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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

The phase difference between voltage and current in the capacitor.(a) 90°(b) 80°(c) 95°(d) 91°This question was addressed to me in an online quiz.The above asked question is from Dynamics of Motor-Load Combination topic in division Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT CHOICE is (a) 90°

For explanation I would SAY: In the case of a capacitor, the voltage lags the CURRENT by 90° or the current leads the voltage by 90^o. The phase difference between voltage and current is 90°.
2.

The phase difference between voltage and current in the resistor.(a) 85°(b) 90°(c) 0°(d) 5°The question was posed to me in class test.I need to ask this question from Dynamics of Motor-Load Combination topic in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Right answer is (c) 0°

The BEST I can EXPLAIN: In the CASE of a resistor, the voltage and current are in the same phase. The phase difference between voltage and current is 0°. The voltage drop in the resistor is GIVEN as V=IR.

3.

Calculate the phase angle of the sinusoidal waveform y(t)=55sin(4πt+π÷8).(a) π÷8(b) π÷5(c) π÷7(d) π÷4I got this question in quiz.Question is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

The CORRECT option is (a) π÷8

Best explanation: SINUSOIDAL waveform is generally EXPRESSED in the form of V=Vmsin(ωt+α) where VM represents PEAK value, ω represents angular frequency, α represents a phase difference.

4.

Calculate the useful power developed by a motor using the given data: Pin = 3000 W, Ia = 60 A, Ra = .4 Ω. Assume frictional losses are 200 W and windage losses are 400 W.(a) 970 W(b) 960 W(c) 980 W(d) 990 WI have been asked this question by my college professor while I was bunking the class.Question is from Dynamics in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Right answer is (b) 960 W

For EXPLANATION: USEFUL power is basically the shaft power DEVELOPED by the motor that can be calculated using the formula Psh = Pdev-(rotational losses). Pdev = Pin-Ia^2Ra = 3000-60^2(.4)=1560 W. The useful power developed by the motor is Psh = Pdev-(rotational losses)=1560 –(200+400)=960 W.

5.

Boost converter is used to _________(a) Step down the voltage(b) Step up the voltage(c) Equalize the voltage(d) Step up and step down the voltageThe question was asked in an internship interview.Query is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (b) STEP up the voltage

The best explanation: Output voltage of boost converter is VO = Vin / 1 – D. Value of duty cycle is less than 1 which makes the Vo > Vin as DENOMINATOR value decreases and becomes less than 1. Boost converter is USED to step up voltage.

6.

230V, 10A, 1500rpm DC separately excited motor having resistance of .2 ohm excited from external dc voltage source of 50V. Calculate the torque developed by the motor on full load.(a) 13.89 N-m(b) 14.52 N-m(c) 13.37 N-m(d) 14.42 N-mThe question was posed to me in my homework.This key question is from Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives

Answer» CORRECT OPTION is (b) 14.52 N-m

To explain: Back EMF developed in the motor during full load can be calculated using equation Eb = Vt- I*Ra = 228 V and machine constant Km = Eb / Wm which is equal to 1.452. Torque can be calculated by using the RELATION T = Km* I = 1.452*10 = 14.52 N-m.
7.

What is the relationship between torque and speed in constant type loads?(a) Torque is independent of speed(b) Torque linearly increases with increase in speed(c) Torque non-linearly increases with an increase in speed(d) Torque non-linearly decreases with an increase in speedI got this question in an interview for job.My question is based upon Dynamics in division Dynamics of Electrical Drives of Electric Drives

Answer»

Correct ANSWER is (a) Torque is INDEPENDENT of SPEED

Explanation: Speed hoist is a perfect example of constant type loads in which torque variation is independent of speed. The speed-torque characteristics of this type of load are given by T=K where K is a constant.

8.

Rolling mills exhibit what type of load torque characteristics?(a) Constant torque characteristics(b) Linearly rising torque characteristics(c) Non-Linearly rising torque characteristics(d) Non-Linearly decreasing torque characteristicsThe question was asked in unit test.This interesting question is from Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»

Right answer is (d) Non-Linearly decreasing TORQUE characteristics

The explanation: Rolling mills are an example of non-linearly decreasing torque characteristics because torque and speed exhibits inversely PROPORTIONAL RELATIONSHIPS and power are constant.

9.

Calculate the value of the duty cycle if the system is on for 5 sec and off for 10 sec.(a) .333(b) .444(c) .201(d) .642The question was posed to me during an interview.I'd like to ask this question from Dynamics topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct OPTION is (a) .333

Best explanation: Duty CYCLE is Ton÷Ttotal. It is the ratio of time for which the system is ACTIVE and the time taken by the signal to complete one cycle. D= Ton÷Ttotal=5÷15=.333.

10.

The slope of the V-I curve is 0°. Calculate the value of resistance. The graph is parallel to the x-axis.(a) 1 Ω(b) 1.8 Ω(c) 0 Ω(d) 2.2 ΩThis question was addressed to me in a national level competition.This interesting question is from Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»

The CORRECT ANSWER is (C) 0 Ω

Explanation: The SLOPE of the V-I CURVE is resistance. The slope given is 0° so R=tan(0°)=0 Ω. The slope of the V-I curve is resistance. It behaves as a short circuit.

11.

Calculate the value of the frequency of the DC supply.(a) 0 Hz(b) 50 Hz(c) 20 Hz(d) 10 HzThe question was asked by my school principal while I was bunking the class.I want to ask this question from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct option is (a) 0 Hz

Explanation: The frequency is defined as the number of OSCILLATIONS per second. It is RECIPROCAL of the time period. DC supply magnitude is CONSTANT. It does not change with time so the frequency of DC supply is 0 Hz.

12.

What is the unit of the apparent or complex power?(a) VAR(b) VA(c) ohm(d) VoltThe question was posed to me in homework.This intriguing question originated from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct choice is (b) VA

Easy explanation: The apparent POWER in AC circuits is VI*. It is EXPRESSED in volt-amperes (VA). It CONSISTS of both active and reactive power. It is the VECTOR sum of the real power and reactive power.

13.

Calculate the reactive power in a 5 Ω resistor.(a) 7 VAR(b) 0 VAR(c) 2 VAR(d) 1 VARThe question was asked by my college director while I was bunking the class.This interesting question is from Dynamics in division Dynamics of Electrical Drives of Electric Drives

Answer»

Right ANSWER is (B) 0 VAR

Explanation: The resistor is a linear element. It only absorbs real power and dissipates it in the form of heat. The voltage and current are in the same phase in case of the resistor so the angle between V & I is 90°. Q = VIsin0 = 0 VAR.

14.

Calculate the power factor during the resonance condition.(a) .58(b) .42(c) .65(d) 1The question was posed to me in final exam.Enquiry is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (d) 1

Explanation: During the resonance condition, the reactive power generated by the CAPACITOR is COMPLETELY ABSORBED by the INDUCTOR. Only active power flows in the circuit. Net reactive power is EQUAL to zero and cosΦ=1.

15.

The unit of reactive power is VAR.(a) True(b) FalseI have been asked this question in final exam.I'd like to ask this question from Dynamics in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

The correct choice is (a) True

The best explanation: The REACTIVE power is the useless power in CASE of electric circuits. It is the energy trapped that keeps on oscillating between INDUCTIVE and capacitive element. It plays a vital role in GENERATING flux in electrical machines. It is expressed in Volt Ampere reactive.

16.

Salient pole machines are more stable than cylindrical rotor machines.(a) True(b) FalseI have been asked this question in an online quiz.The doubt is from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (a) True

Easy explanation: Salient POLE machines are more stable than cylindrical rotor machines because of the high SHORT circuit ratio and more real power transfer capability. The AIR GAP length in salient pole machines is more as compare to cylindrical rotor machines.

17.

What is the formula for the active power in the cylindrical rotor synchronous machine? (Eb represents armature emf, Vt represents terminal voltage, δ represents rotor angle, X represents reactance)(a) Eb×Vt×sinδ÷X(b) Eb×Vt^2×sinδ÷X(c) Eb^2×Vt×sinδ÷X(d) Eb×Vt×sinδ÷X2This question was posed to me at a job interview.This intriguing question originated from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Right option is (a) Eb×Vt×sinδ÷X

For EXPLANATION: The real POWER in the cylindrical rotor MACHINE is Eb×Vt×sinδ÷X. It is inversely PROPORTIONAL to the reactance. The stability of the machine is decided by the maximum power transfer capability.

18.

In a DC shunt motor, the electromagnetic torque developed is proportional to ______(a) Ia(b) Ia^2(c) Ia^3(d) Ia^.5The question was posed to me during an online interview.I need to ask this question from Dynamics in division Dynamics of Electrical Drives of Electric Drives

Answer»

The correct choice is (a) Ia

Easiest explanation: In a DC shunt MOTOR, the ELECTROMAGNETIC torque developed is equal to KmΦIa. In a DC shunt, the motor field windings are CONNECTED SEPARATELY and EXCITED by a constant DC voltage. T = KmΦIa α Ia.

19.

The slope of the V-I curve is 90°. Calculate the value of resistance.(a) 1.732 Ω(b) 1.608 Ω(c) 1.543 Ω(d) 1.648 ΩI got this question by my college professor while I was bunking the class.Question is from Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»

Right option is (a) 1.732 Ω

For EXPLANATION I would say: The SLOPE of the V-I curve is resistance. The slope given is 90° so R=tan(90°)=INFINITE Ω. It BEHAVES as an open-circuit.

20.

Calculate the value of the time period if the frequency of the signal is 70 sec.(a) 0.014 sec(b) 0.013 sec(c) 0.017 sec(d) 0.079 secI got this question in unit test.This interesting question is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

The CORRECT choice is (a) 0.014 SEC

Explanation: The TIME period is DEFINED as the time after the signal repeats itself. It is EXPRESSED in second. T =1÷F=1÷70=.014 sec.

21.

In a DC series motor, the electromagnetic torque developed is proportional to ______(a) Ia(b) Ia^2(c) Ia^3(d) Ia^.5The question was asked during an interview.This intriguing question originated from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

Correct CHOICE is (b) Ia^2

Explanation: In a DC SERIES motor, the electromagnetic torque developed is EQUAL to KmΦIa. In a DC series, the motor field winding is CONNECTED in series with the armature so the flux in the field winding is proportional to CURRENT. T = KmΦIa α Ia^2.

22.

The most suitable servo-motor application is __________(a) AC series motor(b) DC series motor(c) AC two-phase induction motor(d) DC shunt motorThis question was addressed to me in my homework.The question is from Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»
23.

Calculate the moment of inertia of the sphere having a mass of 12 kg and radius of 78 cm.(a) 7.888 kgm^2(b) 7.300 kgm^2(c) 7.545 kgm^2(d) 7.552 kgm^2This question was posed to me in an interview for job.The query is from Dynamics topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct option is (b) 7.300 kgm^2

For EXPLANATION: The moment of inertia of the egg can be CALCULATED USING the formula I=Σmiri^2. The mass of egg and radius is given. I=(12)×(.78)^2=7.300 kgm^2. It depends upon the ORIENTATION of the ROTATIONAL axis.

24.

The unit of current is Tesla.(a) True(b) FalseThe question was posed to me in an international level competition.The above asked question is from Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT choice is (b) False

Explanation: The current is the amount of charge that can flow through an AREA in a given amount of time. It is MATHEMATICALLY represented as d(q)/d(t). It is expressed in TERMS of Ampere.
25.

The generated e.m.f from 70-pole armature having 100 conductors driven at 10 rev/sec having flux per pole as 20 mWb, with wave winding is ___________(a) 730 V(b) 740 V(c) 700 V(d) 690 VThis question was addressed to me in semester exam.My enquiry is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»
26.

Calculate the value of the frequency if the time period of the signal is 20 sec.(a) 0.05 Hz(b) 0.04 Hz(c) 0.02 Hz(d) 0.03 HzI have been asked this question in semester exam.My question is from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Correct option is (a) 0.05 Hz

The explanation is: The frequency is defined as the NUMBER of OSCILLATIONS per second. It is reciprocal of the time PERIOD. It is EXPRESSED in Hz. F = 1÷T=1÷20=.05 Hz.

27.

A 4-pole lap wound generator with 720 armature conductors and a flux per pole of .003 Wb has an armature current of 50 A. The developed torque is _________(a) 17.25 N-m(b) 17.19 N-m(c) 16.54 N-m(d) 16.89 N-mThe question was posed to me in a national level competition.My question is based upon Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Right option is (b) 17.19 N-m

For explanation I would say: The DEVELOPED torque in the MOTOR is KM×I. The value of MACHINE CONSTANT(Km) is Eb÷ωm = Φ×Z×P÷2×3.14×A = .003×720×4÷2×3.14×4 = .3438 Vs/rad. The developed torque is .3438×50 = 17.19 N-m.

28.

Calculate mark to space ratio if the system is on for 5 sec and off for 10 sec.(a) .5(b) .4(c) .2(d) .6This question was addressed to me in my homework.This question is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT option is (C) .2

Explanation: Mark to space is Ton÷Toff. It is the ratio of TIME for which the system is active and the time for which is INACTIVE. M = Ton÷Toff=5÷10=2.
29.

The slope of the V-I curve is 60°. Calculate the value of resistance. Assume the relationship between voltage and current is a straight line.(a) 1.732 Ω(b) 1.608 Ω(c) 1.543 Ω(d) 1.648 ΩI have been asked this question in an interview for job.My doubt is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

The CORRECT OPTION is (a) 1.732 Ω

Explanation: The slope of the V-I curve is RESISTANCE. The slope GIVEN is 60° so R=tan(60°)=1.732 Ω. The slope of the V-I curve is resistance.

30.

What is the unit of resistance?(a) ohm(b) ohm^-1(c) ohm^2(d) ohm^5I got this question in quiz.My enquiry is from Dynamics topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct CHOICE is (a) ohm

Easy EXPLANATION: The resistance is the opposition offered by the body to the flow of CURRENT. It is the ratio of VOLTAGE and current. It is GIVEN in ohms.

31.

Which of the theorems helps in the calculation of the moment of inertia?(a) The theorem of Parallel and Perpendicular axes(b) The theorem of Horizontal and Perpendicular axes(c) The theorem of Vertical and Perpendicular axes(d) The theorem of Parallel and Tilted axesI have been asked this question by my college director while I was bunking the class.I want to ask this question from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT choice is (a) The theorem of Parallel and Perpendicular axes

Easy explanation: The theorem of Parallel and Perpendicular axes helps in the calculation of the moment of INERTIA. The moment of inertia of the COMPLEX BODIES can be easily calculated with the help of these theorems.
32.

Calculate the moment of inertia of the egg having a mass of 7 kg and radius of 44 cm.(a) .968 kgm^2(b) 1.454 kgm^2(c) 1.545 kgm^2(d) 1.552 kgm^2The question was posed to me in final exam.This intriguing question originated from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

The CORRECT choice is (d) 1.552 kgm^2

The best I can explain: The moment of inertia of the egg can be calculated USING the formula I=∑miri^2. The mass of egg and RADIUS is GIVEN. I=(7)×(.44)^2=1.552 kgm^2. It depends upon the ORIENTATION of the rotational axis.

33.

The generated e.m.f from 50-pole armature having 400 conductors driven at 20 rev/sec having flux per pole as 30 mWb, with lap winding is ___________(a) 230 V(b) 140 V(c) 240 V(d) 250 VThe question was posed to me in semester exam.This intriguing question originated from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Right CHOICE is (c) 240 V

Best explanation: The generated can be calculated using the FORMULA Eb = Φ×Z×N×P÷60×A, Φ represent flux per POLE, Z represents the TOTAL number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. In lap winding number of parallel paths are EQUAL to the number of poles. Eb = .03×50×400×1200÷60×50= 240 V.

34.

What is the formula for the moment of inertia? (m – a mass of the body, r – distance from the axis of the rotation)(a) ∑miri^2(b) ∑miri(c) ∑miri^4(d) ∑miri^3I have been asked this question during an interview for a job.I'm obligated to ask this question of Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (a) ∑miri^2

Easiest EXPLANATION: The moment of inertia is the property by the VIRTUE of which the BODY withstand the effect of angular acceleration. It DEPENDS on the shape and mass distribution of the body.

35.

The unit of the moment of inertia is Kgm^2.(a) True(b) FalseThe question was posed to me during an interview for a job.I need to ask this question from Dynamics topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

Right choice is (a) True

To explain I would SAY: The MOMENT of inertia is taken as the SUM of the product of the MASS of each particle with the square of their distance from the axis of the rotation. The unit of the moment of inertia is kg×m^2=kgm^2.

36.

What is a mark to space ratio?(a) Ton÷Toff(b) Ton÷(Ton- Toff)(c) Ton÷2×(Ton*Toff)(d) Ton÷2×ToffThe question was asked in an international level competition.My question is taken from Dynamics of Motor-Load Combination in division Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT CHOICE is (a) Ton÷Toff

The best I can explain: Mark to SPACE is Ton÷Toff. It is the ratio of time for which the SYSTEM is active and the time for which is inactive. It has no unit.
37.

The slope of the I-V curve is 30°. Calculate the value of resistance. Assume the relationship between I and V is a straight line.(a) 1.732 Ω(b) 2.235 Ω(c) 1.625 Ω(d) 1.524 ΩThe question was posed to me in quiz.Enquiry is from Dynamics of Motor-Load Combination topic in division Dynamics of Electrical Drives of Electric Drives

Answer» RIGHT OPTION is (a) 1.732 Ω

Explanation: The slope of the I-V curve is RECIPROCAL of resistance. The slope GIVEN is 30° so R=1÷tan(30°)=1.732 Ω. The slope of the V-I curve is resistance.
38.

The phase difference between voltage and current in the inductor.(a) 45°(b) 90°(c) 80°(d) 55°I had been asked this question in final exam.The doubt is from Dynamics of Motor-Load Combination topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

The correct CHOICE is (b) 90°

The BEST I can EXPLAIN: In the CASE of an inductor, the voltage leads the current by 90° or the current lags the voltage by 90o. The PHASE difference between voltage and current is 90°.

39.

The generated e.m.f from 25-pole armature having 200 conductors driven at 10 rev/sec having flux per pole as 20 mWb, with two parallel paths is ___________(a) 400 V(b) 500 V(c) 200 V(d) 300 VI have been asked this question in homework.This question is from Dynamics of Motor-Load Combination in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Correct answer is (B) 500 V

Best explanation: The generated can be calculated USING the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux PER pole, Z REPRESENTS the total NUMBER of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. Eb = .02×25×200×600÷60×2= 500 V.

40.

Which of the following motor can be referred as a universal motor?(a) DC shunt motor(b) DC compound motor(c) Permanent magnet motor(d) DC series motorI had been asked this question by my school teacher while I was bunking the class.My doubt stems from Dynamics of Motor-Load Combination topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Right OPTION is (d) DC series motor

For explanation I would SAY: DC series motor can OPERATE on DC and AC. It is a universal motor. Universal MOTORS are those motors that can operate on both DC and AC. DC shunt motor can only operate on DC because of pulsating torque in AC.

41.

The axis along which no emf is produced in the armature conductors is called as ____________(a) Geometrical Neutral Axis (GNA)(b) Magnetic Neutral Axis (MNA)(c) Axis of rotation(d) Axis of revolutionI have been asked this question by my college professor while I was bunking the class.I'd like to ask this question from Dynamics of Motor-Load Combination topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (b) Magnetic NEUTRAL AXIS (MNA)

To elaborate: The coil UNDERGOING commutation must lie along the magnetic neutral axis so that no emf is induced and there is no sparking at the time of commutation.

42.

Which of the following devices should be used as a switch for high power and high voltage application?(a) GTO(b) MOSFET(c) TRIAC(d) ThyristorI had been asked this question at a job interview.This key question is from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

Answer»

The correct answer is (d) THYRISTOR

The explanation: Thyristor is USED for high power APPLICATIONS but it has a limited FREQUENCY range and cannot be used at high frequencies. A thyristor is a UNIDIRECTIONAL, bipolar and semi-controlled device.

43.

Calculate the time period of the waveform x(t)=24sin(24πt+π÷4).(a) .064 sec(b) .047 sec(c) .083 sec(d) .015 secThis question was addressed to me in class test.I would like to ask this question from Dynamics topic in section Dynamics of Electrical Drives of Electric Drives

Answer»

Correct OPTION is (c) .083 sec

Best explanation: The fundamental time PERIOD of the sine wave is 2π. The time period of X(t) is 2π÷24π=.083 sec. The time period is independent of PHASE shifting and time shifting.

44.

R.M.S value of the sinusoidal waveform V=Vmsin(ωt+α).(a) Vm÷2^½(b) Vm÷2^¼(c) Vm÷2^¾(d) Vm÷3^½I got this question in an interview.The above asked question is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

The correct option is (a) VM÷2^½

To ELABORATE: R.M.S value of the sinusoidal waveform is Vm÷2^½ and r.m.s value of the trapezoidal waveform is Vm÷3^½. The PEAK value of the sinusoidal waveform is Vm.

45.

The unit of angular velocity is rad/s^3.(a) True(b) FalseThe question was posed to me in a national level competition.This key question is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

Right choice is (b) False

Easy EXPLANATION: Angular velocity is defined as the rate of change of angular displacement with respect to TIME. Angular displacement is generally expressed in terms of a RADIAN. The UNIT of angular velocity is rad/s.

46.

Load torque of the crane is independent of _________(a) Speed(b) Seebeck effect(c) Hall effect(d) Thomson effectThe question was posed to me in a national level competition.My doubt is from Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives

Answer»

Right choice is (a) Speed

The explanation is: The LOAD TORQUE of the crane is independent of speed. They are short time intermittent types of LOADS. They require CONSTANT POWER for a short period of time.

47.

Servo motors are an example of which type of load?(a) Pulsating loads(b) Short time loads(c) Impact loads(d) Short time intermittent loadsI had been asked this question in class test.I'd like to ask this question from Dynamics in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

The correct OPTION is (b) Short time loads

The explanation: Servo motors are motors with control feedback. The MOTOR can be AC or DC. This is an EXAMPLE of short time loads. They have a high torque to inertia RATIO and high-speed.

48.

Calculate the shaft power developed by a motor using the given data: Eb = 50V and I = 60 A. Assume frictional losses are 400 W and windage losses are 600 W.(a) 4000 W(b) 2000 W(c) 1000 W(d) 1500 WThis question was posed to me in an international level competition.Question is from Dynamics in section Dynamics of Electrical Drives of Electric Drives

Answer»

Right answer is (b) 2000 W

Explanation: Shaft power developed by the MOTOR can be CALCULATED using the formula P = Eb*I-(rotational LOSSES) = 50*60 = 3000 – (600+400) = 2000 W. If rotational losses are NEGLECTED, the power developed becomes equal to the shaft power of the motor.

49.

Which one of the following devices have low power losses?(a) MOSFET(b) IGBT(c) SCR(d) BJTI got this question in an internship interview.This interesting question is from Dynamics topic in division Dynamics of Electrical Drives of Electric Drives

Answer»

Correct option is (c) SCR

The explanation is: SCR is a minority carrier device due to which it EXPERIENCES conductivity MODULATION and it’s ON state RESISTANCE REDUCTION due to which conduction losses are very low.

50.

Which of the following converter circuit operations will be unstable for a large duty cycle ratio?(a) Buck converter(b) Boost converter(c) Buck-Boost converter(d) Boost converter and Buck-Boost converterThe question was asked during an internship interview.The above asked question is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (d) Boost converter and BUCK-Boost converter

To elaborate: The OUTPUT voltage of the buck converter and buck-boost converter are Vo=Vin ÷ (1-D) and Vo = D×Vin ÷ (1-D) respectively. When the value of the DUTY CYCLE tends to 1 output voltage tends to INFINITY.