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Calculate the power factor during the resonance condition.(a) .58(b) .42(c) .65(d) 1The question was posed to me in final exam.Enquiry is from Dynamics topic in chapter Dynamics of Electrical Drives of Electric Drives

Answer»

Correct choice is (d) 1

Explanation: During the resonance condition, the reactive power generated by the CAPACITOR is COMPLETELY ABSORBED by the INDUCTOR. Only active power flows in the circuit. Net reactive power is EQUAL to zero and cosΦ=1.



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