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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Atomic number of a transition metal is 25 then its magnetic moment in its +3 oxidation state isA. `1.73 BM`B. `2.84 BM`C. `4.9 BM`D. `5.9 BM` |
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Answer» Correct Answer - C Atomic number `= 25` Electronic configuration is `3d^(5)4s^(2)` In `+3` state contains `4` unpaired electrons, so `mu = 4.9` |
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| 102. |
False statement about the trent in oxidation states of transition element is :A. There exists a general trend of lesser number of oxidation states at each end of the series and higher number in the middleB. There is reduced tendency of higher oxidation states towards the end of the seriesC. The stability of the higher oxidation states decreases going down the groupD. the highest oxidation stetes are oftern stabilized in the oxides and fluoride compounds. |
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Answer» Correct Answer - C The stability of the higheer oxidation states increases going down the group. |
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| 103. |
Metch the properties given in column I with the metals given in column II A. `i-c,ii-d,iii-e,iv-a`B. `i-c,ii-d,iii-b,iv-a`C. `i-c,ii-d,iii-a,iv-e`D. `i-d,ii-c,iii-a,iv-e` |
| Answer» Correct Answer - B | |
| 104. |
Manganese achieves its maximum oxidation state in its compound :A. `K_(2)MnO_(4)`B. `KMnO_(4)`C. `MnO_(2)`D. `Mn_(3)O_(4)` |
| Answer» Correct Answer - B | |
| 105. |
Oxidation number of chromium in potassium dichromate isA. `+4`B. `+5`C. `+6`D. `+3` |
| Answer» Correct Answer - C | |
| 106. |
The highest Manganese fluoride isA. `MnF_(4)`B. `MnF_(7)`C. `MnF_(3)`D. `MnF_(2)` |
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Answer» Correct Answer - A The `+7` state for Mn is not represented in simple halides but `MnO_(3)` F is known. |
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| 107. |
The compound in which nickel has the lower oxidation states is :A. `Ni(CO)_(4)`B. `(CH_(2)COO)_(2) Ni`C. `NiO`D. `[NiCl_(2)(PPh_(3))_(2)]` |
| Answer» Correct Answer - A | |
| 108. |
Each of the following ion contains vanadium the +5 oxidation state exceptA. `VO_(2)^(+)`B. `CV(OH)_(4)^(+)`C. `VO^(2+)`D. `[VO_(3)OH]^(2-)` |
| Answer» Correct Answer - C | |
| 109. |
Which one of the following reactions cannot occur?A. `Cu + ZnSO_(4) rarr CuSO_(4) + Zn darr`B. `Cu + 2AgNO_(3) rarr Cu(NO_(3))_(2) + 2Ag darr`C. `Cu + FeSO_(4) rarr CuSO_(4) + Fe darr`D. `3Ag + AuCl_(3) rarr 3AgCl + Audarr` |
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Answer» Correct Answer - A::C Cu cannot displace as it has higher `E_(SRP)^(0)` (+ve) value. |
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| 110. |
Which one of the following does not exist?A. ScOB. CrOC. MnOD. NiO |
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Answer» Correct Answer - A Oxide of Sc: `Sc_(2)O_(3)` |
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| 111. |
Which is not true statement?A. Ions of d-block element are coloured due to d-d transition.B. Ions of f-block element are coloured due to f-f transition.C. `[Sc(H_(2)O_(6))_(6)]^(3+)` and `[Ti(H_(2)O)_(6)]^(4+)` are coloured complexesD. `Cu^(+)` is colourless ion. |
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Answer» Correct Answer - C They have `d^(0)` configuration. |
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| 112. |
Transition metal and their compounds are used as catalyst in Industry and in biological system for example in the contact process vanadium compounds in the `+5` state `V_(2)O_(5)` and `VO_(3)^(-)` are used to oxidise `SO_(2)` to `SO_(3)` `SO_(2) + 1/2 O_(2) overset(V_(2)O_(2))rarr SO_(3)` It is thought that the actual oxidation process takes place in two stages. In the first step `V^(+5)` in the presence of oxide ions converts `SO_(2)` to `SO_(3)`. At the same time `V^(+5)` is reduced to `V^(+4)` `2V^(+5) + O^(-2) + SO_(2) rarr 2V^(+4) + SO_(3)` In the second step `V^(+5)` is regenerated from `V^(+4)` by oxygen `2V^(+4) + 1/2 O_(2) rarr 2V^(+5) + SO_(3)` The overall process is of course the sum of these two steps. `SO_(2) + 1/2 O_(2) rarr SO_(3)` Catalytic activity of transition metals depends onA. Their ability of exist in different oxidation stales.B. The size of metal atomsC. The number of empty atomic orbitals availableD. None of these. |
| Answer» Correct Answer - A | |
| 113. |
Transition metal and their compounds are used as catalyst in Industry and in biological system for example in the contact process vanadium compounds in the `+5` state `V_(2)O_(5)` and `VO_(3)^(-)` are used to oxidise `SO_(2)` to `SO_(3)` `SO_(2) + 1/2 O_(2) overset(V_(2)O_(2))rarr SO_(3)` It is thought that the actual oxidation process takes place in two stages. In the first step `V^(+5)` in the presence of oxide ions converts `SO_(2)` to `SO_(3)`. At the same time `V^(+5)` is reduced to `V^(+4)` `2V^(+5) + O^(-2) + SO_(2) rarr 2V^(+4) + SO_(3)` In the second step `V^(+5)` is regenerated from `V^(+4)` by oxygen `2V^(+4) + 1/2 O_(2) rarr 2V^(+5) + SO_(3)` The overall process is of course the sum of these two steps. `SO_(2) + 1/2 O_(2) rarr SO_(3)` Transition metals and their compounds catalyze reactions becauseA. They have completely filled s-subshellB. They have a comparable size due to poor shielding of d-subshellC. They introduce an entirely new reaction mechanism with lower activation energyD. They have variable oxidation sates differ during the course of reaction. |
| Answer» Correct Answer - C | |
| 114. |
Which of these are liquids at room temperature ?A. `TiCl_(4)`B. `Zn`C. `Hg`D. `CuCl_(2)` |
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Answer» Correct Answer - A::C `TiCl_(4)` is covalent. Metalic bond strength is weak in Hg. |
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| 115. |
`FeI_(3)` does not exist because:A. of large size of FeB. `Fe^(3+)` oxidises `I^(-)` to `I_(2)`C. of low lattice energyD. iodine is not highly electronegative enough to oxidise `Fe` to `Fe^(3+)` |
| Answer» Correct Answer - B | |
| 116. |
The typical acidic oxides areA. MnOB. `Mn_(2)O_(7)`C. `CrO`D. `CrO_(3)` |
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Answer» Correct Answer - B::D Highest oxidation state. Oxides are acidic |
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| 117. |
Which are the best suitable as coinage metals?A. MgB. CuC. AgD. Au |
| Answer» Correct Answer - B::C::D | |
| 118. |
In which of the following compounds iron has lowest oxidation state?A. `Fe(CO)_(5)`B. `Fe_(2)O`C. `K_(4)[Fe(CN)_(6)]`D. `FeSO_(4)(NH_(4))_(2)SO_(4).6H_(2)O` |
| Answer» Correct Answer - A | |
| 119. |
The correct statement about iron includes I) `Fe_(3)O_(4)` is a mixed oxide of iron II) that the iron show +2 oxidation state with six electrons in the unfilled 3d orbitals (III) The common oxidation state iron is `+3` with five unpaired electrons in the 3d orbitalsA. I,II,IIIB. I,IIC. II,IIID. I only |
| Answer» Correct Answer - A | |
| 120. |
The oxide formed in the maximum oxidation state is `ZrO_(x).x` is |
| Answer» Correct Answer - B | |
| 121. |
Which one of the following does not contain zinc?A. BrassB. German SilverC. BronzeD. Bell metal |
| Answer» Correct Answer - D | |
| 122. |
In a transition series, as the atomic number increases, paramagnetismA. increases graduallyB. decreases graduallyC. first increases to a maximum and then decreasesD. first decreases to a minimum and then increases |
| Answer» Correct Answer - C | |
| 123. |
The correct order of atomic sizes isA. `Sc lt Y lt La`B. `Ti lt Zr lt Hf`C. `Sc gt Y gt La`D. `Sc gt Y lt La` |
| Answer» Correct Answer - A | |
| 124. |
Which metal has the lowest melting point?A. WB. CuC. AuD. Ag |
| Answer» Correct Answer - D | |
| 125. |
The metal that has the least melting point among the following isA. MnB. FeC. CrD. W |
| Answer» Correct Answer - B | |
| 126. |
The magnetic moment of the complex `[Ti(H_(2)O)_(6)]^(3+)` isA. `3.87 BM`B. `1.73 BM`C. `2.84 BM`D. `5.87 BM` |
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Answer» Correct Answer - B `Ti^(3+):3d^(1)` |
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| 127. |
The correct statement among the following is:A. The colour of the transition metal compounds having incompletely filled d- orbitals in the metal ions is due to `d-d` transitionB. Intense colours occur due to charge transfer i.e, transfer of electrons from the ligand to the metalC. The colours of `AgBr, Ag_(2)CO_(3), Ag_(3)PO_(4), Ag_(2)O, Cu_(2)O` etc is due to polarizing power of transition metal ion and polarisability of anionD. The colour of a particular transition metal ion is independent on the nature of ligand |
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Answer» Correct Answer - A::B::C Dependent on the nature of the ligand |
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| 128. |
Correct statements among the following is/are:A. `V_(2)O_(5), Cr_(2)O_(3)` are amphoteric oxidesB. Interstitial compounds are very hardC. In its higher oxidation states, manganese forms stable fluoride.D. Amiong `CuF_(2),CuCl_(2)` and `CuBr_(2) , CuF_(2)` is ionic. |
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Answer» Correct Answer - A::B::D `Mn(+7)` in `Mn_(2)O_(7)` |
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| 129. |
Which of the following statement(s) is/are correctA. Transition element exhibit higher enthalpies of atomization as they have stronger interatomic interactionB. `IE_(2)` of `._(23)Vlt._(24)Crgt_(25)Mn` & `._(28)Nilt_(29)Cugt_(30)Zn`C. Ni(III) compounds are more stable than `Pt(IV)`D. The elements which give the greatest number of oxidation states do not occur in or near the middle of the series. |
| Answer» Correct Answer - A::B::C | |
| 130. |
Which of the following statement(s) is/are correct? (A) Transition metals and many of their compounds show paramagnetic behaviour. (B) The enthapies of atomisation of the transition metals are high (B) The transition metals generally form coloured compounds (D) Transition metals and their many compounds act as good catalyst. |
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Answer» As metal ions generally cotains one or more unpaired electrons in then & hence their complexes are generally paramagnetic. (B) Because of having larger number of unpaired electron intheir atoms, they have stronger inter atomic interaction and hence stronger bonding between the atoms. (C) According to CFT, in presence of ligands the colour of the compound is due to the d-d transition of the electrons. (D) This activity is ascribred to their ability to adopt multiple oxidation state and to form complexes. Therefore, (A,B,C,D) options are correct. |
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| 131. |
Order of paramagnetic character among following element is/are"A. `Mn gt Fe gt Cr`B. `Fe gt Zn gt Cr`C. `Cr gt Fe gt Zn`D. `Cr gt Mn gt Fe` |
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Answer» Correct Answer - C::D `Cr:4s^(1)3d^(5): Mn : 4s^(2)3d^(5) , Fe : 4s^(2)3d^(6)` `Zn : 4s^(2)3d^(10)` |
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| 132. |
The transition metals and their compounds have paramagnetic properties. This is due to the reason that ions of transition metals have unpaired electrons in (n-1)d orbitals. As the number of unpaired Sc to Mn, the paramagnetic character increases accodingly. From Mn onwards, this character decreases as electrons get paired up. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of unpaired electron (n). It is given as Magnetic moment `= sqrt(n(n+2))B.M` Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. due to d-d transition in which unpaired electrons from the lower energy d-orbitals are transferred to higher energy d-orbitals. The energy of this transition correspond to the radiation in visibe region. Thus, when white light falls on such a transition metal compound, some light energy corresponding to a particular colour is absorbed and one or more electrons are raised from lower energy set of orbitals to those of higher energy. With the absorption of radiations corresponding to specific colour from the white light, a colour known asd the complementary colour is observed or transmitted. A compound of metal ion `M^(x+) (z = 24)` has a spin only magnetic moment of `sqrt(15)B.M.` The number of unpaired electrons in the metal ion of the compound areA. 2B. 3C. 4D. 5 |
| Answer» Correct Answer - B | |
| 133. |
The transition metals and their compounds have paramagnetic properties. This is due to the reason that ions of transition metals have unpaired electrons in (n-1)d orbitals. As the number of unpaired Sc to Mn, the paramagnetic character increases accodingly. From Mn onwards, this character decreases as electrons get paired up. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of unpaired electron (n). It is given as Magnetic moment `= sqrt(n(n+2))B.M` Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. due to d-d transition in which unpaired electrons from the lower energy d-orbitals are transferred to higher energy d-orbitals. The energy of this transition correspond to the radiation in visibe region. Thus, when white light falls on such a transition metal compound, some light energy corresponding to a particular colour is absorbed and one or more electrons are raised from lower energy set of orbitals to those of higher energy. With the absorption of radiations corresponding to specific colour from the white light, a colour known asd the complementary colour is observed or transmitted. The compound which have the same magnetic moment like that of `FeCl_(2)`A. `CrCl_(3)`B. `MnCl_(2)`C. `CoCl_(3)`D. `NiCl_(2)` |
| Answer» Correct Answer - C | |
| 134. |
Transition metals are often paramagnetic due toA. high melting point and boiling pointB. the presence of vacant orbitalsC. the presence of unpaired electronsD. mallebility and ductility |
| Answer» Correct Answer - C | |
| 135. |
Paramagnetism is not exhibited byA. `CuSO_(4).5H_(2)O`B. `CuCl_(2).5H_(2)O`C. `CuI`D. `NiSO_(4).6H_(2)O` |
| Answer» Correct Answer - C | |
| 136. |
Paramagnetism is exhibited by :A. `CuSO_(4).5H_(2)O`B. `CuCl_(2).5H_(2)O`C. `CuI`D. `NiSO_(4).6H_(2)O` |
| Answer» Correct Answer - A::B::D | |
| 137. |
Interstitial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following are the characteristic properties of interstitial compounds? I. They have high melting points in comparison to pure metals. II. They are very hard. III. They retain metallic conductivity. IV. They are chemically very reactive.A. I, II and III onlyB. I and III onlyC. II and IV onlyD. IV only |
| Answer» Correct Answer - A | |
| 138. |
Higher oxidation state of manganese in fluoride is `+4 (MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))` becauseA. fluorine is more electronegative than oxygen.B. fluorine does not posses d-orbitals.C. fluorine stabilises lower oxidation state.D. in covalent compounds fluorine can form single bond only while oxygen forms double bond. |
| Answer» Correct Answer - D | |
| 139. |
Although `Cr^(3+)` and `Co^(2+)` ions have same number of unpaired electrons but the magnetic moment of `Cr^(3+)` is `3.87 B.M`. and that of `Co^(2+)` `4.87` B.M. because….A. They have different no. of d electronsB. They have same electronic but different orbital contributionC. They have different electronic but same orbital contrigurationD. they are typical elements. |
| Answer» Correct Answer - B | |
| 140. |
Although zirconium belongs to 4d transition series and hafnium to 5d transition series even then they show similar physical and chemical properties because …….. .A. both belong to d-blockB. both have same number of electrons.C. both have similar ionic radii.D. both belong to the same group of the periodic table. |
| Answer» Correct Answer - C | |
| 141. |
For `Mn^(3+)//Mn^(2+)` system, the `E^(0)` values for some metals are as follows: `Cr^(3+)//Cr^(2+)(-0.4V) , Mn^(3+)//Mn^(2+) (+1.5V)`, `Fe^(3+)//Fe^(2+)(+0.8V)`. Then the relative stabilities of `Fe^(3+), Cr^(3+)` and `Mn^(3+)` is :A. `Mn^(3+) lt Fe^(3+) lt Cr^(3+)`B. `Fe^(3+) lt Mn^(3+) lt Cr^(3+)`C. `Cr^(3+) lt Fe^(3+) lt Mn^(3+)`D. `Fe^(3+) lt Cr^(3+) lt Mn^(3+)` |
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Answer» Correct Answer - A `E_(Cr^(3+)//Cr^(2+))` is negative `(-0.4V)` . Its shows that stability of `Cr^(3+)` ions i.e., `Cr^(3+)` in solution can not be reduced to `Cr^(2+)` ions. Further `Mn^(3+)` has high positive `E^(0)` value. So it is easily converted of `Mn^(2+)` as compared to the conversion of `Fe^(3+)` to `Fe^(2+)` thus, the order of relative stablities of different ions is : `Mn^(3+) lt Fe^(3+) lt Cr^(3+)` |
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| 142. |
Which of the following statement are correct about `Cr^(2+)` (Z = 24) and `Mn^(3+)` (Z = 25) ? (i) `Cr^(2+)` is a reducing agent (ii) `Mn^(3+)` is an oxidizing agent (iii) Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)` configuration (iv) When `Cr^(2+)` is used as a reducing agent, the chromium ion attains `d^(5)` electronic configurationA. `Cr^(2+)` is a reducing agentB. `Mn^(3+)` is an oxidizing agentC. Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)`electronic configurationD. When `Cr^(2+)` is used as a reduding agent, the chormium ion attains `d^(5)`electronic configuration |
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Answer» Correct Answer - D `Cr^(2+) rarr Cr^(3+)(3d^(4))` |
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| 143. |
Which of the following is true for the species having `3d^(4)` configuration? (A) `Cr^(2+)` is reducing in nature. (B) `Mn^(3+)` is oxidising in nature. (C) Both (A) and (B) (D) None of these |
| Answer» `Cr^(2+)` is reducing as its configuration changes from `d^(4)` to `d^(3)` the latter having a half-filled `t_(2g)^(3)` energy level to 3d orbitals in oxtahedral crystal field spliting. On the other hand, the change from `Mn^(3+)` to `Mn^(2+)` results in the half-filled `(d^(5))` configuration which has extra stability. Therefore, (C) option is correct. | |
| 144. |
An element M has the electron configuration `[Ar]3d^(5)4s^(2)`. Which one of its oxide is unlikely to existA. `MO_(2)`B. `M_(2)O_(3)`C. `MO_(4)`D. `M_(2)O_(7)` |
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Answer» Correct Answer - C In metal carbonyl oxidation state of metal is zero as carbonyl is netural ligand. |
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| 145. |
Total number of 3d-series transition elements contain either `3d^(1)` or `4s^(1)` orbital in their ground state electric configuration. |
| Answer» Correct Answer - C | |
| 146. |
Magnetic moment value for a d-block ion is 4.90 BM determine value of total spin for it (consider clock wise spin). |
| Answer» Correct Answer - B | |
| 147. |
How many of the following ions have spin mangnetic moment more than `4 B.M`. `Ti^(3+), Cu^(+), Ni^(2+),Fe^(3+),Mn^(2+), Co^(2+)` |
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Answer» Correct Answer - B `{:(Ti^(3+),3d^(1),1,sqrt(2)),(Cu^(+),3d^(10),0,0),(Ni^(2+),3d^(8),2,sqrt(8)),(Fe^(3+),3d^(5),5,sqrt(35)),(Mn^(2+),3d^(5),5,sqrt(35)),(Co^(2+),3d^(7),3,sqrt(15)):}` |
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| 148. |
Mercury is transported in metal containers made ofA. AgB. Pb, SnC. AlD. Fe |
| Answer» Correct Answer - C | |
| 149. |
Transitions elements show generally positive oxidation state due toA. Large atomic sizeB. low ionization energyC. low electronegativityD. high electronegativity |
| Answer» Correct Answer - B | |
| 150. |
Which of the following set of element are transitions elements?A. `Po, At, Rn`B. `Ga, In, Tl`C. `Cs, Ba, La`D. `Ac, Ku, Ha` |
| Answer» Correct Answer - D | |