529 + Interview Questions in GASEOUS-STATE IN GENERAL AWARENESS Page 7 InterviewSolution

301.	The mass of molecule A is twice that of molecule B. The root mean square velocity of molecule A is twice that of molecule B. If two containers of equal volume have same number of molecules the ratio of pressure `(P_(A))/(P(B))` will be:A. `8:1`B. `1:8`C. `4:1`D. `1:4`
Answer» Correct Answer - a

Discussion

302.	What is kinetic energy of 1 gm of `O_(2)` at `47^(@)C` ?A. `1.24 xx 10^(2) J`B. `2.24 xx 10^(2) J`C. ` 1.24 xx 10^(3) J`D. ` 3.24 xx 10^(2) J`
Answer» Correct Answer - A `K.E. = (3)/(2) nRT = (3)/(2) xx (1)/(32) xx 8.314 xx 320 J` `=1.24 xx 10^(2) J`

Discussion

303.	The value of universal gas constant R depends on :A. temperature of gasB. volume of gasC. number of moles of gasD. units of volume and pressure
Answer» Correct Answer - d (d) `h_(Hg)=(h_("Water")xx1)/(13.6)`

Discussion

304.	Internal energy of an ideal gas depends uponA. PressureB. ForceC. TemperatureD. Molar mass
Answer» Correct Answer - C Tr. `K.E. = (3RT)/(2)` it means that the Translational Kinetic energy of Ideal gas depends upon temperature only.

Discussion

305.	Assertion: Gases do not settle at the bottom of container. Reason: Gases have high kinetic energy.A. If both assertion and reason are true and the reason is correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If the assertion and reason both are false
Answer» Correct Answer - A It is correct that gases do not settle to the bottom of container and the reasonfor this is that due to higher kinetic energy of gaseous molecules they diffuse.

Discussion

306.	A sample of an ideal gas has volume of 0.500L at `25^(@)C` and 1.20 atm pressure. What is its volume at `75^(@)C` and 3.60 atm?A. 0.143LB. 0.195LC. 0.500LD. 1.75L
Answer» Correct Answer - b

Discussion

307.	A gas sample in a flexible container is maintained at constant pressure while its temperature is increased from `25^(@)C` to `75^(@)C`. If the initial volume of the gas is 4.2L, what is the change in volume due to the temperature increase?A. 0.7LB. 4.9LC. 8.4LD. 12.6L
Answer» Correct Answer - a

Discussion

308.	Which of the following is an intensive property for an ideal gas ? .A. `V`B. `P`C. nD. `T`
Answer» Temperature of gas is mass independent .

Discussion

309.	The compressibility factor for a real gas at high pressure is .A. `1`B. `1+Pb//RT`C. `1-Pb//RT`D. `1 +RT//Pb`
Answer» For real `(P+(a)/V^(2))(V-b)=RT` At high pressure `P gt gta//V^(2)` Thus neglecting `a//V^(2)` gives `P(V -b) =RT` or `PV =RT +Rb` `(PV)/(RT) =Z =(RT+Pb)/(RT)` `Z =1 +(Pb)/(RT)` .

Discussion

310.	A and `B` are two idential vessels. `A` contains `15 g` ethane at `1 atm` and `298 K`. The vessel `B` contains `75 g` of a gas `X_(2)` at same temperature and pressure. The vapour density of `X_(2)` is :A. 75B. 150C. 37.5D. 45
Answer» Correct Answer - a

Discussion

311.	The compressibility factor for a real gas at high pressure is .A. `1 +RT//pb`B. 1C. `1+pb//RT`D. `1-pb//RT`
Answer» Correct Answer - C `(P+(a)/(V^(2))) (V-b) = RT` ltbr. At high pressure `(a)/(V^(2))` can be neglected. `PV - Pb = RT` `PV = RT +Pb` `(PV)/(RT) = 1+(Pb)/(RT)` `Z = 1 +(Pb)/(RT) :. Z gt 1` at high pressure

Discussion

312.	In an auto engine having no pollution control device `5%` of the fuel `(C_(8)H_(18))` is left unburnt. Molar ratio under same `P` and `T` of `CO` and `C_(8)H_(18)` emitted in exhaust gas is .A. `100`B. `152`C. `160`D. `10`
Answer» `{:(C_(8) H_(18) +(17)/(2) O_(2) rarr,8CO +,9H_(2)O,,),(100,0,0,,),(5,8xx25,,,):}` `5%C_(8)H_(18)` is left, `CO` formed is `8 xx 95` `:.` Molar ratio `= (8 xx 95)/(5) =152` .

Discussion

313.	The temperature of the gas is raised from `27^(@)C` to `927^(@)C`, the root mean square velocity isA. `sqrt(927//27)` times the earlier valueB. Same as beforeC. HalvedD. Doubled
Answer» Correct Answer - D `U_(2)=U_(1)sqrt((T_(2))/(T_(1)))=U_(1)sqrt((1200)/(300))=U_(1)xx2` r.m.s. velocity will be doubled.

Discussion

314.	Absolute zero is defined as the temperatureA. At which all molecular motion ceasesB. At which liquid helium boilsC. At which ether boilsD. All of the above
Answer» Correct Answer - A

Discussion

315.	Under what conditions will a pure sample of an ideal gas not only exhibit a pressure of `1 atm` but also a concentration of `1 mol litre^(-1)` `[R= 0.082` iltre atm `mol^(-1)K^(-1)]`A. At STPB. When V-22.42LC. When T=12KD. Imposiible under any condition
Answer» Correct Answer - c

Discussion

316.	Which of the following gas will have highest rate of diffusionA. `NH_(3)`B. `N_(2)`C. `CO_(2)`D. `O_(2)`
Answer» Correct Answer - A m.wt of `NH_(3)=17,m.wt.` of `N_(2)=28` m.wt. of `CO-(2)=44, m.wt.` of `O_(2)=32` because `NH_(3)` is lightest gas out of these gases `[ r prop (1)/(sqrt("Molecular Weight"))]`

Discussion

317.	A certain amout of an ideal gas occupies a volume of `1.0m^(3)` at a given temperature and pressure What would be its volume after reducing its pressure to half the initial value and raising the temperature twice the initial value ? .
Answer» Correct Answer - 4 Given, `P_(2) = (1)/(2) P_(1)` and `T_(2) =2T_(1),V_(1) = 1.0m^(3)` Now `(P_(1)xx1.0)/(T_(1)) = (1xxP_(1)xxV_(2))/(2xx2xxT_(1))` `V^(2) = 4m^(3)` .

Discussion

318.	What per cent of its temperature pressure and volume are to `110^(@)C, 0.7 atm` 1.0litre repectively ? .
Answer» Correct Answer - `81.96`

Discussion

319.	A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be :A. 0.025B. 0.05C. 0.075D. 0.09
Answer» Correct Answer - a (a) `Ppropn,` initial mole ` n_(1)=(PV)/(RT)=0.1 " mole" ` `(P_(1))/(P_(2))=(n_(1))/(n_(2))` `(1)/(0.75)=(0.1)/(n_(2)) " "implies n_(2)=0.075` Escape mole =0.025

Discussion

320.	20L of `SO_(2)` diffuse through a porous partition in 60 seconds. Volume of `O_(2)` diffuse under similar conditions in 30 secodns will be:A. 12,14LB. 14.14LC. 18.14LD. 28.14L
Answer» Correct Answer - b

Discussion

321.	The time taken for effusion of 32 mL of oxygen will be the same as the time taken for effusion under identical condition of :A. 64mL of `H_(2)`B. 50mL of `N_(2)`C. 27.3 mL of `CO_(2)`D. 22.62mL of `SO_(2)`
Answer» Correct Answer - c

Discussion

322.	Which of the following curve is correct for an ideal gas ?A. B. C. D.
Answer» Correct Answer - c (c) For ideal gas , PV =nRT

Discussion

323.	`X mL` of `H_(2)` gas effuses through a hole in a container in `5 s`. The time taken for the effusion of the same volume of the gas specified below, under identical conditions, isA. 10 sec. HeB. 20 sec. `O_(2)`C. 25sec. `CO_(2)`D. 55sec. `CO_(2)`
Answer» Correct Answer - b

Discussion

324.	The vapour pressure of water at `20^(@)C` is `17.54 mmHg`. What will be the vapour pressure of the water in the apparatus shown after the piston is lowered, decreasing the volume of the gas above the liquid to one half of its initial volume (assume temperature is constant). A. 8.77 mmHgB. 17.54 mmHgC. 35.08mmHgD. Between 8.77 and 17.54 mmHg
Answer» Correct Answer - b

Discussion

325.	Which statement is correct about the critical point of a phase diagram?A. Solid, liquid and gas are present in equilibrium.B. Liquid and vapour are indistinguishable from one another.C. Liquid can be produced by a change in pressure.D. Vapour can be produced by a change in temperature.
Answer» Correct Answer - b

Discussion

326.	Select correct statement(s).A. we can condense vapours simply by applying pressureB. To liquefy a gas one must lower the temperature below `T_(C)` and also apply pressureC. At `T_(C)`, there is no distinction betwwen liquid and vapour state, hence density of the liquid is nearly equal to density of the vapourD. All the statements are correct.
Answer» Correct Answer - d

Discussion

327.	The critical temperature of water is theA. temperature at which solid, liquid and gaseous water coexist.B. temperature at which water vapour condenses.C. maximum temperature at which liquid water can exit.D. minimum temperature at which water vapor can exist.
Answer» Correct Answer - c

Discussion

328.	For one mole of gas the average kinetic energy is given as E. the `U_("rms")` of gas is:A. `sqrt((2E)/(M))`B. `sqrt((3E)/(M))`C. `sqrt((2E)/(3M))`D. `sqrt((3E)/(2M))`
Answer» Correct Answer - a

Discussion

329.	For a hypothetical gas containing molecules as point masses and having non-zero intermolecular attractions, which of the following is correct?A. The gas shows positive deviations from ideal gas behaviour.B. Graph of Z v/s `(1)/(V)` at a particular temperature will have negative slopeC. The gas will be difficult to compress as compared to ideal gas.D. 2 moles of the gas at a temperature of 273K can be stored in a 45 litre of container at 1 atm pressures.
Answer» Correct Answer - b

Discussion

330.	If `T_(1),T_(2)` and `T_(3)` are the temperatures at which the `u_("rms"),u_("average"),u_("mp")` of oxygen gas are all equal to 1500 m/s then the correct statement is :A. `T_(1)gtT_(2)gtT_(3)`B. `T_(1)ltT_(2)ltT_(3)`C. `T_(1)=T_(2)=T_(3)`D. None of these
Answer» Correct Answer - b (b) `U_("mp")=sqrt((2RT)/(M))` `U_("avg")=sqrt((8)/(pi)(RT_(2))/(M))` `U_("rms")=sqrt((RT_(1))/(M))` `T_(3)gtT_(2)gtT_(1)`

Discussion

331.	Fraction of oxygen molecules `((dN)/(N))` in the range `U_("mps")` to `U_("mps")+fU_("mps")` whre `fltlt1`d:A. `(4f)/(2sqrt(pi))`B. `(4)/sqrt(pi)((M)/(2RT))^(1//2)e^(-1)`C. `(f)/(epi)`D. `1`
Answer» Correct Answer - a

Discussion

332.	2.8 g of a gas at 1atm and 273K occupies a volume of 2.24 litres. The gas can not be:A. `O_(2)`B. COC. `N_(2)`D. `C_(2)H_(4)`
Answer» Correct Answer - a

Discussion

333.	A real gas most closely approaches the behaviour of an ideal gas at:A. 15 atm and 200KB. 1 atm and 273 KC. 0.5 atm and 500KD. 15 atm and 500K
Answer» Correct Answer - c

Discussion

334.	Which gas shows real behaviour?A. 16 g `O_(2)` at 1 atm & 273 K occupies 11.2 LB. 1 g `H_(2)` in 0.5 L flask exerts pressure of 24.63 atm at 300 KC. 1 mole `NH_(3)` at 300 K and 1 atm occupies volume 22.4 LD. 5.6 L of `CO_(2)` at 1 atm & 273 K is equal to 11 g
Answer» Correct Answer - c (c) For ideal gas PV =nRT volume of 1 mole gas at 1 atm pressure and 273 K is 22.4 L and at 300 K and 1 atm pressure volume =24.63 L.

Discussion

335.	A sample of gas at 273K has a pressure of `P_(1)` and a volume of `V_(1)`. When the pressure is changed to `P_(2)`, what is the volume `V_(2)`? (Assume the temperature remains constant)A. `(P_(1)P_(2))/(V_(1))`B. `(P_(1)V_(1))/(P_(2))`C. `(P_(2)V_(1))/(P_(1))`D. `(P_(2))/(P_(1)V_(1))`
Answer» Correct Answer - b

Discussion

336.	For a gas deviation from ideal behaviour is maximum at :A. `0^(@)C` and 1.0 atmB. `100^(@)C` and 2.0 atmC. `-13^(@)C` and 1.0 atmD. `-13^(@)C` and 2.0 atm
Answer» Correct Answer - d (d) Real gas shows ideal behaviour at low pressure and high temperature.

Discussion

337.	A real gas most closely approaches the behaviour of an ideal gas at `,`A. low pressure `&` low temperatureB. high pressure `&` high temperatureC. low pressure `&` high temperatureD. high pressure `&` low temperature
Answer» Correct Answer - 3

Discussion

338.	Positive deviation from ideal behaviour takes place because ofA. molecular interaction between atoms and `(PV)/(nRT) gt1` .B. molecular interaction between atoms and `(PV)/(nRT) gt1` .C. finite size of atoms and `(PV)/(nRT) gt1`D. finite size of atoms and `(PV)/(nRT) gt1`
Answer» For positive deviations `Z gt1` the condition when repulsive forces predominates Also at high `P,V` is small and b cannot be ignored but the factor `(a)/(V^(2))` can be neglected in comparison to `P` Thus `Z =1 +(Pb)/(RT)` .

Discussion

339.	Positive deviation from ideal behaviour takes place because ofA. Molecular interactioin between atoms and `PV //nRT gt 1`B. Molecular interaction between atoms and `PV // nRT lt 1`C. Finite size of atoms and `PV // nRT gt 1`D. Finite size of atoms and `PV // nRT lt 1`
Answer» Correct Answer - C For position deviation `: PV = nRT +nPbimplies (PV)/(nRT)= 1+ (PB)/(RT)` Thus, the factor nPb is responsible for increasing the PV value, above ideal value, b is actually the effective volume of molecule. So, it is the finite size of molecules that leads to the origin of b and hence positive deviation at high pressure.

Discussion

340.	At point `P` and `Q` , the real gas deviation with respect to ideal gas is respectively `:` A. Positive, negativeB. Positive, positiveC. Negative, positiveD. Negative, negative
Answer» Correct Answer - A

Discussion

341.	A certain gas takes three times as long to effuse out as helium. Its molar mass will beA. 27uB. 36uC. 64uD. 9u
Answer» Correct Answer - B `r prop sqrt((1)/(M))implies (r_(2))/(r_(1))=sqrt((M_(2))/(M_(1)))implies ((V(g))/(3t))/((V_(He))/(t))=sqrt((4)/(M))` `(1)/(9) = (4)/(M) implies M = 36 g//` mole

Discussion

342.	The intercept on y-axis and slope of curve plotted between P/T vs. T ( For an ideal gas having 10 moles in a closed rigid container of volume 8.21 L. (P= Pressure in atm and T = Temp. in K, `log_(10)2=0.30))` are respectively :A. 0.01, 0B. 0.1, 0C. 0.1, 1D. 10, 1
Answer» Correct Answer - b (b) Intercept on y-axis `=log_(10)""(nR)/(V)=log_(10)""(10xx0.0821)/(8.21)=-1.0` `(P)/(T) v//s " curve" (P)/(T)=(nR)/(V)` `"intercept"=(nR)/(V)` `=(10xx0.0821)/(8.21)=0.1," slope"=0`

Discussion

343.	A container is divided into two compartments. One compartment contains 2 moles of `N_(2)` gas at 1 atm and 300 K and other compartment contains `H_(2)` gas at the same temperature and pressure. Volume of `H_(2)` compartment is four times the volume of `N_(2)` compartment [Assuming no reaction under these conditions] Calculate the final total pressure if partition between two compartments is removed.A. 2 atmB. 3 atmC. 1 atmD. `1.5` atm
Answer» Correct Answer - c

Discussion

344.	Hydrogen gas diffuses four times as rapidly as a mixture of `C_(2)H_(4)` and `CO_(2)`. The molar ratio of `C_(2)H_(4)` to `CO_(2)` in the mixture isA. `1:1`B. `2:1`C. `3:1`D. `3:2`
Answer» Correct Answer - c

Discussion

345.	For a closed container containing 10 moles of an ideal gas, at constant pressure of `0.82` atm, which graph correctly represent, variation of log V us log T where volume is in litre and temp. in kelvin :A. B. C. D.
Answer» Correct Answer - a (a) `V=(nRT)/(P)=(10xx0.0821xxT)/(0.821)` `V=T` `"log"V="log"T` `"slope"=1` `theta=45^(@) `

Discussion

346.	Assertion: The value of van der Waals constant a is larger for ammonia than for nitrogen. Reason: Hydrogen bonding is present in ammonia.A. If both the statement are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1B. If both the statement are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-1C. If STATEMENT-1 is TRUE and STATEMENT-2 is FALSED. If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Answer» Correct Answer - A

Discussion

347.	At what temperature will the `rms` velocity of `SO_(2)` be the same as that of `O_(2) at 303 K`?A. `273K`B. 606KC. 303KD. 403K
Answer» Correct Answer - B `(u_(SO_(2)))/(u_(o_(2)))=sqrt((M_(O_(2)T_(SO_(2))))/(M_(SO_(2)T_(O_(2)))))=sqrt((32 xx T_(SO_(2)))/(64xx303))=1 ` `I= (32 xx)/(64)( T_(SO_(2)))/(303)implies T_(SO_(2))=606K`

Discussion

348.	A balloon of diameter 21 meter weight 100 kg. Calculate its pay-load, if it is filled with He at 1.0 atm and `27^(@)C`. Density of air is 1.2 kg `m^(-3)` . (Given : R=0.082 L atm `K^(-1)mol^(-1)`)A. 4952.42 kgB. 4932.42 kgC. 493.242 kgD. none of these
Answer» Correct Answer - b (b) Mass of balloon `=100kg=10xx10^(4)g` Volume of balloon `=(4)/(3)pi r^(3)` `=(4)/(3)xx(22)/(7)xx((21)/(2))^(3)` `=4851m^(3)=4851xx10^(3)L` Mass of gas (He in balloon `=(PVM)/(RT)` `=(1xx4851xx10^(3)xx4)/(0.082xx300)` `=78.878xx10^(4)` `:.` Total mass of gas and balloon ` =78.878xx10^(4)+10xx10^(4)` `=88.878xx10^(4) g " or " 888.78 kg` Mass of air displaced `=1.2xx4851` `=5821.2kg` `:.` Pay load =mass of air displaced - mass of (balloon +gas) `:.` Pay load `=5821.2-888.78=4932.42kg`

Discussion

349.	If the pressure of `N_(2)//H_(2)` mixture in a closed vessel is 100 atmospheres and `20%` of the mixture then reacts the pressure at the same temperature would be .A. The sameB. 90 atmospheresC. 110 atmospheresD. 80 atmospheres
Answer» `20%` mixture produced `10%NH_(3)` `N_(2) +3H_(2) =2NH_(3)` Thus mixture left is `90%` .

Discussion

350.	In a gaseous reaction the volume ratio of reactants and product is in agreement with their molar ration Volume of gas in inversely proportional to its mole at definite pressure and temperature .
Answer» `V prop` moles at constant `P,T` .

Discussion

Explore topic-wise InterviewSolutions in .

The mass of molecule A is twice that of molecule B. The root mean square velocity of molecule A is twice that of molecule B. If two containers of equal volume have same number of molecules the ratio of pressure `(P_(A))/(P(B))` will be:A. `8:1`B. `1:8`C. `4:1`D. `1:4`

What is kinetic energy of 1 gm of `O_(2)` at `47^(@)C` ?A. `1.24 xx 10^(2) J`B. `2.24 xx 10^(2) J`C. ` 1.24 xx 10^(3) J`D. ` 3.24 xx 10^(2) J`

The value of universal gas constant R depends on :A. temperature of gasB. volume of gasC. number of moles of gasD. units of volume and pressure

Internal energy of an ideal gas depends uponA. PressureB. ForceC. TemperatureD. Molar mass

A sample of an ideal gas has volume of 0.500L at `25^(@)C` and 1.20 atm pressure. What is its volume at `75^(@)C` and 3.60 atm?A. 0.143LB. 0.195LC. 0.500LD. 1.75L

A gas sample in a flexible container is maintained at constant pressure while its temperature is increased from `25^(@)C` to `75^(@)C`. If the initial volume of the gas is 4.2L, what is the change in volume due to the temperature increase?A. 0.7LB. 4.9LC. 8.4LD. 12.6L

Which of the following is an intensive property for an ideal gas ? .A. `V`B. `P`C. nD. `T`

The compressibility factor for a real gas at high pressure is .A. `1`B. `1+Pb//RT`C. `1-Pb//RT`D. `1 +RT//Pb`

A and `B` are two idential vessels. `A` contains `15 g` ethane at `1 atm` and `298 K`. The vessel `B` contains `75 g` of a gas `X_(2)` at same temperature and pressure. The vapour density of `X_(2)` is :A. 75B. 150C. 37.5D. 45

The compressibility factor for a real gas at high pressure is .A. `1 +RT//pb`B. 1C. `1+pb//RT`D. `1-pb//RT`

In an auto engine having no pollution control device `5%` of the fuel `(C_(8)H_(18))` is left unburnt. Molar ratio under same `P` and `T` of `CO` and `C_(8)H_(18)` emitted in exhaust gas is .A. `100`B. `152`C. `160`D. `10`

The temperature of the gas is raised from `27^(@)C` to `927^(@)C`, the root mean square velocity isA. `sqrt(927//27)` times the earlier valueB. Same as beforeC. HalvedD. Doubled

Absolute zero is defined as the temperatureA. At which all molecular motion ceasesB. At which liquid helium boilsC. At which ether boilsD. All of the above

Under what conditions will a pure sample of an ideal gas not only exhibit a pressure of `1 atm` but also a concentration of `1 mol litre^(-1)` `[R= 0.082` iltre atm `mol^(-1)K^(-1)]`A. At STPB. When V-22.42LC. When T=12KD. Imposiible under any condition

Which of the following gas will have highest rate of diffusionA. `NH_(3)`B. `N_(2)`C. `CO_(2)`D. `O_(2)`

A certain amout of an ideal gas occupies a volume of `1.0m^(3)` at a given temperature and pressure What would be its volume after reducing its pressure to half the initial value and raising the temperature twice the initial value ? .

What per cent of its temperature pressure and volume are to `110^(@)C, 0.7 atm` 1.0litre repectively ? .

A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be :A. 0.025B. 0.05C. 0.075D. 0.09

20L of `SO_(2)` diffuse through a porous partition in 60 seconds. Volume of `O_(2)` diffuse under similar conditions in 30 secodns will be:A. 12,14LB. 14.14LC. 18.14LD. 28.14L

The time taken for effusion of 32 mL of oxygen will be the same as the time taken for effusion under identical condition of :A. 64mL of `H_(2)`B. 50mL of `N_(2)`C. 27.3 mL of `CO_(2)`D. 22.62mL of `SO_(2)`

Which of the following curve is correct for an ideal gas ?A. B. C. D.

`X mL` of `H_(2)` gas effuses through a hole in a container in `5 s`. The time taken for the effusion of the same volume of the gas specified below, under identical conditions, isA. 10 sec. HeB. 20 sec. `O_(2)`C. 25sec. `CO_(2)`D. 55sec. `CO_(2)`

Which statement is correct about the critical point of a phase diagram?A. Solid, liquid and gas are present in equilibrium.B. Liquid and vapour are indistinguishable from one another.C. Liquid can be produced by a change in pressure.D. Vapour can be produced by a change in temperature.

The critical temperature of water is theA. temperature at which solid, liquid and gaseous water coexist.B. temperature at which water vapour condenses.C. maximum temperature at which liquid water can exit.D. minimum temperature at which water vapor can exist.

For one mole of gas the average kinetic energy is given as E. the `U_("rms")` of gas is:A. `sqrt((2E)/(M))`B. `sqrt((3E)/(M))`C. `sqrt((2E)/(3M))`D. `sqrt((3E)/(2M))`

If `T_(1),T_(2)` and `T_(3)` are the temperatures at which the `u_("rms"),u_("average"),u_("mp")` of oxygen gas are all equal to 1500 m/s then the correct statement is :A. `T_(1)gtT_(2)gtT_(3)`B. `T_(1)ltT_(2)ltT_(3)`C. `T_(1)=T_(2)=T_(3)`D. None of these

Fraction of oxygen molecules `((dN)/(N))` in the range `U_("mps")` to `U_("mps")+fU_("mps")` whre `fltlt1`d:A. `(4f)/(2sqrt(pi))`B. `(4)/sqrt(pi)((M)/(2RT))^(1//2)e^(-1)`C. `(f)/(epi)`D. `1`

2.8 g of a gas at 1atm and 273K occupies a volume of 2.24 litres. The gas can not be:A. `O_(2)`B. COC. `N_(2)`D. `C_(2)H_(4)`

A real gas most closely approaches the behaviour of an ideal gas at:A. 15 atm and 200KB. 1 atm and 273 KC. 0.5 atm and 500KD. 15 atm and 500K

Which gas shows real behaviour?A. 16 g `O_(2)` at 1 atm & 273 K occupies 11.2 LB. 1 g `H_(2)` in 0.5 L flask exerts pressure of 24.63 atm at 300 KC. 1 mole `NH_(3)` at 300 K and 1 atm occupies volume 22.4 LD. 5.6 L of `CO_(2)` at 1 atm & 273 K is equal to 11 g

A sample of gas at 273K has a pressure of `P_(1)` and a volume of `V_(1)`. When the pressure is changed to `P_(2)`, what is the volume `V_(2)`? (Assume the temperature remains constant)A. `(P_(1)P_(2))/(V_(1))`B. `(P_(1)V_(1))/(P_(2))`C. `(P_(2)V_(1))/(P_(1))`D. `(P_(2))/(P_(1)V_(1))`

For a gas deviation from ideal behaviour is maximum at :A. `0^(@)C` and 1.0 atmB. `100^(@)C` and 2.0 atmC. `-13^(@)C` and 1.0 atmD. `-13^(@)C` and 2.0 atm

A real gas most closely approaches the behaviour of an ideal gas at `,`A. low pressure `&` low temperatureB. high pressure `&` high temperatureC. low pressure `&` high temperatureD. high pressure `&` low temperature

Positive deviation from ideal behaviour takes place because ofA. molecular interaction between atoms and `(PV)/(nRT) gt1` .B. molecular interaction between atoms and `(PV)/(nRT) gt1` .C. finite size of atoms and `(PV)/(nRT) gt1`D. finite size of atoms and `(PV)/(nRT) gt1`

Positive deviation from ideal behaviour takes place because ofA. Molecular interactioin between atoms and `PV //nRT gt 1`B. Molecular interaction between atoms and `PV // nRT lt 1`C. Finite size of atoms and `PV // nRT gt 1`D. Finite size of atoms and `PV // nRT lt 1`

At point `P` and `Q` , the real gas deviation with respect to ideal gas is respectively `:` A. Positive, negativeB. Positive, positiveC. Negative, positiveD. Negative, negative

A certain gas takes three times as long to effuse out as helium. Its molar mass will beA. 27uB. 36uC. 64uD. 9u

The intercept on y-axis and slope of curve plotted between P/T vs. T ( For an ideal gas having 10 moles in a closed rigid container of volume 8.21 L. (P= Pressure in atm and T = Temp. in K, `log_(10)2=0.30))` are respectively :A. 0.01, 0B. 0.1, 0C. 0.1, 1D. 10, 1

Hydrogen gas diffuses four times as rapidly as a mixture of `C_(2)H_(4)` and `CO_(2)`. The molar ratio of `C_(2)H_(4)` to `CO_(2)` in the mixture isA. `1:1`B. `2:1`C. `3:1`D. `3:2`

For a closed container containing 10 moles of an ideal gas, at constant pressure of `0.82` atm, which graph correctly represent, variation of log V us log T where volume is in litre and temp. in kelvin :A. B. C. D.

At what temperature will the `rms` velocity of `SO_(2)` be the same as that of `O_(2) at 303 K`?A. `273K`B. 606KC. 303KD. 403K

A balloon of diameter 21 meter weight 100 kg. Calculate its pay-load, if it is filled with He at 1.0 atm and `27^(@)C`. Density of air is 1.2 kg `m^(-3)` . (Given : R=0.082 L atm `K^(-1)mol^(-1)`)A. 4952.42 kgB. 4932.42 kgC. 493.242 kgD. none of these

If the pressure of `N_(2)//H_(2)` mixture in a closed vessel is 100 atmospheres and `20%` of the mixture then reacts the pressure at the same temperature would be .A. The sameB. 90 atmospheresC. 110 atmospheresD. 80 atmospheres

In a gaseous reaction the volume ratio of reactants and product is in agreement with their molar ration Volume of gas in inversely proportional to its mole at definite pressure and temperature .