OH. More the bond length more the dissociation. Actinides are larger size than lanthanides. Hencxe actinides compounds are more basic than lanthnide compounds. |
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620. |
The stability of particular oxidation state of a metal in aqueous solution is determined byA. Enthalpy of sublimation of the metalB. Ionisation energyC. Enthalpy of hydration of the metal ionD. All of these |
Answer» Correct Answer - d `M_((s))toM^(n+)+"ne"^(ɵ)` This changes involve sublimation, ionisation and hydration. |
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621. |
Which of the following is not a condition for complex formation?A. Small sizeB. Higher nuclear chargeC. Availability of vacant d orbitalsD. Variable Oxidation State |
Answer» Correct Answer - D | |
622. |
When an orange coloured crystallc compound [A] was heated with common salt and concentrated sulphuric acid , an orange red coloured gas [B] was evolved. The gas [B] on passing through NaOH solution gave a yellow solution [C] . The solution on reacting with an aqueous solution of lead acetate gave a yellow precipitate. The yellow solution [C] contains mainlyA. Sodium sulphateB. Sodium chromateC. Sodium dichromateD. Potassium chromate. |
Answer» Correct Answer - B (b) The yellow solution (C) contains sodium chromate `(Na_(2)CrO_(4))` which is formed on reacting chromyl chloride with sodium hydroxide (NaOH) solution `CrO_(2)Cl_(2)+4NaOH to underset("(yellow solution)")(Na_(2)CrO_(4))+2NaCl+2H_(2)O` |
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623. |
When an orange coloured crystallc compound [A] was heated with common salt and concentrated sulphuric acid , an orange red coloured gas [B] was evolved. The gas [B] on passing through NaOH solution gave a yellow solution [C] . The solution on reacting with an aqueous solution of lead acetate gave a yellow precipitate. This gas [B] is :A. ChlorineB. bromineC. chromyl chorideD. nitrogen percipitate. |
Answer» Correct Answer - C (c) The orange red gas formed during the reaction is of chromyl chloride `(CrO_(2)Cl_(2))` |
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624. |
When an orange coloured crystallc compound [A] was heated with common salt and concentrated sulphuric acid , an orange red coloured gas [B] was evolved. The gas [B] on passing through NaOH solution gave a yellow solution [C] . The solution on reacting with an aqueous solution of lead acetate gave a yellow precipitate. The crystalline compound [A] is:A. Cobalt nitrateB. manganese sulphateC. Potassium dichromate.D. Ammonium dichromate. |
Answer» Correct Answer - C (c) The available information suggests that the orange coloured compound is `K_(2)Cr_(2)O_(7)`. |
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625. |
Which of the following is not a condition for complex formation?A. Small atomic sizeB. High nuclear chargeC. Variable oxidation statesD. Availability of vacant d orbitals |
Answer» Correct Answer - c Tendency of an element to form complexes does not depend on whether the element shows variable O.S. or not. |
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626. |
Both acid and base may react with which of the following oxides?A. CaOB. `Na_2O_2`C. `ZnO`D. `Mn_3O_4` |
Answer» Correct Answer - c Only ZnO is amphoteric. It dissolves both in acids and alkalies. |
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627. |
As increase in both atomic and ionic radii with atomic number occurs in any group of the periodic table and in accordance with this, the ionic radii of `Ti^(4+) and Zr ^(4+)` ion are 68 Pm and 74 Pm respectivelt. But for `Hf ^(4+)` ion, the ionci radius is 75 Pm. Which is most same as that for `Zr ^(4+)` ion. This is due toA. greater degree of covalency in compound of `Hf ^(4+)`B. lanthanide contractionC. difference in co-ordination number of `Zr ^(4+) and Hf ^(4+)` in their compoundD. actinide contraction |
Answer» Correct Answer - B In the same group atomic size increases ad atomic number increaes. But due to the lanthanide contraction atomic size of the elements just following Hf, Ta, W, Re, Os, etc. onwards are close to the element just above them in the respective group i.e. Zr, Nb, Mo, Tc, Ru etc. Due to the same size of Hf and Zr, Ta and Nb, W and Mo, Re and Tc, Os and Ru etc., the two properties and they occurs together in nture and are difficult to separate. This pair of elements is known as chemical twins. As a result of lanthanide contraction the elements of `2 ^(nd)and 3^(rd)` row transition series (d-block) resembles each other much more than the elements of `1^(st) and 2^(nd)` row trsnsition series. So they do not shwo close similarities. |
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628. |
Which of the following salt give coloured aqueous solution ?A. `Cu_2Cl_2`B. `CuCl_2`C. `ZnCl_2`D. `ZnSO_4` |
Answer» Correct Answer - B | |
629. |
The aqueous solution of the salt will be coloured in the case ofA. `Zn(CO_3)_2`B. `LiNO_3`C. `Cl(NO_3)_2`D. `CrCl_3` |
Answer» Correct Answer - c,d | |
630. |
Which is not amphoteric?A. `Al^(3+)`B. `Cr^(3+)`C. `Fe^(3+)`D. `Zn^(2+)` |
Answer» Correct Answer - c `Al^(3+)`, `Cr^(3+)` and `Zn^(2+)` are amphoteric i.e., `Al_2O_3`,`Cr_2O_3` and ZnO dissolve both in acids and alkalies. `Fe^(3+)` is distinctly basic. `Fe_2O_3` dissolves only in acids. |
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631. |
Copper displaces Which of the metal from their salt solutions?A. `AgNO_3`B. `ZnSO_4`C. `FeSO_4`D. `MgSO_4` |
Answer» Correct Answer - A Cu will displace Ag from `AgNO_3` solution as Cu is placed above Ag is emf series (group of Cu gt group of Ag). |
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632. |
An increase in both atomic and ionic radii with atomic number occurs in any group of the perioidc table and in accordance with this, the ionic radii of Ti (IV) and Zr (IV) ionc are 0.68 `A^(@) and 0.74A^(@)` respectively, but for Hf (IV) ion the ionic radius of `0.75A^(@),` which is almost the same as that for Zr (IV) ion. This is due toA. greater degree of covalency in compounds of `Hf^(4+)`B. alntanide contractionC. difference in the coordination number of `Zr^(4+) and Hf^(4+)` in their compoundsD. actinide contraction. |
Answer» Correct Answer - B Normal size increase on moving down the group from Zr to Hf is almost exactly balanced by lanthanide contraction. Lanthanide contraction is the steady decrease in the radii as atomic number of lanthanide elements increases. |
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633. |
Most of the d block elements are known as:A. Normal elementsB. lnert elementsC. Transition elementsD. Inner- transition elements |
Answer» Correct Answer - C | |
634. |
Which of the following ions is not amphoteric?A. `Al^(+3)`B. `Cr^(+3)`C. `Zn^(+2)`D. `Fe^(+3)` |
Answer» Correct Answer - D `Fe^(+3)` is basic in nature whereas `Al^(+3) , Cr^(+3)` and `Zn^(+3)` are amphoteric in nature. |
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635. |
Which of the following pairs is coloured in aqueous solution?A. `Ni^(2+),Cu^(+)`B. `Ni^(2+),Ti^(3+)`C. `Sc^(3+),Ti^(3+)`D. `Sc^(3+),Co^(2+)` |
Answer» Correct Answer - B Both `Ni^(2+)(3d^(8))` and `Ti^(3+)(3d^(1))` have unpaired electrons, Therefore, these are coloured only in the case. |
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636. |
Among the following pairs of ions, the lower oxidation state in aqueous solution is more stable than the other , inA. `Tl^(+),Tl^(3+)`B. `Cu^(+),Cu^(2+)`C. `Cr^(2+),Cr^(3+)`D. `V^(2+), VO^(2+)` |
Answer» `Tl^(+)`is more stable than `Tl^(3+)`due to invert pair effect ( Tl belongs to Group 13 and is the last element of the Group ). | |
637. |
Which of the following is highest paramagneticA. MnB. ZnC. CuD. Co |
Answer» Correct Answer - A Paramagnetism depends upon number of unpaired electrons, more the number of unpaired electrons more the paramagnetic property. Mn has `d^(5)` configuration (five unpaired electrons) hence it is highly paramagnetic. Zn has `d^(10)` configuration (All electrons are paired) Co has `d ^(7)` configuration (Three unpaired electrons) |
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638. |
Which of the following is the stable electron configuration of `Fe^(+3)`ionA. `[Ar] 4s^2 3d^6`B. `[Ar] 3d^5`C. `[Ar] 3d^6`D. `[Ar] 4s^2 3d^4` |
Answer» Correct Answer - B | |
639. |
Which one of the following properties is not a transition elementsA. colourB. catalytic activityC. fixed valencyD. paramagnetism |
Answer» Correct Answer - C Transition metals have variable valence and not fixed valence |
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640. |
`Cu^(+)`and `Cu^(+2)` areA. ParamagneticB. DiamagneticC. Diamagnetic and paramagneticD. Paramagnetic and diamagnetic respectively |
Answer» Correct Answer - C `Cu^(+) to [Ar] 4s^0 3d^10 to` Dimagnetic - All paired `e^-` `Cu^(2+) to [Ar] 4s^0 3d^9 to` Paramagnetic `to ` One unpaired `e^-` |
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641. |
Transition elemtns are colouredA. small sizeB. metallic natureC. unpaired d - electronD. reflection of light |
Answer» Correct Answer - C Unpaired `e^-` in d-orbitals leads to d-d transition |
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642. |
Diamagnetic character arises fromA. spinning motion of paired electronsB. spinning motion of unpaired electronsC. orbital motion of electronsD. spinning motion of protons |
Answer» Correct Answer - A Spin of pair of `e^-` |
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643. |
Diamagnetism is the property ofA. non-transitional elementsB. unpaired electronsC. completely filled electronic sub-shellsD. half filled degenerate orbitals |
Answer» Correct Answer - C Completely filled sub-shell `to` all paired `e^-` `therefore` Dimagnetism |
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644. |
Maximum paramagnetic character would be shown byA. `KMnO_4`B. `K_2MnO_4`C. `K_2Cr_2O_7`D. `K_3CrF_6` |
Answer» Correct Answer - D `{:(,+3 +3 -6),(K_3 Cr F_6 ",",K_3 " "Cr" "F_6),(,+1 " "-1):}` `Cr^(3+) to [Ar]4s^0 3d^3 to `Maximum unpaired `e^-` |
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645. |
Which of the following set has all the coloured ions ?A. `Cu^(+), Cu^(2+), Ni^(2+)`B. `Cu^(2+), Ca^(2+), Sc^(2+)`C. `Cu^(2+), Fe^(2+), Co^(2+)`D. `Na^(+), Mg^(2+), Al^(3+)` |
Answer» Correct Answer - C In set `Cu^(2+), Fe ^(2+), Co^(2+),` all th ions have unpaired d-electrons. Hence, they are all coloured ions. `Cu^(2+)to [Ar] 3d^(9)4s^(0)` `Fe ^(2+)to [Ar] 3d^(6)4s^(0)` `Co^(2+)to [Ar] 3d^(7)4s^(0).` |
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646. |
Which of the following statements is not true in regard to transition elementsA. Show variable valencyB. Paramagnetic in natureC. does not impart colour to flameD. Act as catalytic agent |
Answer» Correct Answer - C Impart colour to the flame |
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647. |
Which of the following statements is not true in regard to transition elementsA. They readily form complex compoundsB. They show variable valencyC. All their ions are colourlessD. Their ions contain partially filled d-electron levels |
Answer» Correct Answer - C "All their ions are colourless" this sentence is false because they are `90%` coloured and only few are colourless. |
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648. |
Which of the following is more ionic hydroxide ?A. `Eu (OH)_(3)`B. `Pr (OH)_(3)`C. `Tm(OH)_(3)`D. `Ho(OH)_(3)` |
Answer» Correct Answer - B | |
649. |
Which of the following pair of atoms have similarA. Hf and OsB. W and MoC. Hf and NbD. Ta and Mo |
Answer» Correct Answer - B | |
650. |
Which ore contains both iron and copper?A. cupriteB. chalcociteC. chalcopyriteD. malachite |
Answer» Correct Answer - C (c) Chalcopyrite `(CuFeS_(2))` contains both Cu and Fe. |
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