InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Uniform circular motion is called continuously accelerated motion mainly because (a) direction of motion changes (b) Speed remains the same (c) Velocity remains the same (d) direction of motion does not change |
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Answer» (a) direction of motion changes |
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| 2. |
Fill in the blanks with suitable words: S.I. unit of acceleration is ……… |
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Answer» S.I. unit of acceleration is meter per second2 /ms-2. |
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| 3. |
What are uniform and non-uniform speed? |
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Answer» 1. If an object covers: Equal distance in equal intervals of time, it is said to be uniform motion. 2. non uniform motion : If an object covers unequal distance in equal intervals of time, it is said to be non uniform motion. |
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| 4. |
Distinguish between distance traveled and displacement. |
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Answer» 1. Distance traveled
2. Displacement
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| 5. |
Find the time taken when the velocity in 35 ms-1 |
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Answer» Time taken to travel a distance of 35 ms-1 is 1.5 second. |
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| 6. |
A cricketer hits a sixer, the cricket ball moves up with a velocity of 2 ms-1 and falls down. Its initial velocity while falling down will be (a) 1 ms-1 (b) 1 ms-2 (c) 0 ms-1 (d) 2 ms-1 |
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Answer» Correct answer is (c) 0 ms-1 |
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| 7. |
What is meant by acceleration? |
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Answer» A change in velocity of a body in unit time or the rate of change of velocity is called acceleration. |
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| 8. |
Find the acceleration. |
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Answer» Acceleration from the graph = \(\frac{40-10}{4-1} = \frac{30}{3} = 10 m/s.\) |
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| 9. |
For an object moving at a uniform speed in a circular path, though the speed is uniform it is continuously accelerated, why? Give reason. |
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Answer» For an object moving in a circular path, the direction is changing at every point even though the speed is the same. Therefore velocity changes and hence it is continuously accelerated. |
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| 10. |
Fill in the blanks with suitable words:If an object starts from A and comes back to A. It displacement will be …………. |
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Answer» If an object starts from A and comes back to A. It displacement will be zero. |
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| 11. |
An object at rest gain an average velocity of 40 ms-1 in 5 second. What will be its acceleration? |
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Answer» Its initial velocity, u = 0 Its final velocity, v = 40 ms-1 Time taken t = 5 second the rate of change of velocity =\(\frac{40}{8}\) = 8 ms-2 acceleration, a = 8 ms-2 |
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| 12. |
An object at rest starts moving and attains a velocity of 10 ms-1 after 5 second. What is the acceleration? |
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Answer» Initial velocity, u = 0 Final velocity, v = 10 ms-1 Time interval, t = 5 second a = \(\frac{u-v}{t}\) = \(\frac{10-0}{5}\)= 2 ms-2. |
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| 13. |
If a body is moving with uniform velocity in a given direction its acceleration will be zero, why? |
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Answer» The acceleration will be zero in the above situation since there is no change in velocity in unit time. |
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| 14. |
An object at rest starts moving. It covers a distance of 2 m in one second. It covers a, further distance of 5 m in two seconds in the same direction what is the average velocity and acceleration? |
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Answer» distance traveled on 1 sec = 2 mts distance traveled on 2 sec = 5 mts total distance traveled = 2 + 5 = 7 mts total time taken to cover 7 mts = 1+2 = 3 sec \(Average =\frac {\textit{Total distance travelld}}{\textit{Total times taken}} \) = \(\frac{7}{3}\)= 2.3 ms-1 Average velocity = 2.3 ms-1 s = ut + \(\frac{1}{2}\) at2 7 = 0 3 +\(\frac{1}{2}\) a × 32 7 =0 + \(\frac{1}{2}\) a × 9 = a = 7 9a =7 × 2 = 14 a =\(\frac{14}{9}\) = 1.5 ms-2. |
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