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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1051. |
Rank then following compounds in order of increasing acidity (weakest acid first ). A. `2lt3lt1`B. `3lt1lt2`C. `1lt2lt3`D. `2lt1lt3` |
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Answer» Correct Answer - D Acidic strength `prop` electron withdrawing groups at acid. |
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| 1052. |
Which of the following phenols has the largest `pK_(a)` value (i.e. , is lest acidic )?A. B. C. D. |
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Answer» Correct Answer - C Acidic strength `prop-Mprop(1)/(+M)` |
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| 1053. |
Phenols are more acidic than alcohols becauseA. phenols are more soluble in water than alcohols are.B. the phenoxide ion is stabilized by resona-nce but resonance is not possible in the alkoxide ion.C. resonance stabilization in the phenoxide ion is greater than that in the alkoxide ion.D. phenol are stabilized by resonance but alcohol are not. |
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Answer» Correct Answer - B Resonance is not possible in alcohols `(ROH)` as well as alkoxide ions. Moreover, with alcoholes, there is no such factor stabilizing the alkoxide anion `(RO^(-))` relative to the alcohols itself. Resonance is possible both in the phenols and phenoxide ions but phenoxide ions are more effeictively resonance stabilized than corresponding pehnols. |
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| 1054. |
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger than phenol. Why ?A. the relative resonance stabilization of the carboxylate ion over carboxylic acid is much greater than the relative resonance stabilization of the phenoxide ion over phenol.B. a carboxylic acid has a greater resonance stabilization than a phenol.C. the carboxylate ion is more resonace-stabilized than the the phenoxide ion.D. A carboxylic acid can form a dimer by intermolecular hydrogen bonding but a phenol cannot. |
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Answer» Correct Answer - A Delocalization of the negative charge in the carboxylate anion involves equivalent resonance structures of identical energy content. Moreover, the negative charge is identical energy content.Moreover, the negative charge is `100%` shared by the two highly electronegative `O` atoms, On the other hand, in phenoxide anion. the resonance structure are not. equivalent. The structure involving negative charge on the benzene `C` are higher energy than those in which it is on oxygen. The relative stabilizartion of the anion, with respect to the undissociated molecule, is thus likely to be less effective with a phenol than with a carboxylic acid, leading to the lower acidic sternth of the former. |
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| 1055. |
The pair of electron in the given carbanion, `CH_(3)C -= C^(Θ)`, is present in which of the following orbitalsA. 2pB. `sp^(3)`C. `sp^(2)`D. sp |
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Answer» Correct Answer - D `CH_(3)-C-=C^(Θ)` N. of `{:(sigma bp-1),(lp-1):}]` 2 & hybridisation is sp. |
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| 1056. |
The decreasing order of the acidic character is : .A. `I gt II gt III`B. `III gt II gt I`C. `II gt I gt III`D. `III gt I gt II` |
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Answer» Correct Answer - A (a) Acidic order : `sp gt sp^2 gt sp^3 (C -= C gt C = C gt C - C)`. |
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| 1057. |
Reaction between propene and HCl to form isopropyl chloride takes place throufhA. Nucleophilic addition reactionB. Electrophilic addition reactionC. Nucleophilic substitution reactionD. Electrophilic substitution reaction |
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Answer» Correct Answer - A Reaction between propene and HCl to yield iso-propyl chloride is an example of nucleophilic addition reaction `{:(""CH_(3)CH=CH_(2)+HCl rarr CH_(3)CH-CH_(3)),(" |"),(" "Cl):}` |
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| 1058. |
Consider the acidity of the carboxylic acids : `(i) PHCOOH" "(ii) o-NO_(2)C_(6)H_(4)COOH" "(iii) p-NO_(2)C_(6)H_(4)COOH" "(iv) m-NO_(2)C_(6)H_(4)COOH`A. `I gt ii gt iii gt iv`B. `ii gt iii gt iv gt i`C. `iii gt ii gt iv gt i`D. `ii gt iv gt iii gt i` |
| Answer» Correct Answer - B | |
| 1059. |
The correct statement(s) about the compound `H_(3)C(HO)HC-CH=CH-CH(OH)CH_(3) (X)` is/areA. the total number of stereo isomers possible is 6B. total number of dia stereo isomers possiblw is 3.C. If the stereo chemistry about the double bond in the compounds is trans, the number of enantimoers is 4.D. If the stero chemistry about the double bond is csis, the number enantimoers possible is 2 |
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Answer» Correct Answer - 1,3 3 seterogenic centers and ends are same `therefore` No. of Stereo Isomers=`2^(n-1)+2^((n-1)/(2))=6` |
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| 1060. |
Arrange the following free radicals in the order of decreasing stability: methyl `(I)`, vinyl `(II)`, allyl `(III)`, benzyl `(IV)`A. `I gt IIgt III gt IV`B. `III gt II gt I gt IV`C. `II gt I gt IV gt III`D. `IV gt III gt I gt II` |
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Answer» Correct Answer - D Benzyl `(C_(6)H_(5)overset(*)(C)H_(2))` with `5` resonance structure is the most stable. Allyl radical has two resonance structures. Vinyl is the least stable as odd `e^(-)` is carried by `sp^(2)` hybrid `C`. |
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| 1061. |
Number of isomers possible for dichlorocyclohexaneA. 8B. 9C. 6D. 7 |
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Answer» Correct Answer - 1 4-structral isomers (1,1,1,2,1,3,1,4) 3-geomentric isomers (1,2,1,3,1,4) 1-optical isomer(1,3) |
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| 1062. |
Aspartame, an artificial sweetener, is a peptide and has the following structure: (i). Identify the four functional groups. (ii). Write the zwitterionic structure. (iii). Write the structures of the amino acids obtained from the hydrolysis of aspartame. (iv). Which of the two amino acids is more hydrophobic? |
| Answer» Correct Answer - (i) Amine, carboxylic acid, Amide, Ester | |
| 1063. |
Arrange increasing order of acidic strength of following dibasic acids: (I) oxalic acid. `" "`(II) succinic acid `" "` (III) malonic acid `" "`(IV) adipic acidA. `III lt II lt I lt IV`B. `II lt III gt I gt IV`C. `I gt III gt II gt IV`D. `II gt I gt III lt IV` |
| Answer» Correct Answer - C | |
| 1064. |
Functional group present in amides isA. `- COOH`B. `-NH_(2)`C. `-CONH_(2)`D. `- COO-` |
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Answer» Correct Answer - C |
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| 1065. |
Hydrogenation of the above compound in the presence of poisoned `Pd` catalyst gives:A. An optically active compoundB. An optically inactive compoundC. A racemic mixtureD. A diastereomeric mixture |
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Answer» Correct Answer - B Due to formation of the plane of symmetry by the syn addition of hydrogen in the triple bond, the compound formed is optically inactive. |
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| 1066. |
Which of the following compounds are not arranged in order of decreasing reactivity towards electrophilic substitutionA. Fluoro benzene `gt` chloro benzene `gt` bromo benzeneB. Phenol `gt` n propyl benzene `gt` benzoic acidC. Chloro toluene `gt` para-nitro toluene `gt` 2-chloro-4-nitro tolueneD. Benzoic acid `gt` phenol `gt` n propyl benzene |
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Answer» Correct Answer - D `-COOH` group is a deactivating group, hence benzoic acid is less reactive towards electrophilic substitution than phenol. |
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| 1067. |
The correct order of stability of the following carbocations is :A. `CH_(3)CH_(2)overset(+)CH_(2)gtCH_(2)=CH-overset(+)CH_(2)gtCH_(2)=CHoverset(+)CHCH_(3)gtCH_(2)=CHoverset(+)C(CH_(3))_(2)`B. `CH_(2)=CHCoverset(+)H_(2)=CH_(3)CH_(2)overset(+)CH_(2)gtCH_(2)=CHoverset(+)CHCH_(3)`C. `CH_(2)=CHoverset(+)C(CH_(3))_(2)gtCH_(2)=CHoverset(+)CHCH_(3)gt"CH_(2)=CHoverset(+)CH_(2)gtCH_(3)CH_(2)overset(+)CH_(2)`D. `CH_(2)=CH-overset(+)CHCH_(3)gtCH_(2)=CHoverset(+)C(CH_(3))_(2)gtCH_(3)CH_(2)-overset(+)CH_(2)gtCH_(2)=CHoverset(+)CH_(2)` |
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Answer» Correct Answer - C As resonance and hyper conjugation increases stability increases. |
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| 1068. |
Which of the following is diasaccharides?A. LactoseB. SucroseC. CelluloseD. Maltose |
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Answer» Correct Answer - A::B::D Disaccharide-They gives two monosaccharide unit on hydrolysis. Cellulose in the linear polymer of glucose unit and in celluloe monomer unit of glucose is 1000-1500 Lactose, sucrose and maltose all are give (2) monosaccharide unit on hydrolysis that why tey are disaccharides. |
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| 1069. |
Amino acids are synthesised fromA. `alpha`-Halo acids by reaction with `NH_(3)`B. Aldehydes by reaction with `NH_(3)` and cyanide ion followed by hydrolysis.C. Alkyl halides by reaction with the enolate anion derived from diethyl acetamidomalonate & hydrolysisD. Alcohols by reaction with `NH_(3)` and `CN^(-)` ion followed by hydroysis. |
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Answer» Correct Answer - A::B::C The hydrogen ion concentration of the solution in which a particular amino acid does not migrate under the influence of an electric field is called the isoelectric point (pI) of that amino acid. The isoelectric point (pI) is the pH at which the amino acid exists only as a dipolar ion with net charge zero. |
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| 1070. |
Isomers of hexane , based on their branching can be divided into three distinct classes as shown in the figure. The correct order of their boiling points is :A. `I gt II gt III`B. `III gt II gt I`C. `II gt III gt I`D. `III gt I gt II` |
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Answer» Correct Answer - B Greater the extent of branching, lesser is the boiling point of hydrocarbon. |
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| 1071. |
Which of the following is not an example of tautomeric equilibrium?A. `CH_(2)=CH-underset(H)underset(|)C=OiffCH_(2)-CH=underset(H) underset(|)C-O^(-)`B. `-N=N-underset(|)NHiff-NH-N=N-`C. D. `-NH-underset(|)C=O iff-N=underset(|)C-OH` |
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Answer» Correct Answer - A No acidd `alpha`-hydrogen |
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| 1072. |
The proper tautomeric structure for 2-aminopyridine (X) is A. B. C. D. |
| Answer» Correct Answer - A | |
| 1073. |
The tautomeric pairs areA. `Me_(2)C=NOH and Me_(2)CH-underset(o+)N=O`B. `CH_(2)=CH-NHCH_(3) and CH_(3)-CH=N-CH_(3)`C. D. `CH_(2)=CH-underset(OH)underset(|)CH-CH_(3) and CH_(3)-CH_(2)-underset(O)underset(||)O-CH_(3)` |
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Answer» Correct Answer - A::B (A,B) `{:("Nitroso" hArr "oxime (Tautomer)"),("lmine" hArr "enamine (Tautomer)"):}` |
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| 1074. |
Which of the following have asymmetric carbon atom?A. `F-underset(H)underset(|)overset(Cl)overset(|)C-underset(H)underset(|)overset(Br)overset(|)C-H`B. `H-underset(H)underset(|)overset(H)overset(|)C-underset(H)underset(|)overset(Cl)overset(|)C-Cl`C. `H-underset(H)underset(|)overset(H)overset(|)C-underset(H)underset(|)overset(Cl)overset(|)C-H`D. `H-underset(Br)underset(|)overset(H)overset(|)C-underset(OH)underset(|)overset(Cl)overset(|)C-CH_(3)` |
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Answer» Correct Answer - A,D Four different groups must be present on carbon |
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| 1075. |
Sum of molecular mass of gas (A+C) is :A. 88B. 90C. 92D. 40 |
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Answer» Correct Answer - B `90 ,Gas (A) =overset(14)CO_(2)," " Gas (C)=CO_(2)," 46+44=90` |
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| 1076. |
Give the decreasing order of acidic character. (1) `NO_2CH_2 OH`, (b) `C1CH_2COOH`, (c) `HCOOH`, (d) `CH_3 COOH`, ( e) `CH_3 OH` (2) (a) `RCOOH` (b) `ROH` ( c) `H_2 O` (d) `NH_3` ( e) `CH -= CH` (f) `RH` (3) (a) `HCOOH` (b) `PhOH` ( c) `CH_3OH` (d) `C_2 H_5OH` ( e)`CH_3 C -= CH` (f) `CH -= CH`, (g) `NH_3` (4) (a) `CH_3COOH` (b) `H_3O^(oplus)` ( c) `H_2O` (d) `C_2H_5 COOH` ( e) `NH_3` (f) `CH -= CH` (g) `CH_2 = CH_2` (h) `CH_4` (i) `C_2 H_6`. (5) (a) `H_2 O` (b) `CH_3OH` ( c) `RC -= CH` (d) `H_2` ( e) `NH_3` (f) `RH` (g) `ROH` (6) Basic character of conjugate base of Problem `5`. |
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Answer» (1) `b gt c gt d gt a gt e` (2) `a gt c gt b gt e gt d gt f` (3) `a gt b gt c gt d gt f gt e gt g gt h` (4) `b gt a gt d gt c gt f gt e gt g gt h gt i` (5) `b gt a gt g gt c gt d gt e gt f` (6) `b lt a lt g lt c lt d lt e lt f` (The stronger is the acid, the weaker is its conjugate base). |
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| 1077. |
What is the relationship between the members of the following pairs of structures gt Are they indentical, structural, or geometrical isomers, or resonance contributors ? . |
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Answer» (a) Position and metamers (b) Resonance contributors and identical ( c) Geometrical isomers. |
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| 1078. |
How many structural and geometrical isomers are possible for dimethlycyclohexane?A. 3,6B. 4,6C. 6,4D. 3,3 |
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Answer» Correct Answer - 2 Except second option remaining compounds having elements of symmetry. |
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| 1079. |
Which skeleton exhibit optical isomerism?A. `C-C-C-C-COOH`B. C. `C-underset(C )underset(|)-C-COOH`D. `C-overset(C )overset(|)underset(C )underset(|)(C )-COOH` |
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Answer» Correct Answer - B `underset(COOH)underset(|)overset(CH_(3)-CH-CH_(2)-CH_(3)` Only this compound has a chiral carbon atom hence it will show optical isomerism |
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| 1080. |
The pair of functional group isomers isA. `underset(NH_(2))underset(|)(C)H_(2)CHO`B. `CH_(3)COOH HCOOCH_(3)`C. `CH_(3)-CH_(2)OHCH_(3)OCH_(3)`D. All of the above |
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Answer» Correct Answer - C Is an example of position isomer while (b) is of metamerism `CH_(3)CH_(2)OH` and `CH_(3)OCH_(3)` are functional group isomers |
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| 1081. |
The total number of geometrical isomers possible in the following compound is |
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Answer» Correct Answer - D `2^(3)=8` Stero isomers |
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| 1082. |
Consider the Hofmann ammonolysis reaction : `R-X +ddotNH_(3)rarr underset(1^(@) amine)(HX + RNH_(2)) overset(R-X)underset(373K)rarr` If `R = Me_2 CH-(isopropyl)`, the correct order of basic character of the above amines in aqueous medium is :A. `3^@ gt 2^@ gt 1^@ gt NH_3`B. `NH_3 gt 1^@ gt 2^@ gt 3^@`C. `1^@ gt 2^@ gt NH_3 gt 3^@`D. `1^@ gt NH_3 gt 2^@ gt 3^@` |
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Answer» Correct Answer - D (d) In gaseous or nonpolar solvent, the basic order is `3^@ gt 2^@ gt 1^@ gt NH_3`. |
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| 1083. |
Consider the Hofmann ammonolysis reaction : `R-X +ddotNH_(3)rarr underset(1^(@) amine)(HX + RNH_(2)) overset(R-X)underset(373K)rarr` If `R = C_2H_5`, the correct of basic character of the above amines in aqueous medium is :A. `2^@ gt 3^@ gt 1^@ gt NH_3`B. `2^@ gt 1^@ gt 3^@ gt NH_3`C. `3^@ gt 2^@ gt 1^@ gt NH_3`D. `NH_3 gt 1^@ gt 2^@ gt 3^@` |
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Answer» Correct Answer - A (a) In gaseous or nonpolar solvent, the basic order is `3^@ gt 2^@ gt 1^@ gt NH_3`. |
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| 1084. |
Molecules can be enolised by which hydrogen ?A. y-HB. `z-H`C. bothD. None of these |
| Answer» Correct Answer - B | |
| 1085. |
A cyclic functional isomer of `H_(3)C-COOH` including itself are |
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Answer» Correct Answer - B `CH_(3)COOH,HCOOCH_(3),`underset(OH)underset(|)(CH)=underset(OH)underset(|)(CH)` |
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| 1086. |
Consider the following carbocations I `overset(+)underset((CH_(3))_(3)C CH_(2)` II `(CH_(3))_(3)C^(+)` III `{:(" " +),(CH_(3)CH_(2)CH_(2)):}` IV `{:(" " +),(CH_(3)-CH-CH_(3)):}` The correct order for the stability of the above carbocations isA. `IgtIIIgtIVgtII`B. `IIIgtIVgtIgtII`C. `IVgtIIIgtIIgtI`D. `IIgtIVgtIIIgtI` |
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Answer» Correct Answer - A Larger the number of `alpha` H-atom linked to a carbocation more will be the stable carbocation hence, the correct order of stability is `I lt III lt IV lt II` |
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| 1087. |
Which among the following compound will give maximum enol content in solution :A. `C_(6)H_(6)-overset(O)overset(||)C-CH_(2)-overset(O)overset(||)C-CH_(3)`B. `CH_(3)-overset(O)overset(||)C-CH_(2)-overset(O)overset(||)C-CH_(3)`C. `CH_(3)-overset(O)overset(||)C-CH_(2)-CH_(2)-CH_(3)`D. `CH_(3)-overset(O)overset(||)C-CH_(2)-COOC_(2)H_(5)` |
| Answer» Correct Answer - A | |
| 1088. |
Consider the Hofmann ammonolysis reaction : `R-X +ddotNH_(3)rarr underset(1^(@) amine)(HX + RNH_(2)) overset(R-X)underset(373K)rarr` If `R = CH_3`, the correct order of basic character of `1^@` amine, `2^@` amine, `3^@` amine, and `NH_3` in aqueous medium is :A. `1^@ gt 2^@ gt 3^@ gt NH_3`B. `2^@ gt 3^@ gt 1^@ gt NH_3`C. `2^@ gt 1^@ gt 3^@ gt NH_3`D. `2^@ gt 1^@ gt NH_3 gt 3^@` |
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Answer» Correct Answer - C ( c) In gaseous or nonpolar solvent, the basic order is `3^@ gt 2^@ gt 1^@ gt NH_3`. |
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| 1089. |
Arrange the following in decreasing order of percentage enol content. A. `I gt II gt III gt IV`B. `II gt I gt III gt IV`C. `II gt III gt I gt IV`D. `III gt II gt IV gt I` |
| Answer» Correct Answer - A | |
| 1090. |
Which of the following has highest `%` enol content in the liquid?A. B. C. D. |
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Answer» Correct Answer - B B has strong active methylene group |
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| 1091. |
Which among the following compounds will give maximum enol content in solution?A. `C_(6)H_(5)-overset(O)overset(||)(C )-CH_(2)-overset(O)overset(||)(C )-CH_(3)`B. `CH_(3)-overset(O)overset(||)(C )-CH_(2)-overset(O)overset(||)(C )-CH_(3)`C. `CH_(3)-overset(O)overset(||)(C )-CH_(2)-CH_(2)CH_(3)`D. `CH_(3)-overset(O)overset(||)(C )-CH_(2)-COOC_(2)H_(5)` |
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Answer» Correct Answer - D The compound must possess only keto group in order to shown enol form The compound `CH_(3)-overset(O)overset(||)(C )-CH_(2)-COOC_(2)H_(5)` contains keto group alongwith ester group which favours the enol formation by this keto group |
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| 1092. |
Which among the following compounds will give maximum enol content in solution? |
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Answer» Correct Answer - B B contains active metylene group |
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| 1093. |
Consider the molecule shown below and of stability (1=moststable ) Arrange them in decreasing order of heire bond energy. |
| Answer» Correct Answer - `B_H_(c)gtH_(e)gtH_(a)gtH_(b)gtH_(d)` | |
| 1094. |
Decreasing order of enol content of the following compounds in liquid phase A. `2 gt 1 gt 3 gt 4`B. `1 gt 2 gt 3 gt 4`C. `4 gt 3 gt 2 gt 1`D. `3 gt 1 gt 2 gt 4` |
| Answer» Correct Answer - B | |
| 1095. |
The most stable resonating structure of p-nitrosonitrobenzene is :A. B. C. D. |
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Answer» Correct Answer - C Negative charge present on electroneagtive oxygen and octet every atom is complete. |
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| 1096. |
Arrange the following in increasing order of their strenght. A. `IIIltIltIVltII`B. `IIltIltIVltIII`C. `IltIIIltIVltII`D. `IIltIIIltIltIV` |
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Answer» Correct Answer - D Acidic stength `prop` stability of resulting anion. |
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| 1097. |
Consider the following : `CH_(3)underset((I))CH_(2)NH_(2)`,`CH_(3)overset(O)underset((II))overset(||)CNH_(2),` Correct order of their basic strenght is :A. `IgtIIgtIII`B. `IIgtIgtIII`C. `IIIgtIIgtI`D. `IIgtIIIgtI` |
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Answer» Correct Answer - C Ist is highly basic as its `lp e^(-)` is localised while in (II) and (II) `lp e^(-)` is delocalised. |
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| 1098. |
which isomer of hexane has only two different sets of structurally equivalent hydrogens atomsA. 2, 2-dimethylbutaneB. 2-methyl pentaneC. 3-methylpentaneD. 2, 3-dimethylbutane |
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Answer» Correct Answer - D It has 9 primary and 2 tertiary hydrogen atoms. |
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| 1099. |
In which of the following compounds, does the substituent not exert its resonance effect?A. `C_(6)H_(5)overset(+)(N)H_(3)`B. `C_(6)H_(5)Cl`C. `C_(6)H_(5)OH`D. `C_(6)H_(5)NH_(2)` |
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Answer» Correct Answer - A `overset(+)NH_(3)` group exert only `-I` effect on account of higher electronegativity of `N` atom than the `C` atom of benzene ring and due to ists `+ve` charge. It is not able to exert `+R` effect as there is no long pair of electrons. It fails to exert `-R` effect beacuse `N` is not `pi` bonded to more electronegative atom. |
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