InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
`{:("Column" (I) , "Column" (II)) , ((a) CH_(3)-overset(o+)(C)H- CH_(3) , P . "Pyramidal structure"), ((b) overset(Theta)(C)H_(3) , Q. "Planar geometry"), ((c) CH_(3)-overset(.)(C)H- CH_(3) , R. "Electrophile"), ((d) "Singlest carbene" , S. "Nucleophile"):}` |
| Answer» Correct Answer - `(a)rarrQ,R; (b) rarr P,S; (c) rarr Q,R; (d) rarr P,S` | |
| 52. |
The number of `pi` electrons required for a planar cyclic conjugated system to exhibit aromatic behaviour is `(4n+2)`. Here n isA. number of C atoms in the systemB. number of `pi` bondsC. a non - negative integerD. number of bonds in the system. |
| Answer» Correct Answer - C | |
| 53. |
If the given compound is planar. Select the correct statement. A. The boron is `sp^(2)` hybridized and the p-orbital contains an unshared pair of electronB. The boron is `sp^(2)` hybridized and a hybrid orbital contains an unshared pair of electron.C. The boron in `sp^(2)` hybridized and hybrid orbital is vacantD. The boron is `sp^(2)` hybridized and the p-orbital is vacant |
| Answer» Correct Answer - D | |
| 54. |
Observed the following compound and answer the following questions. Q. Arrange the H-atom in decreasing order of their acidic strength.A. agtbgteB. agtegtbC. bgtagtcD. egtagtb |
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Answer» Correct Answer - B `a gt e gt b` Phenolic `-OH gt` Alcoholic `-OH gt ` Amine |
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| 55. |
Which of the following compounds have planar molecular configuration?A. `H_(2)C=CH_(2)`B. `H_(2)C=CH-C-=C-H`C. `H_(2)C=C=CH_(2)`D. `H_(2)C=C=C=C=CH_(2)` |
| Answer» Correct Answer - A::B::D | |
| 56. |
Lewis formula for diazomethane, `CH_(2)N_(2)` is shown below. Find out incrroect structures :A. B. `H-C-=overset(o+)N-overset(Ɵ)N-H`C. D. `H-N=C=N-N` |
| Answer» Correct Answer - B::C::D | |
| 57. |
Observed the following compound and answer the following questions. Q. Arrange the H-atom in decreasing order of their acidic strength.A. bgtdgtcB. cgtbgtdC. dgtcgtbD. cgtdgtb |
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Answer» Correct Answer - A `b gt d gt c` b is `1^(@)` amine `gt d 1.p.` delocalized with `gt C=C lt gt 1.p.` delocalized with `gt C=O`. (least basic) |
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| 58. |
What is the increasing order of bond lengths of bonds indicated as `p,q,r` and s in following compound? A. `pltqltrlts`B. `qltrltsltp`C. `sltqltrltp`D. `sltpltqltr` |
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Answer» Correct Answer - D Bond length of r is maximum, as there no hyperconjugation. |
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| 59. |
Which of the following orders of rotations barrier about the C=C bond as indicated is correct,A. `IgtIIgtIII`B. `IIIgtIIgtI`C. `IIIgtIgtII`D. `IIgtIgtIII` |
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Answer» Correct Answer - A More the double bond charcter, more will be the rotational barrier energy. |
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| 60. |
Which of the following orders of rotation barrier about the C=C bond, as indicated, is correct,A. `IgtIIgtIII`B. `IIIgtIIgtI`C. `IIIgtIgtII`D. `IIgtIgtIII` |
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Answer» Correct Answer - A More the double bond charcter, more will be the rotational barrier energy. |
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| 61. |
Which species are more resonance stabilized in the following pairs: `[C_(6)H_(5)Cl, C_(6)H_(5)CH_(3)], [CH_(2)=CHCl, CH_(2)=CHCH_(2)Cl]`, `[C_(6)H_(5)Br, C_(6)H_(5)CH_(2)Br], [CH_(3)COOH, CH_(3)COO^(-)]`A. `C_(6)H_(5)Cl, CH_(2)=CHCH_(2)Cl, C_(6)H_(5)CH_(2)Br, CH_(3)COO^(-)`B. `C_(6)H_(5)CH_(3), CH_(2)=CHCH_(2)Cl, C_(6)H_(5)CH_(2)Br, CH_(3)COO^(-)`C. `C_(6)H_(5)C1, CH_(2)=CHCl, C_(6)H_(5)Br, CH_(3)COOH`D. `C_(6)H_(5)Cl, CH_(2)=CHCl, C_(6)H_(5)Br, CH_(3)COO^(-)` |
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Answer» Correct Answer - D In the first pair, `-Cl` has stronger `+R` effect than `CH_(3)` in the second pair, `Cl` lone pair is in conjugation with double bond, in the third pair, `Br` lone pair is in conjugation with benzene ring, in the fourth pair, `CH_(3)COO^(-)` is more resonace stabilizeed due to equivalent resonating structures. |
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| 62. |
Which one of the following substituents at para-position is most effective in stabilizing the phenoixde , ion ?A. `-CH_(3)`B. `-OCH_(3)`C. `-COCH_(3)`D. `-CH_(2)OH` |
| Answer» Correct Answer - C | |
| 63. |
To which of the following four types does this reaction belong `B^(-) + R - A rarr B - R + A^(-)`A. Unimolecular electrophilic substitutionB. Biomolecular electrophilic substitutionC. Unimolecular nucleophilic substitutionD. Biomolecular nucleophilic substitution |
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Answer» Correct Answer - D It is `S_(N^(2))` type of reaction. |
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| 64. |
In which of the following pairs, indicated bond is of greater strength: |
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Answer» Correct Answer - [(a)II,(b)II] (a). Bond strength will be more in 2nd. Because there is no other option for movement (b). Same explanation. |
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| 65. |
Which one of the following orders is correct regarding the inductive effect of the substituentsA. `-NR_(2) lt -OR gt -F`B. `-NR_(2) gt - OR gt - F`C. `-NR_(2) lt -OR lt - F`D. `-NR_(2) gt - OR lt - F` |
| Answer» Correct Answer - C | |
| 66. |
Which species are more resonance stabilized in the following pairs: `[C_(6)H_(5)Cl, C_(6)H_(5)CH_(3)], [CH_(2)=CHCl, CH_(2)=CHCH_(2)Cl]`, `[C_(6)H_(5)Br, C_(6)H_(5)CH_(2)Br], [CH_(3)COOH, CH_(3)COO^(-)]`A. `C_(6)H_(5)Cl, CH_(2) = CHCH_(2)Cl, C_(6)H_(5)CH_(2)Br, CH_(3)COO^(-)`B. `C_(6)H_(5)CH_(3), CH_(2) = CHCH_(2)Cl, C_(6)CH_(2)Br, CH_(3)COO^(-)`C. `C_(6)H_()CH_(3), CH_(2) = CHCH_(2)CL, C_(6)H_(5)CH_(2)Br, CH_(3)COOH`D. `C_(6)H_(5)Cl, CH_(2) = CHCl, C_(6)H_(5)Br, CH_(3)COO^(-)` |
| Answer» Correct Answer - D | |
| 67. |
The correct order of leaving group ability in a nucleophilic substitution reaction isA. `Br^(-) gt Cl^(-) gt CH_(3)CO_(2)^(-) gt HO^(-) gt H^(-)`B. `H^(-) gt OH^(-) gt CH_(3)CO_(2)^(-) gt Cl^(-) gt Br^(-)`C. `Br^(-) gt CH_(3)CO_(2)^(-) gt Cl^(-) gt OH^(-) gt H^(-)`D. `CH_(3)CO_(2)^(-) gt Br^(-) gt Cl^(-) gt OH^(-) gt H^(-)` |
| Answer» Correct Answer - A | |
| 68. |
Which is least reactive towards nucleophilic substitution `(S_(N^(2)))`A. `CH_(3)=CH - CH_(2)Cl`B. `{:(" "CH_(3)),(" |"),(CH_(3)-C-Cl),(" |"),(" "CH_(3)):}`C. D. `CH_(3)-CH(Cl)CH_(3)` |
| Answer» Correct Answer - C | |
| 69. |
Which of the following compounds will undergo racemisation when solution of KOH hydrolyses A. (iii) and (iv)B. (i) and (iv)C. Only (iv)D. (ii) and (iv) |
| Answer» Correct Answer - C | |
| 70. |
Consider the given reaction: In the above reaction which one of the given ring will undergo reduction? |
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Answer» Correct Answer - A When a ring is reduced then most stable compoud is obtained because of presence of three isolated benzene ring. |
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| 71. |
The following compound will undergo electrophilic substitution more readily than benzeneA. NitrobenzeneB. Benzoic acidC. BenzaldehydeD. Phenol |
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Answer» Correct Answer - D Phenol will undergo electrophilic substitution more readily than benzene. |
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| 72. |
The correct statement about the compounds A, B and C is A. A and B are identicalB. A and B are siastereomersC. A and C are enatiomersD. A and B are enantiomers |
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Answer» Correct Answer - D (i) Enantiomers are the pairs of optical isomers which are related as non superimposable mirror images of each other (ii) Diastereomers are the pairs of optical isomers which cannot to related a non superimposable mirror image of each other :. The only correct statement about given structure is that (A) and (B) are enantiomers |
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| 73. |
Which of the following cannot undergo nucleophilic substitution under ordinary conditionsA. ChlorobenzeneB. Tert-butylchlorideC. Isoproply chlorideD. None of these |
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Answer» Correct Answer - A Chlorobenzene undergoes nucleophilic substitution under a drastic condition because due to resonance C-Cl bond acquire some double bond character as a result substitution of -Cl by nucleophile become difficult ordinary condition. |
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| 74. |
In which case, lonic mechanism is not followed ?A. Reaction of acetylene and bromine waterB. Reaction of HBr and propene in the presence of peroxideC. Reaction of ethyl bromine and alcoholic KOHD. Dehydration of ethyl alcohol catalysed by acid |
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Answer» Correct Answer - B In the presence of peroxide the addition of HBr to propene follows free radical mechanism |
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| 75. |
Which of the following statement are correct about this pair of geometrical isomer?A. `-I` effect of vinylic group on the `-COOH` group is same in both isomers. So there is no role of `-I` on the strength of acidityB. `+M` power of vinylic group is operating effectivel in trans isomer (A) but not in cis-isomer (B) because of steric repulsion in cis-isomer causing loss of coplanarity of `-COOH` gp. With `C=C` bond . Therefore, cis-isomer is more acidec than transC. `+I` power of `CH_(3)-` is greater in trans than cisD. None of the above |
| Answer» Correct Answer - A::B | |
| 76. |
The most geometrical isomer among the following isA. B. C. D. |
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Answer» Correct Answer - A The steric repulsion of the groups makes the cis-isomer less stable than the trans isomer in which the bulky group is far apart. |
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| 77. |
OF the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectivelyA. 3-methylpentane and 2,3-dimethylbutaneB. 2,3- dimethylbutane and n-hexaneC. 2,2- dimethylbutane and 2-methylpentaneD. 2,3- dimethylbutane and 2-methylpentane |
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Answer» Correct Answer - D 2, 3-dimethylbutane will be give two monochlorinated compound whereas 2-methylpentane will give five monochloro derivatives. `{:(" "CH_(3)" "CH_(3)," "CH_(3)),(" |"" |"," |"),(underset("2,3-dimethylbutane")(CH_(3)-CH-CH-CH_(3)),underset("2-methylpentane")(CH_(3)-CH-CH_(2)-CH_(2)-CH_(3))):}` |
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| 78. |
Electronegativity of carbon atoms depends upon their state of hybridisation in which of the following compounds the carbon marked asterisk, is most electronegative ?A. `CH_(3)-CH_(2)-CH_(2)-CH_(3)`B. `CH_(3)-CH=CH-CH_(3)`C. `CH_(3)-CH_(2)-C-=CH`D. `CH_(3)-CH_(2)-CH=CH_(2)` |
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Answer» Correct Answer - C Triple bonded carbon atoms are more electronegative than double and single bonded carbon atoms |
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| 79. |
Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below `H_(2)=C=CH-CH=O`A. `{:(sp^(3),sp^(2),sp),(2,2,0):}`B. `{:(sp^(3),sp^(2),sp),(1,3,0):}`C. `{:(sp^(3),sp^(2),sp),(0,3,1):}`D. `{:(sp^(3),sp^(2),sp),(1,2,1):}` |
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Answer» Correct Answer - C `H_(2)underset(sp^(2))undersetuarrC=underset(sp^(2))undersetuarrC=underset(sp^(2))undersetuarrCH-underset(sp^(2))undersetuarrCH=O` |
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| 80. |
Hybridization of 1 and 2 carbon atoms in `overset(1)(CH_(2))=overset(2)(C)=CH_(2)`A. sp, spB. `sp^(2), sp^(2)`C. `sp^(2), sp`D. `sp^(3), sp^(2)` |
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Answer» Correct Answer - C `underset(sp^(2))(overset(1)(C)H_(2))=underset(sp)(overset(2)(C))=CH_(2)` |
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| 81. |
In which of the compounds below is there more than one kind of hybridization `(sp,sp^(2),sp^(3))` for carbon? (i) `CH_(3)CH_(2)CH_(2)CH_(3)` (ii) `CH_(3)-CH=CH-CH_(3)` (iii) `H_(2)C-CH-CH-CH_(2)` (iv) `H-C-=C-H`A. (ii) and (iv)B. (i) and (iv)C. (ii) and (iii)D. (ii) |
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Answer» Correct Answer - D (i) `overset(sp^(3))(CH_(3))-overset(sp^(3))(CH_(2))-overset(sp^(3))(CH_(2))-overset(sp^(3))(CH_(3))` Only `sp^(3)` hybridized carbon (ii) `overset(sp^(3))(CH_(3))-overset(sp^(2))(CH)=overset(sp^(2))(CH)-overset(sp^(3))(CH_(3))` Both `sp^(2)` and `sp^(3)` hybridized carbon. (iii) `overset(sp^(2))(CH_(2))=overset(sp^(2))(CH)-overset(sp^(2))(CH)=overset(sp^(2))(CH_(2))` Only `sp^(2)` hybridized carbon. (iv) `H-underset(sp)(C)-=underset(sp)(C)-H` Only sp hybridized carbon. |
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| 82. |
Determine the hybridization at the carbon atom indicated in each species. |
| Answer» Correct Answer - `(a) sp^(2), (b) sp^(2),(c)sp^(3)` | |
| 83. |
Consider the given process. And identify the incorrect statementA. Configuration at `C-2` is lost on enolisationB. I and III are epimersC. Proton transfer from water to `C-1` converts ene diol to an aldoseD. D-glucose can isomerise to D-fructose through enol intermediate. |
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Answer» Correct Answer - C D-glucose can isomerise to D-fructose through enol intermediate |
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| 84. |
In which of the following compounds is hydroxylic proton the most acidic ?A. B. C. D. |
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Answer» Correct Answer - D Due to maximum `-I` effect. |
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| 85. |
Methyl`-alpha-D-`glucoside and methyl`-beta-D-`glucoside are:A. EpimersB. AnomersC. EnantiomersD. Conformational diastereomers |
| Answer» Correct Answer - B | |
| 86. |
`alpha - D -(+)-` glucose and `beta-D-(+)-`glucose areA. EpimersB. AnomersC. EnantiomersD. Conformers |
| Answer» Correct Answer - B | |
| 87. |
`alpha-D (+)-`glucose and `beta-D(+)-`glucose are:A. EpimersB. AnomersC. enantiomersD. constitutional isomers |
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Answer» Correct Answer - B Anomers are sterioisomers which differ at a single chiral center out of many & are ring chain tautomer of same open chain compound. |
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| 88. |
Hydrolysis of lactose with dilute acid yields:A. Equimolar mixture of D-glucose and D-glucoseB. Equimolar mixture of D-glucose and D-gluctoseC. Equimolar mixture of D-glucose and D-fructoseD. Equimolar mixture of D-gluctose and D-galactose. |
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Answer» Correct Answer - B Hydrolysis of lactose with dil acid gives equimolar mixture of D-glucose & D-galactose Lactose `overset("dil acid")to"D-Glucose+D-Galactose")` |
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| 89. |
The correct of heats of combustion of above compounds is :A. `IgtIIgtIII`B. `IIgtIgtIII`C. `IIIgtIIgtI`D. `IIIgtIgtII` |
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Answer» Correct Answer - C More the no. of corbons more will be the heat of combustion. |
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| 90. |
Correct order of the heats of combustion of above compounds is :A. `(i)gt(ii) gt(iii)`B. `(i)gt(iii)gt(ii)`C. `(ii) gt (i) gt (i) gt (iii)`D. `(ii) gt (iii) gt (i)` |
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Answer» Correct Answer - A More the numer of carbons more will be the heat of combustion. |
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| 91. |
Write Stability order of following intermediates: |
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Answer» Correct Answer - (i)B,(ii)D,(iii)A (i) In free radical electron releasing group increases the stability. |
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| 92. |
Write stability order of following intermediates: |
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Answer» Correct Answer - (i)A,(ii)A (i). A electron releasing group decreases the stability of carbanion. (ii). In `HC-=C^(-)` this carbon is more electronegative and a more electronegative species contain a negative charge make it more stable. |
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| 93. |
Correct order of heat of combustion for following compounds is: (P) `CH_(3)-CH=CH-CH_(2)-CH_(2)-CH_(2)-CH_(3)` (Q) `CH_(2)=CH-CH_(2)-CH_(2)-CH_(2)-CH_(3)` (R) `CH_(3)-CH_(2)-CH=CH-CH_(2)-CH_(2)-CH_(3)`A. QgtRgtPB. RgtPgtQC. PgtRgtQD. QgtPgtR |
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Answer» Correct Answer - B heat of combution `prop` No of `pi` bond `prop(1)/("stability of alkane")and prop` number of carbon (P). `underset("7 carbon atom"" "5alphaH)(CH_(3)-CH=CH-CH_(2)-)CH_(2)-CH_(2)-CH_(3)` (Q). `underset(6" carbon atom")(CH_(3)=CH-CH_(2)-)CH_(2)-CH_(2)-CH_(3)` (R). `undersetunderset(R gt P gt Q)(7" carbon atom"" "4alphaH)(CH_(3)-CH_(2)-CH=CH-CH_(2))-CH_(2)-CH_(3)` |
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| 94. |
Which order is correct regarding stability of intermediates (I). `CH_(2)=CH-overset(o+)(C)H_(2)` (II). `CH_(2)=overset(o+)(C)H` (III). `CH-=overset(o+)(C)`A. I=II=IIIB. IltIIltIIIC. III=IIgtID. IgtIIgtIII |
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Answer» Correct Answer - D Structure `I^(st)to"Allylic "C^(+)` (More stable) `II^(nd)to"Vinylic "C^(+)`(Less stable) `III^(rd)to`In 3rd option this `(HC-=C)` carbon is more electronegative and contain a positive charge make is less stable. |
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| 95. |
Rate of abstraction of iodine by `Ag^(o+)` isA. agtbgtcB. bgtagtcC. cgtagtbD. agtcgtb |
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Answer» Correct Answer - D (a). Resonance stablised (b). Antiaromatic (c). Hyperconjugative stablised agtcgtb |
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| 96. |
Consider the H-atoms in the given below and answer the following . (B) Arrange them in the decarasing order of their case of abstraction (easiest first ) |
| Answer» Correct Answer - B-Easiest to abstract; `H_(e)gtH_(c)gtH_(b)gtH_(a)gtH_(d) " " ` Hardest to abstract | |
| 97. |
In the structure `{:(" "CH_(3)),(" |"),(.^(1)H_(3)C-^(2)C-^(3)CH_(2)-^(4)CH_(3)),(" |"),(" "CH_(3)):}` Which one is quanternary carbon atomA. C-1B. C-2C. C-3D. C-5 |
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Answer» Correct Answer - B `{:(" "overset(5)(C)H_(3)),(" |"),(.^(1)CH_(3)-.^(2)C-.^(3)CH_(2)-.^(4)CH_(3)),(" |"),(" "underset(6)(C)H_(3)):}` C-2 is quaternary carbon because it is attached to 4 other carbon atoms. |
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| 98. |
In Fructofuranose-OH group of which carbon adds to `gt C=O` groupA. `C_(3)`B. `C_(4)`C. `C_(5)`D. `C_(2)` |
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Answer» Correct Answer - C In fructofuranose `-OH` group of `C_(5)` adds to `gt C =O` groups |
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| 99. |
Which of the following compounds is not chiral?A. `DCH_(2)CH_(2)CH_(2)Cl`B. `CH_(3)CHDCH_(2)Cl`C. `CH_(3)CHClCH_(2)D`D. `CH_(3)CH_(2)CHDCl` |
| Answer» Correct Answer - 1 | |
| 100. |
Number of chiral carbon in Haworth structure of `alpha`-Glucopyranose having OH group downside are _________. |
| Answer» Correct Answer - 3 | |