Explore topic-wise InterviewSolutions in Current Affairs.

The desire Mandela refers to is the greater hunger for the freedom of his people.

In Uttar Pradesh and Punjab.

In 1857 A.D.

Correct option is (C) 2.25

Given equation is 2x – (4 – x) = 5 – x

\(\Rightarrow\) 2x - 4 + x - 5 + x = 0

\(\Rightarrow\) 4x - 9 = 0

\(\Rightarrow\) x = \(\frac94\) = 2.25

Correct option is C) 2.25

Correct option is (C) 6

2(x – 1) – (1 – x) = 2x + 3

\(\Rightarrow\) 2x - 2 - 1 + x = 2x + 3

\(\Rightarrow\) 3x - 3 = 2x + 3

\(\Rightarrow\) 3x - 2x = 3+3

\(\Rightarrow\) x = 6

Correct option is C) 6

Correct option is (C) 3 – x = y² + 4

(A) 5x + 4 = y + 3

\(\Rightarrow\) 5x - y + 4 - 3 = 0

\(\Rightarrow\) 5x - y + 1 = 0

which is a linear equation.

(B) \(x+y^2=y^2-x+2y\)

\(\Rightarrow\) \(x+y^2-y^2+x-2y=0\)

\(\Rightarrow\) 2x - 2y = 0

\(\Rightarrow\) 2 (x - y) = 0

\(\Rightarrow\) x - y = 0 which is also a linear equation.

(C) \(3 - x = y^2 + 4\)

\(\Rightarrow\) \(y^2+4+x-3=0\)

\(\Rightarrow\) \(y^2+x+1=0\) which is not a linear equation.

(D) x + y = 0 which is a linear equation.

Correct option is C) 3 – x = y² + 4

Correct option is (A) x = 3, y = 2

\(\frac{10}{x+y}+\frac{2}{x-y}= 4\)    ________(1)

and \(\frac{15}{x+y}-\frac{5}{x-y}=-2\)   ________(2)

Put \(\frac1{x+y}=X\;\&\;\frac{1}{x-y}=Y\)

Then equations (1) & (2) converts to

10X + 2Y = 4           ________(3)

and 15X - 5Y = -2   ________(4)

Multiply equation (3) by \(\frac52,\) we get

25X + 5Y = 10        ________(5)

By adding equation (4) & (5), we get

(25X + 5Y) + (15X - 5Y) = 10 - 2

\(\Rightarrow\) 40X = 8

\(\Rightarrow\) X \(=\frac8{40}=\frac15\)

Then from (3), we get

\(10\times\frac15+2Y=4\)

\(\Rightarrow\) 2 + 2Y = 4

\(\Rightarrow\) 2Y = 4 - 2 = 2

\(\Rightarrow\) Y = \(\frac22\) = 1

\(\because\) \(X=\frac15\)

\(\Rightarrow\) \(\frac1{x+y}=\frac{1}5\)

\(\Rightarrow\) x+y = 5        ________(6)

and Y = 1

\(\Rightarrow\) \(\frac1{x-y}=1\)

\(\Rightarrow\) x - y = 1        ________(7)

By adding equations (6) & (7), we get

2x = 5+1 = 6

\(\Rightarrow\) x = \(\frac62\) = 3

\(\therefore\) y = 5 - x

= 5 - 3 = 2

Correct option is A) x = 3, y = 2

Correct option is b) 6

Correct option is  b) 2t – 1= 2t + 5

Correct option is c) 3 – x = y² + 4

Correct option is (A) 5 + 4x = y + 3

5 + 4x = y + 3

\(\Rightarrow\) 4x - y + 5 - 3 = 0

\(\Rightarrow\) 4x - y + 2 = 0 which is a linear equation.

Correct option is A) 5 + 4x = y + 3

(d) Pollen grains

(a) Gametes, zygote, embryo, seedling

Correct option is (A) 6

Given equation is 2(x + 3) = 18

\(\Rightarrow\) x+3 = \(\frac{18}2\) = 9

\(\Rightarrow\) x = 9 - 3 = 6

Hence, x = 6 is a solution of given equation.

Correct option is A) 6

Correct option is (D) 2

For coincident lines, we have

\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\)

\(\Rightarrow\) \(\frac36=\frac48=\frac{-k}{-4}\)

\(\Rightarrow\) \(\frac k4=\frac12\)

\(\Rightarrow\) \(k=\frac42=2\)

Correct option is D) 2

In aquatic plants generally, we see the formation of separate male and female flowers. Male flower detach from the plant, float on the surface. The female flowers remain attached to the plant. Male flowers are carried towards the female flowers by water current. Where they release pollen grains, 

Ex: Valisneria, Hydrilla, and Elodea.

Sugarcane, Maize, and grass are common example of w ind pollinated plants.

Fertilization is the fusion of haploid male gamete in the pollen grain with the haploid female gamete in the ovule. To bring about fertilization, the pollen grain which get deposited on the stigma of the carpel must penetrate the style and reach the ovule. Hence it produces a projection called pollen tube which grow through the length of the style and finally reaches the ovule.

The pollen tube contains male gamete inside the ovule, there is a structure called embryo sac which encloses the female gamete, the pollen tube reaches the embryo sac. Then male gamete in pollen tube and female gamete in embryo sac unite, thus fertilization takes place resulting in the formation of a diploid cell called zygote.

The agents of cross pollination are, wind, water and animals.

If the pollen grains get transferred to the stigma of another flower in another plant of the same species, it is called cross pollination.

If the pollen grains get transferred to the stigma of the same flower. It is called self pollination.

1. Pulses : Pulses are the principal sources of proteins. 

2. Pod : The pulses are primarily seeds occurring in variable size and colors inside a type of fruit called pod. 

3. Grains : Grains are small, hard dry seeds with or without the fruit wall attached. Most of the grains are generally described as cereals. 

4. Poaeceae : the plants produced primarily by varieter of grasses belonging to the family called poaeceae. 

Ex: Maize, rice, wheat, barley, oats. 

5. Millet’s : Millet’s are coarse grains where the protein content is said to be higher. 

Ex: Jowar, bajra, ragi.

Flower is the reproductive structure of a plant.

Sexual reproduction involves the formation and fusion of specialized reproductive cells are called gametes.

The process of transfer of pollen grains from the anther to the stigma is called pollination. 

There are two typers of pollination 

1. Self pollination 

2. Cross pollination

• Once in a month one egg is released from either of the ovaries. 
• The egg gets transferred to fallopian tube from the ovaries. 
• Sperms swims towards fallopian tube and only one sperm can penetrate the egg at a time. 
• This process is called fertilization.

Various ways to avoid pregnancy are given below 

a) Physical barrier 

b) Copper-T 

c) Hormone Pills 

d) Surgical procedure 

Barrier method: 

• In the barrier methods of preventing preganancy, the physical devices such as diaphragm (or cap) and condoms are used. 
• Diaphragm (or Cap) is used by human females which is put over the cervix. 
• Condoms are used by males

There are two basic types of reproduction. 

1. Asexual Reproduction and 

2. Sexual Reproduction.

Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.

Now, put x = 3 and y = 4 in given equation, we get
3(4) = a (3)+7

=> 12 = 3a+7

=> 3a = 12 – 7

=> 3a = 5

Hence, the value of a is 5/3.

Correct option is (D) x = 0

Let \(\frac{ax+b}{cx+d}\) \(\neq\frac{b}{d}\)

\(\Rightarrow\) d (ax+b) \(\neq\) b (x+d)    (By cross multiplication)

\(\Rightarrow\) adx + bd \(\neq\) bcx + bd

\(\Rightarrow\) adx \(\neq\) bcx

\(\Rightarrow\) adx - bcx \(\neq\) 0

\(\Rightarrow\) (ad - bc) x \(\neq\) 0

\(\Rightarrow\) ad - bc \(\neq\) 0 and x \(\neq\) 0

\(\Rightarrow\) x \(\neq\) 0 and ad \(\neq\) bc

\(\Rightarrow\) x \(\neq\) 0 and d \(\neq\) b if a = c = 1 which is given.

Hence, if a = c = 1 and \(x\neq0\) then \(\frac{ax+b}{cx+d}\) and \(\frac{b}{d}\) are unequal.

Correct option is D) x = 0

The process of transfer of pollen grains from the anther to the stigma is called pollination.

Correct option is (C) x = 2, y = 3

Given equations are

\(2^x+3^y=31\)    __________(1)

and \(2^{x+2}-3^{y+1}=-65\)

\(\Rightarrow\) \(2^x.2^2-3^y.3=-65\)

\(\Rightarrow\) \(4.2^x-3.3^y=-65\)    __________(2)

Take \(2^x=X\;\&\;3^y=Y\)

Then equations (1) & (2) converts into

X+Y = 31         __________(3)

and 4X - 3Y = -65    __________(4)

Put Y = 31 - X from equation (3) into equation (4), we obtain

4X - 3 (31 - X) = -65

\(\Rightarrow\) 4X - 93 + 3X = -65

\(\Rightarrow\) 7X = -65 + 93 = 28

\(\Rightarrow\) X = \(\frac{28}7\) = 4

\(\therefore\) Y = 31 - X

= 31 - 4 = 27

\(\Rightarrow2^x=4\;\&\;3^y=27\)    \((\because X=2^x\;\&\;Y=3^y)\)

\(\Rightarrow2^x=2^2\;\&\;3^y=3^3\)

\(\Rightarrow\) x = 2 & y = 3

Correct option is C) x = 2, y = 3

Correct option is B) 10y + x

C. 15/4

Condition for parallel lines is

a₁/a₂ = b₁/b₂ ≠ c₁/c₂ …(i)

Given lines, 3x + 2ky - 2 = 0

and 2x + 5y - 1 = 0;

Comparing with ax + by + c = 0;

Here, a₁ = 3, b₁ = 2k, c₁ = - 2

and a₂ = 2, b₂ = 5, c₂ = - 1

From Eq. (i), 3/2 = 2k/5

k = 15/4

Correct option is (A) 1/4

\(\frac{x+y}{xy}=2\;and\;\frac{x-y}{xy}=6\)

\(\Rightarrow\) \(\frac1x+\frac1y=2\)     ________(1)

and \(\frac1y-\frac1x=6\)   ________(2)

Put \(\frac1x=X\;\&\;\frac1y=Y,\) then equations (1) & (2) converts into

X + Y = 2        ________(3)

Y - X = 6         ________(4)

Adding equations (3) & (4), we get

(X + Y) + (Y - X) = 2+6

\(\Rightarrow\) 2Y = 8

\(\Rightarrow\) Y = \(\frac82\) = 4

\(\therefore\) X = 2 - Y

= 2 - 4 = -2

\(\because\) X = -2

\(\Rightarrow\) \(\frac1x=-2\)

\(\Rightarrow\) \(x=\frac{-1}2\)

and Y = 4

\(\Rightarrow\) \(\frac1y=4\)

\(\Rightarrow\) \(y=\frac14\)

Correct option is A) 1/4

Correct option is (A) I

Given lines are 2x + 3y – 5 = 0   _________(1)

and 3x – 4y + 1 = 0                 _________(2)

Multiply equation (1) by 4 & equation (2) by 3, we get

8x + 12y - 20 = 0                  _________(3)

and 9x - 12y + 3 = 0              _________(4)

By adding equations (3) & (4), we obtain

17x - 20 + 3 = 0

\(\Rightarrow\) 17x = 20 - 3 = 17

\(\Rightarrow\) x = \(\frac{17}{17}\) = 1

Then from (1), we obtain

2 + 3y - 5 = 0

\(\Rightarrow\) 3y = 5 - 2 = 3

\(\Rightarrow\) y = \(\frac33\) = 1

Hence, point of intersection of both given lines is (1, 1) which lies in first quadrant.

Correct option is A) I

Correct option: (B) b₁ and b₂ bear a simple whole number ratio 

 (a) 4, 2, -2, +\(\frac{1}{2}\)

(D) law of gaseous volumes

\(\underset{2L}{H_2(g)}+\underset{2L}{O_2(g)}\longrightarrow \underset{2L}{H_2O(g)}\)

Gay-Lussac's states that "At same temperature and pressure, when gases combine or produced in a chemical reaction, they do so in a simple ratio by volume.

Here, \(H_2\), \(O_2\) and \(H_2O(g)\) are in 2 : 1: 2 simple volume ratio.

Therefore, it follow "Law of gaseous volumes"

Option : (D) law of gaseous volumes

(B) \(b_1\) and \(b_2\) bear a simple whole number ratio

Law of multiple proportions state that "If two elements from more than one compound between them, the mass ratio of the second element, that combine with a fixed mass of the first element will always be the ratios of small whole numbers"

Hence, the correct answer will be, \(b_1\) and \(b_2\) bear a simple whole number ratio.

Option : (B) b₁ and b₂ bear a simple whole number ratio.

(b) 3, 1,-l, +\(\frac{1}{2}\)

3p_x electron ; n = 3 (main shell) 

for p_x orbitaI, l = 1, m = -1, s = \(\frac{1}{2}\) .

Correct option: (B) 40, 30

0.1 mol of XY₂ = 10 g

∴ 1 mol of XY₂ = 100 g

i.e, Molecular weight of XY₂ = 100

0.05 mol of X₃Y₂ = 9 g

∴ 1 mol of X₃Y₂ = 180 g

i.e., Molecular weight of X₃Y₂ = 180

Let atomic weights of X and Y be x and y respectively.

x + 2y = 100 ….(1)

3x + 2y = 180 ….(2)

Substrating (1) from (2),

2x = 180 - 100

x = 40

Substituting x = 40 in (1),

40 + 2y = 100

∴ y = 30

H₂SO₄ [358°C] has highest boiling point. HCl [-85°C] has lowest boiling point.

Answer is (d) F > N > C > Si > B

C₂H₅OH (Ethanol)

Dilute sulphuric acid  Lead nitrate,  

Correct Answer is : (b) 1993

(b) consumption

Cyclical unemployment is caused by trade.

(c) Money Supply