Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

The ratio of the rotor gross power and air gap power is _______(a) s(b) 1-s(c) 1+s(d) 0The question was asked in an online quiz.Asked question is from Induction Motors in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct option is (B) 1-s

The best I can explain: The ratio of the rotor gross POWER and AIR GAP power is 1-s. The air gap power in the INDUCTION motor is Pg and the rotor gross power is (1-s)×Pg. The ratio is 1-s.

2.

The unbalanced set of 3-phase voltages causes ________(a) Positive sequence current(b) Negative sequence current(c) Zero sequence current(d) Half sequence currentThe question was asked in unit test.Origin of the question is Induction Motors topic in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct choice is (b) Negative sequence CURRENT

Explanation: The unbalanced set of 3-phase voltages causes a negative sequence current. The magnetic FIELD generated due to negative sequence current is in the opposite direction to the FUNDAMENTAL magnetic field. This induces double the FREQUENCY current in the rotor side which causes overheating of the motor.

3.

The slots used in the Synchronous machines are___________(a) Closed(b) Semi-open(c) Vacuum(d) OpenThis question was posed to me in class test.My doubt stems from Induction Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT option is (d) Open

Explanation: The slots used in the SYNCHRONOUS machine are open. Open slots have higher air gap and MINIMUM flux LEAKAGE. The maximum POWER transfer capability increase due to a decrease in the leakage reactance.

4.

The slots used in the Induction motor are___________(a) Semi-closed(b) Closed(c) Vacuum(d) OpenThe question was posed to me in my homework.The query is from Induction Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer» RIGHT answer is (a) Semi-closed

For EXPLANATION I would SAY: The SLOTS used in the Induction MOTOR are semi-closed. Open slots are used in the synchronous machine. Semi-closed slots have moderate air gap and lesser flux leakage.
5.

Which type of Induction motor is best for e.m.f injection method?(a) SCIM(b) WRIM(c) Single-phase IM(d) Linear IMI have been asked this question in an interview for internship.I would like to ask this question from Induction Motors topic in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right answer is (b) WRIM

Explanation: E.M.F injection METHOD is used to control the speed of INDUCTION MOTOR. It is only applicable for WRIM because WRIM rotor consists of COPPER windings connected in star connection. The external e.m.f can be connected with it using the slip rings.

6.

The concept of the slip is used in___________(a) Synchronous machine(b) Induction machine(c) DC machine(d) TransformerThis question was posed to me in a national level competition.The question is from Induction Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT option is (B) Induction machine

To explain I would say: The slip in the Induction motor is s = Ns-Nr÷ Ns. The slip existence is DUE to the relative SPEED between the stator magnetic field and rotor.

7.

The use of the capacitor banks in the 3-phase Induction motor is ________(a) To increase the power factor(b) To decrease the speed(c) To increase the speed(d) To decrease the power factorThis question was addressed to me in my homework.Question is from Induction Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right choice is (a) To increase the power factor

To ELABORATE: Capacitor BANKS are used with 3-phase Induction motor in order to IMPROVE the power factor of the machine. The inductor motor generally operates with .6-.8 power factor range.

8.

_________ motor operates at high power factor.(a) Capacitor start(b) Capacitor run(c) Shaded pole(d) ReluctanceI got this question by my college director while I was bunking the class.My question is taken from Induction Motors in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct answer is (B) Capacitor RUN

To ELABORATE: In the capacitor run, the capacitor is permanently connected with auxiliary windings. The capacitor is USED for reactive power compensation. It improves the power FACTOR of the machine.

9.

Which type of Induction motor is best for pole changing method?(a) SCIM(b) WRIM(c) Single-phase IM(d) Linear IMI got this question in my homework.This interesting question is from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct OPTION is (a) SCIM

The EXPLANATION: Pole changing METHOD is used to control the SPEED of Induction motor. It is only applicable for SCIM because SCIM rotor is made up of ALUMINUM, copper bars.

10.

Induction motor is analogous to __________(a) Transformer(b) DC machine(c) Synchronous motor(d) Synchronous generatorThis question was posed to me by my college professor while I was bunking the class.Query is from Induction Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»
11.

Which starting method is the best method in Induction motor?(a) Direct online starting(b) Autotransformer starting(c) Reactance starting(d) Star-Delta startingThis question was addressed to me in an international level competition.I would like to ask this question from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct choice is (d) Star-Delta starting

The explanation: The Star-Delta starting METHOD is one of the best methods for the starting of the Induction MOTOR. This method is cheaper and the line CURRENT in the star is 1÷3 times of in delta connection.

12.

Choose the Induction motor with peak speed.(a) 10 Pole(b) 12 Pole(c) 14 Pole(d) 16 PoleThe question was asked in a national level competition.I'm obligated to ask this question of Induction Motors topic in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right OPTION is (a) 10 Pole

The explanation: Synchronous SPEED of Induction motor is Ns=120×f÷P. Ns∝(1÷P). The synchronous speed is inversely proportional to the pole. The maximum speed will be achieved with a MINIMUM NUMBER of poles.

13.

In Induction motor rotor laminations are thicker than stator laminations.(a) True(b) FalseThe question was posed to me in examination.The above asked question is from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer» RIGHT answer is (a) True

Easy explanation: The lamination thickness basically depends upon the frequency. The ROTOR frequency is s×f where f is stator supply frequency. The rotor LAMINATIONS are thicker than stator laminations because rotor frequency is LESS.
14.

Order of the circuit is the number of memory elements present in the circuit.(a) True(b) FalseThis question was posed to me in examination.My question is from Induction Motors in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»
15.

Calculate the three-phase power using the following data: Vp=23 V, Ip=23 A, ∅=60.(a) 793.5 W(b) 790 W(c) 792 W(d) 791 WI have been asked this question in exam.The query is from Induction Motors topic in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct ANSWER is (a) 793.5 W

To explain: POWER input to a 3-Φ induction motor is 3VpIpcosΦ. The power REMAINS the same for Delta and STAR CONNECTION. P=3×23×23×co60°=793.5 W.

16.

A 3 – phase, 4 pole IM is supplied from a 40 Hz source. Calculate rotor frequency when the rotor runs 100 rpm.(a) 35 Hz(b) 36.6 Hz(c) 9 Hz(d) 8 HzI had been asked this question in my homework.My enquiry is from Induction Motors in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct CHOICE is (B) 36.6 Hz

To EXPLAIN I would say: The SLIP of the induction motor can be calculated using the relation s = Ns-Nr÷ Ns. Ns=120F÷P=1200 rpm. The VALUE of slip is .91. The rotor frequency is 36.6 Hz.

17.

What is the speed of the 11^th order harmonics in the induction motor?(a) Ns(b) Ns/11(c) 2×Ns(d) NrThe question was posed to me during an online interview.The query is from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT answer is (B) Ns/11

The BEST explanation: The SPEED of the 6k±1 is Ns÷6k±1. The speed of the 11^th order time harmonics in the induction motor is Ns/11.

18.

What is the speed of the 6^th order time harmonics in the induction motor?(a) Ns(b) Ns/6(c) 6×Ns(d) 0I got this question in unit test.I would like to ask this question from Induction Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT OPTION is (c) 6×Ns

The EXPLANATION: The time harmonics are present in the supply voltage. The speed of the 6^th ORDER time harmonics in the induction motor is Ns/6.

19.

Single phase induction motor is self-starting.(a) True(b) FalseThis question was addressed to me by my school principal while I was bunking the class.I need to ask this question from Induction Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT OPTION is (B) False

Easy explanation: The single-phase induction motor is not self-starting because of the equal and opposite forward & backward magnetic field. The net torque developed is zero.

20.

Magnetizing current in the induction motor is ______(a) more than the transformer(b) equal as a transformer(c) less than the transformer(d) 0I had been asked this question by my school principal while I was bunking the class.Origin of the question is Induction Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct answer is (a) more than the TRANSFORMER

To explain: The MAGNETIZING CURRENT in the induction motor is (23-25)% of the full load current. The magnetizing current in the transformer is 3-5% of the full load.

21.

The ratio of the rotor copper loss and air gap power is _______(a) s(b) 1-s(c) 1+s(d) 0I have been asked this question during an interview.Question is taken from Induction Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT answer is (a) s

Explanation: The RATIO of the ROTOR COPPER loss and air gap power is s. The air gap power in the induction motor is Pg and the rotor copper loss is s×Pg. The ratio is s.

22.

What will happen if we increase the air gap in the induction motor?(a) Power factor will reduce(b) Power factor will increase(c) Reduction in harmonics(d) Speed will increaseI got this question by my college professor while I was bunking the class.This interesting question is from Induction Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct answer is (a) Power FACTOR will REDUCE

To explain I would say: If we increase the air gap in the induction MOTOR, the MACHINE will draw more MAGNETIZING current to maintain flux in the air gap. The power factor of the machine will reduce.

23.

The relative speed between the rotor and stator in the induction motor is ______(a) Nr(b) Ns-Nr(c) Ns+Nr(d) 0This question was posed to me during an online exam.I want to ask this question from Induction Motors topic in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right choice is (a) Nr

Explanation: In INDUCTION motor rotor tries to catch up the stator MAGNETIC field in order to satisfy LENZ law. EFFECT opposes the cause. Stator remains at REST. The relative speed is Nr-0=Nr.

24.

The relative speed between the stator magnetic field and stator in the induction motor is ______(a) Ns(b) Ns-Nr(c) Ns+Nr(d) 0I got this question during an online exam.I'd like to ask this question from Induction Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct option is (a) Ns

For explanation I would say: In Induction MOTOR STATOR magnetic field rotates at the SPEED of synchronous speed. The stator is MADE up of Silicon STEEL and remains at rest. The relative speed is Ns-0 = Ns.

25.

The relative speed between the stator magnetic field and rotor in the synchronous generator is ______(a) Ns(b) Ns-Nr(c) Ns+Nr(d) 0I have been asked this question in homework.This intriguing question originated from Induction Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right option is (d) 0

The EXPLANATION is: In SYNCHRONOUS generator rotor and stator magnetic field rotates at speed of synchronous speed in order to PRODUCE the steady state TORQUE.

26.

The relative speed between the stator magnetic field and rotor in the induction motor is ______(a) Ns(b) Ns-Nr(c) Ns+Nr(d) 0This question was addressed to me in exam.The above asked question is from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct OPTION is (b) Ns-Nr

Explanation: In induction motor ROTOR tries to catch up the STATOR magnetic field in order to satisfy Lenz law. Effect OPPOSES the cause. Stator magnetic field rotates at the speed of synchronous speed.

27.

For motoring mode, the phase angle between the stator phase voltage and stator phase current should be _______(a) < 90°(b) > 90°(c) < 40°(d) 180°This question was posed to me during an interview for a job.The query is from Induction Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT CHOICE is (a) < 90°

Explanation: For motoring mode, the phase angle between the stator phase voltage and stator phase current should be < 90°. The rotor magnetic FIELD tries to catch up the stator magnetic field.
28.

Power input to an induction motor is given by _________(a) 3VpIpcosΦ(b) 2VpIpcosΦ(c) VpIpcosΦ(d) 5VpIpcosΦThis question was addressed to me by my school teacher while I was bunking the class.Query is from Induction Motors in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct CHOICE is (a) 3VpIpcosΦ

Best explanation: Power INPUT to a 3-Φ INDUCTION motor is 3VpIpcosΦ. The power remains the same for Delta and star CONNECTION. The power is CONSTANT and has no vibrations.

29.

Calculate the bandwidth in series RLC circuit if the frequency is 20 Hz and the quality factor is 5.(a) 2 Hz(b) 4 Hz(c) 6 Hz(d) 8 HzThis question was addressed to me in quiz.My doubt stems from Countercurrent Braking of DC Shunt Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right answer is (b) 4 Hz

For explanation I would SAY: BANDWIDTH is defined as the range of frequencies for which the signal exists. SELECTIVITY is INVERSELY proportional to the bandwidth. B.W(Hz)=f÷Q=20÷5=4 Hz.

30.

The value of current at time of starting is ___________(a) High(b) Low(c) Very low(d) 0This question was posed to me in class test.My question is taken from Countercurrent Braking of DC Shunt Motors in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct ANSWER is (a) HIGH

The explanation is: At the TIME of starting the MOTOR is at rest. The e.m.f developed in the motor is zero. Ia×Ra = Vt-Eb. Ia=Vt÷Ra. The starting current is very high about 10-15 times of FULL load current.

31.

The relationship between the torque(T) and power(P) developed in the DC shunt motor is ___________ (Neglecting all the losses)(a) T ∝ √P(b) T ∝ P^2(c) T ∝ ∛P(d) T ∝ PI got this question during an interview.I need to ask this question from Countercurrent Braking of DC Shunt Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT CHOICE is (d) T ∝ P

The explanation is: The torque DEVELOPED in the DC SHUNT motor is the ratio of power developed and angular

speed of the motor. T=EbIa÷ωm=P÷ωm. T ∝ P.
32.

Calculate the current in DC shunt field winding using the following data: Ia=15 A, IL=21, R=22, N=484.(a) 4 A(b) 2 A(c) 7 A(d) 6 AI had been asked this question in my homework.I'm obligated to ask this question of Countercurrent Braking of DC Shunt Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct answer is (d) 6 A

The best explanation: In DC shunt MOTOR, FIELD windings are connected in PARALLEL with the armature circuit. IF=IL-Ia=11-5=6 A. Motor CURRENT is the SUM of field and armature current.

33.

Full form of TVR is _________(a) Terminal voltage reversal(b) Total voltage reversal(c) Terminal voltage redirect(d) Total voltage reversalI got this question in examination.My question is from Countercurrent Braking of DC Shunt Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right CHOICE is (a) Terminal voltage reversal

The explanation is: TVR stands for terminal voltage reversal. It is ONE of the METHODS of COUNTERCURRENT braking of the DC shunt motor. It HALTS the motor rapidly and reverses its direction of rotation.

34.

The sine function is an odd function.(a) True(b) FalseThis question was addressed to me in an interview for job.This intriguing question comes from Dynamic Braking of DC Shunt Motors topic in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct choice is (a) True

To explain: The odd functions are those functions which are symmetric about the ORIGIN. The sine function is an odd function WHOSE TIME PERIOD is 2π.

35.

Calculate the value of inductor voltage during resonance condition if the value of supply voltage is 7 V and the quality factor is 9.(a) 59 V(b) 63 V(c) 73 V(d) 33 VThe question was posed to me in an international level competition.I would like to ask this question from Regenerative Braking of DC Series Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right option is (b) 63 V

The EXPLANATION: During the RESONANCE condition XL=Xc. The value of the inductor voltage is Q×Vs. The power FACTOR of the CIRCUIT is one. Vc=7×9=63 V.

36.

The shape of the current-torque characteristics in DC shunt motor is __________(a) Rectangular Hyperbola(b) Parabola(c) Straight line(d) EllipseI have been asked this question in a job interview.I'd like to ask this question from Countercurrent Braking of DC Shunt Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT OPTION is (c) Straight line

The explanation is: The SHAPE of the current-torque characteristics in the DC shunt motor is a straight line. The motor equation is Eb=Vt-IaRa=Km∅ωm. T=Km∅IA. ∅∝If. Torque ∝ Ia.
37.

DC shunt motors are used where the high _________ is required.(a) Starting torque(b) Maximum torque(c) Minimum torque(d) Breakdown torqueThe question was asked during an internship interview.This intriguing question comes from Countercurrent Braking of DC Shunt Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The correct option is (a) Starting TORQUE

Explanation: DC SERIES motors are used where the high starting torque is required. At starting the torque produced by DC series MOTOR is very high.

38.

The shape of the speed-torque characteristics in DC shunt motor is __________(a) Rectangular Hyperbolic(b) Whole x-y plane(c) Circle(d) EllipseI have been asked this question by my school teacher while I was bunking the class.This interesting question is from Countercurrent Braking of DC Shunt Motors topic in section Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT OPTION is (a) Rectangular Hyperbolic

To elaborate: The SHAPE of the speed-torque characteristics in the DC shunt motor is a rectangular hyperbola. The motor EQUATION is Eb=Vt-IaRa=Km∅ωm. N=(Vt/KmIa)-Ra/Km. Ia∝√T.N∝1÷√T.
39.

Calculate the flux produced by the DC shunt field winding using the following data: Ia=5 A, IL=11, R=2, N=4.(a) 14 Wb(b) 12 Wb(c) 17 Wb(d) 18 WbI got this question during an online interview.My question is from Countercurrent Braking of DC Shunt Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

The CORRECT answer is (b) 12 WB

To explain: In DC shunt motor, field windings are connected in parallel with the ARMATURE circuit. IF=IL-Ia=11-5=6 A. F=NIF=R∅. IF∝∅. ∅=F÷R=12 wb.

40.

The shape of the speed-armature current characteristics in DC shunt motor is __________(a) Hyperbolic(b) Parabola(c) Negative slope linear line(d) EllipseThe question was posed to me by my school teacher while I was bunking the class.My doubt is from Countercurrent Braking of DC Shunt Motors in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT choice is (c) Negative slope linear line

Explanation: The shape of the speed-armature current characteristics in DC SHUNT motor is negative slope linear line. The motor EQUATION is Eb=Vt-IaRa=Km∅ωm. N=(Vt-IRa)/Km. N vs IA is a negative slope line with slope = -Ra/Km.
41.

Torque developed in the motor is ___________(a) KmΦIa(b) KmΦIa^3(c) 2KmΦIa(d) KmΦIa^2This question was posed to me by my college professor while I was bunking the class.My query is from Countercurrent Braking of DC Shunt Motors topic in division Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct OPTION is (a) KmΦIa

To EXPLAIN: The torque developed in the MOTOR is DIRECTLY proportional to the FLUX, machine constant, armature current. It is mathematically represented as T= KmΦIa.

42.

Braking resistance should be selected in order to limit the braking current.(a) True(b) FalseThis question was posed to me by my college director while I was bunking the class.This interesting question is from Countercurrent Braking of DC Shunt Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT answer is (a) True

The explanation: During BRAKING, a high CURRENT flows in the armature circuit. To limit the braking current a PROPER value of braking resistance should be selected.
43.

In DC shunt machine ∅ is directly proportional to Ia.(a) True(b) FalseThis question was posed to me in an interview for job.Query is from Countercurrent Braking of DC Shunt Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»
44.

Plugging is suitable for __________ type loads.(a) Gravitational(b) Electrostatic(c) Weightless(d) LeadingThe question was posed to me in an interview for internship.The question is from Countercurrent Braking of DC Shunt Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right CHOICE is (a) Gravitational

The best explanation: Plugging is SUITABLE for gravitational type loads. It halts the motor operation. It can REVERSE the DIRECTION of rotation of the motor. It can hold the motor at zero speed.

45.

The field diverter resistance for a DC series motor is kept ________(a) High(b) Low(c) zero(d) oneI had been asked this question in a national level competition.This interesting question is from Dynamic Braking of DC Series Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right choice is (B) Low

For explanation: The field diverter resistance for a DC SERIES motor is kept low in order to INCREASE the speed of the motor. This will REDUCE the field FLUX and increase the armature current.

46.

For a given torque, increasing diverter resistance of a DC series motor causes the ________(a) decrease in speed and less armature current(b) decrease in speed but armature current remains the same(c) increase in speed and more armature current(d) increase in speed but armature current remains the sameI got this question in homework.Question is from Dynamic Braking of DC Series Motors in chapter Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right option is (a) decrease in speed and less armature current

Explanation: In DC series motor, INCREASING diverter resistance increases the field current and field FLUX and ALSO DECREASES the armature current and therefore decreases the speed.

47.

Calculate the current in DC series field winding using the following data: Ia=3 A.(a) 4 A(b) 2 A(c) 3 A(d) 6 AI have been asked this question in a job interview.This interesting question is from Dynamic Braking of DC Series Motors topic in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Correct choice is (C) 3 A

Easiest explanation: In DC series motor, FIELD WINDINGS are CONNECTED in series with the armature circuit. The armature current will also flow through the series winding. If=Ia=3 A.

48.

The shape of the current-torque current characteristics in DC series motor is a __________(a) Rectangular Hyperbolic(b) Parabola(c) Circle(d) EllipseThis question was addressed to me in exam.Question is from Dynamic Braking of DC Series Motors in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right CHOICE is (b) Parabola

The explanation is: The shape of the current-torque CHARACTERISTICS in the DC SERIES motor is a parabola. The motor equation is Eb=Vt-IaRa=Km∅ωm. T=Km∅Ia. ∅∝Ia. T∝Ia^2.

49.

DC series motors are used where the high ________ torque is required.(a) Maximum(b) Minimum(c) Starting(d) StallingThe question was asked during an interview.The origin of the question is Dynamic Braking of DC Series Motors in section Braking of DC Motors & Induction Motors of Electric Drives

Answer»

Right option is (c) Starting

To elaborate: DC series MOTORS are used where the HIGH starting TORQUE is required. At starting the torque PRODUCED by DC series motor is very high. To start a motor torque should be greater than load torque.

50.

The shape of the speed-torque current characteristics in DC series motor are __________(a) Rectangular Hyperbolic(b) Parabola(c) Circle(d) EllipseThe question was asked during an interview.The query is from Dynamic Braking of DC Series Motors topic in portion Braking of DC Motors & Induction Motors of Electric Drives

Answer» CORRECT option is (a) Rectangular Hyperbolic

Easiest explanation: The SHAPE of the speed-torque CHARACTERISTICS in the DC series MOTOR is a rectangular HYPERBOLA. The motor equation is Eb=Vt-IaRa=Km∅ωm. N=(Vt/KmIa)-Ra/Km. Ia∝√T.N∝1÷√T.