Explore topic-wise InterviewSolutions in Current Affairs.

Gate turn off Thyristor.

\(I_A=\frac{\propto_2I_G+I_{C_o}}{1-(\propto_1+\propto_2)}\)

Latching current is that current such that when anode current is greater than it, the thyristor will be in ON state.

Holding current is that current such that when anode current is less than it. the thyristor is turned OFF.

In ac circuit with resistive loads, turn off happens automatically during negative zero crossing of supply voltage. This is called natural or line commutation.

Forced commutation is the arrangement made with dc circuits to ensure an OFF condition.

Residential lamp dimmers, heater control.

Power diode.

One bidirectional semicondutor device is TRIAC.

correct answer is (D) TESTER 

Her father is a lawyer and her mother is a teacher.

Yes, she is good in her studies.

She has a younger brother. His name is Rohan.

(i) Main terminal 1(MT₁)

(ii) Main terminal 2(MT₂).

(iii) Gate

She helps with all my work. We study and play together. Mayura is my friend. She is 13 years old. She is 5 tall. She is tall. She has brown eyes. She has long, black hair. Mayura is my neighbour. Her father is a lawyer. Her mother is a teacher.

She has a younger brother. His name is Rohan. Mayura is good in her studies. She also likes sports and music. Mayura is kind, helpful and active. She helps me with all my work. We study and play together.

(B) The word CORRESPONDING contains all the letters of the word SUPERIOR except U. So, the word SUPERIOR can’t be formed.

correct answer is (D) 4 

(C) Sanjana’s new position is 25th from left. But it is the some as Mrudula’s earlier position which is 18th from the right. then the total number of girls are = (rank from left + rank from right - 1)

= (18 + 25) - 1 = 43 - 1 = 42.

(C) As per the question

2 8 2 8 3 8 5 8 8 5 3 2 8 2 3 8 4 7 1 5 8 3 8 2 8 6

Thus, three such numbers are there

(i) Gate

(ii) Drain

(iii) Source

correct answer is (C) Ecstasy. 

cute / beautiful / graceful / handsome

She is kind, helpful and very active.

study / study / housewife / businessman

crew-cut / short / long / short

Given sin^-1 (1/3) + cos^-1 x = π/2 

⇒ sin^-1 (1/3) = π/2 – cos^-1 x 

We know that sin^-1 x + cos^-1 x = π/2 

⇒ sin^-1 (1/3) = sin^-1 x 

∴ x = 1/3

Given sin^-1 (1/3) – cos^-1 (-1/3) 

We know that cos^-1 (-θ) = π – cos^-1 θ

\(=sin^{-1}(\frac{1}{3})-[\pi-cos^{-1}(\frac{1}{3})]\)

\(=sin^{-1}(\frac{1}{3})-\pi+cos^{-1}(\frac{1}{3})\)

\(=sin^{-1}(\frac{1}{3})+cos^{-1}(\frac{1}{3})-\pi\)

\(=\frac{\pi}{2}-\pi\)

\(=-\frac{\pi}{2}\)

\(\therefore sin^{-1}(\frac{1}{3})-cos^{-1}(\frac{1}{3})\)\(=-\frac{\pi}{2}\)

Given 4 sin^-1 x + cos^-1 x = π 

We know that sin^-1 x + cos^-1 x = π/2

\(\Rightarrow 4sin^{-1}x+\frac{\pi}{2}-sin^{-1}x=\pi\)

\(\Rightarrow 3sin^{-1}x=\pi-\frac{\pi}{2}\)

\(\Rightarrow 3sin^{-1}x=\frac{\pi}{2}\)

\(\Rightarrow sin^{-1}x=\frac{\pi}{6}\)

\(\Rightarrow sin^{-1}x=sin^{-1}\frac{1}{2}\)

∴ x = 1/2

Let sin^-1(3/5) = x and sin^-1(8/17) = y

Therefore  sinx = 3/5 and siny = 8/17

Now, cosx = √(1 - sin²x) = √(1 - (3/5)²) = √(1 - 9/25) = 4/5

and cosy = √(1 - sin²y) = √(1 - (8/17)²) = √(1 - 64/289) = 15/17

We have cos(x - y) = cosx cosy + sinx siny 

= 4/5 x 15/17 + 3/5 x 8/17 = 60/85 + 24/85 = 84/85

⇒ x - y = cos^-1(84/85)

⇒ sin^-1(3/5) - sin^-1(8/17) = cos^-1(84/85)

Let x = secθ, then θ = sec^–1x ………………… (i)

cot^-1(1/√(x² - 1)) = cot^-1(1/√(sec2θ - 1)) = cot^-1(1/√tan²θ)

= cot^-1 (1/tanθ) = cot^-1(cotθ) = θ = sec^-1x

अवकल समीकरण में उच्चतम अवकलज

d²y/dx²  जिसकी कोटि

कोटि 2 है।

अतः विकल्प (a) सही है।

(i) \(\overline{OP}\)= 4i - 2j + 5k

(ii) Then is perpendicular unit vector to the required plane is

\(\frac{\overline{OP}}{OP}=\frac{4i-2j+5k}{\sqrt{16+4+25}}\\=\frac{4i-2j+5k}{\sqrt{45}}\)

The perpendicular distance from the origin is

\(\sqrt{16+4+25}=\sqrt{45}\)

Vector equation of the Plane can be written as

\(\bar{r}.\bar{m}=d⇒\bar{r}.\frac{4i-2j+5k}{\sqrt{45}}\\=\sqrt{45}{}\)

⇒ \(\bar{r}.4i-2j+5k=45\)

Cartesian from is 4x – 2y + 5z = 45

(i) (c) \(\frac{4}{\sqrt3}\)

(ii) Equation of the plane passing through 

(1, 0, -2) is a(x – 1) + b(y – 0) + c(z + 2) = 0……………..(1)

 Plane (1) is perpendicular to the given planes 

2a + b – c = 0 ……………..(2)

 a – b – c = 0 ……………..(3)

Solving (2) and (3) we get;

\(\frac{a}{-2}=\frac{b}{1}=\frac{c}{-3}=k\)

a = -2k; b = k ; c = -3k

(1) ⇒ -2x + y - 3z - 4 = 0

⇒2x - y + 3z + 4 = 0

tan^-1x + cot^-1x = \(\frac{\pi}{2}\)

= tan(tan^-1x + cot^-1x)

= tan\(\frac{\pi}{2}\)= ∞ (not defined)

Bark: Ship 

Compass: Time range

(i) tan p = cosec C

Law of floatation states that a body will float in a liquid, if weight of the liquid displaced by the immersed part of the body is at least equal to or greater than the weight of the body. 

The height of the blood column in the human body is more at the feet than at the brain as since pressure is directly dependent on height of the column, so pressure is more at feet than at the brain. 

It is measured as the force acting on a unit length of a line imagined to be drawn tangentially anywhere on the free surface of the liquid at rest  

Angle of contact between a liquid and a solid is defined as the angle enclosed between the tangents to the liquid surface and the solid surface inside the liquid, both the tangents being drawn at the point of contact of liquid with the solid. It depends upon:- 

1) Upon nature of liquid and solid in contact 

2) The Medium which exists above the free surface of liquid.

Dipole moment of an electric dipole is defined as the product of one of the charges and the distance between the two charges. 

The net force on an electric dipole placed in a uniform electric field is Zero. 

An electric dipole is a set of two equal and opposite point charges separated by a small distance.

From the relation 

Δl = L_o∝ Δθ 

or, Δl ∝ Δθ   

In winter, the wires contract and hence become tight. They expand during summer and become slack.

Answer is J. S. Mill