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151.

If peak voltage on a center tapped full wave rectifier circuit is 5V and diode cut-in voltage is 0.7, then peak inverse voltage on diode will be ___________(a) 4.3 V(b) 10 V(c) 5.7 V(d) 9.3 VI have been asked this question in my homework.I'd like to ask this question from Fullwave Rectifier topic in portion Diode Circuit of Analog Circuits

Answer»

The correct option is (b) 10 V

For explanation: PIV is the maximum reveres bias VOLTAGE that can be appeared across a diode in the circuit. If PIV rating of the diode is less than this value breakdown of diode may OCCUR. For a center tapped FULL wave rectifier, PIV of diode is 2Vm. Therefore, PIV is 10 V.

152.

In a center tapped full wave rectifier, the input sine wave is 20sin500 ᴨt. The average output voltage is __________(a) 12.73V(b) 6.93V(c) 11.62V(d) 3.23VThis question was posed to me in final exam.Query is from Fullwave Rectifier topic in portion Diode Circuit of Analog Circuits

Answer»

Right OPTION is (a) 12.73V

To elaborate: The EQUATION of sine wave is in the FORM Em sin wt.

Therefore, Em=20

Hence output VOLTAGE is 2Em/ ᴨ. That is 40/ ᴨ.

153.

Efficiency of center tapped full wave rectifier is ___________(a) 50%(b) 81.2%(c) 40.6%(d) 45.3%I had been asked this question in exam.I would like to ask this question from Fullwave Rectifier topic in portion Diode Circuit of Analog Circuits

Answer»

Correct choice is (b) 81.2%

Best explanation: Efficiency of a rectifier is the effectiveness of rectifier to convert AC to DC. It is obtained by TAKING a ratio of DC power output to maximum INPUT power DELIVERED to load. It is usually expressed in percentage. For CENTER tapped full wave rectifier, it is 81.2%.

154.

In a center tapped full wave rectifier, the input sine wave is 200sin50 ᴨt. If load resistance is of 1k then average DC power output of half wave rectifier is __________(a) 12.56W(b) 16.20W(c) 4.02W(d) 8.04WThe question was posed to me by my college professor while I was bunking the class.I want to ask this question from Fullwave Rectifier topic in portion Diode Circuit of Analog Circuits

Answer»

Right choice is (b) 16.20W

The explanation: The equation of SINE wave is in the FORM EM sin wt.

On comparing Em = 200

Power = 4Em2/ ᴨ^2RL = 800/ ᴨ^2x 1000 = 16.20W.

155.

In a center tapped full wave rectifier, the input sine wave is 250sin100 ᴨt. The output ripple frequency of rectifier will be __________(a) 50Hz(b) 200Hz(c) 100Hz(d) 25HzI have been asked this question in examination.I need to ask this question from Fullwave Rectifier in section Diode Circuit of Analog Circuits

Answer»

Correct option is (c) 100Hz

For explanation I would SAY: The EQUATION of sine wave is in the form Em sin wt.

Therefore, w = 100ᴨ that is, frequency f = w/2ᴨ = 50Hz

Since the output of center tapped full wave rectifier have double the frequency of INPUT, output frequency is 100Hz.

156.

Ripple factor of bridge full wave rectifier is _________(a) 1.414(b) 1.212(c) 0.482(d) 1.321The question was posed to me in unit test.This is a very interesting question from Bridge Rectifier topic in chapter Diode Circuit of Analog Circuits

Answer»

The correct OPTION is (c) 0.482

For explanation I would say: Ripple factor of a RECTIFIER measures the ripples or AC CONTENT in the output. It is obtained by dividing AC rms output with DC output. For FULL WAVE bridge rectifier it is 0.482.

157.

If input frequency is 50Hz then ripple frequency of bridge full wave rectifier will be equal to _________(a) 200Hz(b) 50Hz(c) 45Hz(d) 100HzThis question was addressed to me in exam.This intriguing question originated from Bridge Rectifier in division Diode Circuit of Analog Circuits

Answer»

Correct choice is (d) 100HZ

The best I can explain: SINCE in the output of bridge rectifier ONE half cycle is repeated HENCE frequency will twice as that of INPUT frequency. That is 100Hz.

158.

Transformer utilization factor of a bridge full wave rectifier is equal to _________(a) 0.62(b) 0.69(c) 0.81(d) 0.43This question was posed to me during an online exam.My doubt is from Bridge Rectifier topic in section Diode Circuit of Analog Circuits

Answer»

Right option is (c) 0.81

Explanation: Transformer UTILIZATION factor is the ratio of AC power delivered to load to the DC power rating. This factor INDICATES effectiveness of transformer usage by rectifier. For BRIDGE full wave rectifier it is equal to 0.81.

159.

If peak voltage on a bridge full wave rectifier circuit is 5V and diode cut-in voltage is 0.7, then peak inverse voltage on diode will be _________(a) 4.3V(b) 5.7V(c) 10V(d) 5VThis question was posed to me in an international level competition.This intriguing question originated from Bridge Rectifier topic in chapter Diode Circuit of Analog Circuits

Answer»

The correct CHOICE is (d) 5V

The explanation: PIV is the maximum reveres bias voltage that can be appeared across a diode in the circuit. If PIV rating of the diode is LESS than this Value breakdown of diode MAY OCCUR. Therefore, PIV rating of diode should be GREATER than PIV in the circuit. For bridge rectifier PIV is 5V.

160.

Efficiency of bridge full wave rectifier is _________(a) 81.2%(b) 50%(c) 40.6%(d) 45.3%The question was posed to me in homework.Origin of the question is Bridge Rectifier in chapter Diode Circuit of Analog Circuits

Answer»

Correct choice is (a) 81.2%

The best I can explain: It is obtained by taking ratio of DC power output to maximum AC power delivered to load. Efficiency of a rectifier is the EFFECTIVENESS of rectifier to convert INPUT power to DC. It is usually EXPRESSED in percentage. For bridge full wave rectifier, it is 81.2%.

161.

In an bridge full wave rectifier, the input sine wave is 40sin100 ᴨt. The average output voltage is ________(a) 22.73V(b) 16.93V(c) 25.47V(d) 33.23VThis question was addressed to me in an online interview.My doubt is from Bridge Rectifier in section Diode Circuit of Analog Circuits

Answer»

Correct option is (c) 25.47V

The BEST I can explain: The equation of SINE WAVE is in the FORM EM sin wt.

Therefore, Em=40

Hence output voltage is 2Em/ᴨ. That is 80/ᴨ.

162.

Number of diodes used in a full wave bridge rectifier is ________(a) 1(b) 2(c) 4(d) 6I had been asked this question in an internship interview.Question is taken from Bridge Rectifier in chapter Diode Circuit of Analog Circuits

Answer»

The correct OPTION is (c) 4

Best explanation: The MODEL of bridge rectifier is same as a Wien bridge CIRCUIT. Like a Wien bridge circuit NEEDS 4 resistors, bridge rectifier needs 4 diodes while center tap configuration requires only one.

163.

In a bridge full wave rectifier, the input sine wave is 250sin100 ᴨt. The output ripple frequency of rectifier will be ________(a) 50Hz(b) 200Hz(c) 100Hz(d) 25HzThe question was asked in an interview for job.The query is from Bridge Rectifier in section Diode Circuit of Analog Circuits

Answer»

Correct answer is (c) 100HZ

Explanation: In a bridge FULL wave rectifier, the INPUT sine wave is 250sin100 ᴨt Volts. The OUTPUT ripple frequency of the rectifier will be 100Hz.

164.

Consider the circuit provided.Total discharge time = 0.5 ms. Consider the diode to be an ideal diode, for a square wave input of ± 10 V, what is the percentage tilt? (C = 1MF & R = 50k Ohms)(a) 10%(b) 1%(c) 0.1%(d) 1.1%I have been asked this question in examination.Asked question is from Clamper Circuit in portion Diode Circuit of Analog Circuits

Answer» RIGHT answer is (B) 1%

The EXPLANATION is: Total discharge time Td=0.5ms. For ideal diode, no cut-in VOLTAGE.

% TILT = ΔVo/2Vm * 100

Idischarge = 2Vm/R = 2*10/50k = 0.4 mA

ΔVo = Tdischarge*Idischarge/C = 0.5ms*0.4mA/1MF = 0.2

% Tilt = (0.2/20) * 100 = 1 %.
165.

Find the output voltage for the circuit below. (Use constant voltage drop model of diode and take cut-in voltage as 0.7V)(a) 5v(b) 2v(c) 0V(d) 10vThis question was addressed to me in an online interview.This interesting question is from Parallel Clipper-2 topic in chapter Diode Circuit of Analog Circuits

Answer»

The correct option is (c) 0V

To elaborate: In circuit of PARALLEL clipper VOLTAGE across the DIODE D2 will be same as a simple parallel clipper. The output of the circuit is null because the output of diode D2 is NEGATIVE and diode D will not conduct negative voltage.

166.

Which of the following is not true regarding clamper?(a) A positive clamper adds a positive DC voltage(b) A clamper can also be called as a re-inserter(c) To reduce tilt, reduce the RC value(d) Negative clamper will clamp the positive peak of output to the reference voltageThe question was posed to me during an internship interview.Asked question is from Clamper Circuit topic in chapter Diode Circuit of Analog Circuits

Answer»

The CORRECT ANSWER is (c) To reduce tilt, reduce the RC value

Explanation: Clamper is called a re-inserter since it adds DC voltage to wave, inserts DC. Also, a POSITIVE clamper adds a positive DC voltage, shifting the wave up, and vice versa for the NEGATIVE clamper. HOWEVER, to reduce the tilt in the output, RC should be large, not small.

167.

What is A, B, C and D to design a voltage doubler in the given circuit?(a) A=B=Resistors, C=D=Diodes(b) A=D=Capacitors, B=C=Diodes(c) A=Capacitor, B=D=Diodes, C=Resistor(d) A=C=Diodes, B=D=CapacitorsI have been asked this question in homework.I would like to ask this question from Clamper Circuit topic in section Diode Circuit of Analog Circuits

Answer»

Correct option is (b) A=D=Capacitors, B=C=Diodes

The explanation: During the negative cycle, D1 conducts and C1 charges up to peak input. When the input is POSITIVE, then D2 conducts and C2 charges up to 2Vm. This creates a voltage doubler.

168.

In the given circuit, given that C=2MF and diode cut-in voltage, Vγ =0. Calculate the average output voltage.(a) 2V(b) 4V(c) -2V(d) -3VI have been asked this question in unit test.Asked question is from Clamper Circuit in division Diode Circuit of Analog Circuits

Answer» RIGHT option is (c) -2V

The BEST I can explain: Maximum input is Vm = 32 + 5 = 37 V

Capacitor charges up to37 – 3 = 34 V

Vout = Vin – VC = 32 + 5 sinωt – 34 = -2 + 5sinωt

Average OUTPUT voltage = – 2 V.
169.

Considering a clamper circuit, where capacitance C, load R, the cut-in voltage of diode are unknown, which is the correct statement?(a) The DC level of the signal changes(b) The peak-to-peak value of signal changes(c) The shape of signal changes(d) The DC level shifts upThe question was posed to me in quiz.The origin of the question is Clamper Circuit topic in division Diode Circuit of Analog Circuits

Answer»

Right ANSWER is (a) The DC level of the SIGNAL changes

The explanation: The shape and PEAK to peak value of signal remain unchanged in a CLAMPER. A clamper only affects the DC voltage level of the wave, which can be both moved up and down, not simply up.

170.

Consider the circuit shown. The input is a square wave ± 15 V, for a silicon diode and an output voltage swing of 30 V. Choose the validity of the statement. If the value of resistance R = 10KΩ and capacitance C = 1MF.(a) True(b) FalseI got this question in a national level competition.The doubt is from Clamper Circuit topic in section Diode Circuit of Analog Circuits

Answer»

The correct answer is (a) True

The best EXPLANATION: The output VOLTAGE SWING is always equal to the input voltage swing. The output swing doesn’t depend on the values of R and C. All values are valid, RC values only are changed to decrease the tilt /distortion.

171.

Tilt of output waveform for the circuit is 1%. Given that input is a square wave ± 10 V, f = 2 kHz, diode cut-in voltage = 0.7, what is the relation between C and R?(a) RC=20(b) RC=1/2(c) RC=2(d) RC=1/20I got this question in an internship interview.Origin of the question is Clamper Circuit topic in portion Diode Circuit of Analog Circuits

Answer»

The correct OPTION is (d) RC=1/20

To elaborate: To = 1/f = 1 MS; Tdischarge = 0.5 ms

Tilt = 100 *ΔVo/2Vm = 100 *ΔVo/20 = 5 * ΔVo = 1

Thus ΔVo = 0.2 = Idischarge * Tdischarge/C

Idischarge/C = 0.2/Tdischarge = 0.2/0.5 ms = 400

RC = 2Vm/400 = 20/400 = 1/20.

172.

From the given circuit diagram, considering the diode to be a silicon semiconductor diode, what is the magnitude of diode current? (Use an appropriate model of the diode)(a) 43 mA(b) 0 mA(c) 4.3 mA(d) 5 mAI have been asked this question at a job interview.The origin of the question is Diode Approximations and Series Connection topic in chapter Diode Circuit of Analog Circuits

Answer»

The CORRECT CHOICE is (c) 4.3 mA

Easy EXPLANATION: ID = (V-VD)/R = 4.3 mA.

173.

Choose the correct option for the relation between the two circuits.(a) Circuit (a) is a voltage doubler circuit, while Circuit (b) does not double the voltage(b) Both are similar and double the voltage to 2Vm(c) Circuit (a) is a doubler circuit with output +2Vm and Circuit (b) is a doubler with output -2Vm(d) Circuit (a) is a doubler circuit, while Circuit (b) is a clipperI had been asked this question by my college professor while I was bunking the class.This interesting question is from Clamper Circuit topic in section Diode Circuit of Analog Circuits

Answer»

Correct answer is (c) Circuit (a) is a DOUBLER circuit with OUTPUT +2Vm and Circuit (b) is a doubler with output -2Vm

Explanation: Both circuits are half-wave VOLTAGE doublers, in which capacitor C2 charges up to TWICE the positive (or negative for Circuit (b)) peak for ONE half of the wave. Neither of the circuits acts as a clipper.

174.

Which of the following models of a semiconductor diode is the most widely used for the purpose of calculation?(a) Approximate Equivalent Model(b) Ideal Diode Model(c) Piecewise Linear Model(d) Hybrid modelI had been asked this question in a national level competition.I'm obligated to ask this question of Diode Approximations and Series Connection topic in chapter Diode Circuit of Analog Circuits

Answer»

Correct choice is (a) APPROXIMATE EQUIVALENT Model

Easiest EXPLANATION: Approximate Equivalent model not only saves TIME and efforts but also provides results with a considerable amount of accuracy.

175.

From the given circuit diagram, what is the value of diode current? Use an appropriate diode model.(a) 8 mA(b) 0 mA(c) 7.3 mA(d) 7 mAThe question was posed to me during an online interview.I'm obligated to ask this question of Diode Approximations and Series Connection topic in section Diode Circuit of Analog Circuits

Answer» RIGHT answer is (d) 7 mA

For explanation: The DIODES have a drop of 0.3V for Ge and 0.7V for SILICON in forward bias. We can USE the constant voltage model, and hence in forward bias, the current FLOWING is

ID = (V-VD1-VD2)/R = 7 mA.
176.

From the given circuit diagram, what is the value of diode current?(a) 8 mA(b) 0 mA(c) 7.3 mA(d) 7 mAThis question was posed to me during a job interview.My doubt stems from Diode Approximations and Series Connection in section Diode Circuit of Analog Circuits

Answer»

Correct CHOICE is (b) 0 mA

The best I can explain: As the SILICON diode in the CIRCUIT is reverse BIASED, hence the current in the circuit is zero.

177.

From the given circuit diagram, what is the value of diode current?(a) 8 mA(b) 7.3 mA(c) 0 mA(d) 7 mAI got this question during a job interview.My enquiry is from Diode Approximations and Series Connection topic in section Diode Circuit of Analog Circuits

Answer»

Right option is (c) 0 mA

The best I can explain: As both the DIODES are reverse BIASED, the CURRENT in the circuit is ZERO.

178.

From the given circuit diagram, what is the value of diode current?(a) 2 mA(b) 0 mA(c) 1.3 mA(d) 1 mAThe question was asked in an internship interview.The origin of the question is Diode Approximations and Series Connection topic in chapter Diode Circuit of Analog Circuits

Answer»

The CORRECT choice is (b) 0 mA

The BEST I can EXPLAIN: The diodes in forward bias, have drops of 0.3V for Ge and 0.7V for Si, and the TOTAL drops cancel out the source voltage, and hence the diode current is zero.

179.

From the given circuit diagram, what is the value of voltage across the resistor?(a) 2 V(b) 1.3 V(c) 1 V(d) 0 VThis question was addressed to me in an interview for internship.This intriguing question comes from Diode Approximations and Series Connection topic in chapter Diode Circuit of Analog Circuits

Answer»

Right option is (d) 0 V

To explain: The diodes in FORWARD BIAS, have drops of 0.3V for Ge and 0.7V for Si, and the total drops cancel out the source VOLTAGE, and hence the diode CURRENT is ZERO. Hence voltage drop is also zero.

180.

From the given circuit diagram, what is the value of diode current?(a) 2.425 mA(b) 5.2 mA(c) 2.325 mA(d) 0 mAThis question was posed to me during an internship interview.Question is taken from Diode Approximations and Series Connection topic in division Diode Circuit of Analog Circuits

Answer» CORRECT choice is (C) 2.325 mA

Best EXPLANATION: Here, ID=(V-VD)/R = 2.325 mA.
181.

From the given circuit diagram, what is the value of voltage across R2?(a) 9.324 V(b) 5.3 V(c) 0 V(d) 5.8125 VThis question was addressed to me in my homework.Question is from Diode Approximations and Series Connection topic in portion Diode Circuit of Analog Circuits

Answer» CORRECT answer is (d) 5.8125 V

The explanation is: Here, CURRENT I=10-0.7/4k=2.325 mA

Here, VR2 = I x R2 = 5.8125 V.
182.

From the given circuit diagram, what is the value of diode current?(a) 2.425 mA(b) 5.2 mA(c) 2.325 mA(d) 0 mAThis question was posed to me in examination.The question is from Diode Approximations and Series Connection in section Diode Circuit of Analog Circuits

Answer»

The CORRECT choice is (d) 0 mA

The BEST explanation: As the diode is reverse biased, the current in the CIRCUIT is ZERO.

183.

From the given circuit diagram, what is the voltage across diode?(a) 10 V(b) 5 V(c) 0.7 V(d) 0 VI got this question in final exam.I'd like to ask this question from Diode Approximations and Series Connection in portion Diode Circuit of Analog Circuits

Answer»

Right CHOICE is (a) 10 V

Best EXPLANATION: As the diode is reverse biased, the current in the circuit is zero and hence the voltage ACROSS the diode is equal to the SOURCE voltage = 10 V.

184.

What is the circuit in the given diagram called?(a) Clipper(b) Clamper(c) Half wave rectifier(d) Full wave rectifierThis question was posed to me in final exam.This question is from Diode Clipper and Clamper topic in section Diode Circuit of Analog Circuits

Answer»

Right OPTION is (a) Clipper

The explanation: The circuit given above is a clipper. The diode conducts when it is forward biased, i.e, WHENEVER the input VI is greater than 5V (for ideal diode). For lower voltages, the diode does not conduct and the OUTPUT is zero.

185.

For the given circuit for a 20 Vpeak sinusoidal input vi,what is the value of vi at which the clipping begins?(a) 5 V(b) 0 V(c) -5 V(d) Clipping doesn’t occurThe question was asked in quiz.This interesting question is from Diode Clipper and Clamper in division Diode Circuit of Analog Circuits

Answer» RIGHT option is (c) -5 V

Easiest explanation: Considering the connection of diode, it is evident that the diode BECOMES reverse biased when vi < -5 V. Hence, clipping STARTS at -5 V.
186.

For a sinusoidal input of 20 Vpeak to the given circuit, what is the peak value of the output waveform?(a) 20 V(b) 25 V(c) 0 V(d) -25 VThis question was posed to me by my school teacher while I was bunking the class.This is a very interesting question from Diode Clipper and Clamper in portion Diode Circuit of Analog Circuits

Answer»

Correct CHOICE is (b) 25 V

For explanation: In the given circuit, the output BECOMES zero for vi less than -5 V. HENCE, the peak value of the output is 25 V owing to the additive effect of V for vi.

187.

For a sinusoidal input of 20 Vpeak to the given circuit, what is the minimum value of the output waveform?(a) 20 V(b) 25 V(c) -25 V(d) 0 VThe question was asked during an interview.Query is from Diode Clipper and Clamper in division Diode Circuit of Analog Circuits

Answer»

Right option is (d) 0 V

To explain I would SAY: The given CIRCUIT is a clipper that cuts off a part of the negative cycle of the input SINUSOID i.e. the OUTPUT becomes ZERO for a certain region of the input waveform. Hence, the minimum value is 0 V.

188.

For the given input waveform to the given circuit, what is the peak value of the output waveform?(a) 0 V(b) 16 V(c) 12 V(d) 0 VThe question was asked in an international level competition.My question is from Diode Clipper and Clamper topic in portion Diode Circuit of Analog Circuits

Answer»

Correct ANSWER is (b) 16 V

Explanation: In the GIVEN circuit, the diode is in the off stage when vi > 4 V. Hence, when vi > 4 V, vo = vi and hence the PEAK value of vo = the peak value of vi = 16 V.

189.

For the given input waveform to the given circuit, what is the minimum value of the output waveform?(a) 4 V(b) 16 V(c) 12 V(d) 0 VThe question was asked in final exam.I would like to ask this question from Diode Clipper and Clamper in section Diode Circuit of Analog Circuits

Answer»

Correct ANSWER is (a) 4 V

Best explanation: The circuit above is a PARALLEL clipper. When the input is less than 4V, then DIODE is forward biased and thus output voltage is 4V. When input increases above 4V, the diode is reverse biased and output is equal to the input. Hence, MINIMUM output is 4V.

190.

Which of the following is not a necessary component in a clamper circuit?(a) Diode(b) Capacitor(c) Resistor(d) Independent DC SupplyI got this question during an online exam.My question is from Diode Clipper and Clamper in section Diode Circuit of Analog Circuits

Answer»

Correct choice is (d) Independent DC Supply

Explanation: DIODE, Capacitor and Resistor are necessary to build a CLAMPER circuit. An independent DC supply is REQUIRED to bring an additional SHIFT.

191.

For the given circuit and input waveform, the peak value of the output is +30V.(a) True(b) FalseThe question was asked by my college professor while I was bunking the class.This question is from Diode Clipper and Clamper in portion Diode Circuit of Analog Circuits

Answer»

Correct option is (a) True

The best I can explain: The given circuit is a clamper with an independent DC supply of +10 V. Keeping in mind the CONNECTION of the diode and the DC supply, we SEE that the output waveform is clamped at +10V i.e. it shifts up by +10V. Hence, the MAXIMUM value of vo=+30 V.

192.

Which of the following statements best describes the reason for not using diodes to implement logic gates?(a) Diodes are expensive(b) Diodes are unreliable and less efficient(c) The diode circuits have limited range of operation(d) Diodes are bulky for a logic gateThe question was posed to me in an online interview.My question is from Diode Gates and Rectifiers topic in portion Diode Circuit of Analog Circuits

Answer» CORRECT choice is (c) The diode circuits have LIMITED range of operation

The explanation is: The diode circuits are RELATIVELY less STABLE when compared to the transistor circuits, which are easy to tune in TERMS of stability and reliability.
193.

What is the logic gate implemented in the following circuit?(a) OR(b) AND(c) NOT(d) NORThis question was addressed to me by my college professor while I was bunking the class.I need to ask this question from Diode Gates and Rectifiers topic in section Diode Circuit of Analog Circuits

Answer»

Right option is (a) OR

Best explanation: In the given CIRCUIT, as a logic gate, E1 and E2 are digital inputs, 1 or 0. If the input is 1, the diode is FORWARD biased and conducts, else it is reverse biased. So, the output is high whenever either of the input is high, or both of them are high, hence it acts as an OR gate.

194.

In the given circuit, what is the output V0 if E1 = 10V and E2 = 0V?(a) 0 V(b) 0.7 V(c) 10 V(d) 9.3 VThe question was posed to me during an interview.The above asked question is from Diode Gates and Rectifiers topic in division Diode Circuit of Analog Circuits

Answer»

Correct option is (d) 9.3 V

The explanation is: Here, current through the grounded branch = (10-0.7)/1k = 9.3 mA. HENCE, VOLTAGE drop ACROSS the resistor=9.3 V. Hence, V0 = 9.3V.

195.

In the given circuit, what is the ideal output V0 if E1 = 10V and E2 = 0V?(a) 0 V(b) 0.7 V(c) 10 V(d) 9.3 VThis question was addressed to me in quiz.My query is from Diode Gates and Rectifiers in chapter Diode Circuit of Analog Circuits

Answer»

The correct option is (c) 10 V

To explain I would SAY: In an IDEAL DIODE, the voltage drop is ZERO. Hence, complete voltage 10V appears across the resistor and as the output too.

196.

A 12 V, 50 Hz sine wave is fed to the given circuit as input? What is the output for 0.01s < t < 0.02s?(a) True(b) FalseI had been asked this question in semester exam.This is a very interesting question from Diode Gates and Rectifiers topic in division Diode Circuit of Analog Circuits

Answer»

The correct answer is (b) False

To explain I WOULD say: The given circuit is that of a HALF wave rectifier in which the diode REMAINS in the off state for the negative half and conducts for POSITIVE half. During the time 0.01 sec to 0.02sec, the input 12sin(2π50t) is positive, hence a certain output not equal to zero is AVAILABLE.

197.

Which circuit has been represented in the associated circuit diagram?(a) Half wave rectifier(b) Full wave rectifier(c) NOT gate(d) AND gateThis question was posed to me by my school teacher while I was bunking the class.The doubt is from Diode Gates and Rectifiers in chapter Diode Circuit of Analog Circuits

Answer»

Correct OPTION is (a) Half wave rectifier

The explanation: Both the diodes are SIMILARLY BIASED and are in series. HENCE, they form a half wave rectifier.

198.

Which of the following equations is correct for a full wave rectified output?(a) |Vdc| = 0.318 Vp(b) |Vdc| = 0.636 Vp(c) |Vdc| = 0.477 Vp(d) |Vdc| = 0.211 VpThis question was posed to me at a job interview.The question is from Diode Gates and Rectifiers topic in section Diode Circuit of Analog Circuits

Answer»

Right choice is (b) |Vdc| = 0.636 Vp

To ELABORATE: The output DC level of a half wave RECTIFIED wave is equal to 0.318 Vp. But, for a FULLY rectified wave, it becomes equal to 0.636 of the peak VALUE.

199.

What is the value of DC equivalent output voltage for the given circuit, given that the input voltage is 20 Vp-p and 50 Hz and the diode is a silicon diode?(a) 2.9574 V(b) -2.9574 V(c) -3.125 V(d) 0 VThe question was posed to me in quiz.My doubt stems from Diode Gates and Rectifiers topic in division Diode Circuit of Analog Circuits

Answer»

Correct answer is (b) -2.9574 V

For explanation: Vdc is GIVEN by 0.318(Vp). Here Vp = 10-0.7 V = 9.3 V and hence, Vdc = 0.318 x 9.3 V = 2.9574 V. Now, as the OUTPUT Is NON zero only for the negative half cycles of the input, Vdc = -2.9574 V.

200.

Which of the following statements are true about the given circuit?(a) The circuit is that of a bridge rectifier(b) The PIV of the diode D1 must be greater than v0 for the circuit to function as a bridge rectifier(c) For silicon diodes, the value of v0=(vi-1.4) V(d) All of the mentionedThe question was asked in an international level competition.I want to ask this question from Diode Gates and Rectifiers in portion Diode Circuit of Analog Circuits

Answer»

The correct choice is (d) All of the mentioned

To explain: The circuit is that of a BRIDGE rectifier. For proper functioning, the PIV of diodes must be at least greater than v0 and SINCE, the CURRENT through any path flows through 2 diodes. There is a drop of 1.4 V.