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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your BITSAT knowledge and support exam preparation. Choose a topic below to get started.
| 501. |
Which of the following metal is obtained by the electro-metalluragy ? (a) Ag (b) Na (c) Fe (d) Pb |
| Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (b) Na</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Electro-metallurgy is done for chemically active and electropositive metals like Na.</span></span></p> | |
| 502. |
The correct formula of Borax is : (a) Na2B4O7⋅8H2O (b) Na2 [B4O5 (OH)4 ]⋅10H2O (c) Na2B4O7⋅4H2O (d) Na2 [B4O5 (OH)4 ]⋅8H2O |
| Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (b) Na<sub>2</sub> [B<sub>4</sub>O<sub>5</sub> (OH)<sub>4</sub> ]⋅10H<sub>2</sub>O</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Borax (sodium tetraborate decahydrate) Na<sub>2</sub>B<sub>4</sub>O<sub>7</sub>.10H<sub>2</sub>O. Borax occurs naturally as tincal. </span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Na<sub>2</sub>[B<sub>4</sub>O<sub>5</sub>(OH)<sub>4</sub>].8H<sub>2</sub>O = Na<sub>2</sub>B<sub>4</sub>O<sub>7</sub>.10H<sub>2</sub>O</span></span></p> | |
| 503. |
Potassium is kept in : (a) ammonia (b) alcohol (c) kerosene (d) water |
| Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (c) kerosene</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Potassium is kept in kerosene oil because potassium reacts with water, ammonia and alcohol.</span></span></p> | |
| 504. |
Why is an ammonia maser not useful in communication?(1) Because it has low power(2) Because itsfrequency is not convenient(3) Because the frequency is not stable(4) Because it is not continuous |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">The Correct option is (2) Because itsfrequency is not convenient</span></span></p> | |
| 505. |
At NTP, the ratio of molecules in 1cc of oxygen to that in 1cc of hydrogen is : (a) 1 : 1 (b) 1 : 4 (c) 1 : 16 (d) 1 : 2 |
| Answer» <p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (a) 1 : 1</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">From the formula, the number of molecules in V litres of gas at NTP is = NV/22.4</span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">It represents that at NTP, all the gases have same number of molecules in same volume. Hence, ratio of molecules in both cases is 1 : 1.</span></span></p> | |
| 506. |
The 15th term of (3 × 5) + (7 × 8) + (11 × 11) + . . . . is (1) 225 (2) 813 (3) 2773 (4) 3473 |
| Answer» <p></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option(3) 2773</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">The first factors are in A.P., so also the second factors. </span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">The fifteenth term of 3 × 5 + 7 × 8 + . . . is </span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">[3 + 14 × 4] [5 + 14 × 3] = 59 × 47 = 2773 </span></span></p> | |
| 507. |
Penetrating power of X-rays can be increased by : (a) increasing the potential difference between anode and cathode (b) decreasing the potential difference between anode and cathode (c) decreasing the current of cathode filament (d) increasing the current of cathode filament |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (a) increasing the potential difference between anode and cathode</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">We know that by increasing the potential difference between anode and cathode, X-rays having short wavelength will be produced which have more penetrating power.</span></span></p> | |
| 508. |
The sensitivity of a beam balance may be increased by (1) increasing the length of the beam (2) lowering the centre of gravity of the beam (3) decreasing the weight of the beam (4) increasing the number of divisions on the scale behind the pointer |
| Answer» <p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong><span style="font-size:11pt; line-height:115%">The Correct option is (2) lowering the centre of gravity of the beam </span></strong></span></span></p> | |
| 509. |
Threshold wavelength for sodium is 5 × 10−7 m. Photoelectric emission occurs for light of : (a) any wavelength (b) wavelength above 6 × 10−7 m (c) wavelength below 5 × 10−7 m (d) all frequency below 5 × 1014 Hz |
| Answer» <p class="MsoNormal" style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (c) wavelength below 5 × 10<sup>−7 </sup>m</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">For photoelectric emission, it is necessary that the wavelength of the incident light is less than threshold value. </span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">i.e., λ < λ<sub>0</sub> </span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Hence, the photo emission occurs for light of wavelength below 5 × 10<sup>−7</sup> m.</span></span></p> | |
| 510. |
In a transofrmer if the transfer of energy occurs at the same voltage, then the transformer is (1) current transformer (2) potential transformer (3) isolating transformer (4) step-up transformer |
| Answer» <p><span style="color:#000000"><strong><span style="font-family:Calibri,sans-serif; font-size:18px">The Correct Option is </span>(3) isolating transformer</strong></span></p> | |
| 511. |
In post office box, the graph of galvanometer deflection versus resistance R (pulled out of resistance box) for the ratio 100 : 1 is given as shown (due to unsuitable values of R, galvanometer shows deflection). The two consecutive values of R are shown in the Figure:The value of unknown resistance would be (1) 3.2 Ω (2) 3.24 Ω (3) 3.206 Ω (4) 3.2375 Ω |
| Answer» <p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>The Correct Option is (2) 3.24 Ω</strong></span></span></p><p style="text-align:justify"><span style="color:#000000; font-family:Arial, Helvetica, sans-serif"><strong>Explanation:</strong></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">For post office box (Wheatstone bridge), under balanced conditions</span></span></p> | |
| 512. |
Directions: In each of the following questions a capitalised word is followed by four words numbered 1 to 4. Choose the word that is most opposite to the meaning of the capitalised word and mark your answer in the appropriate place in your answer sheet.(a)PRODIGIOUS (1) portentous (2) astounding (3) usual (4) monstrous(b)GALLANT (1) brave (2) intrepid (3) valiant (4) cowardly(c)BEWITCH (1) charm (2) disillusionize (3) confound (4) embarrass |
| Answer» <p class="MsoNormal"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>The Correct option is </strong></span></span></p><p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(a) </strong>(3) usual </span></span></p><p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(b) </strong>(4) cowardly</span></span></p><p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(c) </strong>(2) disillusionize</span></span></p> | |
| 513. |
Directions:Each question below has a word capitalised followed by four words or phrases numbered 1 to 4. Choose the word that has nearly the same meaning as the capitalised word. (a)ENAMORED (1) wearing armour (2) charmed (3) modest (4) conceited(b)RECUMBENT (1) leaning (2) twisted (3) elected (4) bent(c)DISCURSIVE (1) discuss (2) curse (3) credence (4) digressive |
| Answer» <p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong><span style="font-size:11pt">The Correct option is </span></strong></span></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(a)(</strong>2) charmed</span></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(b)</strong>(1) leaning</span></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(c</strong>)(4) digressive</span></span></p> | |
| 514. |
Directions:Each question below has a word capitalised followed by four words or phrases numbered 1 to 4. Choose the word that has nearly the same meaning as the capitalised word. (a)CREDULOUS (1) easily deceived (2) unbelievable (3) suspicious (4) trusts(b) ACUITY (1) bitterness (2) sharpness (3) active (4) accept |
| Answer» <p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong><span style="font-size:11pt; line-height:115%">The Correct option is </span></strong></span></span></p><p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(a)</strong>(1) easily deceived</span></span></p><p><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>(b)</strong>(2) sharpness</span></span></p> | |
| 515. |
Match List-I (Polarization process) with List-II (Approximate frequency) and select the correct answer using the codes given below the lists.List-I (Polarization process)List-II (Approximate frequency)A. Electronic polarizationi 102 HzB. Ionic polarizationii 105 HzC. Orientation polarizationiii 1013 HzD. Space-charge polarizationiv 1015 Hz |
| Answer» <p></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong><span style="background-color:white">The Correct option is (2) iv iii ii i</span></strong></span></span></p><p></p> | |
| 516. |
Match the waveforms and the form factors (FFs). |
| Answer» <p><span style="color:#000000"><strong><span style="font-family:Calibri,sans-serif; font-size:18px">The Correct Option is </span>(4) 4 3 2 1</strong></span></p> | |
| 517. |
Directions: In each question you find a set of sentences arranged in a haphazard way. Choose the correct arrangement of sentences as indicated by the number to make a coherent paragraph. A. Knowledge of a wide and diversified vocabulary enables you to detect subtle differences in sentence meaning. B. A primary skill needed for good reading comprehension is the understanding of the meanings of individual words.C. A second reading skill to be developed is the ability to discover the central theme of the passage. D. For this reason, it is important that you familiarize yourself with as many words as possible. E. Although the central theme may vary from passage to passage, if can usually be found in the title or in the topic sentence. F. By making yourself aware of what the entire passage is about, you can relate what you read to the central theme. (1) BEACDF (2) BEDCAF (3) BEDAFC (4) BADCFE |
| Answer» <p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>The Correct option is (4) BADCFE</strong></span></span></p> | |
| 518. |
Directions:In each question you find a set of sentences arranged in a haphazard way. Choose the correct arrangement of sentences as indicated by the number to make a coherent paragraph.A. Some found work in transporting goods or selling them. B. Trade started from person to person, but grew to involve different towns and different lands. C. Trade encouraged specialization, which led to improvement in quality. D. Men also realized that different men could make different products. E. No doubt it started from a desire to have something different. F. Trade exists for many reasons. (1) FEDCBA (2) EFBCAD (3) DEAFBC (4) DFEBCA |
| Answer» <p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>The Correct option is (1) FEDCBA</strong></span></span></p> | |
| 519. |
The probable energy of electrons at absolute zero is called (1) fermi energy (2) emission energy (3) work function (4) potential energy |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">The Correct option is (1) fermi energy</span></span></p> | |
| 520. |
Read the following passage carefully and answer the questions given below the passage. Certain words/phrases in the passage are given in bold to locate them while answering some of the questions : A man may usually be known by the books he reads as well as by the company he keeps; for there is a companionship of books as well as of men and one should always live in the best company, whether it be of books or of men. A good book may be among the best of friends. It is the same today that it always was and it will never change. It is the most patient and cheerful of companions. It does not turn its back upon us in times of adversity or distress. It always receives us with the same kindness; amusing and interesting us in youth, comforting and consoling us in age.Which of the following statement is not ture ? (a) good books as well as good men always provide the finest company (b) we have sometimes to be patient with a book as it may bore us (c) a good book serves as a permanent friend (d) a good book never betrays us |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (b) we have sometimes to be patient with a book as it may bore us</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">According to passage, the statement— ‘We have sometimes to be patient with a book at it may bore us’ is not true because a book having good knowledge and informations may sometimes bore but it may worth something.</span></span></p> | |
| 521. |
If vector AB = k vector AC, where k is a scalar, then : (a) A, B, C are coincident (b) vector (AB, AC) have the same magnitude (c) A, B, C are coplanar (d) A, B, C are collinear |
| Answer» <p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (d) A, B, C are collinear</strong></span></span></p><p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">A, B, C are collinear if vector AB = k vector AC.</span></span></p> | |
| 522. |
Directions: In each question you find a set of sentences arranged in a haphazard way. Choose the correct arrangement of sentences as indicated by the number to make a coherent paragraph.A. However there is no absolute rule. B. Usually the topic sentence is found in the beginning of a paragraph. C. The term topic sentence is used to describe the sentence that gives the key to an entire paragraph. D. Read the whole passage first. Then try to decide which sentence comes closest to expressing the main point of the paragraph.E. Before you try to locate the topic sentence in a paragraph, remember that this technique depends upon reading and judgement. F. A writer may build his paragraph to a conclusion, putting the key sentence at the end. (1) EFDABC (2) CBAFED (3) DACFBE (4) CFDEBA |
| Answer» <p><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>The Correct option is (2) CBAFED</strong></span></span></p> | |
| 523. |
The most suitable material for making an LDR (Light dependent resistor) is a semiconductor material having (1) Eg >> hν (2) Eg > hν (3) Eg = hν (4) Eg << hν |
| Answer» <p></p><p class="MsoNormal"><span style="color:#000000"><strong><span style="background-attachment:initial; background-clip:initial; background-image:initial; background-origin:initial; background-position:initial; background-repeat:initial; background-size:initial; font-family:Arial,sans-serif">The Correct option is (4) E<sub>g</sub> << hν</span></strong></span></p><p class="MsoNormal"></p><p></p> | |
| 524. |
Silicon is not suitable for fabrication of light emitting diodes because it is (1) an indirect band gap semiconductor (2) a direct band gap semiconductor (3) a wide band gap semicoductor (4) a narrow band gap semiconductor |
| Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong><span style="font-size:18px">The Correct Option is </span>(1) an indirect band gap semiconductor</strong></span></span></p> | |
| 525. |
Read the following passage carefully and answer the questions given below the passage. Certain words/phrases in the passage are given in bold to locate them while answering some of the questions : A man may usually be known by the books he reads as well as by the company he keeps; for there is a companionship of books as well as of men and one should always live in the best company, whether it be of books or of men. A good book may be among the best of friends. It is the same today that it always was and it will never change. It is the most patient and cheerful of companions. It does not turn its back upon us in times of adversity or distress. It always receives us with the same kindness; amusing and interesting us in youth, comforting and consoling us in age.‘‘A man may usually be known by the books he reads’’ because : (a) books provids him a lot of knowledge (b) the books he reads affect his thinking and character (c) his selection of books generally reveals his temperament and character(d) his reading habit shows that he is a scholar |
| Answer» <p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (c) his selection of books generally reveals his temperament and character </strong></span></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align:justify"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">It is true that the selection of books by the readers generally reveal their temperament and character. </span></span></p><p style="text-align:justify"></p> | |
| 526. |
Read the following passage carefully and answer the questions given below the passage. Certain words/phrases in the passage are given in bold to locate them while answering some of the questions : A man may usually be known by the books he reads as well as by the company he keeps; for there is a companionship of books as well as of men and one should always live in the best company, whether it be of books or of men. A good book may be among the best of friends. It is the same today that it always was and it will never change. It is the most patient and cheerful of companions. It does not turn its back upon us in times of adversity or distress. It always receives us with the same kindness; amusing and interesting us in youth, comforting and consoling us in age.The statement ‘‘A good book may be among the best friend’’ in the middle of the passage, means that, (a) a good book can be included among the best friends of mankind (b) our best friends read the same good books (c) there can not be a better friend than a good book (d) books may be good friends, but not better than good man |
| Answer» <p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (a) a good book can be included among the best friends of mankind</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">According to passage, a good book can be included among the best friends of mankind because it gives a good company and sometimes good suggestions. </span></span></p> | |
| 527. |
Read the following passage carefully and answer the questions given below the passage. Certain words/phrases in the passage are given in bold to locate them while answering some of the questions : A man may usually be known by the books he reads as well as by the company he keeps; for there is a companionship of books as well as of men and one should always live in the best company, whether it be of books or of men. A good book may be among the best of friends. It is the same today that it always was and it will never change. It is the most patient and cheerful of companions. It does not turn its back upon us in times of adversity or distress. It always receives us with the same kindness; amusing and interesting us in youth, comforting and consoling us in age.Which one of the following would be the most suitable title for the passage ? (a) books are useful for our youth (b) books as man’s abiding friends (c) books show the reader’s character (d) the importance of books in old age |
| Answer» <p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (b) books as man’s abiding friends</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">The most suitable title of the passage is ‘‘books are man’s abiding friends’’.</span></span></p> | |
| 528. |
The value of ΔHO—H is 109 kcal mol−1 . Then formation of one mole of water in gaseous state from H (g) and O (g) is accompained by : (a) absorption of 218 kcal of energy (b) release of 218 kcal of energy (c) release of 109 kcal of energy (d) unpredictable |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (b) release of 218 kcal of energy</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">In water 2(O—H) bonds are formed. </span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">So the value of ΔH for the formation of one mole of water in gaseous state is </span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">ΔH = −2 × 109 = −218 kcal</span></span></p> | |