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The lowest possible temperature of 0 K (-273.15˚C) at which a gas is supposed to have zero volume (and zero pressure) and at which entire molecular motion stops is called absolute zero of temperature. The temperature scale which starts with -273.15˚C as its zero is called Kelvin scale or absolute scale. The size of degree on Kelvin scale is same as that on celsius scale.

Given: Area = 108m², Height = 3m

and Length of a cold storage is double its breadth

So, Let breadth of a cold storage = x

∴ length of the cold storage = 2x

Area of four walls = 108m²

∴ 2(l + b)× h = 108

⇒ 2 (x + 2x)×3 = 108

⇒ 6(3x) = 108

⇒ x = 108/18

⇒ x = 6

∴ Breadth of a cold storage = 6m

and Length of a cold storage = 2×6 = 12m

Hence, Volume of the cold storage = l × b × h

= 12 × 6 × 3

= 216m³

Given: Radius of base, r = 7cm

Height , h = 13.5cm

(i) Lateral Surface Area of right circular cylinder = 2πrh

= 2 x 22/7 x 7 x 13.5 

= 2×22×13.5

= 594cm²

(ii) Total Surface Area of cylinder = 2πrh + 2πr²

= 2πr(h + r)

= 2 x 22/7 x 7 (13.5 + 7)

= 2×22×20.5

= 902cm²

(iii) Volume of cylinder = πr²h

= 22/7 x 7 x 7 x 13.5

= 22×7×13.5

= 2079cm³

(C) same

Explanation:

Let the radius of a cylinder = r unit

Let the height of a cylinder = h unit.

According to question,

Radius is doubled = 2r

Height is halved = h/2

Then,

Curved surface area of a cylinder = 2 × π × r × h

And according to the above condition,

Curved surface area = 2 × π × 2 × r × h/2

= 2 × π × r × h

This is same as the curved surface area of the cylinder with radius r and height h.

Hence, option C is the correct answer.

Consider a right circular cone, with

Height = h

Radius = r

And slant height = l

We know, right triangle = one angle 90°

Using Pythagoras theorem in

⇒ l² = h² + r²

This justifies that height, radius and slant height of cone can always be the sides of a right triangle.

Hence, the given statement “in a right circular cone, height, radius and slant height do not always be sides of a right triangle” is true.

Correct option is (B) Halved

\(R=\frac r2\) and H = 2h

Then volume \(V=\pi R^2H\)

\(=\pi(\frac r2)^2\times2h\) \(=\frac{2\pi r^2h}4=\frac{\pi r^2h}2\)

Thus, volume will be halved.

Correct option is  B) Halved

Vijayanagara was located on the banks of the Tungabhadra River In Karnataka. It was founded by two brothers named Harihara Raya and Bukka Raya with the blessings of the sage Sri Vidyaranya in 1336 AD.

(C) 1336 A.D

(C) Vidyaranya

The answer is (c) Tapetum

The answer is (c) Nutrition

• The wall of pollen sac comprises of four layers: Epidermis, Endothecium, Middle layers and Tapetum. 
• Epidermis is followed by a single layer of Endothecium, 2-3 middle layers and a single layer of Tapetum. 
• Tapetum is the innermost layer of the anther wall which completely surrounds the sporogenous tissue. 
• Epidermis is outermost layer and provides protection. 
• Endothecium develops fibrous thickenings at maturity and help in anther dehiscence. 
• Middle layers store reserve food materials. 
• Tapetum nourishes the developing pollen grains.

The answer is (d) 25

• Meiotic divisions are responsible for gamete formation. 
• Pollen grains are microscopic bodies that contain the male reproductive cell of a plant. 
• 1 Meiosis produces 4 pollen grains. 
• Therefore to produce 100 pollen grains, 25 meiotic divisions are required.

• Tapetum cells provide nutrition for developing pollen. 
• Besides this, the tapetum cells deposit sporopollenin substance and help in the formation of the epidermal coat of pollen. 
• The importance of tapetum can be understood by the fact that if the tapetum degenerates before the formation of pollen grains, the pollen grains remain sterile or abortive.

• There are two types of tapetum in angiosperms. 
• These are amoeboid or plasmodial and secretory or glandular. 
• These provide nutrients to the pollen grains.

The monosporic embryo sac is eight puçleated.

Dengue fever is one such disease in which the number of platelets get reduced to as  low as 25-30 thousands per cubic mm of blood. The major symptoms of dengue are  high fever, rashes or red spots on body, nausea or vomiting, pain in abdomen, back, or  back of the eyes and muscles.

Difference between white blood cells and the red blood cells:

During surgical operation or an accident when excess of bleeding takes place, the patient may be given blood from outside to save his life. The transfer of blood from the donor to the recipient is called blood transfusion. 

The following precautions are taken before the blood is given to the needy person: 

1. Matching of the donor’s blood with that of the recipient should be done. 

2. It should be made sure clinically that blood of donor is free from any infection. 

3. Sterilization of all the instruments to be used during the operation is must.

(a) Citric acid

(a) butyric acid

1. The little boat. 

2. Personification. 

3. Very small in size. 

4. Metaphor. 

5. The smooth, pleasant and light movement of the boat.

The poet wanted to take the boat near a craggy ridge, but the sudden appearance of the huge, black peak unnerved him. The more he rowed the boat, the bigger the peak seemed to become in front of him. Soon it seemed to move with a measured step like a living being towards the poet. This made the poet turn back towards the rocky cave.

The boy takes away the boat without the permission of the owner of the boat.

Inside a rocky cave, tied to a willow tree.

The attraction of the boat to the boy is so much that it acquires a human presence in his mind.

In the beginning the children did not know whose garden it was. But after some days one day when the Giant came and stopped the children from playing there, they came to know that it was his.

Step 1:

Write the chemical equation from the given word equation.

CaCl₂ + H₂SO₄ → CaSO₄ + HCl

Step 2:

Write the number of atoms of each element in the unbalanced on both sides of equation.

Step 3:

In the given equation H₂SO₄ is a compound and it contains hygrogen element. On the left hand side there are two hydrogen atoms and on the right side one hydrogen atom. Equalise H atoms on both sides.

To equalise the number of hydrogen atoms we use 2 as the factor in the product so that the number of H atoms on both sides are equal. Therefore, the equation becomes

CaCl₂ + H₂SO₄ → CaSO₄ + 2 HCl

Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal hence, the balanced equation is

CaCl₂ + H₂SO₄ → CaSO₄ + 2 HCl

Now, indicate the physical state of the reactants and products.

CaCI_2(s) + H₂SO_4(I) → CaSO_4(s) + HCI_(I)

Step 1:

Rewrite the given equation as it is

N_2(g) + H_2(g) ⇌ NH_3(g)

Step 2:

Write the number of atoms of each element in the unbalanced equation on both sides of equations

Step 3:

In the given equation. NH₃ is a compound and it contains hydrogen element. On the left hand side there are two H atoms and on the right side 3H atoms. Equalise H atoms on both sides.

To equalise the number of hydrogen atoms, we use 3 as the factor in the reactant and 2 as the factor in the products. Now the equation becomes

N₂ + 3H₂ → 2NH₃

Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is

N₂ + 3H₂ → 2NH₃

Now indicate the physical states of the reactants and products

N_2(g) + 3H_2(g) ⇌ 2NH_3(g)

Its result was that the children did not enter the garden. But the spring also went away. There was only snow, frost, North wind and hail. The garden became desolated. So the Giant was not happy even after this.

Potassium permanganate is an oxidising agent. It oxidises dissolved iron, manganese and hydrogen sulphide into solid particles that are filtered out of the water tank. It is used to control iron bacteria growth in tank.

Silver nitrate is used in the voters-ink. It is used as reactant in the laboratory. Silver nitrate is used to prevent infection in wounds and skin burns.

Cycle:

• It is exhibited by all eutherian mammalian females except the order -primate.
• The mammalian females which exhibit one estrus cycle in one breeding season are called as monoestrous.
  Example: Dogs, Fox, Bats, Deer etc.
• The mammalian females which exhibit two or more oestrous cycles in one breeding season are called polyestrous.
  Example: Rat, squirrel, cow, pig, horse, cat, sheep rabbit etc.
• The oestrous cycle is studied with the help of vaginal smears.
• The duration of various phases of the oestrous cycle varies from species to species. In the rat, it is from 4 to 5 days and in the rabbit is 16 to 17 days.

The oestrous cycle has 4 phases –

1. Diestrus phase:

• It is also called as anestrus phase.
• It is the longest phase & its duration is of 60 to 70 hours.
• The ovary is without Graffian follicles.
• The uterine gland is thin, small & inactive.
• The vaginal smear shows leucocytes.
• During the non-breeding season, the female remains in the diestrus phase.

2. Proestrus phase:

• It is the smallest phase. Its duration is 1/2 to 5 hours.
• There is no growth of ovarian follicles.
• Vaginal smear exhibits epithelial cells.
• The uterine glands begin to increase in number & size.
• The thickness & contractability of the uterine wall begins to increase.

3. Oestrous phase:

• Its duration in the rat is 9 to 15 hours.
• It is also called a heat period.
• The basal temperature of the body is increased.
• Formation of Graffian follicles in the ovary.
• The vaginal smear shows the presence of cornified cells.
• The maximum level of estrogen in the blood.
• Ovulation takes place.

4. Post-Estrus or metestrus phase:

• Its duration is of 10 to 14 hours.
• The vaginal smear shows cornified cells & leucocytes.
• The maximum level of progesterone in the blood.
• Formation of Corpus luteum in the ovaries.
• If there is fertilization, the female remains in metestrus till the parturition.
• The oestrous cycle repeats if there is no fertilization and after parturition.

Oxytocin and Relaxin.

Progesterone and LH.

The answer is (b) 28 days

(a) 3 – 5 days

The answer is (c) Both of the above

Correct answer is (b) 28 days

The answer is Progesterone and LH.

(c) Both of the above

The answer is Oxytocin and Relaxin.

Oestrous phase:

• It is a phase of Menstrual cycle.
• Its duration in the rat is 9 to 15 hours.
• It is also called a heat period.
• The basal temperature of the body is increased.
• Formation of Graffian follicles in the ovary.
• The vaginal smear shows the presence of cornified cells.
• The maximum level of estrogen in the blood.
• Ovulation takes place.

(d) Oxytocin

The answer is (a) 3 – 5 days

Menstrual cycle and Estrus cycle.

Correct answer is (b) LH

(b) R explains A

(d) Sterilization → Inoculation → Incubation → Embryogenesis → Hardening

Endorsee

Explanation: On endorsement, the person in whose favour the bill is transferred (i.e. the holder’s creditor) is known as an endorsee.

Endorser

Explanation: The holder of a bill has an option to transfer the bill in favour of his/her creditor. In such cases, the person who transfers the bill is known as an endorser. Generally, a drawer is an endorser.