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1.

A cell of emf 12v is connected in series with a 5ohms resistor. Determine the current in the circuit.

Answer» V=IR

⇒I=V/R

⇒I=12/5=2.4

Therefore the correct answer is 2.4A

V = 12 v

R =  5 Ω

V = iR

\(i = \frac VR\) 

\(i = \frac {12}5\) 

i = 2.4 A