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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What Is The Need For Ber? |
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Answer» Bit ERROR RATE is the EMPIRICAL record of Systems actual bit error PERFORMANCE. Bit error Rate is the empirical record of Systems actual bit error performance. |
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| 2. |
Define Dpsk? |
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Answer» DPSK is the difference between TWO successive SIGNALLING ELEMENTS rather than the ABSOLUTE phase. DPSK is the difference between two successive signalling elements rather than the absolute phase. |
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| 3. |
What Is Quad Bits? |
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Answer» A 16 bit PSK modulator ACTS on the incoming data in groups of FOUR bit is CALLED QUAD bits. A 16 bit PSK modulator acts on the incoming data in groups of four bit is called Quad bits. |
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| 4. |
What Is The Need Of Maximum Distance Code? |
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Answer» It is USED to REDUCE the NUMBER of TRANSMISSION ERRORS. It is used to reduce the number of transmission errors. |
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| 5. |
What Is Eight Phase Psk? |
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Answer» EIGHT PHASE PSK (8-PSK) is an M-ary ENCODING TECHNIQUE where M=8. Eight Phase PSK (8-PSK) is an M-ary encoding technique where M=8. |
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| 6. |
What Is Offset Qpsk? |
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Answer» IT is a modified form of QPSK where the bit WAVEFORMS on the I and Q CHANNELS are offset or phase shifted in phase from each other one by one half of a bit TIME. IT is a modified form of QPSK where the bit waveforms on the I and Q channels are offset or phase shifted in phase from each other one by one half of a bit time. |
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| 7. |
Define Phase Reversal Keying? |
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Answer» Since Phase of the output CARRIER SHIFTS between TWO phases PSK is also CALLED as Phase reversal keying. Since Phase of the output carrier shifts between two phases PSK is also called as Phase reversal keying. |
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| 8. |
Define Baud? |
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Answer» Baud is the RATE of CHANGE and is equal to the reciprocal of ONE SIGNALING ELEMENT. Baud is the rate of change and is equal to the reciprocal of one signaling element. |
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| 9. |
Define Bit Rate? |
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Answer» The rate of change at the INPUT to the MODULATION is CALLED bit ra and is EXPRESSED in bits PER second. The rate of change at the input to the modulation is called bit ra and is expressed in bits per second. |
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| 10. |
Why Digital Amplitude Modulation Is Called As Continuous Wave Modulation? |
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Answer» When the carrier is being TRANSMITTED it has CONSTANT amplitude, constant FREQUENCY and constant PHASE. When the carrier is being transmitted it has constant amplitude, constant frequency and constant phase. |
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| 11. |
Why Digital Amplitude Modulation Is Commonly Called On –off Keying? |
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Answer» CARRIER is EITHER in ON or Off STATE so it is CALLED as On Off KEYING. Carrier is either in ON or Off state so it is called as On Off Keying. |
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| 12. |
What Is The Unit Of Information Capacity? |
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Answer» Unit is bits per second |
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| 13. |
Define Information Capacity? |
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Answer» INFORMATION capacity represents the NUMBER of INDEPENDENT symbols that can be CARRIED in the system for a given time. Information capacity represents the number of independent symbols that can be carried in the system for a given time. |
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| 14. |
Give The Two Basic Operation Of Dpsk Transmitter? |
Answer»
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| 16. |
Define Qpsk? |
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Answer» QPSK is Quadriphase –shift keying. In QPSK the phase of the CARRIER takes on ONE of the four equally spaced values Such as ?/4 , 3?/4, 5?/4 and 7?/4. QPSK is Quadriphase –shift keying. In QPSK the phase of the carrier takes on one of the four equally spaced values Such as ?/4 , 3?/4, 5?/4 and 7?/4. |
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| 17. |
Give The Equation For Average Probability Of Symbol Error For Coherent Binary Psk? |
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Answer» Average probability of signal ERROR, Average probability of signal error, Pe = 1 / 2 erfc? Eb / No |
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| 18. |
Explain How Qpsk Differs From Psk In Term Of Transmission Bandwidth And Bit Information It Carries? |
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Answer» For a given bit rate 1/Tb, a QPSK wave requires HALF the transmission bandwidth of the corresponding binary PSK wave. EQUIVALENTLY for a given transmission bandwidth, a QPSK wave carries twice as MANY BITS of INFORMATION as the corresponding binary PSK wave For a given bit rate 1/Tb, a QPSK wave requires half the transmission bandwidth of the corresponding binary PSK wave. Equivalently for a given transmission bandwidth, a QPSK wave carries twice as many bits of information as the corresponding binary PSK wave |
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