This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Describe the ritual of burying the dead in the village settlements. |
|
Answer» i. A dead person was buried either in the house or in the courtyard with the idea that the person’s bond with the family should not get cut off even after death. ii. Families would also bury various articles with the dead person for them to use even after death. |
|
| 2. |
Describe the structure of houses in the New Stone Age. |
|
Answer» 1. The houses at the beginning of the New Stone Age were made of wattle and daub i.e. the walls were screens woven from sticks or bamboo and plastered with mud or cow dog. 2. Later when the population in the village ettlement grew, people began to build quadrangular” houses of sun-dried bricks. These houses were also bigger and had more than one room. 3. Regional differences are seen in the styles of constructing houses, depending on the local climate. |
|
| 3. |
How was barter system established? |
|
Answer» 1. When the farmers in the village-settlements 2. produced surplus food, they felt the need for skilled craftsmen who would provide them with agricultural implements and also repair them. 3. Such craftsmen were paid in the form of food grains or other articles. The craftsmen also purchased the required raw material in the form of foodgrains and other useful articles. 4. Thus, buying and selling by exchanging goods for goods called barter system was established. |
|
| 4. |
Who are given the credit to have started cultivation? |
|
Answer» Women are credited to have started cultivation |
|
| 5. |
How did the village administrative system came into being? |
|
Answer» 1. The village community made rules for mutual co-operation in order to keep trade running smoothly. 2. People responsible for the implementation of these rules became the chiefs of village settlements 3. These chiefs were also entrusted with the protection of the village. 4. This is how the village administrative system came into being. |
|
| 6. |
How did a social system based on agriculture came into existence? |
|
Answer» 1. Essential things like sharing of agricultural tasks and water resources and the security of the village-settlement gained importance. 2. People in the village-settlements established some rules and customs to manage these things. 3. Thus, a social system based on agriculture came into existence. |
|
| 7. |
What cannot be defined without oversimplifying it? |
|
Answer» Poetry is something so intimate and essential that it cannot be defined without oversimplifying it. |
|
| 8. |
Explain the idea of separateness as perceived by Vandana Shiva. |
|
Answer» The idea of separateness refers to the illusion that human beings and nature are different entities. Secondly, the Earth/nature is dead matter and human beings have the capacity to conquer nature, subdue her, and shake her to her foundations. This idea was popularized by Francis Bacon and other leaders of the scientific revolution. Further, it triggered many scientific experiments which culminated in new inventions and discoveries. These scientific inventions and discoveries served as the basis for the industrial revolution. Cormac Cullinan, a South African environmentalist, calls it ‘eco-apartheid’ and urges us to overcome it just like the apartheid in South Africa. |
|
| 9. |
What did they use to sow seeds? |
|
Answer» They used pointed sticks to sow seeds. |
|
| 10. |
Conversation:Alifano: What is your first literary reading? Borges: My first reading is Grimm’s Fairy Tales in an English version.Alifano: Where did you read it?Borges: I read it in my father’s library. It taught me more than any high school. |
|
Answer» Alifano asked Borges what was his first literary reading. Borges replied that his first reading was Grimm’s Fairy Tales in an English version. Alifano further asked him where he had read it. Borges replied that he had read it in his father’s library. He added that it taught him more than any high school would. |
|
| 11. |
What is reflection ? |
|
Answer» The process of bouncing back of light rays in the same medium after hitting the surface of an object is called reflection. |
|
| 12. |
How objects are visible to our eyes ? |
|
Answer» Objects are visible only when light falls on the objects and bounces back to the eye. |
|
| 13. |
Can there be an element with atomie mass 53 or 54 in between the two elements, chromium \(^{52}_{24}Cr\) and manganese \(^{55}_{25}Mn?\) |
|
Answer» In Mendeleev’s periodic table, the difference between atomic masses of two consecutive elements is not the same (52Cr and 55Mn). Moseley found out the atomic number of the elements. The atomic number of any element is increased by one unit (number) from the atomic number of subsequent element. \(^{52}_{24}Cr\rightarrow\,^{55}_{25}Mn\) that means in between two elements (Cr aind Mn), element with mass 53 or 54 do not exist. |
|
| 14. |
How thd the position of \(^{35}_{17}Cl \) get fixed in the modern periodic table? |
|
Answer» In Mendeleev’s periodic table, the difference between atomic masses of two consecutive elements is not the same 35Cl and 35Cl. Moseley found out the atomic number of the elements. The atomic number of any element is increased by one unit (number) from the atomic number of subsequent element. Isotopes \(^{35}_{17}Cl\) and \(^{37}_{17}Cl\) occupy the same position in the modern periodic table. Both isotopes have the same atomic number. In the modern periodic table, the elements are arranged in the order of their increasing atomic numbers, that the problem of discrepancy in the pairs of isotopes elements observed in Mendeleev’s periodic table was solved. The isotopes of \(^{35}_{17}Cl\) and \(^{37}_{17}Cl\) were placed in the same group as both have the same atomic number. |
|
| 15. |
What is a focus? |
|
Answer» The point where rays converge or the point from which rays seem emanate is called focal point (or) focus. |
|
| 16. |
What is the distance between pole and focal point called? |
|
Answer» Focal length. |
|
| 17. |
The refracted ray ………………. when a ray travelling parallel to the principal axis, strikes a convex surface and passes from denser medium to rarer medium A) moves towards the principal axis B) moves away from the principal axis C) moves parallel to the principal axisD) moves along the normal |
|
Answer» B) moves away from the principal axis |
|
| 18. |
Name the different apparatus where we are using the convex and concave lenses. |
|
Answer» The magnifying lense, telescope, microscope |
|
| 19. |
The diagram below shows two incident rays P and Q which emerge as parallel rays R and S respectively. The appropriate device used in the box is... |
|
Answer» The rays are diverging and they produced the parallel from the device after refraction. So the device is concave lens |
|
| 20. |
What happens if the ray passes through principal axis? |
|
Answer» It will be undeviated |
|
| 21. |
The refracted ray ……………… when a ray travelling parallel to the principal axis, strikes a concave surface and passes from denser medium to rarer medium A) moves towards the principal axis B) moves away from the principal axis C) moves parallel to the principal axis D) moves along the normal |
|
Answer» A) moves towards the principal axis |
|
| 22. |
How do rays betide when they are incident on a curved surface? |
|
Answer» A ray will bend towards the normal when it travels from rarer to denser medium and bends away from the normal when it travels from denser to a rarer medium. |
|
| 23. |
What happens when PCl5 is heated ? |
|
Answer» PCl5 → PCl3 + Cl2 |
|
| 24. |
Explain about the extent of reaction of dissociation of bromine mono chloride at 1000 K. |
|
Answer» 2BrCl(g) ⇌ Br2(g) + Cl2(g), KC = 5 10-3 < KC < 103 Both forward and backward reaction make significant progress. Neither forward nor reverse reaction predominates. |
|
| 25. |
What is the KC value of formation of HCI at 300 K? |
|
Answer» H2(g) - CI2(g) ⇌ 2HCl(g) at 300 K K2 = 4 x 1031 KC > 103 So [products] >> [Reactant] Reaction nearly goes to completion. So forward reaction is favoured. |
|
| 26. |
What is the KC value for formation of HCl at 700 K? Predict the extent of the reaction? |
|
Answer» H2(g) + I2(g) ⇌ 2HI(g) at 700 K KC = 57.0 10-3 < KC < 103 So both forward and backward reaction make significant progress. Neither forward nor reverse reaction predominates. |
|
| 27. |
How the reaction between sodium and water can be made less vigorous? |
|
Answer» By amalgamating sodium. |
|
| 28. |
Predict giving reason the outcome of the reaction, LiI +KF -----> |
|
Answer» LiI +KF ------>LiF +KI;Larger cation stabilizes larger anion. App |
|
| 29. |
Write short notes on Peptisation. |
|
Answer» Peptisation:- It is observed that freshly precipitated substances can often be redispersed into colloidal state by suitable reagents, generally with an ion in common with the material to be dispersed. Thus fresh precipitate of Re(OH)3 readily passes into colloidal form when treated with dil. FeCl3 solution. This process of transferrin back a precipitate into colloidal state is called Peptisation. The ferric chloride which has caused the dispersion is known as Peptising Agent. It the converse of coagulation and may be regarded as redispersion of coagulation sol. |
|
| 30. |
Write short notes on Coagulation. |
|
Answer» Coagulation:- The colloidal particle carry similar type of charge and thus due to mutual electrical repulsions are kept apart. But if this charge be somehow neutralized, the particles will come together to form large particles and hence precipitate out. "This precipitation of colloidal solution is known as Coagulation or Flocoulation." For example:- An addition of little barium chloride to a colloidal solution As2S3 the latter precipitates out. It is due to the fact that +vely charged Ba++ ions are attracted by -vely charged particles of As2S3 with the result that the charged of the latter gets neutralized. Thus robbed or their charge, the As2S3 particles gather together to form bigger aggregates and finally settle down in the form of a precipitate. |
|
| 31. |
Write short note on Cataphoresis or electrophoresis. |
|
Answer» Cataphoresis or Electrophoresis:- The particles of colloidal solution are electrically charged either +ve or -ve and hence when and electric current is passed through colloidal solution, the colloidal particles move towards opposite electrodes. On reaching the electrodes they get discharged and precipitate out. Thus a negatively charges sol like that of AS2S3 when taken in a U-tube the colloidal particles move towards +ve electrodes while positively charged sol. like that of Fe(OH)3 when taken in a U-tube the sol. particles move towards -ve electrode. "This movement of colloidal particle in electric field is known as Cataphoresis." |
|
| 32. |
What is cancer? What are three main types of cancer? |
|
Answer» Cancer starts in our cells. Cells are tiny building blocks that make up the body’s organs and tissues. Cells receive signals from the body, telling them when to grow and when to divide to make new cells. This is how our bodies grow and heal. These cells can become old, damaged or no longer needed. When this happens, the cell gets a signal from the body to stop working and die. Types of cancer: Carcinoma – cancer that begins in the skin or in tissues that line or cover internal organs. There are different subtypes, including adenocarcinoma, basal cell carcinoma, squamous cell carcinoma and transitional cell carcinoma. Sarcoma – cancer that begins in the connective or supportive tissues such as bone, cartilage, fat, muscle or blood vessels. Leukaemia – cancer that starts in blood forming tissue such as the bone marrow and causes abnormal blood cells to be produced and go into the blood. |
|
| 33. |
If the units of force, velocity and energy are 100 dyne, 10cm/sec and 400 ergs respectively, what will be the units of mass, length and time? |
|
Answer» F = 100 dyne = [MLT-2] V = 10 cm s-1 = [LT-1] E = 400 ergs = [ML2T-2] L = [ML2T-2]/[MLT-2] = [E]/[F] = 400/100 L = 4 cm [LT-1] = 10 ⇒ 4T-1 = 10 ⇒ T = 0.4 sec [MLT-2] = 100 ⇒ M 4 × (0.4)-2 = 100 ⇒ M = 4 gm |
|
| 34. |
The stereoisomens related to each other as non-superimposable mirror images are called:(A) diasteeromers(B) enantiomers(C) chiral compound(D) Racemic mixture |
|
Answer» Answer is (B) enantiomers |
|
| 35. |
Which of the following is harmful for vegetavbles?A. PAN B. FluorideC. Both A and B. D. CO2 |
|
Answer» C. Both A and B |
|
| 36. |
The stereoisomens related to each other as non-superimposable mirror images are called: (A) Diastereomers (B) Enantiomer (C) Chiral compound (D) Racemic mixture |
|
Answer» Correct Answer is: (B) Enantiomer Enantiomer, also known as optical isomers, are two stereoisomer that are related to each other by a reflection: they are mirror images of each other that are non-superposable |
|
| 37. |
Which of the following is harmful for vegetables? A. PAN B. Fluoride C. Both A and B. D. CO2 |
|
Answer» Correct Answer is: C. Both A and B. |
|
| 38. |
Chloroform on treatment with O2 in presence of light gives: (A) Phosgene (B) Phosgene (C) Phosphorescence (D) Methane |
|
Answer» Correct Answer is: (A) Phosgene Chloroform vapour slowly reacts with oxygen in the presence of light to generate phosgene, a highly toxic gas with a smell similar to freshly-cut grass. |
|
| 39. |
Which of the following is a heavy metal water pollutants?A. Nickel B. ArsenicC. Both A and B D. Phosphorus |
|
Answer» C. Both A and B |
|
| 40. |
Iodoform gives precipitate with silver nitrate but chloroform does not. Explain. |
|
Answer» C - I bond is much weaker than C - Cl bond. Therefore, when CHI3 is heated it gives I- ions which give a yellow precipitate of AgI when treated with AgNO3 solution. On the other hand C - Cl bond of CHCl3 does not break on heating to give Cl- ions and hence precipitate of AgCl is not formed when treated with AgNO3 solution. |
|
| 41. |
A three times magnified virtual image of an object kept at a distance of 24 cm from a convex lens is formed focal length of the lens is A) 72 B) 24C) 36 D) -12 |
|
Answer» The correct option is D) -12. Here Magnification "M" = 3 u= -8 cm as u (object distance) is always negative. M = -v/u 3 = -v/-8 3 = v/8 v (position of image)= 24 cm The image is formed in front of the mirror. By using lens mirror formula, focal length can be calculated. For focal length: 1/f = 1/u +1/v 1/f = 1/-8 + 1/24 1/f = 1/24 - 1/8 1/f =1/24 - 3/24 1/f = -2/24 = -1/12 f= -12 cm Hence the focal length of the lens is - 12 cm. |
|
| 42. |
Distinguish between spermatogenesis and oogenesis. |
|
Answer» Spermatogenesis 1. It occurs inside testis 2. All stages are completed inside testis. 3. It is a continuous process. 4. Spermatogonia develop from germinal epithelium lining the seminiferous tubules. 5. Some cells of the germinal epithelium function as support , also called sertoli cells. 6. All the spermatogonia divide to form spermatocytes. 7. Growth phase is short. 8. Primary spermatocyte divides by meiosis I to form two secondary spermatocytes. 9. Secondary spermatocyte divides by meiosis II to produce two spermatids. 10. A spermatocyte forms four spermatozoa. 11. Sperms are smaller than spermatocytes. 12. Nucleus undergoes condensation in the sperm. 13. Reserve food is little in the sperms. 14.It produces motile male gametes. Oogenesis 1. It occurs inside ovary. 2. Major part of oogenesis occurs inside ovary but last stages occur inside oviduct. 3. It is discontinuous process with early stages taking place in foetus and the rest later in life. 4. Oogonia develop from germinal epithelium overlying the ovary. 5. There is no such differentiation. 6. Only some oogoinia give rise to oocytes. 7. Growth phase is prolonged. 8. Primary oocyte undergoes meiosis I to form one secondary oocyte and one polar body 9. Secondary oocyte divides by meiosis II to form one ovum and one polar body. 10. A oocyte forms only one egg or ovum. 11. Eggs are larger than oocytes. 12. Nucleus remains uncondensed in the ovum. 13. Ovum collects a lot of reserve food and other biochemicals. 14. It forms non motile female gametes. |
|
| 43. |
Which of the following is a heavy metal water pollutant? A. Nickel B. Arsenic C. Both A and B D. Phosphorus |
|
Answer» Correct Answer is: B. Arsenic Examples of heavy metals include lead, mercury, cadmium, sometimes chromium. Less commonly, metals including iron, copper, zinc, aluminum, beryllium, cobalt, manganese and arsenic may be considered heavy metals. |
|
| 44. |
In young's double slit experiment, if the wavelength of light is doubled then fringe-width will be A) Equal B) Double C) Half D) one fourth |
|
Answer» The correct option is B) Double. As we know that the formula of fringe width is given as ω = λL/d Here we know that d = distance between two slits L = distance of slits from the screen λ = wavelength of the light Now from above formula we can see that the fringe width is directly depending on the wavelength of light So here if the wavelength of light is double then the fringe width must be double of initial value. |
|
| 45. |
Distinguish between SN1 and SN2 reaction. |
||||||||||
Answer»
|
|||||||||||
| 46. |
What type of lens would you use as a magnifying glass ? How close must the object be to the lens ? |
|
Answer» Convex lens The object must be withing the focus of the lens. |
|
| 47. |
Acid rain occurs is due to(A) CO and CO2(B) NO2 and SO2(C) CO2 and NO2(D) N2 and NO2 |
|
Answer» (B) NO2 and SO2 |
|
| 48. |
Which pollutant is responsible for Acid rain?A. SO2 B. CO2C. CO D. All of these |
|
Answer» The Correct option is A. SO2 |
|
| 49. |
Write two ores of Cu. |
|
Answer» Cu: (i) Cuprite - Cu2O (ii) Copper pyrites - CuFeS2 |
|
| 50. |
SiF62- is known but SiCl62- is not, why? |
|
Answer» Due to smaller size of F as compared to Cl, steric repulsions will be less in SiF62- than in SiCl62-. Because of smaller S-F bond as compared to S-Cl bond, the interaction of F lone pair of electrons with Si is stronger than that of Cl lone pairs. |
|