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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following is electron deficient? a) PH3 b) (CH3)2 c) BH3 d) NH3 |
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Answer» (BH3)2 is electron deficient among. |
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| 2. |
Directions : Each of these questions contain two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion.(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion(c) Assertion is correct, reason is incorrect(d) Assertion is incorrect, reason is correct.Assertion : N2 is less reactive than P4.Reason : Nitrogen has more electron gain enthalpy than phosphorus |
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Answer» (c) Assertion is correct, reason is incorrect |
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| 3. |
Xe cannot form XeF3 , XeF5 type of compound. Why? |
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Answer» The electronic configuration of Xe is 5s2 5p6 . So, all the electrons are paired up and when it is excited, then either 2, or 4 or 6 etc. electrons will be unpaired .There is no scope to get odd number of unpaired electrons in its outer most shell. For this reason it cannot form XeF3 or XeF5 type of compound. |
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| 4. |
Alkali metals are characterized by: (a) good conductor of heat and electricity (b) high oxidation potentials (c) high melting points (d) solubility in liquid ammonia |
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Answer» (a) good conductor of heat and electricity (b) high oxidation potentials (d) solubility in liquid ammonia |
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| 5. |
White phosphorus (P4) has (a) six P-P single bonds (b) four P-P single bonds (c) four lone pairs of electrons (d) PPP angle of 600 |
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Answer» (a) six P-P single bonds (c) four lone pairs of electrons (d) PPP angle of 600 |
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| 6. |
The pairs of compound which cannot exist together in aqueous solution are (a) NaH2PO4 and Na2HPO4 (b) Na2CO3 and NaHCO3 (c) NaOH and NaH2PO4 (d) NaHCO3 and NaOH |
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Answer» (c) NaOH and NaH2PO4. (d) NaHCO3 and NaOH |
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| 7. |
Highly pure dilute solution of sodium in liquid ammonia : (a) shows blue colour (b) exhibits electrical conductivity (c) produces sodium amide (d) produces hydrogen gas |
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Answer» (a) shows blue colour (b) exhibits electrical conductivity |
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| 8. |
Given that the CO2-3 anion is approximately the same size as the early Group I cations, what would occur if Na2CO3 were heated ? (a) It would decompose to yield Na2 (b) It would decompose to yield Na2CO2 (c) It would decompose to yield NaOH (d) No decomposition would occur |
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Answer» (d) No decomposition would occur |
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| 9. |
Ammonia, on reaction with hypochlorite anion, can form (a) NO (b) NH4Cl (c) N2H4 (d) HNO2 |
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Answer» Ammonia, on reaction with hypochlorite anion, can form N2H4 . |
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| 10. |
100 mL of `PH_(3) on decomposition produced phosphorus and hydrogen. The change in volume is :-A. 50 mL increaseB. 500 mL decreaseC. 900 mL decreaseD. nil |
| Answer» Correct Answer - A | |
| 11. |
Maximum deviation from ideal gas is expected fromA. `H_(2)(g)`B. `N_(2)(g)`C. `CH_(4)(g)`D. `NH_(3)(g)` |
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Answer» Correct Answer - D Easily liquefiable gases like `NH_(3),SO_(4)`, etc ., exhibit maximum deviation from ideal gas as for them `Z lt lt lt 1.CH_(4)` also exhibits deviation but it is less as compared to `NH_(3)` but permaent gases like `H_(2) ,N_(2)` cannot be liquefied , thus shown no deviation . |
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| 12. |
The number of atoms in 0.1 mol of a triatomic gas is:A. `6.026xx10^(22)`B. `1.806xx10^(23)`C. `3.600xx10^(23)`D. `1.800xx10^(22)` |
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Answer» Correct Answer - B Number of atoms = number of moles `xxN_(A)xx` atomicity `=0.1xx6.023xx10^(23)xx3` `=1.806xx10^(23)` atoms |
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| 13. |
How many of the given compounds will give a positive Biuret test ______ ? Glycine, Glycylalanine, Tripeptide, Biuret |
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Answer» Correct answer is 2 Biuret test is given by all proteins and peptides having atleast two peptide linkages. Hence positive test must be given by tripeptide and Biuret. |
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| 14. |
Peroxodisulphate salts, `(e.g., Na_(2)S_(2)O_(8))` are strong oxidizing agents used be bleaching agents for fats, oils, ets. Given `:` `O_(2)(g)+4H^(o+)(aq)+4e^(-)rarr 2H_(2)O(l)" "E^(c-)=1.23V` `S_(2)O_(8)^(2-)(aq)+2e^(-)rarr 2SO_(4)^(2-)(aq)" "E^(C-)=2.01V` Which of the following statement is `(` are `)` correct ?A. Oxygen gas can oxidize sulphate ion to per-oxo disulphate ion `(S_2O_8^(-2))` in acidic solution.B. `O_2(g)` is reduced to waterC. Water is oxidised to `O_2`D. `S_2O_8^(-2)` ions are reduced to `SO_4^(-2)` ions. |
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Answer» Correct Answer - CD Create a cell with required cell reaction `O_2 +SO_4^(-)2 to S_2O_8^(-)2+H_2O " " E_(cell)^@=1.23-2.01 lt0` `implies` Nonspontaneous cell reaction |
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| 15. |
Statement-1: Cl of Al(Al2Cl6) and Be(BeCl2) form bridged structure and acts as Lewis base Statement-2: Hydrolysis of aluminium and beryllium reacts with excess of alkalis to give beryllate and aluminate ion(a) Both statement 1 and 2 are correct (b) Statement 1 is correct but statement 2 is incorrect (c) Statement 1 is incorrect but statement 2 is correct (d) Both statement 1 and 2 are incorrect |
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Answer» (c) Statement 1 is incorrect but statement 2 is correct Beryllium hydroxide dissolves in excess of alkali to give a beryllate ion, [Be(OH)4]2- just as aluminium hydroxide gives aluminate ion, [AI(OH)4]-. The chlorides of both beryllium and aluminium have Cl- bridged chloride structure in vapour phase. Both the chlorides are soluble in organic solvents and are strong Lewis acids. They are used as Friedel Craft catalysts. |
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| 16. |
Statement I: Chlorides of both beryllium and aluminium have CI bridged chloride structure in vapour phase and both are lewis bases.Statement II: Beryllium and aluminium hydroxides dissolve in excess of alkali to give beryllate and aluminate ions.(1) Both Statement I & Statement II are true(2) Statement I is true & Statement II is false(3) Statement I is false & Statement II is true(4) Both Statement I& Statement II are false |
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Answer» Correct option is (3) Statement I is false & Statement II is true The chlorides of both beryllium and aluminium have Cl- bridged chloride structure in vapour phase. Both the chlorides are soluble in organic solvents and are strong Lewis acids. Beryllium hydroxide dissolves in excess of alkali to give a beryllate ion, [Be(OH)4]2- just as aluminium hydroxide gives aluminate ion, [Al(OH)4]-. |
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| 17. |
Statement-1:Beryllium resembles aluminium. Statement-2: Charge/radius ratio of `Be^(2+)` ion is nearly the same as that of the `Al^(3+)` ion.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - A Beryllium and aluminium have diagonal relationship. |
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| 18. |
Wolframite `(FeWO_(2))` present as an inpurity in cassiteric `(SaO_(2))` can be removed by the process ofA. zone refiningB. gravity separationC. electromagnetic separationD. froth flotation separation |
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Answer» Correct Answer - c Electronomagnetic separaration can be used for separation when compound elther the one or tempurity is magnitude is nature .Wolfratent`(FeWO_(2) MnWO_(4))` is major magnetic ore ,is separated from the notunagnetic ore, cassierric `(SaO_(2))` by this method . |
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| 19. |
Sodium hydride when dissolved in water produces(1) acidic solution (2) basic solution (3) neutral solution (4) cannot be predicted |
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Answer» (2) basic solution |
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| 20. |
The best water soluble hydroxide is(1) Ca(OH)2 (2) Mg(OH)2 (3) Ba(OH)2 (4) Sr(OH)2 |
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Answer» (3) Ba(OH)2 |
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| 21. |
which of the following statement is incorrect? (1) pure sodium metal dissolves in liquid ammonia to give blue solution.(2) Aluminium reacts with excess of NaOH to give Al(OH)3 (3) NaOH reacts with glass to give sodium silicate. (4) NaHCO3 on heating gives Na2CO3 |
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Answer» (2) Aluminium reacts with excess of NaOH to give Al(OH)3 |
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| 22. |
The alkali halide that is soluble in Pyridine is(1) NaCl (2) LiCl (3) KCl (4) CsI |
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Answer» The alkali halide that is soluble in Pyridine is LiCl |
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| 23. |
`Aunderset(Delta)overset(.^(-)OH)rarr1-"Acetyl-1-Cyclopentene"`. A will beA. 6-OxoheptanalB. 5-OxohexanalC. Heptan -2, 6-dioneD. Heptandial |
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Answer» Correct Answer - D `ln"K"=(DeltaS^(0))/(R )- (DeltaH^(0))/(RT)` `(DeltaS^(o))/(R)=-2 " "(DeltaH^(o))/(R )=1200` `DeltaG^(o)=1200R+400xx2R=2000R` |
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| 24. |
किसी रेजीमेण्ट में युद्ध से पहले अफसरों का जवानो का अनुपात `3:31` था। युद्ध में 6 अफसरों और 22 जवान मारे गए और यह अनुपात `1:13` हो गया। युद्ध से पहले रेजिमेन्ट में अफसरों की संख्या क्या थी ?A. 31B. 38C. 21D. 28 |
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Answer» Correct Answer - C Let the no. of officers and soliders `= 3x,31x` According to the questions `(3x - 6)/(31x - 22)=(1)/(33)` `39 x - 78 = 31 x -22` `8x = 56` `x=7` So, No. of officer before `=3x = 3 xx 7 =21`. |
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| 25. |
एक व्यक्ति रू10,000 के कुछ भाग को 5% तथा शेष भाग को 6% ब्याज दर पर निवेश करता है। 5% की दर पर निवेश किया गया भाग, 6% की दर पर निवेश किए गए भाग से 76.50 रुपये अधिक अर्जित करता है, तो 6% की दर पर कितना रुपया निवेश किया गया था ?A. रु 3,600B. रु 3,500C. रु 3,850D. रु 4,000 |
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Answer» Correct Answer - c (c ) Let the part investedon 5% = Rs. X Remaining part = Rs. ( 10,000- x) According to the question, `(x xx5)/100-((10000-x)x6)/100=76.50` `(5x)/100-600+(6x)/100=76.50` `(11x)/(100)=76.50+600` `(11x)/(10)=676.50` `rArrx=67650/11` `rArrx=6150` Amount invested on 6% = (10,000-6150) = Rs. 3850 Alternate : In such type of questions to save your valuble time go through options. (नोटः इस तरह के प्रश्नो में अपने बहुमूल्य समय के बचत के लिए आप विकल्पों की सहायता ले सकते है।) Option (c ) Amount spend on 6% = 3850 Interest `=(3840xx6)/100=Rs.231` Amount speed on `5%=(10000-3850)=Rs.6150` Interest `=(6150xx5)/100=307.50` Difference in interest = (307.50-231) = Rs. 76.50 Now option (c ) satisfy both the conditions. Hence option (c ) is correct. |
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| 26. |
एक संख्या को 25% घटा दिया जाता है तो वह संख्या 225 हो जाती है । इस संख्या में कितने प्रतिशत की वृद्धि की जाए की यह संख्या 375 हो जाए ?A. `25%`B. `30%`C. `35%`D. `75%` |
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Answer» Correct Answer - a (a) Let the number = x According to the question `(x x(100-25))/(100)=225` `x=(225xx100)/(75)=300` Required percentage `=((375-300))/(300)xx100` = 25% |
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| 27. |
यदि P का P %, 36 है तो P किसके बराबर है ?A. 3600B. 600C. 60D. 15 |
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Answer» Correct Answer - c (c ) According to the question (प्रश्नानुसार), `Pxx(P)/(100)=36` `rArrP^(2)=3600rArrP=60` |
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| 28. |
किसी सेना के 10% जवान युद्ध में शहीद हुए शेष 10% जवान रोगग्रस्त हो कर मर गए और शेष से 10% को अशक्त घोषित कर दिया गया। इस प्रकार सेना में सक्रिय जवानो की संख्या 7,29,000 रह गई। बताइए मूल रूप से सेना में कितने जवान थे ?A. 1500000B. 1000000C. 1200000D. 1100000 |
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Answer» Correct Answer - b (b) `10%to 1/10` `{:(10%,to,9,"in war"),(10 ,to,9, "in disease"),(10,to,9,"disabled"),(100,,,729):}` 729 `to` 729 000 1 `to` 1000 1000 `to` 1000 `xx` 1000 = 1000000 |
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| 29. |
यदि x का 8%, y के 4% के बराबर है, तो x का 20% किसके बराबर होगा ?A. 10% of yB. 16% of yC. 80% of yD. 50% of y |
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Answer» Correct Answer - a (a) According to the question (प्रश्नानुसार), `rArr(8)/(100)x=(4)/(100)y` `rArr2x=y` `rArrx=y/2` `rArr20%"of" x=(20)/(100)xxy/2=y/10` Required (अभीष्ट) `%=y/10xx100` = 10% of y. |
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| 30. |
2,50 का कितना प्रतिशत है ?A. `2%`B. `2.5%`C. `4%`D. `5%` |
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Answer» Correct Answer - c ( c) Rrquired `%=(2)/(50)xx100=4%` |
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| 31. |
यदि वृत्त की त्रिज्या 5% तक बढ़ा दी जाए तो उसके क्षेत्रफल में कितना वृद्धि होगी ?A. `10.25%`B. `5.75%`C. 0.1D. 0.05 |
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Answer» Correct Answer - a (a) Quicker approach (तीव्र विधि) `uarr "in"A =a+b+(ab)/(100)` Here a=b=5% `uarr "in"A = (5+5+(5xx5)/100)` = 10.25% |
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| 32. |
900 अधिकतम अंको में से A ने एक विषय में 72% अंक प्राप्त किए और दूसरे विषय में अधिकतम 700 अंक में से 80% अंक प्राप्त किए। यदि परिणाम दोनों विषयो की सम्मिलित प्रतिशतता पर आधारित हो तो बताइए सम्मिलित प्रतिशतता क्या है ?A. `77.5%`B. `76%`C. `76.5%`D. `77%` |
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Answer» Correct Answer - a (a) `900xx72%=648` `700xx82%=560` Total scored marks = 1208 = % combined marks `=1208/((900+700))xx100=75.5%` |
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| 33. |
राम अपने वेतन का 14% बचत करता है जबकि श्याम अपने वेतन का 22% बचत करता है। यदि दोनों को बराबर वेतन मिलता है और श्याम 1540 रू बचत करता है, तो राम कितना बचत करता है ?A. रू 990B. रू 980C. रू 890D. रू 880 |
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Answer» Correct Answer - b (b) Salary of shyam `=1540/22xx100=Rs.7000` According to the question, Salary of Ram = Salary of shyam Hence salary of Ram =m Rs. 7000 Savings of Ram `=7000xx10/100=Rs.900` |
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| 34. |
यदि m का 10%, n के 20% के बराबर है तो m : n का मान क्या होगा ?A. `2:1`B. `1:2`C. `1:10`D. `1:20` |
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Answer» Correct Answer - a (a) According to the question (प्रश्नानुसार), `(10)/(100)xxm=(20)/(100)xxn` `m/n (20)/(10)=2/1` m : n = 2 : 1 |
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| 35. |
इस वर्ष रमन के वेतन में 5% की बढ़ोतरी हुई । यदि उसका वर्तमान वेतन रू1,806 है, तो पिछले वर्ष उसका वेतन कितना था ?A. रू1720B. रू1620C. रू1520D. रू1801 |
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Answer» Correct Answer - a (a) Required last year salary (पिछले अंतिम वर्ष में अभीष्ट वेतन) `=1806/((100+5))xx1400=Rs. 1720` |
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| 36. |
एक चुनाव में दो उम्मीदवार है 75% मतदाताओं ने वोट डाले, जिसमे से 2% वोट अवैध घोषित कर दिए गए, एक उम्मीदवार को 9261 वोट मिले जो वैध वोटो का 75% है, तो चुनाव में कुल कितने मतदाता है?A. 16000B. 16400C. 16800D. 18000 |
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Answer» Correct Answer - c (c ) Total valid votes got candidates = `=9261/75xx100=12348` Let total number of votes = x Total votes polled `=x xx75/100` `=(75x)/100` Valid votes `=(75x)/100xx98/100` According to the question (प्रश्नानुसार), `(75x)/100xx98/100=12348` Hence, thtal votes = 16800 Alternate Note: In such type of quwstion try to write the statement in one line. (नोटः इस तरह के प्रश्नो में कथनो में एक पंक्ति में लिखने का प्रयास करे।) Let total votes = x `x xx75/100xx98/100=9261/75xx100` x = 16800 Hence required number of total votes = 16800 |
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| 37. |
जल कर में 20% की वृद्धि हुई लेकिन उसकी खपत 20% कम हुई है। तो धन के खर्च में वृद्धि या कमी कितनी हुई ?A. 4% increase/ वृद्धिB. 4% decrease कमीC. no change / कोई परिवर्तन नहींD. 5% decrease/ कमी |
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Answer» Correct Answer - b (b) Shortcut method (संक्षिप्त विधि) `rArr+20%-20%-(20xx20)/(100)=-4 `rArr 4%` Decreace |
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| 38. |
एक परीक्षा में तीन विषय है और प्रत्येक का अधिकतम अंक 100 है। एक छात्र पहले विषय में 60% तथा दूसरे विषय में 80% अंक प्राप्त करता है । उसे कुल 70% अंक प्राप्त होते है, तो तीसरे विषय में उसे कितने प्रतिशत अंक प्राप्त हुए ?A. 80B. 60C. 65D. 70 |
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Answer» Correct Answer - d (d) According to the question, First subject = 60% Second subject = 80% Aggregate in all subject = 70% Sum of all those subject = 3`xx`70=210 `therefore` First + Second + Third = 210 60 + 80 + Third = 210 Third = 210 - 140 = 70 |
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| 39. |
एक विद्यालय में लड़के तथा लड़कियों का योग 150 है। यदि लड़को की संख्या x है, तो लड़कियों की संख्या लड़के तथा लड़कियों की कुल संख्या का x% हो जाता है, तो लड़को की संख्या ज्ञात करे ?A. `90`B. `75`C. `25`D. `60` |
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Answer» Correct Answer - d (d) Number of boys (लड़को की संख्या) = x Number of boys (राम) = (150-x) According to the question (प्रश्नानुसार), `rArr1510xx x/100=(150-x)` `rArr3x = 300-2x` `rArr5x =300` `rArr` x = 60 Hence, the required number of boys (लड़को की अभीष्ट संख्या) = 60 |
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| 40. |
एक कक्षा में 72% छात्र जीव-विज्ञान तथा 44% छात्र गणित का चयन करते है । यदि प्रत्येक छात्र ने जीव-विज्ञान तथा गणित में से कम से कम 1 विषय लिया हो और 40 छात्रों ने दोनों विषय लिए हो, तो कक्षा में कुल कितने छात्र है ?A. `200`B. `240`C. `250`D. `320` |
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Answer» Correct Answer - c (c ) Percentage of students took biology = 72% Percentage of students took Mathematics = 44% Percentage of studehnts took both subjects = (72 + 44) -100 = 16% According to the question, Total number of students `=40/16xx100=250` |
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| 41. |
एक छात्र के पास होने के लिए कुल अंक का 33% अंक प्राप्त करना है उसे कुल अंक का 25% अंक प्राप्त है तो वह 40 अंक से असफल हो जाता है, तो कुल अंक क्या है ?A. `800`B. `300`C. `500`D. `600` |
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Answer» Correct Answer - c (c ) Let the total marks = x According to the question (प्रश्नानुसार) `=x xx33/100=x xx20/100=40` `1/100[33x-25x]=40` `rArr 8x = 40xx100` `rArr` x = 500 Marks obtained = 25% Required marks to be pass = (33-25) = 8% According to the question (प्रश्नानुसार) 8% of total marks = 40 Total marks (100%) `=40/8xx100=500` |
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| 42. |
विद्यालय में 90% छात्र अंग्रेजी में, 85% छात्र गणित में सफल होते है। 150 छात्र दोनों विषयो में सफल होते है। यदि कोई भी छात्र दोनों में विषयो में असफल नहीं होता है, तो छात्रों की कुल संख्या क्या है ?A. `120`B. `220`C. `200`D. `300` |
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Answer» Correct Answer - c (c ) Percentage of passed students in both subjects (दोनों विषयो में उत्तीण छात्रों का प्रतिशत) = (90 + 85) - 100 = 75% According to the question, Total number of students `=150/75xx100=200` |
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| 43. |
5:4 के अनुपात को प्रतिशत में कितना लिखा जाएगा ?A. 1.25B. 0.8C. 0.4D. `12.5%` |
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Answer» Correct Answer - a (a) Required % (अभीष्ट%) `=5/4xx100=125%` Always write a : b in% `rArra/bxx100` |
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| 44. |
रू10000 के `33(1)/(3)%` का कितना होगा ?A. Rs. 5B. Rs. 150C. Rs. 0.05D. Rs.105 |
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Answer» Correct Answer - a (a) Required answer (अभीष्ट उत्तर) `10000xx(1)/(3)xx(15)/(100xx100)=5` |
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| 45. |
A अपने मासिक वेतन का 20% बचत करता है। यदि उसका मासिक खर्च र6000 है, तो उसकी मासिक बचत क्या है ?A. Rs. 1,500B. Rs. 1,800C. Rs. 1,200D. Rs. 4,800 |
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Answer» Correct Answer - a (a) Let the salary = 100 units savings = 20% savings `=100xx20/100=20` units Expenditure = (100-20) = 80 units According to the question, 80 units = Rs. 6000 1 unit = Rs. 75 Saving = 75 `xx` 20 = Rs. 1500 |
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| 46. |
एक फैक्ट्री में 2 वर्षो में साईकिल का उत्पादन 40,00 से बढ़कर 48,400 हो गया तो वार्षिक वृद्धि दर ज्ञात करे ।A. `10.5%`B. `9%`C. `8%`D. `10%` |
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Answer» Correct Answer - d (d) The production of cycles rose to 48,400 from 40,00 in 2 years (2 वर्षो में साईकिल का उत्पादन 40,000 से बढ़कर 48,400 हो गया।) `rArr` Present production = 40,000 `rArr` After two years = 48,000 `rArr` Time = 2 years Rate of increasement = ? According to the question, Producion after 2 years = Present production `(1+R/100)` `rArr484/400=(1+R/100)^(2)` `rArr1R/100=22/20` `rArrR/100=1/10` `rArrR= 10%` `rArr` Rate of increasement = 10% |
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| 47. |
यदि मोहन की आय महेश से 150% अधिक हो तो बताइए की महेश की आय मोहन से कितने प्रतिशत कम है ?A. `40%`B. `50%`C. `60%`D. `45%` |
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Answer» Correct Answer - c (c ) Let mahesh income = 100 than, Mohan Income = 100 + `(100xx150)/(100)=250` Required precentage `=(250-100)/(250)xx100=(150)/(250)xx100` = 60 % |
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| 48. |
एक व्यक्ति का 2007 में वार्षिक वेतन रु 8,80,000 था, जो 2006 में उसके वार्षिक वेतन से 10% अधिक था, तो 2006 में उसका वेतन क्या था ?A. रु4,80,000B. रु8,00,00C. रु4,00,000D. रु8,40,000 |
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Answer» Correct Answer - b (b) Salary in 2006 `= 880000/110xx` 100=Rs.8,00,000 |
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| 49. |
राम अपने वेतन का 40% भोजन पर, 20% घर के किराए पर, 10% मनोरंजन पर, और 10% यातायात पर खर्च करता है। यदि महीने के अंत में उसकी बचत रु1500 है तो उनका मासिक वेतन कितना है ?A. रु 500000B. रु 40000C. रु 30000D. रु 20000 |
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Answer» Correct Answer - b (b) Expenditure (खर्च) Food (खाना) `to` 40% House Rent (घर का किराया) `to 20%` Entertainment (मनोरंजन) `to 10%` Cnveyance (यातायात) `to10%` Total expenditure (कुल खर्च)= 80% Savings = 100% - 80% = 20% 20% `to` 1500 `1%to1500/20` Salary `(100%)to1500/20xx100` = Rs. 7500 |
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| 50. |
एक जिले में 64000 निवासी है। यदि जनसँख्या वृद्धि दर `2(1)/(2)%` वार्षिक हो, तो ३ वर्ष के अंत में जिले में कितने निवासी होंगे ?A. 70000B. 69200C. 68921D. 68911 |
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Answer» Correct Answer - c (c ) `2(1)/2%=/52%1/40= (41)/40{:(to"Final"),(to"Initial"):}` `({:("Initial Population","Final Population"),(40,41),(40,41),(40,41):})/{:(64000" ",68921" "):}` Hence required population = 68921 |
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