Explore topic-wise InterviewSolutions in Current Affairs.

The viviparous

Correct answer is (c) Mercury 

Correct answer is (b) stock

1. Due to the process of gastrulation, three germinal layers, viz. ectoderm, mesoderm and endoderm are formed. 

2. Cells of embryonal knob become embryonic disc which develop into embryo due to gastrulation. 

3. Gastrulation is necessary for the formation of amniotic cavity which is filled with amniotic fluid.

Significance of fertilization:

1. Fertilization forms the zygote which eventually produces new offspring. 

2. Fertilization restores diploid number of chromosomes in the zygote as two haploid gametes come together in a zygote. 

3. During fertilization, centrioles are passed on to the ovum, due to this secondary oocyte can complete meiosis-II. The fertilization thus concludes the process of oogenesis. 

4. By fertilization the genetic characters of two parents are mixed. This leads to variation and has significance in evolution. 

5. Due to fertilization the sex of young one is determined.

1. Fertilization of the ovum takes place in fallopian tube where it starts cleavages immediately. 

2. Zona pellucida which remains on the surface of the ovum prevents the implantation of the blastocyst at an abnormal site such as fallopian tube. 

3. Zona pellucida keeps the sticky and phagocytic trophoblast cells unexposed till the ovum reaches the uterine lumen. 

4. Zona pellucida also protects the ovum. Therefore zona pellucida is retained for some time after fertilization

Ampulla of fallopian tube

Fertilization membrane prevents any further entry of other sperms into the egg, i.e. polyspermy is avoided.

Properties of metalloids : 

1. Metalloids usually look like metals but behave largely like non-metals. 

2. Physically they are shiny, brittle solids with intermediate to relatively good electrical conductivity. 

3. They can from alloys with metals. 

4. Most of their physical and chemical properties are intermediate in nature, (v) They are semiconductors. 

5. All are solids at room temperature.

6. Example : Germanium, Boron, Antimony, Silicon.

Elements contains two or more kinds of atoms and compounds contains two or more kinds of elements.

Metals and their uses in our houses & schools :

1. Magnesium is used in the laboratory as magnesium ribbon. 

2. Copper is used cooking utensils. 

3. Zinc is mainly used as a protective coat for iron is our school and house gates. 

4. Aluminum is used as cooking utensils and electrical cables which are used in our schools and houses. 

5. Iron and steel are widely used is construction of house and school. 

6. Sodium is used as a table salt and for flavoring, preserving food. 

7. Coins are made up of nickel.

8. Lead is used in car batteries. Lead based alloys find extensive use in printing

Non-metals and their uses in houses & school: 

1. Oxygen is essential for the breathing. It is used as oxidising agent in laboratory. Chlorine is used for purifying water. 

2. Graphite is used in pencil leads. 

3. Carbon is used as a fuel. 

4. Bromine is used in dyes. 

5. Iodine is used in laboratory to test for starch.

Metalloids and their uses in houses & schools : 

1. Silicon is used in glass items. 

2. Antimony is used in optical discs. 

3. Tellurium is used in solar cells. 

4. Boron is used in washing powders.

5. Germanium is used to make transistors which is used in laboratory in electrical devices.

Comparsion of properties of metals, non-metals & metalloids

On earth the three most abundant atom are iron, oxygen, and silicon.

Antibiotic which kill or inhibit a range of Gram-positive and Gram-negative bacteria.

1. A molecule which contains only one atom is called monatomic molecule (inert gases)

2. A molecule which contains two atoms is called diatomic molecule (oxygen, nitric oxide, hydrogen, etc.).

Chemical compound which are used for the treatment of excess acid produced in the stomach.

Correct Option  (c) 60%, 40%

Explanation: 

Fraction of energy supplied for increment in internal energy = 1/γ  = 3/5 [AS γ  = 5/3 for monoatomic gas]

:. Percentage energy = 30/5 = 60%

Fraction of energy supplied for external work done = 1 - 1/γ = γ - 1/γ = (5/3 - 1)/5/3 = 2/5

:.    Percentage energy = 2/5 x 100% = 40%

Due to the large mass of a baseball, the de Broglie wavelength [λ = \(\frac{h}{mv}\)] associated with a moving baseball is very small. Hence its wave nature is not visible.

De Broglie hypothesis, all matter particles like electrons, protons, neutrons in motion are associated with waves.

Correct option : (2) Blue light

Explanation:

Green light ejects electrons but yellow does not. The only option out of given four only blue light can cause emission (VIGB YOUR). 

(i) {(5² + 12²)^1/2}³

= {(25 + 144)^1/2}³

= {(169)^1/2}³

= {(13²)^1/2}³

= (13)³

= 2197

(ii) {(6² + 8²)^1/2}³

= {(36 + 64)^1/2}³

= {(100)^1/2}³

= {(10²)^1/2}³

= (10)³

= 1000

Given area of one face of cube = 64 m²

Let the length of edge of cube be ‘a’ metre

a² = 64

a = √64

= 8m

Now, volume of cube = a³

a³ = 8³ 

= 8 × 8 × 8

= 512 m³

∴ Volume of a cube is 512 m³

(i) 3? 

Let the number is = a 

Its cube will be = a³ 

According to the question, the number is multiplied by 3 

New number become = 3a 

Its new cube will be = (3a)³ = 27a³ 

Hence, cube will become 27 times

(ii) 4? 

Let the number is = a 

Its cube will be = a³ 

According to the question, the number is multiplied by 4 

New number become = 4a 

Its new cube will be = (4a)³ = 64a³ 

Hence, cube will become 64 times 

(iii) 5? 

Let the number is = a 

Its cube will be = a³ 

According to the question, the number is multiplied by 5 

New number become = 5a Its new cube will be = (5a)³ = 125a³

Hence, cube will become 125 times

(i) 3

Let the number be a

So its cube will be = a³

According to the question, the number is multiplied by 3

New number becomes = 3a

So the cube of new number will be,

 = (3a)³ 

=  27a³

Hence, number will become 27 times the cube of the number.

(ii) 4

Let the number be a

So its cube will be = a³

According to the question, the number is multiplied by 4

New number becomes = 4a

So the cube of new number will be, 

= (4a)³ 

= 64a³

Hence, number will become 64 times the cube of the number.

(iii) 5

Let the number be a

So its cube will be = a³

According to the question, the number is multiplied by 5

New number becomes = 5a

So the cube of new number will be, 

= (5a)³ 

= 125a³

Hence, number will become 125 times the cube of the number.

Let the number be a

So the cube of the number is = a³

Now, the number is trebled ,

= 3 × a 

= 3a

So the cube of new number,

= (3a)³ 

= 27a³

∴ New cube is 27 times of the original cube.

Hence ,it is proved

Let the number is = a 

Cube of number will be = a³ 

Now, the number is trebled = 3 × a = 3a 

Cube of new number = (3a)³ = 27a³ 

Hence, new cube is 27 times of original cube. Hence, proved.

Given details are,

Volume of wooden block = 36 cm³

Length of the wooden block = 4 cm

Breadth of a wooden block = 3 cm

Let height of wooden block be ‘h’ cm

We know that, l × b × h = 36 cm³

h = 36/( l × b)

= 36/(4×3)

= 3cm

For this we have to find out volume of the water tank 

We know that, 

Volume of a cuboid = Length × Breadth × Height 

Therefore, 

Volume of water tank = 3 × 2 × 5 

= 30 m³ 

= 30000 L (As, 1 m³ = 1000 L) 

Hence, option A is correct

Correct option is  B) iris

Correct option is  A) cornea

(d) 7 cm

From the question it is given that, dimensions of rectangle length = 14 cm, breadth = 11 cm

As area of rectangle = area of circle

length × breadth = πr²

14 × 11 = (22/7) × r²

r² = (14 × 11 × 7)/22

r² = 49

r = √49

r = 7 cm

Length and breadth

True

Because the triangles on same base and between same parallel lines have equal in area.

(i) From the figure, P is the midpoint of AD.

Thus AP = PD = 25 cm and AB = CD = 20 cm

From the figure, we observed that,

Area of Triangle APB = Area of Triangle PDC

Area of Triangle APB = ½ (AB x AP)

= ½ (20 x 25)

= 250 cm²

Area of Triangle PDC = Area of Triangle APB = 250 c m²

Area of Triangle RPQ = ½ (Base x Height)

= ½ (25 cm x 10 cm)

= 125 cm²

Hence, Sum of the three triangles = (250 + 250 + 125) cm² 

= 625 cm²

(ii) From the figure, area of the rectangle ABCD = 50 cm x 20 cm

= 1000 cm²

Thus, Area of the rectangle – Sum of the areas of three triangles

= (1000 – 625) cm² 

= 375 cm²

i) Area = 1/2 = 1/2 x 5 x 8 = 20 cm²

ii) Area = 1/2 = 1/2 x 6 x 4 = 12 cm²

iii) Area = 1/2 = 1/2 x 5.4 x 7.5 = 20.25 cm²

iv) Area = 1/2 = 1/2 x 6 x 4 = 12 cm²

Plane figures

Given that,

Length of parallel sides of trapezium = 10m and 6m

Area = 72 m² 

Let the distance between parallel sides of trapezium = x meter

We know that,

Area of trapezium = 1/2 (Sum of lengths of parallel sides) × distance between parallel sides

i.e., Area of trapezium = 1/2 (Sum of sides) × distance between parallel sides

72 = 1/2 (10 + 6) × x

72 = 8 × x

x = 72/8 = 9

∴ The depth is 9m.

Given that,

Let the length of one parallel side of trapezium = x meter

Length of other parallel side of trapezium = (x+8) meter

Area of trapezium = 91 cm²

Height = 7 cm

We know that,

Area of trapezium = 1/2 (Sum of lengths of parallel sides) × altitude

91 = 1/2 (x+x+8) × 7

91 = 1/2(2x+8) × 7

91 = (x+4) × 7

(x+4) = 91/7

x+4 = 13

x = 13 – 4

x = 9

∴ Length of one parallel side of trapezium = 9 cm

And, Length of other parallel side of trapezium = x+8 = 9+8 = 17 cm

Vertices = 10 

Faces = 7 

Using Eulers formula, 

F + V – E = 2 

7 + 10 – E = 2 

-E = -15 

E = 15

For A Polyhedron
Number of faces = ?;
Number of vertices = 6,
Number of Edges = 12

By using Euler’s formula
F + V = E + 2
or F = E + 2 – V = 12 + 2 – 6
F = 14 – 6 = 8
∴ Number of faces F = 8

For B Polyhedron
Number of faces = 5;
Number of vertices = ?,
Number of Edges = 9 ,

By using Euler’s formula
F + V = E + 2
or V = E + 2 – F = 9 + 2 – 5 = 6
∴ Number of vertices = 6

A pyramid becomes a cone provided the number of sides of its base becomes larger and larger.

We know that polyhedron is a solid, which is bounded by four or more polygonal faces in such a way that pairs of faces meet along edges and three or more edges meet in each vertex, therefore,

(i) It is not possible that a polyhedron has 3 triangles for its faces.

(ii) 4 triangles can be the faces of a polyhedron.

(iii) A square and 4 triangles can be the faces of a polyhedron.

Number of faces (F) = 7

Number of vertices (V) = 10

We know that a prism is a polyhedron whose base and top are congruent polygons and lateral faces are parallelogram. Therefore, 

(i) A nail is not a prism. 

(ii) An unsharpened pencil is a prism. 

(iii) A table weight is not a prism. 

(iv) A box is a prism.

(a) F + V = E + 2

The point where the edges of a solid, is called vertex.

(i) Triangle

(ii) Congruent

(iii) 15

(iv) Prism.

(a) (iii) Metaphor

(b) (ii) Alliteration

(c) (i) Epigram

(d) (iii) Antithesis

1. Metaphor – bower stands for rest and peace

2. Alliteration – Repetition of the sound of the letter ‘s’. Personification – beauty is given the human quality of moving away the pall.

3. Epigram – the sentence is a short, pithy statement.

4. Antithesis – the use of opposite words, old and young, in the same line.

The things of beauty include a quiet bower, the heavenly bodies like the sun and the moon, the old and young trees that provide cool shelter to sheep, daffodils with greenery around them, clear streams that make cool thickets for themselves and ferns with musk-roses scattered in between.