InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 901. |
The longest `C-N` bond length in the given compound is : A. xB. yC. zD. w |
| Answer» Correct Answer - D | |
| 902. |
`H_(3)C-overset(o+)CH-CH=CH_(2)` does not involve :A. `sigma-p` overlapB. `sigma-pi^(**)` overlapC. `ppi-ppi` overlapD. `ppi-dpi` overlap |
| Answer» Correct Answer - D | |
| 903. |
Select the correct order of heat of hydrogenation? A. `IgtIIgtIIIgtIV`B. `IVgtIIIgtIIgtI`C. `IIgtIIIgtIVgtI`D. `IIgtIIIgtIgtIV` |
| Answer» Correct Answer - B | |
| 904. |
Incorrect order of Heat of hydrogenation per `pi`-bond isA. B. C. D. |
| Answer» Correct Answer - D | |
| 905. |
The pKa values of the acids A to D are found to be 4.19,3.41, 4.46 and 4.76. The acid having pKa of 3.41 isA. B. `CH_(3)COOH`C. D. |
| Answer» Correct Answer - C | |
| 906. |
Which of the following has the most negative heat of hydrogenation ?A. B. C. D. |
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Answer» Correct Answer - A Heat of hydrogenation `prop` Unsatability of Alkene & It is represented by `DeltaHrarr` which has negative value |
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| 907. |
The order of basicity is `(I) Ph-CONH_(2)" "(II)Ph-NH_(2)" "(III)Ph-CH_(2)-NH_(2)" "(IV)p-OCH_(3)Ph-NH_(2)`A. `II gt IV gt I gt III`B. `III gt II gt IV gt I`C. `III gt IV gt II gt I`D. `I gt II gt IV gt III` |
| Answer» Correct Answer - C | |
| 908. |
Which will show geometrical isomerism ?A. B. C. D. |
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Answer» Correct Answer - A,B,D Symmetrical ketoximes don not show geometrical isomerism |
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| 909. |
Which have active methylene group?A. B. C. D. |
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Answer» Correct Answer - A,B,C,D All contains `CH_(2)` groups adjacent to strong electron withdrawing group |
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| 910. |
Hyperconjugation involves overlap of the following orbitals :A. `sigma-sigma`B. `sigma-p`C. `p-p`D. `pi-pi` |
| Answer» Correct Answer - B | |
| 911. |
Which one of the following has inductive, mesomeric and hyperconjugation effect ?A. `CH_(3)Cl`B. `CH_(3)-CH=CH_(2)`C. `CH_(3)CH=CH-underset(O)underset(||)C-CH_(3)`D. `CH_(2)=CH-CH=CH_(2)` |
| Answer» Correct Answer - C | |
| 912. |
The bond dissociation energy needed to form the benzyl radical from toluence is……….. Than the formation of the methyl radical from methane. |
| Answer» Correct Answer - Less | |
| 913. |
Arrange the following in decreasing order of stability. `{:underset((I))(Cl^(-)),underset((II))(RCOO^(-)),underset((III))(OH^(-)),underset((IV))(RO^(-)),underset((V))NH_(2)^(-):}`A. `IgtIIltIIIgtIVltV`B. `VgtIVgtIIgtIIIgtI`C. `IgtIIgtIIIgtIVgtV`D. `VgtIVgtIIIgtIIgtI` |
| Answer» Correct Answer - D | |
| 914. |
Which of the following act as nucleophilesA. `CH_(3)NH_(2)`B. `RO^(-)`C. `AlCl_(3)`D. `CH_(3)MgBr` |
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Answer» Correct Answer - A::B::D `CH_(3)overset(..)(N)H_(2), R-underset(..)overset(..)(O)-, CH_(3)-Mg-underset(..)overset(..)(Br):` are nucleophiles due to presence of lone pairs. |
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| 915. |
Hyperconjugation effect is also known asA. Baker-Nathan effectB. No bond resonanceC. Both (a) and (b)D. None of these |
| Answer» Correct Answer - C | |
| 916. |
Choose the chain terminating step (1) `H_(2) rarr H^(*)+H^(*)` (2) `Br_(2) rarr Br^(*) + Br^(*)` (3) `Br^(*) + HBr rarr H^(*) + Br_(2)` (4) `H^(*) + Br_(2) rarr HBr + Br^(*)` (5) `Br^(*) + Br^(*) rarr Br_(2)`A. 1B. 3C. 4D. 5 |
| Answer» Correct Answer - D | |
| 917. |
Which of the following molecules does not have net dipole moment?A. `CH_(3)-Br`B. `CH_(2)Cl_(2)`C. HCOOHD. |
| Answer» Correct Answer - D | |
| 918. |
Which compound shows dipole momentA. 1,4-dichloro benzeneB. 1, 2-dichloro benzeneC. Trans-1, 2-dichloro ethaneD. Trans-2-butene |
| Answer» Correct Answer - B | |
| 919. |
Tautomerism will be exhibited byA. `(CH_(3))_(2)NH`B. `CH_(3))_(3)CNO`C. `R_(3)CNO_(2)`D. `RCH_(2)NO_(2)` |
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Answer» Correct Answer - D A,B,C does not contain acidic `alpha`-hydrogen |
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| 920. |
Tautomerism is exhibited by :A. B. C. D. |
| Answer» Correct Answer - A::C::D | |
| 921. |
Aromatic properties of benzene are proved byA. Aromatic sextet theoryB. Resonance theoryC. Molecular orbital theoryD. All of these |
| Answer» Correct Answer - D | |
| 922. |
The maximum number of optically active stereoisomers that could exist for the compound below A. 6B. 8C. 1D. 6 |
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Answer» Correct Answer - 2 No optical isomer`=2^(n-1)` |
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| 923. |
Match the compounds/ions in Column I with their properties/reactions in Column II. |
| Answer» Correct Answer - `A rarr p, q, s; B rarr q; C rarr q, r, s; D rarr q, r` | |
| 924. |
For the given compound X, the total number of optically active stereoisomers is _________ This type of bond indicates that the configuration at the specific carbon and the geometry of the double bond is fixed This type of bond indicates that the configuration at the specific carbon and the geometry of the double bond is NOT fixed |
| Answer» Correct Answer - 7 | |
| 925. |
Select the correct statementA. A recemic mixture can be distinguished from a meso or an achiral compound by optical resolutionB. d and l stereoisomer of the same compound are enantiomerC. A chiral compound may or may not have assymetric carbonD. There is no obvious correlation that exists between the configurations (R or S) of enantiomers and the direction [(+) or (-)] in which they rotate plane polarised light |
| Answer» Correct Answer - A,B,C,D | |
| 926. |
correct relation between above compoundsA. I & II are position isomersB. I & II are chain isomersC. II &III are metamersD. II & III are identical |
| Answer» Correct Answer - A,C | |
| 927. |
An organic compound (A) and `(C_(10)H_(20))` on reductie ozonolysis gives 2--methyl butanal. Based on this information, answer the following questions. Compound (A) is :A. B. C. D. |
| Answer» Correct Answer - A | |
| 928. |
An organic compound (A) `(C_(10)H_(20))` on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question. The total number of stereoisomers possible for (A) is :A. 8B. 7C. 6D. 4 |
| Answer» Correct Answer - C | |
| 929. |
An organic compound (A) `(C_(10)H_(20))`on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question. If the stereochemistry about the double bound in (A) is trans, the total number of stereoisomers for (A) is:A. 2B. 3C. 4D. 5 |
| Answer» Correct Answer - B | |
| 930. |
An organic compound (A) `(C_(10)H_(20))` on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question. If the stereochemistry about the double bound in (A) is cis, the total number of enantiomers for (A) is :A. NoneB. 2C. 4D. 6 |
| Answer» Correct Answer - B | |
| 931. |
An organic compound (A) `(C_(10)H_(20))`on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question. If the stereochemistry about the double bond in (A) is cis, the total number of stereoisomers for (A) is :A. 2B. 3C. 4D. 5 |
| Answer» Correct Answer - B | |
| 932. |
The relative reactivities of acyl compound towards nucleophilic substitution are in the order ofA. Acid anhydride `gt` Amide `gt` Ester `gt` Acyl chlorideB. Acyl chloride `gt` Ester `gt` Acid anhydride `gt` AmideC. Acyl chloride `gt` Acid anhydride `gt` Ester `gt` AmideD. Ester `gt` Acyl chloride `gt` Amide `gt` Acid anhydride |
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Answer» Correct Answer - C order of leaving ability is `Cl^(-) gt R-overset(O)overset(||)(C)-O^(-) gt RO^(-) gt NH_(2)^(-)` |
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| 933. |
Assertion : Cis-1, 3-dihydroxyl cyclohexane exists in boat conformation. Reason : In the chair form, there will not be hydrogen bonding between the two hydroxyl groups.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. If both assertion and reason are true and the reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If the assertion and reason both are false. |
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Answer» Correct Answer - D Here both assertion and reason are incorrect because cis-1, 3-dihydroxy cyclohexane exist in chair conformation and in chair conformation hydrogen bonding is present. |
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| 934. |
Geometrical isomerism is shown byA. `CH_(2)=C(Br)I`B. `CH_(3)CH=C(Br)I`C. `(CH_(3))_(2)C=C(Br)I`D. `CH_(3)CH=C Cl_(2)` |
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Answer» Correct Answer - 2 Double bond carbon posses two different groups. |
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| 935. |
The acceptable resonating structure(s) of the following molecule is/are : A. B. C. D. |
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Answer» Correct Answer - A::B A & B are proper resonating structures while C & D violate octet rule. |
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| 936. |
Which of the following in the rearranged in the rearranged more stable carbocation of the given species? A. B. C. D. |
| Answer» Correct Answer - B | |
| 937. |
CATENATION AND THE SHAPES OF CARBON COMPOUNDSA. Carbon has high catenation abilityB. Tetravalency of carbonC. Isomerism of organic compoundsD. All of these |
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Answer» Correct Answer - D |
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| 938. |
Assetion: Carbon possesses property of catenation. Reason: Carbon atoms form double as well as triple bonds during catenation.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. If both assertion and reason are true and the reason is not the correct explanation of the assertion.C. If assertion is true of the reason is false.D. If the assertion and reason both are false. |
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Answer» Correct Answer - B Catenation property of carbon is primarily due to its small size. Electronic configuration and unique strength of carbon-carbon bonds. |
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| 939. |
Amongest the following compounds, the one which would not form a white precipitate with ammonical silver nitrate solution isA. `HC -= CH`B. `H_(3)C - C -= C - CH_(3)`C. `H_(3)C - C = CH`D. `CH_(3)CH_(2)CH_(2)C -= CH` |
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Answer» Correct Answer - B The structure of but-2-yne shows that there is no acidic hydrogen attached to the sp hybri carbon atom. Hence no reaction with ammonical `AgNO_(3)` is expected. |
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| 940. |
Select the most stable carbocation from amongst the following.A. B. C. D. |
| Answer» Correct Answer - B | |
| 941. |
Total number of stereoisomers of compound is: `CH_(3)-overset(Br)overset(|)CH-CH=CH-overset(Br) overset(|)CH-CH_(3)`A. 2B. 4C. 6D. 8 |
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Answer» Correct Answer - C cis has 3 isomers and trans has 3 isomers |
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| 942. |
The number of stereoisomers possible for a compound of the molecular formula `CH_(3)-CH=CH-CH(OH)-Me` isA. 3B. 2C. 4D. 6 |
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Answer» Correct Answer - C `{:(CH_(3)-CH=CH-overset(**)(C)H-CH_(3)),(" |"),(" "OH):}` Total possible isomers are four. cis - R trans - R cis - S trans - S |
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| 943. |
Compound A gives white precipitate with `AgNO_(3)` and a highly stable cation. Whereas compound B which is antiaromatic reacts with Na metal to give an aromatic compound. Q. Which of the following is A?A. A is more soluble than bromocyclopropaneB. A is having even number of DBEC. A is having lower dipole moment than bromocylopropaneD. A is more ionic than |
| Answer» Correct Answer - C | |
| 944. |
Arrange the carbanions , `(CH_(3))_(3) bar(C), bar(C) Cl_(3), (CH_(3))_(2) bar(C) H, C_(6)H_(5) bar(C) H_(2)` in order of their decreasing stability :A. `(CH_(3))_(2)bar(C)H gt bar(C) Cl_(3) gt C_(6)H_(5)barC H_(2) gt (CH_(3))_(3) barC`B. `barC Cl_(3) gt C_(6)H_(5)barCH_(2) gt (CH_(3))_(2) barC H gt (CH_(3))_(3)barC`C. `(CH_(3))_(3)barC gt (CH_(3))_(2)bar CH gt C_(6)H_(6) barC H_(2) gt barC Cl_(3)`D. `C_(6)H_(5)barC H_(2) gt barC Cl_(3) lt (CH_(3))_(3) barC gt (CH_(3))_(2)barC N` |
| Answer» Correct Answer - B | |
| 945. |
Correct decreasing stability order of following carbanions : `""^(Ө)underset(" "I)(CH_(2))-CHO" "CH_(3)-underset(O)underset(||)C-""^(Ө)CH-underset(II" ")underset(O)underset(||)C-CH_(3)" "H-underset(III)underset(O)underset(||)-overset(Ө)(CH)-underset(O)underset(||)C-H" "OHC-underset(IV)underset(CHO)underset(|)overset(Ө)C-CHO`A. `III gt IV gt II gt I`B. `IV gt II gt III gt I`C. `IV gt III gt II gt I`D. `III gt II gt I gt IV` |
| Answer» Correct Answer - C | |
| 946. |
Arrange the following carbanions in increasing order of stability: A. `III gt VI gt I gt II`B. `I gt III gt IV gt II`C. `I gt II gt III gt IV`D. `I gt IV gt III gt II` |
| Answer» Correct Answer - D | |
| 947. |
Which of the following may exist in enantiomorphsA. `{:(" "CH_(3)),(" |"),(CH_(3)-CH-COOH):}`B. `CH_(2)=CHCH_(2)CH_(2)CH_(3)`C. `{:(" "NH_(2)),(" |"),(CH_(3)-CH-CH_(3)):}`D. `{:(" "NH_(2)),(" |"),(CH_(3)-CH_(2)-CH-CH_(3)):}` |
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Answer» Correct Answer - D `{:(" "NH_(2)),(" |"),(CH_(3)-CH_(2)-C^(**)-CH_(3)),(" |"),(" "H):}` Chiral centre is present. Hence, it exists as optical isomers or enantiomorphs. |
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| 948. |
Geometrical isomers differ inA. Position of atomsB. Length of carbonC. Spatial arrangement of atomsD. Position of functional group |
| Answer» Correct Answer - C | |
| 949. |
Which of the following is not chiralA. 3-bromopentaneB. 2-hydroxypropanoic acidC. 2-butanolD. 2, 3-dibromopentane |
| Answer» Correct Answer - A | |
| 950. |
The chirality of the compound A. RB. SC. ZD. E |
| Answer» Correct Answer - A | |