

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
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A pipe of 100 mm diameter is suddenly stretched to a diameter of 200 mm. If the discharge is 60 L/s, then calculate the loss of energy per unit weight of water.1. 2.0 m2. 3.2 m3. 1.5 m4. 1.67 m |
Answer» Correct Answer - Option 4 : 1.67 m Concept: Head loss due to sudden enlargement of pipeis given by, \({\left( {{h_L}} \right)_{exp}} = \frac{{{{\left( {{v_1} - {v_2}} \right)}^2}}}{{2g}}\) Where, v1is the velocity in smaller section and v2is the velocity in enlarged section Calculation: Given, Q = 60 L/s = 0.06 m3/s d1= 100 mm = 0.1 m, \({A_1} = \frac{\pi }{4}d_1^2 = 0.00785\;{m^2}\) d2= 200 mm = 0.2 mm \({A_2} = \frac{\pi }{4}d_2^2 = 0.0314\;{m^2}\) \({v_1} = \frac{Q}{{{A_1}}} = \frac{{0.06}}{{0.00785}} = 7.643\;m/s\) \({v_2} = \frac{Q}{{{A_2}}} = \frac{{0.06}}{{0.0314}} = 1.91\;m/s\) \({\left( {{h_L}} \right)_{exp}} = \frac{{{{\left( {{7.643} - {1.91}} \right)}^2}}}{{2\times 9.81}}=1.675\;m\) Loss of energy per unit weight of water is given by 1.675 m |
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