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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
651. |
Important ore of iron isA. GarnieriteB. PentalanditeC. HaematiteD. Smaltite |
Answer» Correct Answer - c Haematite `(Fe_2O_3)` is an ore of iron. Garnierite is hydrated double silicate of Mg and Si having `5-8%` Ni. |
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652. |
Which of the following oxides of Cr is amphoteric.A. `CrO_2`B. `Cr_2O_3`C. `CrO_5`D. `CrO_3` |
Answer» Correct Answer - a Acidic nature of oxides increases with the increase in O.S. Of the metal atom e.g. `Cr_2O_3` is basic. `CrO_2` is acidic `CrO_5` is also acidic in nature. |
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653. |
When `(NH_4)_2CrO_2O_7` is heated, the gas evolved isA. `N_2`B. `NO_2`C. `O_2`D. `Na_2O` |
Answer» Correct Answer - a Due to the formation of `Cr^(3+)` from `Cr_2O_7^(2-)` and the solution turns green. |
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654. |
Blister copper is `98%` copper. |
Answer» Correct Answer - True. | |
655. |
Which of the following d-block elements has `d^(10)` configuration ?A. `Cu, Ag, An`B. `Zn, Cd, Hg`C. `Fe, Co, Ni`D. `Ru, Rh, Pd` |
Answer» Correct Answer - B | |
656. |
The transition elements are so named becauseA. they shows reducing propertyB. their properties are similar to other elementsC. their properties are different from other elementsD. they have party filled d-orbitals |
Answer» Correct Answer - D | |
657. |
Which one of the following elements exhibits highest valency ?A. MnB. OsC. WD. Mo |
Answer» Correct Answer - B | |
658. |
The atomic radii of transition series elementsA. increas as thatomic number increases.B. decrease as atomic number increases.C. remains almost constant.D. increase as atomic mass decreases. |
Answer» Correct Answer - B | |
659. |
Why does Mn(III) undergo disproportionation reaction easily ? |
Answer» Mn(III) is highly unstable as it is clear from its very `E_(Mn^(3+)//Mn^(2+))^(@)` value (+1.57 V). As such, it undergoes disproportionation reaction as follows: `2Mn^(3+)(aq) to Mn^(2+)(aq)+Mn^(4+)(aq)` |
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660. |
The stability of ferric ion is due toA. Half- filled f-orbitalsB. half-filled d-orbitalsC. completely filled f-orbitalsD. completely filled d-orbitals |
Answer» Correct Answer - B `Fe^(3+)` ion has the following configuration . `Fe^(3+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6)3d^(5)` Thus, ferric ion is quite stable due to half-filled d-orbital `(3d^(5))`. |
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661. |
The stability of ferric ionis due toA. half-filled d-orbitalsB. half-filled f-orbitalsC. compltetly filled d-orbitalsD. completely filledf-orbitals |
Answer» `Fe(Z= 26) = 3d^(6)4s^(2)` `:. Fe^(3+) = 3d^(5)` . Thus`,Fe^(3+)` ion is quite stabledue to half-filled d-orbitals. |
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662. |
Which one of the following ions is the most stable in aqueous solutions ? (At. No. `Ti=22, V=23, Cr= 24 , Mn = 25)A. `Mn^(2+)`B. ` Cr^(3+)`C. `V^(3+)`D. `Ti^(3+)` |
Answer» Out of the given species, `Cr^(3+)` has the highest negative reduction potential.Hence, it cannot be reduced to `Cr^(2+)` and, therefore, is the most stable ion in aqueous solution. Alternatively, `Mn^(3+) = [ AAr] 3d^(4) , Cr^(3+)= [Ar]3d^(3)` `V^(3+) =[Ar]3d^(2)Ti ^(3+) = [ Ar] 3d^(1)` In `Cr^(3+)`, all three d electrons enter into lower energy `t_(2g)` orbitals. The lowering of energy is maximum and hence stability is maximum. |
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663. |
The common oxidation state of transition elements isA. `+2`B. `+4`C. `+3`D. `+7` |
Answer» Correct Answer - A | |
664. |
(a). Explain why `Mn^(3+)` is less stable than `Mn^(22+)` and `M^(4+)` ions? (b). Standard reduction potential of copper is greatr than that of hydrogen yet is librates hydrogen from a concentrated solution of hydrochloric acid. Explain this fact with proper reasoning. `Cu^(2+)+2etoCu_(s)` `E_((Cu^(2+))/(Cu))^(ɵ)=0.34"volt"` `2H^(o+)+2etoH_(2(g))` `E_((H^(o+))/(H_2))=0.00"volt"` (c). An aqueous solution of `FeCl_3` is slightly yellowish in colour. (d). `Cu(I)` compounds are not known in aqueous solution. |
Answer» (a). `Mnto3d^5,4s^2`, `Mn^(3+)to3d^4,4s^(0)` `Mn^(2+)to3d^5,4s^0`,`Mn^(4+)to3d^3,4s^0` On the basis of electron configuration `Mn^(2+)` and `Mn^(4+)` are expected to be more stable, hence `Mn^(3+)` undregoes disproportionation. `2Mn^(3+)toMn^(2+)+(mn^(4+)` (b). When copper is treated with conc.HCl then formation of stable complex ion `[CuCl_4]^(2-)` along with liberation of `H_2` gas takes place. `Cu+4HCl_((conc.))to[CuCl_4]^(2-)+2H^(o+)+H_2uarr]` (c). An equeous solution of `FeCl_3` is colloidal. It is yellowish in colour due to Tyndall Effect. (d). `Cu(I)` compounds undergo disproportionation in aqueous medium. `Cu_2Cl_2toCuCl_2+Cu` |
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665. |
The most stable oxidation state of copper isA. `+1`B. `+2`C. `+3`D. `+4` |
Answer» Correct Answer - A | |
666. |
Transitions elements show generally positive oxidation state due toA. large atomic sizeB. low inization energyC. low electronegativityD. high electronegativity |
Answer» Correct Answer - C | |
667. |
Which element does not show variable oxidation state ?A. ScB. VC. FeD. Hg |
Answer» Correct Answer - a | |
668. |
which forms interstitial compounds?A. FeB. CoC. NiD. All |
Answer» Correct Answer - D All transition metals form interstitial compounds |
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669. |
The pair of elements which can show +1 odidation state.A. `Cr, Zn`B. `Fe, Zn `C. `Cr, Cu`D. `Cu, Zn` |
Answer» Correct Answer - C | |
670. |
Formation of interstitial compound makes the transition metalA. more softB. more ductileC. more metallicD. more hard |
Answer» Correct Answer - D Vacant spaces in the lattice are occupied by smaller atoms, that gives hardness. |
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671. |
Variable oxidation state is shown byA. normal elementsB. metallic elementsC. nonmetallic elementsD. transition elements. |
Answer» Correct Answer - D | |
672. |
Anhydrous ferric chloride is prepared byA. Heating hydrated ferric chloride at a high temperature in a stream of air.B. Heating metallic iron in astream of dry chlorine gasC. Reaction of ferric oxide with HClD. Reaction of metallic iron with HCl |
Answer» Correct Answer - B By heating metallic iron in a stream of dry chlorine gas. `2FE+3Cl_2to2FeCl_3` |
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673. |
Which of the following is an organometallic compound?A. Lithium methoxideB. Lithium acetateC. Lithium dimethylamideD. methyl lithium |
Answer» Correct Answer - D Organometallic compound are those compounds in which metal atom is directly bonded with C atom. Methyl lithium is one such compound. |
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674. |
Among the following, identify the species with an atom in `+6` oxidation state.A. `MnO_4^(ɵ)`B. `[Cr(CN)_6]^(3-)`C. `[NiF_6]^(2-)`D. `CrO_2Cl_2` |
Answer» Correct Answer - D `MnO_4^(ɵ)implies(Mn=+7)[Cr(CN)_6]^(3-)impliesCr(+3)` `[NiF_6]^(2-)implies(Ni=+2)CrO_2Cl_2implies(Cr=+6)` |
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675. |
The reason for the stability of `Gd^(3+)` ion isA. 4f-subshell-half filledB. 4f subshell-completely filledC. Possesses the general electronic configuration of noble gasesD. 4f-subshell empty. |
Answer» Correct Answer - a `Gd(Z=64)implies4f^75d^16s^2` `Gd^3=4f^7` `Gd^(3+)` is stable due to the presence of exactly half-filled 4f-subshell. |
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676. |
Arrange `(I)Cr^(3+),(II)La^(3+),(III)Pm^(3+)` and `(IV)Yb^(3+)` in increasing order of their ionic radii.A. `IVltIIIltIltII`B. `IltIVltIIIltII`C. `IVltIIIltIIltI`D. `IIIltIIltIltIV` |
Answer» Correct Answer - a Ionic radii decrease across lanthanide series due to lanthanide contraction. As all ions are in `+3` O.S. ionic radii will follow the trend of atomic radii. `La^(3+)gtCe^(3+)gtPm^(3+)gtYb^(3+)` |
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677. |
Anelement which is highly toxic for plants and animals is-A. AuB. MnC. HgD. Ca |
Answer» Correct Answer - C `HgCl_(2)` is dangerous poison, the antidote being white of an egg which is coagulated by the salt in the system and is eliminated by the system with salts absorbed in it, also `Hg` itself is very poisonous. |
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678. |
(a) How do you prepare `:` (i) `K_(2)MnO_(4)` from `MnO_(2)` (ii) `Na_(2)Cr_(2)O_(7) ` from `Na_(2)CrO_(4)` ? (b) Account for the following `:` (i) `Mn^(2+)` is more stable than `Fe^(2+)` towards oxidation to `+3` state. (ii) The enthalpy of atomisation is lowest for Zn in 3d series of transition elements. (iii) Actinoid elements show wide range of oxidation states. or (i) Name the elements of 3d transition series which shows maximum number of oxidation states. Why dows it show so ? (ii)Which transition element of 3d series has positive `E_(M^(+)//M)^(@)` value and why ? (iii) Out of `Cr^(3+)` and `Mn^(3+)` which is stronger oxidizing agent and why ? (iv) Name a member of the lanthanoid series which is well known to exhibit `+2`oxidation state. (v) Complete the equation `: ` `MnO_(4)^(-) +8 H^(+) + 5e^(-) rarr` |
Answer» (i) Mn, (ii)Cu, (ii) `Mn^(3+)`, `(E_(M^(+)//Mn^(2+))^(@)= + 1.57V)` (iv) `Eu^(2+)` due to exactly half filled `f^(7)` configuration and `Yb^(2+)` due to completely filled `f^(14)` configuration (v) `MnO_(4)^(-) +8 H^(+)+ 5e^(-) rarr Mn^(2+) 4H_(2)O)` |
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679. |
Give balance chemical equation for the following : (i) Silverf nitrate is added to dilute sodium thiosulphate solution. (ii) Potassium dichromate is treated with acidified ferrous sulphate solution. |
Answer» (i) `2AgNO_(3)+Na_(2)S_(2)O_(3) to Ag_(2)S_(2)O_(3) +2NaNO_(3)` (ii) `K_(2)Cr_(2)O_(7)+7H_(2)SO_(4) +6FeSO_(4) to K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3Fe_(2)(SO_(4))_(3)+7H_(2)O` |
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680. |
When sulphur dioxide gas is passed throught acidified potassium dichromate solution, the colour of the solution changes from:A. orange to blueB. orange to greenC. green to orangeD. orange to colourless |
Answer» Correct Answer - B `K_2Cr_2 O_7 + 4H_2SO_4 to K_2SO_4 + underset"Green"(Cr_2(SO_4)_3) + 4H_2O + 3[O]` `SO_2 + [O] + H_2O to H_2SO_4` |
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681. |
In context of the lanthanoids, which of the following statements is not correct?A. There is gradual decrease in the radii of the members with increasing atomic number in the seriesB. All the members exhibit +3 oxidation stateC. Because of similar properties the separation of lanthanoids in not easyD. Availability of 4f electrons results in the formation of compounds in +4 state for all members of the series |
Answer» Correct Answer - D | |
682. |
In context of the lanthanoids, which of the following statements is not correct?A. There is a gradual decrease in the radii of the members with increasing atomic number in the seriesB. All the members exhibit + 3 oxidation stateC. Because of similar properties, the separation of lanthanoids is not easyD. Availability of 4f electrons results in the formation of compounds in + 4 state for all the members of the series |
Answer» Correct Answer - D Formation of + 4 state requires very high energy, thus incorrect. |
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683. |
Which of the following is radioactive element among the 4-f series ?A. CeB. PmC. HoD. Yb |
Answer» Correct Answer - B All lanthanide mineral contains all elements except Pm. Which is radioactive |
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684. |
Actinum isA. f-block elementB. d-block elementC. p-block elementD. s-block element |
Answer» Correct Answer - B Actinium is d-block element because its has electronic configuration `7s ^(2) , 5f^(0), 6d^(1).` |
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685. |
Actinum is the element ofA. transition seriesB. inner transition seriesC. 5f seriesD. none of these |
Answer» Correct Answer - A We know that, actinium has electronic configuration `7s^(2), 5f^(0), 6d^(1).` No electrons in 5f orbital. Hence it is niot f-block element. It is d-block or transition element. |
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686. |
The total number of rare earth elements isA. 8B. 32C. 14D. 10 |
Answer» Correct Answer - C 4f series elements also known as rare earth, are 14. |
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687. |
Which of the following can exhibit +4 oxidation state?A. LaB. CeC. EuD. Gd |
Answer» Correct Answer - B Ce can exhibit +4 oxidation state. Electronic configuration of Ce is `[Xe]4f^2 5d^0 6s^0 ` . It loses 2 electrons from 4f and 2 electrons from 6s orbitals and gives stable electronic configuration for `Ce^(+4)` ion `[Xe] 4f^0 5d^0 6s^2` |
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688. |
Why in any transition series, melting points first increase and then decrease and also they show a dip in the middle? |
Answer» Milting points first increase because the number of unpaired electrons increases and hence strength of metallic bond increases. After reaching the maximum, the melting points decrease because the pairing of electrons starts in the d-subshell and number of unpaired electrons decreases and so the strength of metallic bond decreases. The dip in the middle is due to exactly half-field configuration of d-subshell which has higher stability. Hence electrons are held tightly by the nucleous .As a result metallic bond is weaker. | |
689. |
Why does vanadium pentaoxide act as a catalyst? |
Answer» Vanadium exists in multiple oxidation states. | |
690. |
Write all possible oxidation states of an element having atomic number 25 |
Answer» E.C.of `._(25)Mn= [Ar]^(18) 3d^(5) 4s^(2)`. It shows oxidation states of`+2, +3,+4,+5,+6` and `+7`. | |
691. |
Why in any transition series, melting points first increase and then decrease and also they sow a dip in the middle ? |
Answer» Melting points first increase because the number of unpaired electrons increasesand hence strength of metallic bondincreases. After reaching themaximum, the melting points decrease the pairing of electrons starts in the d-subshell and number of unpaired electrons decreases and so the strength of metallic bond decreases. Thedip in teh middle is due to exactly half-filled configuration of d-subshell which has higher stability . Hence, electrons are held tightly by the nucleus. As a result , metallic bond is weaker. | |
692. |
Why hydrated copper sulphate is blue while anhydrous copper sulphate is white ? |
Answer» In hydrated copper sulphate , four water molecules are present as ligands. In the presence of these ligands d-orbitals are no longer degenerate in energy. Hence, d-d transition takes place absorbing red wavelength. The complementary colour, viz, blue is reflected . In anhydrous`CuSO_(4)`, d-orbitals remain degenerate.Hence,no d-d transition can occur. The white light is completely reflectedback. Hence, it looks white. | |
693. |
A hydrated metallic salt A, light green in colour, gives a white anhydrous residue B after being heated gradually. B is soluble in water and its aqueous solution reacts with NO to give a dark brown compound C. B on strong heating gives a brown resiodue D and a mixture of two gases E and F. The gaseous mixture, when passed through acidified `KMnO_4` discharges the pink colour, when passed through acidified `BaCl_2` solution, gives a white precipitate. Identifty A, B, C, D, E and F |
Answer» `FeSO_4.7H_2O(A)overset(triangle)toFeSO_4(B)` (White) `FeSO_4+No overset(H_2O)to[Fe(H_2O)_5NO]SO_4(C)` `FeSO_4overset(triangle)toFe_2SO_3(D)+SO_3(E)+SO_3(F)` `SO_2+SO_3+KMnO_4toMn^(2+)` (pink solution) `SO_2+SO_3+BaCl_2toBaSO_4` (White precipitate) |
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694. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition element, which shows highest magnetic moment.A. `3d^(7)`B. `3d^(5)`C. `3d^(8)`D. `3d^(2)` |
Answer» Correct Answer - B (b) The element with `3d^(5)` configuration has maximum unpaired electrons. It shows highest magnetic movement. |
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695. |
`MnO_(4)^(2-)` in acidic solution undergoes disportionation to give `"…....................."` and `"…..................."`. |
Answer» Correct Answer - `MnO_(4)^(-), MnO_(2)` | |
696. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements, which shows highest magnetic moment.A. `3d^(7)`B. `3d^(5)`C. `3d^(8)`D. `3d^(2)` |
Answer» Correct Answer - b `3d^(5)` has maximum unpaired electrons `( = 5)`. |
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697. |
Which of the following reactions are disproportionation reactions ?A. `Cu^(+) rarr Cu^(2+) + Cu`B. `3MnO_(4)^(-) + 4H^(+) rarr 2MnO_(4)^(-) + MnO_(2)+ 2H_(2)O`C. `2KMnO_(4) +rarr K_(2)MnO_(4) + 2H_(2)O`D. `2MnO_(4)^(-) + 3Mn^(2+) + 2H_(2)O rarr 5MnO_(2) + 4H^(+)` |
Answer» Correct Answer - a In (i) , `Cu^(+)` is oxidized as well as reduced. In (ii) , `MnO_(4)^(-)` ions are oxidised as well as reduced. |
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698. |
When heated strongly , `KMnO_(4)` decomposes to form `"…..................."` and `"….................."` |
Answer» Correct Answer - `K_(2)MnO_(3) , O_(2)` | |
699. |
Which one of the following reactions involves disproportionation ?A. `2H_(2)SO_(4)+Cu rarrCuSO_(4) + 2H_(2)O + SO_(2)`B. `As_(2)O_(3) + 3H_(2)S rarrAs_(2)S_(3) + 3H_(2)O`C. `2KOH + Cl_(2) rarr KCl + KOCl + H_(2)O`D. `Ca_(3)P_(2) + 6H_(2)O rarr 3Ca(OH)_(2)+ 2PH _(3)` |
Answer» A disproportionation reaction is one in which the same substance undergoes oxidation as well as reduction. In (c ) . `overset(0)(Cl_(2))rarrKoverset(-1)(Cl) ` and also `overset(0)(Cl_(2))rarr KOoverset(-1)(Cl)` |
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700. |
Prussian blue isA. `K_(3)[Fe(CN)_(6)]`B. `K_(4) [Fe(CN)_(6)]`C. `Kfe[Fe(CN)_(6)]`D. `Fe_(4)[Fe(CN)_(6)]` |
Answer» Prussian blue in `K overset(III)(Fe)[overset(II) (Fe) (CN)_(6)]` | |