InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 951. |
Chirality of carbon compound is because to itsA. Tetrahedral nature of carbonB. Monovalent nature of carbonC. Divalent nature of carbonD. Trivalent nature of carbon |
|
Answer» Correct Answer - A Chirality of carbon compound is because of tetrahedral nature of carbon. |
|
| 952. |
The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane isA. 3B. 4C. 1D. 2 |
|
Answer» Correct Answer - D `{:(overset(1)(C)H_(3)-overset(2)(C)H-overset(3)(C)H_(2)-overset(4)(C)H_(3)),(" |"),(" "CH_(3)):}` Its monochloro derivatives are as follows : (i) `{:(ClCH_(2)-overset(*)(C)H-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` or `{:(CH_(3)-overset(*)(C)H-CH_(2)-CH_(3)),(" |"),(" "CH_(2)Cl):}` It will exist as enantiomeric pair (d and l-forms) (ii) `{:(" "Cl),(" |"),(CH_(3)-C-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` no asymmetric C-atom (iii) `{:(" "Cl),(" |"),(CH_(3)-CH-CH-CH_(3)),(" |"),(" "CH_(3)):}` It will exist as enantiomeric pair (d-and l-forms) (iv) `{:(CH_(3)-CH-CH_(2)-CH_(2)-Cl),(" |"),(" "CH_(3)):}` No asymmetric carbon atom Hence, only two enantiometric pairs will be obtained by the monochlorination of 2-methylbutane. |
|
| 953. |
If `CH_(4)` is known as methane, then `C_(9)H_(20)` is known asA. HexaneB. NonaneC. OctaneD. Butane |
| Answer» Correct Answer - B | |
| 954. |
Ratio of pure and hybrid orbitals in benzeneA. `3:2`B. `2:3`C. `1:2`D. `2:1` |
|
Answer» Correct Answer - B |
|
| 955. |
The ratio of pure and hybrid orbitals `H_(2)C=CH-CH=CH_(2)`A. `7 : 12`B. `14 : 13`C. `12 : 10`D. `5 : 6` |
|
Answer» Correct Answer - D |
|
| 956. |
Neo-heptyl alcohol is correctly represented asA. B. C. D. |
|
Answer» Correct Answer - C |
|
| 957. |
IUPAC name of `{:(CH_(3)-CH-CH_(3)),(" |"),(" "NH_(2)):}` isA. Dimethyl amineB. 2-aminopropaneC. IsopropylamineD. 2-propanamine |
|
Answer» Correct Answer - B `{:(overset(3)(CH_(3))-overset(2)(CH)-overset(1)(CH_(3))),(" |"),(" "NH_(2)),("2-amino propane"):}` |
|
| 958. |
IUPAC name of `{:(CH_(3)-CH_(2)-CH-NH_(2)),(" |"),(" "CH_(3)):}` isA. 1-methyl-1-aminopropaneB. 2-aminobutaneC. 2-methyl-3-aminopropaneD. None of the above |
| Answer» Correct Answer - B | |
| 959. |
The IUPAC name of `CH_(3)C-=C CH(CH_(3))_(2)` isA. 4-methyl-2-pentyneB. 4, 4-dimethyl-2-butyneC. Methyl isopropyl acetyleneD. 2-methyl-4-pentyne |
| Answer» Correct Answer - A | |
| 960. |
IUPAC name of `(CH_(3))_(2)CH - CH = CH - CH_(3)` isA. 2-methyl-3-penteneB. 4-methyl-2-penteneC. 1, 2-isopropyl-1-propeneD. 3-isopropyl-2-propene |
| Answer» Correct Answer - B | |
| 961. |
The process whereby a hydrogen atom attached to the `alpha`-carbon carbonyl compound moves to the cabonyl oxygen atom is nown as enolization or keto-enol tautomerism. Isomeric carbonyll and enol structures are tautomers. Normally, the carbonyll form is favoured but structural factor market affect `K_(T)`. Which of following compounds will not exhibit enolization?.A. B. C. D. `Ph-overset(O)overset(||)(C)-CH_(3)` |
|
Answer» Correct Answer - C `alpha`.H absent in C |
|
| 962. |
In this paragraph, some statements are given based on isomerism. Read the following statements given for every question and provide the answer. Which of the following cyclic dienes does not show geometrical isomerism?A. B. C. D. |
| Answer» Correct Answer - D | |
| 963. |
The IUPAC name of `(CH_(3))_(2)CH-CH_(2)-CH_(2)Br` isA. 1-bromo pentaneB. 2-methyl-4-bromo butaneC. 1-bromo-3-bromo propaneD. 2-methyl-3-bromo propane |
| Answer» Correct Answer - C | |
| 964. |
Write the IUPAC name of `{:(" "H" "Br),(" |"" |"),(CH_(3)-C-CH_(2)-CH_(2)-CH_(2)-C-CH_(3)),(" |"" |"),(" "OH" "Br):}`A. 6,6-dibromoheptane-2-olB. 2,2-dibromoheptane-6-olC. 6, 6 dibromoheptane-2-olD. None of these |
| Answer» Correct Answer - A | |
| 965. |
IUPAC name of `{:(" "H" "C_(4)H_(9)),(" |"" |"),(CH_(3)-C-C-CH_(3)),(" |"" |"),(" "C_(2)H_(5)CH_(3)):}` isA. 2-butyl-2-methyl-3-ethylbutaneB. 2-ethyl-3, 3-dimethylheptaneC. 3, 4, 4-trimethylheptaneD. 3, 4, 4-trimethyloctane |
| Answer» Correct Answer - D | |
| 966. |
The IUPAC name of the compound `{:(CH_(3)-C=CH_(2)CH_(2)OH),(" |"),(" "CH_(3)):}` isA. 2-methyl-2-butenolB. 2-methyl-3-butenolC. 3-methyl-2-butenolD. 3-methyl-but-2-ene-1-ol |
| Answer» Correct Answer - D | |
| 967. |
How many positional isomer of n-Decene will show geometerical isomerismA. 2B. 3C. 4D. 5 |
|
Answer» Correct Answer - C 2-decen,3-decene,4-decene,5-decene |
|
| 968. |
Which of the following are pericyclic reactions? A. (i), (iv)B. (i), (ii), (iv)C. (i), (ii), (iii), (iv)D. (ii), (iii), (iv) |
|
Answer» Correct Answer - C All of these are pericyclic reactions as they occur in single step via a cyclic `TS`. |
|
| 969. |
The IUPAC name of the compound `CH_(3)-CH(C_(2)H_(5))-CH=CH-CH_(3)` isA. 4-ethyl-2-penteneB. 4-methyl 2-hexeneC. 3-ethyl-2-penteneD. 2-ethyl-3-pentene |
| Answer» Correct Answer - B | |
| 970. |
The number of enantiomers of the compound `CH_(3)CHBrCHBrCOOH` is |
|
Answer» Correct Answer - D `{:(" "H" "H),(" |"" |"),(CH_(3)-C_(**)-C_(**)-COOH),(" |"" |"),(" "Br" "Br):}` Number of enantiomers `= 2^(n)` (n = asymmetric Carbon atom ) `= 2^(2) = 4`. |
|
| 971. |
Which is an alicyclic compoundA. BenzeneB. cyclo penteneC. pyridineD. pyrrole |
|
Answer» Correct Answer - B |
|
| 972. |
Alicyclic compounds areA. AromaticB. AliphaticC. HeterocyclicD. Aliphatic cyclic |
| Answer» Correct Answer - D | |
| 973. |
Which of the following statements is not correct for resonance strucuture?A. None of the individual resonace structures explians all the characteristics of the actual molecule.B. The resonance hybrid has equal contribution from all the resonating strucuture.C. The different resonace structure of a molecule should have the same number of unpaired electrons.D. The different resonating structures of a molecule have fixed arrangements of atomic nuclei. |
|
Answer» Correct Answer - B Equivalent resonance structure make equal contributions to the hybrid while structure that are not equivalent do not make equal contributions. |
|
| 974. |
Which of the following is hetero cyclic compound?A. AnthraceneB. PyrroleC. PhenolD. Isobutylene |
|
Answer» Correct Answer - B |
|
| 975. |
Which of the following is a chiral compoundA. HexaneB. MethaneC. n-butaneD. 2,3,4-trimethyl hexane |
|
Answer» Correct Answer - D `{:(" "CH_(3)" "CH_(3)" "CH_(3)),(" |"" |"" |"),(CH_(3)-CH_(2)-CH-CH-CH-CH_(3)):}`, It is a chiral compound. |
|
| 976. |
Which of the following reactions involves molecular rearrangement?A. `CH_(3)CH_(2)CH_(2)OHoverset(H_(2)SO_(4))rarrCH_(3)CH=CH_(2)`B. `CH_(3)CH_(2)underset(OH)underset(|)CHCH_(3)overset(H_(2)SO_(4))rarrCH_(3)CH=CHCH_(3)`C. D. `(CH_(3))_(3)C CH_(2)OHoverset(H_(2)SO_(4))rarr(CH_(3))_(2)C=CHCH_(3)` |
|
Answer» Correct Answer - D It involves the rearrangement of carbon skeleton through the rearrangement of intermediate carbocation. Reaction `(1)` and `(2)` are `beta`-elimination reaction while reaction `(3)` is an example of electrophilic aromatic substiution. |
|
| 977. |
Which of the following is not an isomerization reaction?A. `3CH=CHoverset("Red hot")underset("Fe tube")rarrC_(6)H_(6)`B. `CH_(3)CH_(2)C-=CHoverset(NaNH_(2))underset(Delta)rarrCH_(3)C-=C CH_(3)`C. `cis-But-2-"ene"-overset(hv)hArr trans -But-2-"ene"`D. `CH_(3)CH_(2)CH_(2)Br_(2)overset("Anhyd.")underset(AlC_(3))rarrCH_(3)underset(Br)underset(|)CHCH_(3)` |
|
Answer» Correct Answer - A Reactions `(2), (3), and (4)` are isomerization reactions are they effect interconversion of isomers wherein the molecular formulas and carbon skeletons of reactant and product always remain the same. Reaction `(1)` is an example of polymerization reaction. |
|
| 978. |
Carbon atoms in `C_2(CN)_4` are :A. sp and `sp^(2)` hybridisedB. `sp^(2)` hybridisedC. sp hybridisedD. sp, `sp^(2)` and `sp^(3)` hybridised |
|
Answer» Correct Answer - A |
|
| 979. |
Which of the following statements is not correct about the resonance strucuture?A. Contributing structures are less stable than the resonance hybrid.B. Contributing structures represent molecules having no real existence.C. Equivalent resonating structure make the resonance very important.D. Contributing structure contribute to the resonance hybrid in proportion of their relative energies. |
|
Answer» Correct Answer - D Relative contribution of a resonance structure is inversly proportional its energy but directly proportional to its stability. Thus, the lesser the energy and the more stable the sturcutre, the greater is its contribution to the hybrid. |
|
| 980. |
Which is an alicyclic compoundA. BenzeneB. cyclohexaneC. pyridineD. pyrrole |
|
Answer» Correct Answer - B |
|
| 981. |
Which of the following is the least stable ?A. `CH_(3)CH_(2)overset(+)CH_(2)`B. `CH_(3)overset(+)CH_(2)CH_(2)CH_(3)`C. `CH_(3)-underset(CH_(3))underset(|)overset(+)C-CH_(3)`D. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-overset(+)CH-C_(6)H_(5)` |
|
Answer» Correct Answer - A The order of stability of carbocation is `"benzyl" gt 3^(@) gt 2^(@) gt 1^(@)` Thus, `CH_(3)CH_(2)overset(+)CH_(2)` being `1^(@)` cation is the least stable. |
|
| 982. |
Among the following the most stable compound isA. cis - 1,2 - cyclohexanediolB. trans - 1,2 - cyclohexanediolC. cis - 1,3 - cyclohexanediolD. trans - 1,3 - cyclohexanediol |
|
Answer» Correct Answer - D Trans configuration is more stable than cis configuration because in cis-configuration the H groups are thrown closely enough together to cause crowding or repulsion. Again between 1,2-and 1,3-configuration, 1-3, the OH groups are placed further apart to minimise the repulsion. Hence, more stable is 1,3-configuration. |
|
| 983. |
Which of the following groups shows the strongest` -R` effect?A. `-COOR`B. `-CN`C. `-NO_(2)`D. `-CHO` |
|
Answer» Correct Answer - C `-R` effect of different substituents generally follows the order: `(CH_(3))_(3)N^(+)gt -NO_(2)gt - CNgt -SO_(3)H gt -CHO gt -COMegt -CO_(2)H` |
|
| 984. |
Which compound given below has `sp^(3), sp^(2)` and sp orbitals in the ratio of `6:3:2`?A. `CH_(3)-CH=CH-CH_(2)-C-=C-CH_(3)`B. `CH_(3)-CH=CH-CH_(2)-C-=CH`C. `CH_(3)-CH_(2)-C-=C-CH=CH_(2)`D. `CH_(3)-CH=CH-C-=CH` |
|
Answer» Correct Answer - A |
|
| 985. |
Among the following which one can have a meso formA. `CH_(3)CH(OH)CH(Cl)C_(2)H_(5)`B. `CH_(3)CH(OH)CH(OH)CH_(3)`C. `C_(2)H_(5)CH(OH)CH(OH)CH_(3)`D. `HOCH_(2)CH(Cl)CH_(3)` |
|
Answer» Correct Answer - B It is plane of symmetry. |
|
| 986. |
The ratio of the number of sp, `sp^(2)`, and `sp^(3)` orbitals in the compound is `CH_(3)-CH=C=CH-C-=C-CH_(3)`A. `1:1:1`B. `2:2:1`C. `3:2:1`D. `3:3:4` |
|
Answer» Correct Answer - D |
|
| 987. |
Which of the following ion is the most stable?A. `CH_(3)CH_(2)overset(+)CH_(2)`B. `CH_(3)overset(+)CH_(2)CH_(2)CH_(3)`C. `CH_(3)-underset(CH_(3))underset(|)overset(+)C-CH_(3)`D. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-overset(+)CH_(2)` |
|
Answer» Correct Answer - C The order of satbility of carbocation is `3^(@)R^(+)gt 2^(@)R^(+) gt 1^(@)R^(+) gt overset(+)CH_(3)` `(CH_(3))_(3)overset(+)C`, being a `3^(@)R`, is the most stable. |
|
| 988. |
The type of isomerism observed in urea molecule isA. ChainB. PositionC. GeometricalD. Tautomerism |
|
Answer» Correct Answer - D Tautomerism is observed in urea. `{:(" "O" "OH),(" ||"" |"),(underset("Keto form")(H_(2)N-C-NH_(2))hArr underset("enol form")(HN=C-NH_(2))):}` |
|
| 989. |
The decreasing order of `- I` effect of the orbitals is : (I) `sp` (II) `sp^2` (III) `sp^3`.A. `I gt II gt III`B. `III gt II gt I`C. `I gt III gt II`D. `II gt III gt I` |
|
Answer» Correct Answer - A (a) The more the `s` character, the more is the penetration effect of `s` orbital towards the nucleus, and hence more `overline e`-withdrawing effect. So `sp(50 % s) gt sp^2(33 % s) gt sp^3 (25 % s)`. |
|
| 990. |
In carbonium ion the carbon bearing the positive charge in theA. `sp^(2)`-hybridized stateB. `sp^(3)d`-hybridized stateC. sp-hybridized stateD. `sp^(3)`-hybridized state |
|
Answer» Correct Answer - A The central carbon atom in carbonium ion is `sp^(2)` hybridised and it has three `sp^(2)` hybrid orbitals for single bonding to three substituents. |
|
| 991. |
In which `(C - C)` bond of `(H_3 overset (3)C - overset (2) C H_2 - overset (1) CH_2 - Br)`, the inductive effect is expected to be the least ? |
|
Answer» The electron withdrawing inductive effect is least in the bond between `C_(2)` and `C_(3)` `overset(deltadeltadelta+)underset(3)(C)H_(3)-overset(deltadelta+)underset(2)CH_(2)-overset(delta+)underset(1)CH_(2)-overset(delta^(-1))(B)r` |
|
| 992. |
Which of the following species act as electro-philes? (i) `BF_(3)` (ii) `:overset(..)underset(..)C1^(+)` (iii) `Cl_(2)C:` (iv) `(CH_(3))_(2)CH^(+)`A. (i). (ii), (iii), (iv)B. (i), (iii)C. (ii), (iv)D. (i), (iii), (iv) |
|
Answer» Correct Answer - A They all are electrophiles as they have six valance electrons and can accept an electron pair from a nucleophile to acquire the stable octet. |
|
| 993. |
Which of the following are nucleophiles? (i) `CH_(3)COoverset(..)underset(..)O:^(-)` (ii) `CH_(3)overset(..)underset(..)O:^(-)` (III)`(CH_(3))_(3)C:^(-)` (iv) `:overset(..)underset(..)Br:^(-)`A. (i),(ii)B. (i), (ii), (iii)C. (i), (ii), (iii), (iv)D. (ii), (iii), (iv) |
|
Answer» Correct Answer - C They are all nucleophiles as they are anions. |
|
| 994. |
Which is most stable compound among the followingA. B. C. D. All the compounds have same stability |
| Answer» Correct Answer - C | |
| 995. |
The number of isomers of `C_(6)H_(14)` isA. 4B. 5C. 6D. 7 |
|
Answer» Correct Answer - B (i) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-CH_(3)` (ii) `{:(CH_(3)-CH-CH_(2)-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` (iii) `{:(CH_(3)-CH-CH-CH_(3)),(" |"" |"),(" "CH_(3)" "CH_(3)):}` (iv) `{:(" "CH_(3)),(" |"),(CH_(3)-C-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` (v) `{:(CH_(3)-CH_(2)-CH-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}` |
|
| 996. |
Hexa - 2-ene-4-yne isA. `CH_(3)-CH_(2)-C-=C-CH = CH_(2)`B. `CH_(3)-C-=C-CH=CH-CH_(3)`C. `CH_(3)CH_(2)-CH=CH-C-=CH`D. `CH_(3)-C-=C-CH_(2)-CH=CH_(2)` |
|
Answer» Correct Answer - B `underset("Hexa-2-ene-4-yne")(CH_(3)-C-=C-CH=CH-CH_(3))` |
|
| 997. |
If two compounds have the same empirical formula but different molecular formulae, they must haveA. Different percentage compositionB. Different molecular weightC. Same velocityD. Same vapour density |
|
Answer» Correct Answer - B The two compounds with different molecular weights can have the same empirical formula but different molecular formulae. |
|
| 998. |
Which is the correct structure of the compound 3-hexyn-1-oic acidA. `CH_(3)-CH_(2)-CH_(2)-C-=C-COOH`B. `CH_(3)-CH_(2)-C-=C-CH_(2)-COOH`C. `CH_(3)-C-=C-CH_(2)-CH_(2)-COOH`D. `CH_(3)-CH_(2)-CH=CH-CH_(2)-COOH` |
| Answer» Correct Answer - B | |
| 999. |
Which one following formulae does not represent an organic compoundA. `C_(4)H_(10)O_(4)`B. `C_(4)H_(8)O_(4)`C. `C_(4)H_(7)ClO_(4)`D. `C_(4)H_(9)O_(4)` |
| Answer» Correct Answer - D | |
| 1000. |
Which of the following compound has the functional group `-OH`A. 1, 2-ethandiolB. 2-butanoneC. NitrobenzeneD. Ethanal |
| Answer» Correct Answer - A | |