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1051.

State the precautions against static charge.

Answer»

1. Home appliances should be grounded. 

2. Avoid using rubber soled footwear. 

3. Keep your surroundings humid (dry air can retain static charges).

1052.

Explain the concept of static charge.

Answer»

1. Static charges can be created whenever there is a friction between an insulator and other object.

2. For example, when an insulator like rubber or ebonite is rubbed against a cloth, the friction between them causes electrons to be transferred from one to the other.

3. This property of insulators is used in many applications such as photocopier, inkjet printer, painting metal panels, electrostatic precipitation/separators etc.

1053.

A dipole of electric dipole moment p is placed in a uniform electric field of strength E. If `theta` is the angle between positive direction of p and E, then the potential energy of the electric dipole is largest when `theta` isA. ZeroB. `pi//2`C. `pi`D. `pi//4`

Answer» Correct Answer - C
1054.

A dipole of electric dipole moment p is placed in a uniform electric field of strength E. If `theta` is the angle between positive direction of p and E, then the potential energy of the electric dipole is largest when `theta` isA. `(pi)/(4)`B. `(pi)/(2)`C. `pi`D. zero

Answer» Correct Answer - C
1055.

Explain the concept of continuous charge distribution.

Answer»

i. A system of charges can be considered as a continuous charge distribution, if the charges are located very close together, compared to their distances from the point where the intensity of electric field is to be found out.

ii. Thus, the charge distribution is said to be continuous for a system of closely spaced charges. It is treated equivalent to a total charge which is continuously distributed along a line or a surface or a volume.

1056.

The ratio of electrostatic and gravitational force acting between electron and proton separated by a distance `5 xx 10^(-11)m`, will be (charge on electron `= 1.6 xx 10^(-19)C`, mass of electron `= 9.1 xx 10^(-31) kg`, mass of proton `= 1.6 xx 10^(-27) kg, G = 6.7 xx 10^(-11) N - m^(2)//kg^(2)`)A. `2.36 xx 10^(39)`B. `2.36 xx 10^(40)`C. `2.34 xx 10^(41)`D. `2.34 xx 10^(42)`

Answer» Correct Answer - A
1057.

The dimensional formula of electric field intensity is(A) [M1E1T-2A-1](B) [M1L1T-3A-1](C) [M-1L2T-3A-1](D) [M1L2T-3A-2]

Answer»

Correct option is: (B) [M1L1T-3A-1]

1058.

A force of 2.25 N acts on a charge of 15 × 10-4 C. Calculate the intensity of electric field at that point.(A) 1500 NC-1(B) 150 NC-1(C) 15000NC-1(D) 2500 NC-1

Answer»

Correct option is: (A) 1500 NC-1

1059.

Two points A and B are maintained at a potential of 7 V and -4 V respectively. The work done in moving 50 electrons from A to B is- (a) 8.80 x 10-17J (b) -8.80 x 10-17J(c) 4.40 x10-17J (d) 5.80 x 10-17J

Answer»

Correct answer is (a) 8.80 x 10-17

1060.

If voltage applied on a capacitor is increased from V to 2V, choose the correct conclusion. (a) Q remains the same, C is doubled (b) Q is doubled, C doubled (c) C remains same, Q doubled (d) Both Q and C remain same

Answer»

(c) C remains same, Q doubled

1061.

A parallel plate capacitor stores a charge Q at a voltage V. Suppose the area of the parallel plate capacitor and the distance between the plates are each doubled then which is the quantity that will change?(a) Capacitance (b) Charge(c) Voltage (d) Energy density

Answer»

(d) Energy density.

1062.

Three capacitors are connected in triangle as shown in the figure. The equivalent capacitance between the points A and C is(a) 1 μF(b) 2 μF (c) 3 μF (d) 1/4 μF

Answer»

Correct answer is (b) 2 μF

1063.

How much work is doen in moving a `500 muC` charge between two points on an equipotential surface ?

Answer» Zero. As `W = q DeltaV = 500 muC xx 0 = 0`.
1064.

What are the points at which electric potential of a dipole has (i) maximum value (ii) minimum value ?

Answer» (i) At axial points, the electric potential of a diople has maximum positive or negative value.
(ii) At equatorial points, the electric potential of a dipole is zero.
1065.

Can you say that earth is an equipotential surface ?

Answer» Yes, As earth is a conductor, so its surface is equipotential`.
1066.

A capacitor C is charged to a potential V by a battery. It is then disconnected from the battery and again connected with its polarity reversed to the batteryA. The work done by the battery is `CV^(2)`B. The total charge the passes through battery is 2 CVC. The initial and final energy of the capacitor is sameD. The work done by the battery is `2 CV^(2)`

Answer» Correct Answer - B::C::D
1067.

Four identical charges q are placed at the corners of a square of side a. Find the potential energy of one of the charges due to the remaining charges. .

Answer» The electric potential of point A due to the charges placed at B, C and D is
`V=1/(4piepsi_(0))q/a+1/(4pi epsi_(0))q/(sqrt(2)a)+1/(4piepsi_(0))q/a=1/(4pi epsi_(0))(2+1/sqrt(2))q/a`
`:.` Potential energy of the charge at a is `=qV=1/(4piepsi_(0))(2+1/sqrt(2))q^(2)/a`.
1068.

In a parallel plate capacitor , the capacity increases ifA. area of plate is decreasedB. distance between plate increasesC. area of plate is increasedD. dielectric constant decreases

Answer» Correct Answer - C
1069.

Ampere second is a unit ofA. capacitanceB. chargeC. energyD. power

Answer» Correct Answer - B
1070.

In a parallel plate capacitor , the capacity increases ifA. increase of its areaB. decrease of its areaC. increase of distance between platesD. it is independent on area

Answer» Correct Answer - A
1071.

The effective capacity between A and B of the given network is A. 3CB. 2CC. CD. `C/3`

Answer» Correct Answer - A
1072.

Series combination is used when a high voltage is to be divided on several capacitors. Capacitor with minimum capacitance has the maximum potential difference between the plates.

Answer»

Series combination of capacitors

1. Equivalent capacitance is less than the smallest capacitance in series. For several capacitors of given capacitances, the equivalent capacitance of their series combination is minimum. 

2. All capacitors in the combination have the same charge but their potential differences are in the inverse ratio of their capacitances

3. Series combination of capacitors is sometimes used when a high voltage, which exceeds the breakdown voltage of a single capacitor, is to be divided on more than one capacitors. Capacitive voltage dividers are only useful in AC circuits, since capacitors do not pass DC signals.

Parallel combination of capacitors

1. For several capacitors of given capacitances, the equivalent capacitance of their parallel combination is maximum. 

2. The same voltage is applied to all capacitors in the combination, but the charge stored in the combination is distributed in proportion to their capacitances. The maximum rated voltage of a parallel combination is only as high as the lowest voltage rating of all the capacitors used. That is, if several capacitors rated at 500 V are connected in parallel to a capacitor rated at 100 V, the maximum voltage rating of the capacitor bank is only 100 V.

3. Parallel combination of capacitors is used when a large capacitance is required, i.e., a large charge is to be stored, at a small potential difference.

1073.

If we apply a large enough electric field, we can ionize the atoms and create a condition for electric charge to flow like a conductor. The fields required for the breakdown of dielectric is called dielectric strength.

Answer»

In a sufficiently strong electric field, the molecules of a dielectric material become ionized, allowing flow of charge. The insulating properties of the dielectric breaks down, permanently or temporarily, and the phenomenon is called dielectric breakdown. During dielectric breakdown, electrical discharge through the dielectric follows random-path patterns like tree branches, called a Lichtenberg figure. Dielectric strength is the voltage that an insulating material can withstand before breakdown occurs. It usually depends on the thickness of the material. It is expressed in kV/mm. For example, the dielectric strengths of air, polystyrene and mica in kV/mm are 3, 20 and 118. Higher dielectric strength corresponds to better insulation properties.

1074.

Is electrostatic potential necessarily zero at a point where electric field strength is zero? Justify.

Answer»

Electric potential is a scalar quantity while electric field intensity is a vector quantity. When we add potentials at a point due two or more point charges, the operation is simple scalar addition along with the sign of V, determined by the sign of the q that produces V. At a point, the net field is the vector sum of the fields due to the individual charges. Midway between the two charges of an electric dipole, the potentials due to the two charges are equal in magnitude but opposite in sign, and thus add up to zero. But the electric fields due to the charges are equal in magnitude and direction-towards the negative charge-so that the net field there is not zero. But midway between two like charges of equal magnitudes, the potentials are equal in magnitude and have the same sign, so that the net potential is nonzero. However, the fields due to the two equal like charges are equal in magnitude but opposite in direction, and thus vectorially add up to zero.

1075.

What is gravitational Potential ?

Answer»

We measure the gravitational potential energy U of a body (1) by assigning U = 0 for a reference configuration (such as the body at a reference level) (2) then equating U to the work W done by an external force to move the body up or down from that level to a point. We then define gravitational potential of the point as gravitational potential energy per unit mass of the body.

We follow the same procedure with the electric force, which is also a conservative force with the only difference that while the gravitational force is always attractive, electric force can be attractive (for unlike charges) or repulsive (for like charges).

1076.

Electric lines of force about negative point charge areA. circular ,anticlockwiseB. circular ,clockwiseC. radial ,inwardD. radial , outward

Answer» Correct Answer - 3
1077.

The spatial distribution of the electric field due to charges `(A,B)` is shown in figure. Which of the following statements is correct? A. A is `+ve` and `B -ve` and `|A| gt |B|`B. A is `-ve` and `B + ve ,|A| gt|B|`C. Both are `+ve` but `A gt B`D. Both are `-ve` but `A gt B`

Answer» Correct Answer - 1
1078.

An infinite number of charges each equal to q, are placed along the X-axis at `x = 1, x = 2, x = 4, x = 8`,…….. and so on. (i) find the electric field at a point `x = 0` due to this set up of charges. (ii) What will be the electric field if the above setup, the consecutive charges have opposite signs.A. `(2q)/(3) , 4q`B. `(2q)/(5) ,(4q)/(5)`C. `(2q)/(3),(4q)/(5)`D. `(2q)/(5),(4q)/(7)`

Answer» Correct Answer - 3
`V_(o) = (q)/(4 pi in_(0)) [ 1 - (1)/(2) + (1)/(4) + …oo = (1)/(1 - (-1//2))]`
` = (1)/(4 pi in_(0)) [ (2q)/(3)]`
`E_(0) = (q)/(4 pi in_(0)) [ 1 - (1)/(4) + (1)/(16) - … = (1)/( 1 - (-1//4))]`
`= (1)/(4 pi in_(0)) .(4q)/(5)`
1079.

A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the center of the cube.

Answer» We know that the length of diagonal of the cube side b is `sqrt(3b^(2)) = b sqrt(3)`
`:.` Distance between center of cube and each vertex, `r = (b sqrt(3))/(2)`
AS `V = (1)/(4pi in_(0)) (q)/(r )`
and 8 charges each of value q are present at the eight verticies of the cube, therefore,
`V = (1)/(4pi in_(0)) (8q)/(b sqrt(3)//2) or V = (4q)/(sqrt(3) pi in_(0) b)`
Further electric field intensity at the center due to all the eight charges is zero, because the fileds due to individual charges cancel in pairs.
1080.

A parallel plate capacitor of area `100 cm^(2)` and plate separation 8.85 mm is charged to a potential difference of 100 V when air is used between the plates. The capacitor is now isolated and air is replaced by glass `(epsi_(r) - 5)`, then:A. The original capacity will be 10 pFB. The new capacity will be 50 pFC. The new potential difference is 200 VD. The new energy stored is `mu J`

Answer» Correct Answer - A::B
1081.

If E = 0 at all points on a closed surfaceA. electric flux through the surface is zeroB. the total charge enclosed by the surface is zeroC. no charge resides on the surfaceD. all of these

Answer» Correct Answer - D
1082.

A metal sphere is electrically charged to `Q_(0)` and hangs on an insulting cord. The sphere slowly loses it charge because the air has a non zero resistivity `rho`. The potential of sphere of radius `r_(0)` is to be calculated with reference to infinity. Assume that resistivity of air is every where the same. Mass the correct statementsA. Capacitance of sphere is `4 pi epsilon_(0)r_(0)`B. Electrical resistance of air is `R = (rho)/(4 pi r_(0))`C. Initial current is `(Q_(0))/(rho epsilon_(0))`D. Time in which charge gets halved is `rho epsilon_(0) ln 2`

Answer» Correct Answer - A::B::C::D
1083.

Assertion. When charges are shared between any two bodies, no charge is really lost but some loss of energy does occur. Reason. Some energy disappears in the from of heat, sparking etc.A. If both Assertion and Reason are correct and Reason is the correct explanation of AssertionB. If both Assertion and Reason are correct but Reason is not the correct explanation of AssertionC. If Assertion is true but Reason is falseD. If Assertion is false but Reason is true

Answer» Correct Answer - B
1084.

A particle having positive charge is released from rest in the electric field and moves under the influence of both electric field and gravity. The quantity connected with the charged particle that increases continuously with time isA. electric chargeB. kinetic energyC. electric potential energyD. gravitational potential energy

Answer» Correct Answer - B
1085.

Electric lines of force about negative point charge areA. circular, anticlockwiseB. circular, clockwiseC. radial inwardD. radial outward

Answer» Correct Answer - C
1086.

Which of the following statement is correct in case of lines of charge ?A. they originate from positive charge and end at negative chargeB. they do not pass through conductorC. they exhibit longitudinal tension and lateral pressureD. all of these

Answer» Correct Answer - D
1087.

Give two properties of electric lines of force. Sketch them for an isolated positive point charge and an electric dipole.A. positive chargeB. neutral chargeC. negative chargeD. none of these

Answer» Correct Answer - C
1088.

A conductor `A` is given a charge of amount `+Q` and then placed inside a deep metal can `B`, without touching itA. The potential of `A` does not change when it is placed inside `B`.B. If `B` is earthed `+Q`, amount of charge flows from it inot the earth.C. If `B` is earthed, the potential of `A` is reduced.D. Eigther (b) or (c) are true, or both are true only if the outer surface of `B` is connected to the earth andnot its inner surface.

Answer» Correct Answer - A::B::C
1089.

Consider a uniform electric field in the `hat (z)` direction. The potential is a constant.A. in all spaceB. for any `x` for a given `z`C. for any `y` for a given `z`D. on the `x-y` plane for a given `z`.

Answer» Correct Answer - B::C::D
As electric field in the `hat(z)` direction is uniform, equipotentail surfaces are in `XY` plane. Hence the potential for given `z_(1)` is constant (i) on `x-y` plane (ii) for any `x` in this plane and (iii) for any `y` in this plane.
Hence Choics (b), (c), (d) are correct.
1090.

Equipotential surfacesA. are closer in regions of large electric fields compared to regions of lower electric fieldsB. will be more crowded near sharp edges of a conductorC. will be more crowded near regions of large charge densitiesD. will always be equally spaced

Answer» Correct Answer - A::B::C
From `E = - (dV)/(dr)`, we find that `dr prop (1)/(E)`, i.e., equipotential surfaces are closer in regions of large electric fields compared to regions of lower electric fields. At sharp edges of a condutor, charge density is more. Therefore, electric field is stronger. Hence equipotentials surfaces are more crowded. Same argument is true for option (c). The choices (a), (b), (d) are correct.
1091.

The electric field is measured at a point 0,0, generated due to various charge distributions and the dependence of on is found to be different for different charge distributions. List-I contains different relations between E and . List-II describes different electric charge distributions, along with their locations. Match the functions in List-I with the related charge distributions in List-II. A. `P rarr 5, Q rarr 3, 4, R rarr 1, S rarr 2`B. `P rarr 5, Q rarr 3, R rarr 1, 4, S rarr 2`C. `P rarr 5, Q rarr 3, R rarr 1, 2, S rarr 4`D. `P rarr 4, Q rarr 2, 3, R rarr 1, S rarr 5`

Answer» Correct Answer - B
1092.

In an isolated parallel plate capacitor of capacitance `C`, the four surfaces have charges `Q_(1),Q_(2),Q_(3)` and `Q_(4)` as shown. The potential difference between the plates is A. `(Q_(1)+Q_(2))/C`B. `|(Q_(2))/C|`C. `|(Q_(3))/C|`D. `1/C [(Q_(1)+Q_(2))-(Q_(3)-Q_(4))]`

Answer» Correct Answer - B::C
1093.

By what factor does the capacity of a metal sphere increase if its volume is tripied ?

Answer» As `V = (4)/(3) pi R^(3)`
`:. V prop R^(3) pr R prop V^(1//3)`
`:. (C_(2))/(C_(1)) = (R_(2))/(R_(1)) = ((V_(2))/(V_(1)))^(1//3)`
`:. C_(2) = C_(1) ((V_(2))/(V_(1)))^(1//3) = C_(1) (3)^(1//3) = 1.44 C_(1)`
1094.

As shown in Fig, a dielectric material of dielectric constant K is insered in half portan between plates of parallel plate capacitor. If its initial capacitance is C, what is the new capacitance ?

Answer» The new arrangement is equivalent to two capacitors connected in parallel.
`C_(1) = (in_(0) A//2)/(d) C_(2) = (K in_(0) A//2)/(d)`
`C_(P) = C_(1) + C_(2) = (in_(0) A)/(2d) + (K in_(0) A)/(2d)`
`= (in_(0)A)/(2d) (K + 1) = (C )/(2) (K + 1)`
1095.

A few electric field lines for a system of two charges `Q_(1) and Q_(2)` fixed at two different points on the X-axis are shown in Fig. (i) what is the nature of charges ? (ii) which one of the two is bigger ? (iii) What is the ratio of magnitude of two charges ? (iv) Where can the electric field due to two charges be zero ?

Answer» (i) As electric lines of force start from `Q_(1)` and end at `Q_(2)`, therefore `Q_(1)` is possitive and `Q_(2)` is negative.
(ii) Strength of charge is determined by the number fo electric lines of force. Therefore, `Q_(1) gt Q_(2)`.
(iii) `(Q_(1))/(Q_(2)) = (14)/(9)`
(iv) The electric field due to the sytem fo two charges will be zero at a point to the right of charge `Q_(2)`.
1096.

What is a linear isotropic dielectric? Give one example.

Answer»

A linear isotropic dielectric is one which when placed in a uniform electric field acquires an induced electric dipole moment in the direction of the field and proportional to the applied electric field intensity. Examples : Mica, glass.

1097.

Define electric polarization in dielectrics.

Answer»

Definition The electric polarization at every point within a dielectric is defined as the electric dipole moment per unit volume. It has the direction of the external electric field.

1098.

The variation of potential `V` with distance `r` from dixed point is shown in Fig. The magnitude of electric field at, `r = 2 cm` (in volt/cm) is :

Answer» Correct Answer - 2
From `E = (-dV)/(dr)`, Fig
`E = (-(4-0))/(2-0) = -2 V//cm`
In magnitude, `E = 2 vol t//cm`
1099.

What is the basic difference between a charged capacitor and an electric cell ?

Answer» A capacitor supplies electric energy stored in it. A cell supplies electric energy by converting chemical energy at constant potential difference.
1100.

What is the effect of temperature on dielectric constant ?

Answer» Dielectric constant varies inverseley with temperture. i.e, dielectric constant decreases with rise in temperature.