This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
months=['dec'.'jan'.'feb'.'mar']atendence=[70,90,75,95]pli.plot(months.attendence)plt.show() |
|
Answer» matplotlib. pyplot is a collection of command style functions that make matplotlib work like MATLAB. Each pyplot function makes some change to a figure: e.g., creates a figure, creates a plotting area in a figure, plots some lines in a plotting area, decorates the plot with labels, etc. |
|
| 2. |
Write one advantage and one disadvantage of using optical fiber cable |
|
Answer» Advantages of Optical Fiber Cheap—Long, continuous miles of optical fiber cable can be made cheaper than equivalent lengths of copper wire. With numerous vendors swarm to compete for the market share, optical cable price would sure to drop. Thinner and light-weighted—Optical fiber is thinner, and can be drawn to smaller diameters than copper wire. They are of smaller size and light weight than a comparable copper wire cable, offering a better fit for places where space is a concern. Higher carrying capacity—Because optical fibers are much thinner than copper wires, more fibers can be bundled into a given-diameter cable. This allows more phone lines to go over the same cable or more channels to come through the cable into your cable TV box. Less signal degradation—The loss of signal in optical fiber is less than that in copper wire. Light signals—Unlike electrical signals transmitted in copper wires, light signals from one fiber do not interfere with those of other fibers in the same fiber cable. This means clearer phone conversations or TV reception. Long lifespan—Optical fibers usually have a longer life cycle for over 100 years. Disadvantages of Optical Fiber Low power—Light emitting sources are limited to low power. Although high power emitters are available to improve power supply, it would add extra cost. Fragility—Optical fiber is rather fragile and more vulnerable to damage compared to copper wires. You’d better not to twist or bend fiber optic cables too tightly. Distance—The distance between the transmitter and receiver should keep short or repeaters are needed to boost the signal. |
|
| 3. |
If `(a)/(2b) = (c )/(d) = (e )/(3f)`, then the value of `(2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f)/(32b^(6)+12b^(2)d^(2)-405f^(5))` isA. `(a^(4))/(16b^(4))`B. `(16c^(4))/(d^(4))`C. `(e^(4))/(27f^(4))`D. `(81c^(4))/(d^(4))` |
|
Answer» Correct Answer - A If `(a)/(2b) = (c )/(d) = (e )/(3f)` , then ……….. `(a)/(2b) = (c )/(d) = (e )/(3f) = x` (left) `implies a = 2bx, c = dx, e = 3fx` Now, `N r. = 2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f` `= 2(2bx)^(4)b^(2)+3(2bx)^(2) (dx)^(2) - 5(3fx)^(4)f` `(32b^(6)+12b^(2)d^(2)-405f^(5))xx4` now `(2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f)/(32b^(6)+12b^(2)d^(2)- 405f^(5))` `=((32b^(6)+12b^(2)d^(2)-405f^(5))x^(4))/(32b^(6)+12b^(2)d^(2)-405f^(5))` `x^(4) = (a^(4))/(16b^(4)) or (e^(4))/(81f^(4))` |
|
| 4. |
Which cell address is valid – B12 or 12B? What will be the address of a Cell at Column Z and row number 35? |
|
Answer» B12 is a valid cell address. Z35 will be the address of a Cell at Column Z and row number 35. |
|
| 5. |
Write SQL command to remove column named ‘Games’ from a table named ‘player’. |
|
Answer» ALTER TABLE player DROP Games Alter table player drop games |
|
| 6. |
Suggest a command to remove all the records of the table named “Club” at one go along with its structure permanently. |
|
Answer» Answer: Drop table Club Drop table "club"Drop table "club"Drop table "club" |
|
| 7. |
Who was the first Advocate-General of Madhya Pradesh?1. P.V. Dixit2. M. Adhikari3. Kunjilal Dubey4. Pt. Ravi Shankar Shukla |
||||||||||||||||||||||||||||||||
|
Answer» Correct Answer - Option 2 : M. Adhikari The correct answer is M.Adhikari.
|
|||||||||||||||||||||||||||||||||
| 8. |
स्थाई विकास क्या है एवं स्थाई विकास के लक्ष्यों की पहचान करें |
|
Answer» स्थायी विकास ऐसा विकास है जो भावी पीढ़ियों की अपनी निजी आवश्यकताओं की पूर्ति की योग्यता से बिना किसी तरह का समझौता किए बिना अपनी मौजूदा आवश्यकताओं की पूर्ति करता है। |
|
| 9. |
Akbar was enthroned in a garden at (a) Kalanaur(b) Ajmer (c) Gaur(d) Kabul |
|
Answer» Akbar was enthroned in a garden at Kalanaur. |
|
| 10. |
⊕ and ⊙ are two operators on numbers p and q such that p ⊙ q = p - q, and p ⊕ q = p × qThen, (9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = 1. - 332. 403. - 404. - 26 |
|
Answer» Correct Answer - Option 3 : - 40 Explanation: given, p ⊙ q = p - q, and p ⊕ q = p × q, that means ⊙ = - (subtraction) and ⊕ = × (multiplication) Then, (9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = (9 - (6 × 7)) - (7 × (6 - 5)) = (9 - 42) - 7 = - 40 (9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = - 40 |
|
| 11. |
Why is pure ethanoic acid called glacial ethanoic acid (or glacial acetic acid)? |
| Answer» The melting point of pure ethanoic acid is 290 K and hence it often freezes in cold climate to form a colourless, ice-like liquid. This has given it the name glacial acetic acid. | |
| 12. |
There’s a paper ______ the floor. Please put it ______ the wastebasket. A) at / into B) on / at C) on / in D) over / at |
|
Answer» Correct option is C) on / in |
|
| 13. |
It must have rained ________ the night. The ground’s still wet. A) ago B) during C) for D) since E) while |
|
Answer» Correct option is B) during |
|
| 14. |
There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring `Q=4sqrt(2lambda)R`. An electron of mass m is released from rest on the axis of the ring at a distance `x=sqrt(3) R` from the centre. Magnitude of initial acceleration of the electron.A. `(elambda)/(pivarepsilon_(0)mR)((3-2sqrt(2))/(4sqrt(6)))`B. `(elambda)/(pivarepsilon_(0)mR) ((3+2sqrt(2))/(4sqrt(6)))`C. `(elambda)/(pivarepsilon_(0)mR)((3+2sqrt(2))/(4sqrt(3)))`D. none |
|
Answer» Correct Answer - A Magnitude of initial acceleration of the electron. Electricfield `E=-lambda/(2pivarepsilon_(0)x)+Q/(4pivarepsilon_(0)) x/((R^(2)+x^(2))^(3//2))` (considering right direction as positive) `=lambda/(2pivarepsilon_(0))[-1/x+(x4sqrt(2)R)/(2(R^(2)+x^(2))^(3//2))]` `=lambda/(2pivarepsilon_(0))[-1/x+(2sqrt(2)xxR)/((R^(2)+x^(2))^(3//2))]` Initially`x=sqrt(3)R` `E=lambda/(2pivarepsilon_(0)R)[-1/sqrt(3)+(2sqrt(2)sqrt(3))/8]` `lambda/(2pivarepsilon_(0)R)[(-2sqrt(2)+3)/(sqrt(3)(2sqrt(2)))]=lambda/(2pivarepsilon_(0)R)((3-2sqrt(2))/(2sqrt(6)))` a(acceleration)`=((-e)(E))/m=-(elambda)/(pivarepsilon_(0) mR) ((3-2sqrt(2))/(4sqrt(6)))` Sol(2) Force on electron is zero at point where `E=0Rightarrow x=R` Sol(3) Potential difference between two points `DeltaV=-E dx` P.d. due to line charge between `x=R& x=sqrt(3)R` `V_(A)-V_(B)=-underset(R)oversetsqrt((3)R)(int) -(lambda dx)/(2pivarepsilon_(0)x)=lambda/(pivarepsilon_(0))((l n3)/4)` Potential difference due to ring between `x=sqrt(3) R and x=R` `V_(A)-V_(B)=1/(4pivarepsilon_(0))((4sqrt(2)lambda R)/(2R)-(4sqrt(2)lambdaR)/(sqrt(2)R))=(-lambda)/(pivarepsilon_(0))(1-1/sqrt(2))` Net `V_(A)-V_(B)=-lambda/(pivarepsilon_(0))[(1-1/sqrt(2))-(l n3)/4]` |
|
| 15. |
There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring `Q=4sqrt(2lambda)R`. An electron of mass m is released from rest on the axis of the ring at a distance `x=sqrt(3) R` from the centre. The distance from centre of ring on the axis where the net force on the electron is zero.A. 2RB. `sqrt(2)`RC. RD. none of these |
|
Answer» Correct Answer - C Electricfield `E=-lambda/(2pivarepsilon_(0)x)+Q/(4pivarepsilon_(0)) x/((R^(2)+x^(2))^(3//2))` (considering right direction as positive) `=lambda/(2pivarepsilon_(0))[-1/x+(x4sqrt(2)R)/(2(R^(2)+x^(2))^(3//2))]` `=lambda/(2pivarepsilon_(0))[-1/x+(2sqrt(2)xxR)/((R^(2)+x^(2))^(3//2))]` Initially`x=sqrt(3)R` `E=lambda/(2pivarepsilon_(0)R)[-1/sqrt(3)+(2sqrt(2)sqrt(3))/8]` `lambda/(2pivarepsilon_(0)R)[(-2sqrt(2)+3)/(sqrt(3)(2sqrt(2)))]=lambda/(2pivarepsilon_(0)R)((3-2sqrt(2))/(2sqrt(6)))` a(acceleration)`=((-e)(E))/m=-(elambda)/(pivarepsilon_(0) mR) ((3-2sqrt(2))/(4sqrt(6)))` Sol(2) Force on electron is zero at point where `E=0Rightarrow x=R` Sol(3) Potential difference between two points `DeltaV=-E dx` P.d. due to line charge between `x=R& x=sqrt(3)R` `V_(A)-V_(B)=-underset(R)oversetsqrt((3)R)(int) -(lambda dx)/(2pivarepsilon_(0)x)=lambda/(pivarepsilon_(0))((l n3)/4)` Potential difference due to ring between `x=sqrt(3) R and x=R` `V_(A)-V_(B)=1/(4pivarepsilon_(0))((4sqrt(2)lambda R)/(2R)-(4sqrt(2)lambdaR)/(sqrt(2)R))=(-lambda)/(pivarepsilon_(0))(1-1/sqrt(2))` Net `V_(A)-V_(B)=-lambda/(pivarepsilon_(0))[(1-1/sqrt(2))-(l n3)/4]` |
|
| 16. |
There was a storm ______ the night, it rained _____ three or four hours. A) at / in B) during / for C) in / since D) during / at |
|
Answer» Correct option is B) during / for |
|
| 17. |
We are giving him a surprise party ______ his birthday. A) in B) at C) with D) on |
|
Answer» Correct option is D) on |
|
| 18. |
Which of the following formula represents a saturated hydrocarbon?CnH2n + 2, Cn H2n + 1, CnH2n, CnH2n- 2 |
|
Answer» CnH2n+2 represents a saturated hydrocarbon. |
|
| 19. |
Which of the following are alkenes?CH4, C2H6, C2H4, C3H6 and C3H8 . |
|
Answer» C2H4 and C3H6 are alkenes. |
|
| 20. |
A test tube contains a brown coloured liquid. The colour of the liquid in test tube remains unchanged when methane is passed through it, but disappears when ethene is passed. Which element is present in the liquid? |
| Answer» The element present in the liquid is bromine | |
| 21. |
In two identical communicating vessel we poured water (see picture). In one of them we put an ice ball of volume `V=100 cm^(3)` which gets exactly half immersed in the water. The density of water `rho_(w)=1000kg//m^(3)` the density of ice `rho_(i)=900kg//m^(3)` Select the correct statement (s). Soon after placing the ice ball in left vessel.A. The volume of water flowing to the right vessel is 25cc.B. The volume of water flowing to the right vessel is 50ccC. The ice ball is resting on the bottom of vessel.D. The ice ball is floating on the water surface. |
|
Answer» Correct Answer - A::C Half immersed `=50cc` displaced water. So 25cc rise in left and 25cc rise in right according to archemedies principle, buoyant force is equal to weight of displaced fluid, here, is equal to weight of 50cc water and if is less than the w.r.t. of 100cc ice ball, so, the ball cannot float. |
|
| 22. |
In two identical communicating vessel we poured water (see picture). In one of them we put an ice ball of volume `V=100 cm^(3)` which gets exactly half immersed in the water. The density of water `rho_(w)=1000kg//m^(3)` the density of ice `rho_(i)=900kg//m^(3)` Which of the following actions will raise the water level.A. Heating the systemB. Putting a coin on top of ice ball.C. Putting a coin in right vesselD. Accelerating the system upwards. |
|
Answer» Correct Answer - A::C (A) Heating will melt the ice and increase the volume of water. (C) coin placed in right vessel will displace some volume of water, which will be equally distributed to both vessels raising level in both. |
|
| 23. |
Direction: Each question below is followed by two statements I and II. You have to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.Find the present age of Ram.Statement I. Ram’s brother is 8 years younger to Ram.Statement II. The ratio of the present age of Ram and his brother is 3 ∶ 21.The statement I alone is sufficient to answer the question but, statement II alone is not sufficient.2.The statement II alone is sufficient to answer the question but, statement I alone is not sufficient.3.Both the statements I and II together are needed to answer the question.4.Either statement I alone or statement II alone is sufficient to answer the question.5.Neither statement I nor statement II is sufficient to answer the question. |
|
Answer» Correct Answer - Option 3 : Both the statements I and II together are needed to answer the question. Statement I. Relation between Ram and his brother’s age is given. None of the ages are given So, Statement I alone is not sufficient Statement II. Ratio of the ages are given Let Ram’s age be 3x Ram’s Brother age = 2x Value of the ages are not given So, statement II alone is not sufficient Combining Statement I and Statement II 3x – 8 = 2x x = 8 Ram’s age = 3 × 8 = 24 years ∴ Both the statements I and II together are needed to answer the question. |
|
| 24. |
Ram and Shayam can complete a work together in 28 days, Shayam alone complete it in 49 days, both of them work for 8 days then Ram leave the work, In how many days Shayam will finish the remaining work?1. 40 days2. 25 days3. 30 days4. 35 days5. None of these |
||||||||||||
|
Answer» Correct Answer - Option 4 : 35 days Given: Ram and Shayam can complete a work together = 28 days Shayam alone can complete work = 49 days Both Ram and Shayam work for 8 days then Ram leave the work Concept: Total work = Time × Efficiency Calculation:
Both Ram and Shayam work done in 8 days = 8 × 7 = 56 unit Remaining work = 196 – 56 = 140 unit Let, Remaining work done by Shayam in x days Then, x = 140/4 = 35 days ∴ Shayam will finish the remaining work in 35 days. |
|||||||||||||
| 25. |
A tap drips at a rate of one drop/sec, 1200 drops make 200 ml. The number of liters wasted in 600 days is?1. 8640 liter2. 9000 liter3. 4150 liter4. 5500 liter |
|
Answer» Correct Answer - Option 1 : 8640 liter Given: A tap drips at a rate of one drop/sec 1200 drops make 200 ml Number of liters wasted in 600 days Concept used: 1 liter = 1000 ml 1 hours = 60 minutes 1 minutes = 60 seconds Calculation 600 days = 600 × 24 × 60 × 60 seconds Given 1200 drops = 200 ml Then 12 drops = 2 ml 6 drops = 1 ml Wasted water = (600 × 24 × 60 × 60) ÷ 6 Wasted water = 8640000 ml Wasted number in liters = 8640 liters ∴ Wasted quantity is 8640 liters |
|
| 26. |
While cooking, if the bottom of the vessel is getting blackend on the outside, it means that:(a) the food is not cooked completely.(b) the fuel is not burning completely.(c) the fuel is wet.(d) the fuel is burning completely. |
| Answer» (b) the fuel is not burning completely | |
| 27. |
A person can swim with 7 Km/hr in direction of flow and 3 Km/hr in opposite to the direction of flow. What is speed of person in still water?1. 4 Km/hr2. 5 Km/hr3. 6 Km/hr4. 4.5 Km/hr5. 5.5 Km/hr |
|
Answer» Correct Answer - Option 2 : 5 Km/hr Calculation: Let the speed of person in still water be x and speed of current be y According to question, x – y = 3 …..1 x + y = 7 …..2 Adding equation 1 and 2 2x = 10 X = 5 km/hr ⇒ Speed of person in still water = 5 km/hr |
|
| 28. |
Butanone is a four carbon compound with the functional group:(a) carboxylic acid(b) aldehyde(c) ketone(d) alcohol |
|
Answer» Answer is (c) ketone |
|
| 29. |
In an organic compound, which parts largely determine its physical and chemical properties? |
|
Answer» The alkyl part (carbon chain) of an organic compound determines its physical properties whereas the functional group determines its chemical properties |
|
| 30. |
'Mathematics Day' is observed on1. 20th December2. 21st December3. 22nd December4. None of the above |
|
Answer» Correct Answer - Option 3 : 22nd December Mathematics is the study of geometrical figures, their co-relation, and their dependency on each other. It deals with quantity, measurement, and spatial relationships.
Hence, it could be concluded that Mathematics day is observed on 22nd December.
|
|
| 31. |
A and B together can do a work in 7 days and B and C together in 8.75 days and A can do the same work in 10.5 days. How many days will C take to complete double the same amount of work when working alone?1. 312. 31.253. 304. 32.5 |
|
Answer» Correct Answer - Option 3 : 30 Given: Time taken by A and B to together complete the work = 7 days Time taken by B and C to together complete the work = 8.75 days Time taken by A to complete the work alone = 10.5 days Concept Used: If a person takes x days to complete a work, the part of the work completed by him in 1 day = 1/x Calculation: Part of the work completed by A and B together in 1 day is obtained as: (1/A) + (1/B) = 1/7 ----(i) Part of the work completed by B and C together in 1 day is obtained as: (1/B) + (1/C) = 1/8.75 = 4/35 ----(ii) Part of the work completed by A alone in 1 day is obtained as: 1/A = 1/10.5 = 2/21 ----(iii) We substitute the value of (1/A) into equation(i) to obtain: (2/21) + (1/B) = 1/7 ⇒ 1/B = 1/21 ----(iv) Hence, B takes 21 days to complete the work alone Now, we substitute the value of (1/B) into equation(ii) to obtain: (1/21) + (1/C) = 4/35 ⇒ 1/C = (4/35) – (1/21) = 1/15 Hence, the time required by C to complete the work alone = 15 days So, the time C will need to complete double the amount of work will be: 2 × 15 = 30 days ∴ The time C will take to complete double the same amount of work, when working alone, will be 30 days |
|
| 32. |
A is 30% more efficient than B and B is 20% less efficient than C. If A takes 8 days less than C to complete a work, then in how many days B can complete the work?1. 230 days2. 240 days3. 260 days4. 250 days5. 210 days |
|
Answer» Correct Answer - Option 3 : 260 days Given: A is 30% more efficient than B B is 20% less efficient than C Concept Used: Efficiency = Total work/Total time Calculation: C : B = 100 : 80 A : B = 104 : 80 A : B : C = 104 : 80 : 100 ⇒ A : B : C = 26 : 20 : 25 (Efficiency Ratio) L.C.M of 26, 20, 25 is 1300 Ratio of their days is A : B : C = \(\frac{{1300}}{{26}}{\rm{\;}}:{\rm{\;}}\frac{{1300}}{{20}}{\rm{\;}}:{\rm{\;}}\frac{{1300}}{{25}}\) ⇒ A : B : C = 50x : 65x : 52x A takes 8 days less than C to complete the work. (52x – 50x) = 2x ⇒ 2x = 8 days ⇒ 65x = 260 days ∴ B takes 260 days to complete the job |
|
| 33. |
If A, B and C alone can complete a work in x, y and z days respectively, then in how many days will they complete the same work, working together?1. \(\frac{{x + y + z}}{{xyz}}\) days2. \(\frac{{xy + yz + zx}}{{xyz}}\) days3. \(\frac{{xyz}}{{xy + yz + zx}}\) days4. None of the above |
|
Answer» Correct Answer - Option 3 : \(\frac{{xyz}}{{xy + yz + zx}}\) days Calculation A can complete work in 'x' days B can complete work in 'y' days C can complete work in 'z' days A's one-day work = 1/x B's one-day work = 1/y C's one-day work = 1/z A, B and C's one-day work = 1/x + 1/y + 1/z \(\Rightarrow {xy + yz + zx \over xyz}\) Time taken by A, B and C together to complete the work = 1/A, B and C's one-day work \(\Rightarrow \frac{{xyz}}{{xy + yz + zx}} days\) |
|
| 34. |
See you ______ Monday morning. A) under B) at C) in D) on |
|
Answer» Correct option is D) on |
|
| 35. |
Suppose that two events A and B are mutually exclusive and P[B]>0. Under what conditions will A and B be independent? |
| Answer» Given A and B are mutually exclusive events and P(B)>0.For A and B to be independent, P(A)=0 | |
| 36. |
In a school, a Science project has been assigned to three students Rajat, Rohan, and Bishal and it was told that they should work together on that project. Working alone Rohan can finish the project in 20 days, it is also given that if Rajat and Bishal work on the project they will take 9 days to complete the project. Bishal alone can complete the project in 15 days. Rohan started working on the project from Monday but after 8 days he left and after that Rajat and Bishal started working on it but Bishal also left 6 days before completion of the work and Rajat completed the remaining project, in how many days will the project be completed and on which day will it be completed?1. 17 days, Thursday2. 15 days, Tuesday3. 16 days, Wednesday4. 18 days, Friday5. 14 days, Monday |
|
Answer» Correct Answer - Option 1 : 17 days, Thursday Given: Rohan can complete the project in 20 days Rajat and Bishal together can complete it in 9 days. Bishal alone takes 15 days to complete the project. Concept: Efficiency = Total work/Total time Calculation: The L.C.M of 20, 9, and 15 is 180 ⇒ Efficiency of Rohan = 180/20 = 9 ⇒ Efficiency of Rajat and Bishal = 180/9 = 20 ⇒ Efficiency of Bishal = 180/15 = 12 Efficiency of Rajat is (20 – 12) = 8 At first, Rohan will work for 8 days So he will do 9 × 8 = 72 units So remaining (180 - 72) = 108 units is to be done by Rajat and Bishal. Bishal has left 6 days before completion of the project. So last 6 days only Rajat will work Rajat alone will do 6 × 8 = 48 units So remaining (108 - 48) = 60 units have been completed by Rajat and Bishal in 60/20 ⇒ 3 days Total time taken by all of them is 8 + 3 + 6 = 17 days ∴ In 17 days the project be completed and on Thursday will it be completed. |
|
| 37. |
Assuming that on an average 1% of the output in a factory making certain part of an article are defective and that 200 units are in a package, find the probabilities that: (i) at most 2 defectives, and (ii) at least two defectives, may be found in the package. |
|
Answer» p = 1% = \(\frac1{100}\) q = 1 - p = 1 - \(\frac1{100}\) = \(\frac{99}{100}\), n = 200 (i) Probability that almost two defective part in the package = \(P(x\le 2)\) \(P(0) + P(1) + P(2)\) \(= \,^{200}C_0 \,p^0\, q^{200} + \,^{200}C_1 \,p\,q^{199}+ \,^{200}C_2 p^2 q^{198}\) \(= \left(\frac1{100}\right)^0 \left(\frac{99}{100}\right)^{200}+ \,^{200}\left(\frac1{100}\right) \left(\frac{99}{100}\right)^{199} + \frac{200.199}{2}\left(\frac1{100}\right)^2\left(\frac{99}{100}\right)^{198}\) \(= \left(\frac{99}{100}\right)^{198} \left(\left(\frac{99}{100}\right)^2 + 2\left(\frac{99}{100}\right)+ \frac{199}{100}\right)\) \(= \left(\frac{99}{100}\right)^{198} \left(\frac{9801 + 19800 + 19900}{10000}\right)\) \(= \left(\frac{99}{100}\right)^{198} \times \left(\frac1{100}\right)^2 \times 49501\) (ii) Probability that at least two defective part in the package = \(P(x\ge 2)\) \(= 1- P(0) - P(1)\) \(= 1- \,^{200}C_0 \,p^0\,q^{200} -\, ^{200}C_1\,p\,q^{199}\) \(= 1 - \left(\frac1{100}\right)^0 \left(\frac{99}{100}\right)-\,^{200}\frac1{100}\left(\frac{99}{100}\right)^{99}\) \(= 1 - \left(\frac{95}{100}\right)^{199} \left(\frac{99}{100}+2\right)\) \(= 1 - \left(\frac{99}{100}\right)^{199} \left(\frac{299}{100}\right)\) |
|
| 38. |
The police don’t know who made ______ with the money of that big company. A) for B) out c) off |
|
Answer» Correct option is C) off |
|
| 39. |
Reshma and Ritam are two friends studying in same class 10 of different school Delhi. In order to complete their holidays project work on historical monuments they decide to visit Redfort. For this they decided to tons coin. If heads appear they decide to visit otherwise not. For Redfort they toss coin separately and result of both was head. Redfort remains close on Monday. So none of them visited Redfart. Now to decide day of visit from remaining days of week, each of them throw a die. On the basis of outcome they went to Redfort. (i) What is the probability of visiting Redfort on Monday? (ii) What is the probability of not visiting Redfort on Monday? (iii) What is the probability of visiting Redfort on same day of week? (iv) What is the probability of visiting Redfort on different day of week? |
|
Answer» (i) Since, Redfort remains close on Monday. So, none of them visits Redfort on Monday ∴ Probability of visiting Redfort on Monday = 0. (ii) Probability of not visiting Redfort on Monday = 1 - Probability of visiting Redfort on Monday = 1 - 0 = 1 (iii) They both decides the visiting day by throwing a die. If out comes of both dies are same then the visit Redfort on Same day otherwise on different day. ∴ Probability of visiting Redfort on same day = Probability that both die will give same out comes \(=\frac{6}{36} = \frac16\) (iv) Probability of visiting Redfort on different day = Probability that both die will give different outcomes \(= \frac{30}{36} = \frac56\) |
|
| 40. |
I don’t know how many candidates are running ______ President. A) up B) for C) off |
|
Answer» Correct option is B) for |
|
| 41. |
He ran for the bus but it pulled ______ from the stop just as he got there. A) up B) over C) back D) away |
|
Answer» Correct option is D) away |
|
| 42. |
They ran ______ against several problems when they tried to build the bridge in that area.A) off B) on C) up |
|
Answer» Correct option is C) up |
|
| 43. |
Which is the additional official language of Bihar?1. Hindi2. English3. Urdu4. Sanskrit |
|
Answer» Correct Answer - Option 3 : Urdu The correct answer is option (3) i.e. Urdu.
|
|
| 44. |
We ran ______ of beer when the party was half over. A) away B) out C) off |
|
Answer» Correct option is B) out |
|
| 45. |
We have an extra room in our house. We will gladly ____ you ____ for a week or two. A) put / up B) put / off C) put / through D) put / in |
|
Answer» Correct option is A) put / up |
|
| 46. |
Which is the formation year of Bihar?1. 19122. 19223. 19324. 1942 |
|
Answer» Correct Answer - Option 1 : 1912 The correct answer is option (1) i.e. 1912.
|
|
| 47. |
How do you find your new neighbors? I’ve heard they are difficult to ____ . A) get up B) get on with C) get down D) get over |
|
Answer» Correct option is B) get on with |
|
| 48. |
John didn’t notice he had run ______ his neighbor’s little dog. A) over B) on C) off |
|
Answer» Correct option is A) over |
|
| 49. |
What is the scope and importance of environmental studies |
|
Answer» The scope of environmental studies is very wide and it deals with many areas like i) Conservation of natural resources, ii) ecological aspects, iii) pollution of the surrounding natural resources, iv) controlling the pollution, v) social issues connected to it, and vi) impacts of human population on the environment. |
|
| 50. |
Our garden is ___ than that of the neighbor’s. A) little B) the least C) most difficult D) the best E) less |
|
Answer» Correct option is E) less |
|