InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A battery of emf 6V internal resistance 5`Omega` is joined in parallel with another cell of emf of 10V and internal resistance `1Omega` and the combination is used to send current through a resistor of `12Omega`. Calculate the current through each battery. |
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Answer» Correct Answer - `6/11 A through 6-V battery in opposition to its emf and `(1)3/11` A through 10-V battery in direction of the emf |
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| 2. |
A battery of emf 6 volts and internal resistance `1Omega` is connected in parallel to another battery of emf 8V and internal resistance `2Omega`. The combination is then used to send current through an external resistance of `10Omega`. Find the current through the external resistance. |
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Answer» Correct Answer - `5/8`A |
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| 3. |
Calculate the the resistivity of the material of a wire whose resistance is `5Omega`, length 1m and radius 0.6mm. |
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Answer» Correct Answer - `5.656 xx 10^(-6)` `Omegam` |
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| 4. |
In a wheatstone bridge, the resistance of the arms of the bridge are AB = `2Omega`, BC = `4Omega` ,AD = `1Omega` and DC = `3Omega`. The terminals of negligible resistance to A and C. If a galvanometer of resistance `100Omega` is connected between B and D, find the current in the galvanometer. |
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Answer» Correct Answer - 0.0016 A |
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| 5. |
How you would arrange 24 cells, each of emf 1.5V and internal resistance `0.5Omega`, to deliver maximum current to a resistor of `4Omega`? What is the maximum current? |
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Answer» Correct Answer - 2 rows each containing 12 cells, ; 2.6 A |
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| 6. |
A straight copper-wire of length `100m` and cross-sectional area `1.0mm^(2)` carries a current `4.5A`. Assuming that one free electron corresponds to each copper atom, find (a) The time it takes an electron to displace from one end of the wire to the other. (b) The sum of electrostatic forces acting on all free electrons in the given wire. Given resistivity of copper is `1.72xx10^(-8)Omega-m` and density of copper is `8.96g//cm^(3)`. |
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Answer» Correct Answer - t = `SN_(A)sigmale//IM`= 1 day 13 hour 30 minutes |
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| 7. |
Twelve identical resistor are arranged on all edges of a cube. Then find the equivalent resistance between the corners 1 and 6 as shown in fig 5.126(use nodal method) . |
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Answer» Correct Answer - i) 5/6r, ii)7/12r, (iii) 3/4r |
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| 8. |
A moving coil galvanometer of resistance `50Omega` is connected in series with a fixed resistance `50Omega` and the combination to a cell of steady emf and negligible internal resistance. What is the shunt required to halve the current through the galvanometer? |
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Answer» Correct Answer - `25 Omega` |
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| 9. |
Three wires whose lengths are in the ratio `3:8:18` and radii in the ratio `1:2:3` are connected in parallel. Find the ratio of the currents through them. |
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Answer» Correct Answer - `2:3:3` |
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| 10. |
A shunt is to be applied to a galvanometer of `99Omega` so that only 10% of the total current passes through it. Find the shunt required. What additional shunt will be required to send `1%` of the total current through the galvanometer? |
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Answer» Correct Answer - `11 Omega`, `1.1 Omega` |
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| 11. |
Show that drift velocity of electrons in a conductor is given by u = `J/(ne)` where J is the current density, n is the number of mobile electrons per unit volume and e is the charge carried by each electron. Calculate the same in a copper wire of radius of 0.6mm when a current of 1A flows through it assuming that one mobile electron is available from one atom of copper. Atomic weight of copper = 63.55, density of copper = 8930 kgm^(-3)`, Avogadro number = `6.01 xx 10^(26)`Kg `mol^(-1)` and e = `1.6 xx 10^(-19)`C |
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Answer» Correct Answer - `6.5 xx 10^(-5)ms^(-1)` |
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