Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

months=['dec'.'jan'.'feb'.'mar']atendence=[70,90,75,95]pli.plot(months.attendence)plt.show()

Answer»

matplotlib. pyplot is a collection of command style functions that make matplotlib work like MATLAB. Each pyplot function makes some change to a figure: e.g., creates a figure, creates a plotting area in a figure, plots some lines in a plotting area, decorates the plot with labels, etc.

2.

Write one advantage and one disadvantage of using optical fiber cable

Answer»

Advantages of Optical Fiber

Cheap—Long, continuous miles of optical fiber cable can be made cheaper than equivalent lengths of copper wire. With numerous vendors swarm to compete for the market share, optical cable price would sure to drop.

Thinner and light-weighted—Optical fiber is thinner, and can be drawn to smaller diameters than copper wire. They are of smaller size and light weight than a comparable copper wire cable, offering a better fit for places where space is a concern.

Higher carrying capacity—Because optical fibers are much thinner than copper wires, more fibers can be bundled into a given-diameter cable. This allows more phone lines to go over the same cable or more channels to come through the cable into your cable TV box.

Less signal degradation—The loss of signal in optical fiber is less than that in copper wire.

Light signals—Unlike electrical signals transmitted in copper wires, light signals from one fiber do not interfere with those of other fibers in the same fiber cable. This means clearer phone conversations or TV reception.

Long lifespan—Optical fibers usually have a longer life cycle for over 100 years.

Disadvantages of Optical Fiber

Low power—Light emitting sources are limited to low power. Although high power emitters are available to improve power supply, it would add extra cost.

Fragility—Optical fiber is rather fragile and more vulnerable to damage compared to copper wires. You’d better not to twist or bend fiber optic cables too tightly.

Distance—The distance between the transmitter and receiver should keep short or repeaters are needed to boost the signal.

3.

If `(a)/(2b) = (c )/(d) = (e )/(3f)`, then the value of `(2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f)/(32b^(6)+12b^(2)d^(2)-405f^(5))` isA. `(a^(4))/(16b^(4))`B. `(16c^(4))/(d^(4))`C. `(e^(4))/(27f^(4))`D. `(81c^(4))/(d^(4))`

Answer» Correct Answer - A
If `(a)/(2b) = (c )/(d) = (e )/(3f)` , then ………..
`(a)/(2b) = (c )/(d) = (e )/(3f) = x` (left)
`implies a = 2bx, c = dx, e = 3fx`
Now, `N r. = 2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f`
`= 2(2bx)^(4)b^(2)+3(2bx)^(2) (dx)^(2) - 5(3fx)^(4)f`
`(32b^(6)+12b^(2)d^(2)-405f^(5))xx4`
now `(2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f)/(32b^(6)+12b^(2)d^(2)- 405f^(5))`
`=((32b^(6)+12b^(2)d^(2)-405f^(5))x^(4))/(32b^(6)+12b^(2)d^(2)-405f^(5))`
`x^(4) = (a^(4))/(16b^(4)) or (e^(4))/(81f^(4))`
4.

Which cell address is valid – B12 or 12B? What will be the address of a Cell at Column Z and row number 35?

Answer»

B12 is a valid cell address. 

Z35 will be the address of a Cell at Column Z and row number 35.

5.

Write SQL command to remove column named ‘Games’ from a table named ‘player’.

Answer»

ALTER TABLE player DROP Games

Alter table player drop games
6.

Suggest a command to remove all the records of the table named “Club” at one go along with its structure permanently.

Answer»

Answer: Drop table Club

Drop table "club"

Drop table "club"

Drop table "club"

7.

Who was the first Advocate-General of Madhya Pradesh?1. P.V. Dixit2. M. Adhikari3. Kunjilal Dubey4. Pt. Ravi Shankar Shukla

Answer» Correct Answer - Option 2 : M. Adhikari

The correct answer is M.Adhikari.

  • The Advocate General office of M.P. came into existence in November 1956 upon the formation of the State of M.P. as per the State Re-Organisation Act 1956 when the High Court of M.P. was established. 
  • On the formation of the new State of M.P., Shri M. Adhikari became the first Advocate General for the State of Madhya Pradesh.
  • The AG's Office presents all the cases in which the Govt. of Madhya Pradesh is one of the parties, in the High Court of M.P. Central Administrative Tribunal (CAT).

  • Shri Purshendra Kaurav is the Advocate General at present. (Dec-2020)

StateMadhya Pradesh
Established1st November 1956
Chief MinisterShivraj Singh Chauhan(Dec-2020)
Capital Bhopal
GovernorAnandiben Patel(Dec-2020)
Districts52
HeadquartersBhopal City
LegislatureUnicameral (230)
Area (Total)308,252 (km) (132,139 (sq mi)
Population (2011) total72,626,809
Density236/km (610 sq/mi)
Literacy rate70.06%
Sex Ratio931
Lok Sabha Constituencies29 seats
Rajya Sabha Constituencies11 seats
High courtJabalpur high court

 

8.

स्थाई विकास क्या है एवं स्थाई विकास के लक्ष्यों की पहचान करें

Answer»

स्थायी विकास ऐसा विकास है जो भावी पीढ़ियों की अपनी निजी आवश्यकताओं की पूर्ति की योग्यता से बिना किसी तरह का समझौता किए बिना अपनी मौजूदा आवश्यकताओं की पूर्ति करता है।

9.

Akbar was enthroned in a garden at (a) Kalanaur(b) Ajmer (c) Gaur(d) Kabul 

Answer»

Akbar was enthroned in a garden at Kalanaur.

10.

⊕ and ⊙ are two operators on numbers p and q such that p ⊙ q = p - q, and p ⊕ q = p × qThen, (9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = 1. - 332. 403. - 404. - 26

Answer» Correct Answer - Option 3 : - 40

Explanation:

given,

p ⊙ q = p - q, and p ⊕ q = p × q, that means

⊙ = - (subtraction) and ⊕ = × (multiplication)

Then,

(9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = (9 - (6 × 7)) - (7 × (6 - 5)) = (9 - 42) - 7 = - 40

(9 ⊙ (6⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) = - 40

11.

Why is pure ethanoic acid called glacial ethanoic acid (or glacial acetic acid)?

Answer» The melting point of pure ethanoic acid is 290 K and hence it often freezes in cold climate to form a colourless, ice-like liquid. This has given it the name glacial acetic acid.
12.

There’s a paper ______ the floor. Please put it ______ the wastebasket. A) at / into B) on / at C) on / in D) over / at

Answer»

Correct option is C) on / in

13.

It must have rained ________ the night. The ground’s still wet. A) ago B) during C) for D) since E) while

Answer»

Correct option is B) during

14.

There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring `Q=4sqrt(2lambda)R`. An electron of mass m is released from rest on the axis of the ring at a distance `x=sqrt(3) R` from the centre. Magnitude of initial acceleration of the electron.A. `(elambda)/(pivarepsilon_(0)mR)((3-2sqrt(2))/(4sqrt(6)))`B. `(elambda)/(pivarepsilon_(0)mR) ((3+2sqrt(2))/(4sqrt(6)))`C. `(elambda)/(pivarepsilon_(0)mR)((3+2sqrt(2))/(4sqrt(3)))`D. none

Answer» Correct Answer - A
Magnitude of initial acceleration of the electron.
Electricfield `E=-lambda/(2pivarepsilon_(0)x)+Q/(4pivarepsilon_(0)) x/((R^(2)+x^(2))^(3//2))` (considering right direction as positive)
`=lambda/(2pivarepsilon_(0))[-1/x+(x4sqrt(2)R)/(2(R^(2)+x^(2))^(3//2))]`
`=lambda/(2pivarepsilon_(0))[-1/x+(2sqrt(2)xxR)/((R^(2)+x^(2))^(3//2))]`
Initially`x=sqrt(3)R`
`E=lambda/(2pivarepsilon_(0)R)[-1/sqrt(3)+(2sqrt(2)sqrt(3))/8]`
`lambda/(2pivarepsilon_(0)R)[(-2sqrt(2)+3)/(sqrt(3)(2sqrt(2)))]=lambda/(2pivarepsilon_(0)R)((3-2sqrt(2))/(2sqrt(6)))`
a(acceleration)`=((-e)(E))/m=-(elambda)/(pivarepsilon_(0) mR) ((3-2sqrt(2))/(4sqrt(6)))`
Sol(2) Force on electron is zero at point where `E=0Rightarrow x=R`
Sol(3) Potential difference between two points
`DeltaV=-E dx`
P.d. due to line charge between
`x=R& x=sqrt(3)R`
`V_(A)-V_(B)=-underset(R)oversetsqrt((3)R)(int) -(lambda dx)/(2pivarepsilon_(0)x)=lambda/(pivarepsilon_(0))((l n3)/4)`
Potential difference due to ring between `x=sqrt(3) R and x=R`
`V_(A)-V_(B)=1/(4pivarepsilon_(0))((4sqrt(2)lambda R)/(2R)-(4sqrt(2)lambdaR)/(sqrt(2)R))=(-lambda)/(pivarepsilon_(0))(1-1/sqrt(2))`
Net `V_(A)-V_(B)=-lambda/(pivarepsilon_(0))[(1-1/sqrt(2))-(l n3)/4]`
15.

There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring `Q=4sqrt(2lambda)R`. An electron of mass m is released from rest on the axis of the ring at a distance `x=sqrt(3) R` from the centre. The distance from centre of ring on the axis where the net force on the electron is zero.A. 2RB. `sqrt(2)`RC. RD. none of these

Answer» Correct Answer - C
Electricfield `E=-lambda/(2pivarepsilon_(0)x)+Q/(4pivarepsilon_(0)) x/((R^(2)+x^(2))^(3//2))` (considering right direction as positive)
`=lambda/(2pivarepsilon_(0))[-1/x+(x4sqrt(2)R)/(2(R^(2)+x^(2))^(3//2))]`
`=lambda/(2pivarepsilon_(0))[-1/x+(2sqrt(2)xxR)/((R^(2)+x^(2))^(3//2))]`
Initially`x=sqrt(3)R`
`E=lambda/(2pivarepsilon_(0)R)[-1/sqrt(3)+(2sqrt(2)sqrt(3))/8]`
`lambda/(2pivarepsilon_(0)R)[(-2sqrt(2)+3)/(sqrt(3)(2sqrt(2)))]=lambda/(2pivarepsilon_(0)R)((3-2sqrt(2))/(2sqrt(6)))`
a(acceleration)`=((-e)(E))/m=-(elambda)/(pivarepsilon_(0) mR) ((3-2sqrt(2))/(4sqrt(6)))`
Sol(2) Force on electron is zero at point where `E=0Rightarrow x=R`
Sol(3) Potential difference between two points
`DeltaV=-E dx`
P.d. due to line charge between
`x=R& x=sqrt(3)R`
`V_(A)-V_(B)=-underset(R)oversetsqrt((3)R)(int) -(lambda dx)/(2pivarepsilon_(0)x)=lambda/(pivarepsilon_(0))((l n3)/4)`
Potential difference due to ring between `x=sqrt(3) R and x=R`
`V_(A)-V_(B)=1/(4pivarepsilon_(0))((4sqrt(2)lambda R)/(2R)-(4sqrt(2)lambdaR)/(sqrt(2)R))=(-lambda)/(pivarepsilon_(0))(1-1/sqrt(2))`
Net `V_(A)-V_(B)=-lambda/(pivarepsilon_(0))[(1-1/sqrt(2))-(l n3)/4]`
16.

There was a storm ______ the night, it rained _____ three or four hours. A) at / in B) during / for C) in / since D) during / at

Answer»

Correct option is B) during / for

17.

We are giving him a surprise party ______ his birthday. A) in B) at C) with D) on

Answer»

Correct option is D) on

18.

Which of the following formula represents a saturated hydrocarbon?CnH2n + 2, Cn H2n + 1, CnH2n, CnH2n- 2

Answer»

CnH2n+2 represents a saturated hydrocarbon.

19.

Which of the following are alkenes?CH4, C2H6, C2H4, C3H6 and C3H8 .

Answer»

C2H4 and C3H6 are alkenes.

20.

A test tube contains a brown coloured liquid. The colour of the liquid in test tube remains unchanged when methane is passed through it, but disappears when ethene is passed. Which element is present in the liquid?

Answer» The element present in the liquid is bromine
21.

In two identical communicating vessel we poured water (see picture). In one of them we put an ice ball of volume `V=100 cm^(3)` which gets exactly half immersed in the water. The density of water `rho_(w)=1000kg//m^(3)` the density of ice `rho_(i)=900kg//m^(3)` Select the correct statement (s). Soon after placing the ice ball in left vessel.A. The volume of water flowing to the right vessel is 25cc.B. The volume of water flowing to the right vessel is 50ccC. The ice ball is resting on the bottom of vessel.D. The ice ball is floating on the water surface.

Answer» Correct Answer - A::C
Half immersed `=50cc` displaced water. So 25cc rise in left and 25cc rise in right according to archemedies principle, buoyant force is equal to weight of displaced fluid, here, is equal to weight of 50cc water and if is less than the w.r.t. of 100cc ice ball, so, the ball cannot float.
22.

In two identical communicating vessel we poured water (see picture). In one of them we put an ice ball of volume `V=100 cm^(3)` which gets exactly half immersed in the water. The density of water `rho_(w)=1000kg//m^(3)` the density of ice `rho_(i)=900kg//m^(3)` Which of the following actions will raise the water level.A. Heating the systemB. Putting a coin on top of ice ball.C. Putting a coin in right vesselD. Accelerating the system upwards.

Answer» Correct Answer - A::C
(A) Heating will melt the ice and increase the volume of water. (C) coin placed in right vessel will displace some volume of water, which will be equally distributed to both vessels raising level in both.
23.

Direction: Each question below is followed by two statements I and II. You have to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer.Find the present age of Ram.Statement I. Ram’s brother is 8 years younger to Ram.Statement II. The ratio of the present age of Ram and his brother is 3 ∶ 21.The statement I alone is sufficient to answer the question but, statement II alone is not sufficient.2.The statement II alone is sufficient to answer the question but, statement I alone is not sufficient.3.Both the statements I and II together are needed to answer the question.4.Either statement I alone or statement II alone is sufficient to answer the question.5.Neither statement I nor statement II is sufficient to answer the question.

Answer» Correct Answer - Option 3 :

Both the statements I and II together are needed to answer the question.


Statement I.

Relation between Ram and his brother’s age is given. None of the ages are given

So, Statement I alone is not sufficient

Statement II.

Ratio of the ages are given

Let Ram’s age be 3x

Ram’s Brother age = 2x

Value of the ages are not given

So, statement II alone is not sufficient

Combining Statement I and Statement II

3x – 8 = 2x

x = 8

Ram’s age = 3 × 8 = 24 years

Both the statements I and II together are needed to answer the question.

24.

Ram and Shayam can complete a work together in 28 days, Shayam alone complete it in 49 days, both of them work for 8 days then Ram leave the work, In how many days Shayam will finish the remaining work?1. 40 days2. 25 days3. 30 days4. 35 days5. None of these

Answer» Correct Answer - Option 4 : 35 days

Given:

Ram and Shayam can complete a work together = 28 days

Shayam alone can complete work = 49 days

Both Ram and Shayam work for 8 days then Ram leave the work

Concept:

Total work = Time × Efficiency

Calculation:

Work done by

Time taken

(in day)

Efficiency

Ram + Shayam

28

196/28 = 7

Shayam

49

196/49 = 4

Total work = L. C. M. = 196

 

 

 

 

 

 

Both Ram and Shayam work done in 8 days = 8 × 7 = 56 unit

Remaining work = 196 – 56 = 140 unit

Let, Remaining work done by Shayam in x days

Then, x = 140/4 = 35 days

Shayam will finish the remaining work in 35 days.

25.

A tap drips at a rate of one drop/sec, 1200 drops make 200 ml. The number of liters wasted in 600 days is?1. 8640 liter2. 9000 liter3. 4150 liter4. 5500 liter

Answer» Correct Answer - Option 1 : 8640 liter

Given:

A tap drips at a rate of one drop/sec 1200 drops make 200 ml

Number of liters wasted in 600 days

Concept used:

1 liter = 1000 ml

1 hours = 60 minutes

1 minutes = 60 seconds

Calculation

600 days = 600 × 24 × 60 × 60 seconds

Given 1200 drops = 200 ml

Then 12 drops = 2 ml

6 drops = 1 ml

Wasted water = (600 × 24 × 60 × 60) ÷ 6

Wasted water = 8640000 ml

Wasted number in liters = 8640 liters

Wasted quantity is 8640 liters 

26.

While cooking, if the bottom of the vessel is getting blackend on the outside, it means that:(a) the food is not cooked completely.(b) the fuel is not burning completely.(c) the fuel is wet.(d) the fuel is burning completely.

Answer» (b) the fuel is not burning completely
27.

A person can swim with 7 Km/hr in direction of flow and 3 Km/hr in opposite to the direction of flow. What is speed of person in still water?1. 4 Km/hr2. 5 Km/hr3. 6 Km/hr4. 4.5 Km/hr5. 5.5 Km/hr

Answer» Correct Answer - Option 2 : 5 Km/hr

Calculation:

Let the speed of person in still water be x and speed of current be y

According to question,

x – y = 3           …..1

x + y = 7           …..2

Adding equation 1 and 2

2x = 10

X = 5 km/hr

⇒ Speed of person in still water = 5 km/hr

28.

Butanone is a four carbon compound with the functional group:(a) carboxylic acid(b) aldehyde(c) ketone(d) alcohol

Answer»

Answer is (c) ketone 

29.

In an organic compound, which parts largely determine its physical and chemical properties?

Answer»

The alkyl part (carbon chain) of an organic compound determines its physical properties whereas the functional group determines its chemical properties

30.

'Mathematics Day' is observed on1. 20th December2. 21st December3. 22nd December4. None of the above

Answer» Correct Answer - Option 3 : 22nd December

Mathematics is the study of geometrical figures, their co-relation, and their dependency on each other. It deals with quantity, measurement, and spatial relationships.

  • The National Policy of Education (1986) lays down the importance of "mathematics" as a vehicle for developing creativity.
  • The teacher should use effective teaching methods of mathematics so that individualized discovery-oriented (or problem-solving) learning could be fostered.

  • In 2012 our former prime minister Dr. Manmohan Singh declared that every year 22nd December will be celebrated as the National Mathematics Day in India.
  • It is to give respect and homage to the legendary mathematician "Srinivasa Ramanujan" who was born on 22nd December 1887 in Tamilnadu and died at the age of 32.
  • The main aim of celebrating this day is to make people aware of the importance of mathematics in our daily life.
  • At the age of 12, he had mastered trigonometry and he developed many theorems on his own without any formal training in mathematics.
  • He mainly contributed to the number theory and infinite series. In 1918, he was elected to the royal society of London.

Hence, it could be concluded that Mathematics day is observed on 22nd December.

  • The international day of mathematics is celebrated on 14th march as declared by UNESCO (United Nations Educational, Scientific and Cultural Organization).
  • 14th march also celebrated as (π) Pi Day.
31.

A and B together can do a work in 7 days and B and C together in 8.75 days and A can do the same work in 10.5 days. How many days will C take to complete double the same amount of work when working alone?1. 312. 31.253. 304. 32.5

Answer» Correct Answer - Option 3 : 30

Given:

Time taken by A and B to together complete the work = 7 days

Time taken by B and C to together complete the work = 8.75 days

Time taken by A to complete the work alone = 10.5 days

Concept Used:

If a person takes x days to complete a work, the part of the work completed by him in 1 day = 1/x

Calculation:

Part of the work completed by A and B together in 1 day is obtained as:

(1/A) + (1/B) = 1/7      ----(i)

Part of the work completed by B and C together in 1 day is obtained as:

(1/B) + (1/C) = 1/8.75 = 4/35      ----(ii)

Part of the work completed by A alone in 1 day is obtained as:

1/A = 1/10.5 = 2/21       ----(iii)

We substitute the value of (1/A) into equation(i) to obtain:

(2/21) + (1/B) = 1/7

⇒ 1/B = 1/21       ----(iv)

Hence, B takes 21 days to complete the work alone

Now, we substitute the value of (1/B) into equation(ii) to obtain:

(1/21) + (1/C) = 4/35

⇒ 1/C = (4/35) – (1/21) = 1/15

Hence, the time required by C to complete the work alone = 15 days

So, the time C will need to complete double the amount of work will be:

2 × 15 = 30 days

∴ The time C will take to complete double the same amount of work, when working alone, will be 30 days

32.

A is 30% more efficient than B and B is 20% less efficient than C. If A takes 8 days less than C to complete a work, then in how many days B can complete the work?1. 230 days2. 240 days3. 260 days4. 250 days5. 210 days

Answer» Correct Answer - Option 3 : 260 days

Given:

A is 30% more efficient than B

B is 20% less efficient than C

Concept Used:

Efficiency = Total work/Total time

Calculation:

C : B = 100 : 80

A : B = 104 : 80

A : B : C = 104 : 80 : 100

⇒ A : B : C = 26 : 20 : 25 (Efficiency Ratio)

L.C.M of 26, 20, 25 is 1300

Ratio of their days is A : B : C = \(\frac{{1300}}{{26}}{\rm{\;}}:{\rm{\;}}\frac{{1300}}{{20}}{\rm{\;}}:{\rm{\;}}\frac{{1300}}{{25}}\)

⇒ A : B : C = 50x : 65x : 52x

A takes 8 days less than C to complete the work.

(52x – 50x) = 2x

⇒ 2x = 8 days

⇒ 65x = 260 days

∴ B takes 260 days to complete the job          

33.

If A, B and C alone can complete a work in x, y and z days respectively, then in how many days will they complete the same work, working together?1. \(\frac{{x + y + z}}{{xyz}}\) days2. \(\frac{{xy + yz + zx}}{{xyz}}\) days3. \(\frac{{xyz}}{{xy + yz + zx}}\) days4. None of the above

Answer» Correct Answer - Option 3 : \(\frac{{xyz}}{{xy + yz + zx}}\) days

Calculation

A can complete work in 'x' days

B can complete work in 'y' days

C can complete work in 'z' days

A's one-day work = 1/x

B's one-day work = 1/y

C's one-day work = 1/z

A, B and C's one-day work = 1/x + 1/y + 1/z

\(\Rightarrow {xy + yz + zx \over xyz}\)

Time taken by A, B and C together to complete the work = 1/A, B and C's one-day work

\(\Rightarrow \frac{{xyz}}{{xy + yz + zx}} days\)

34.

See you ______ Monday morning. A) under B) at C) in D) on

Answer»

Correct option is D) on 

35.

Suppose that two events A and B are mutually exclusive and P[B]>0. Under what conditions will A and B be independent?

Answer» Given A and B are mutually exclusive events and P(B)>0.For A and B to be independent, P(A)=0
36.

In a school, a Science project has been assigned to three students Rajat, Rohan, and Bishal and it was told that they should work together on that project. Working alone Rohan can finish the project in 20 days, it is also given that if Rajat and Bishal work on the project they will take 9 days to complete the project. Bishal alone can complete the project in 15 days. Rohan started working on the project from Monday but after 8 days he left and after that Rajat and Bishal started working on it but Bishal also left 6 days before completion of the work and Rajat completed the remaining project, in how many days will the project be completed and on which day will it be completed?1. 17 days, Thursday2. 15 days, Tuesday3. 16 days, Wednesday4. 18 days, Friday5. 14 days, Monday

Answer» Correct Answer - Option 1 : 17 days, Thursday

Given:

Rohan can complete the project in 20 days

Rajat and Bishal together can complete it in 9 days.

Bishal alone takes 15 days to complete the project.

Concept:

Efficiency = Total work/Total time

Calculation:

The L.C.M of 20, 9, and 15 is 180

⇒ Efficiency of Rohan = 180/20 = 9

⇒ Efficiency of Rajat and Bishal = 180/9 = 20

⇒ Efficiency of Bishal = 180/15 = 12

Efficiency of Rajat is (20 – 12) = 8

At first, Rohan will work for 8 days

So he will do 9 × 8 = 72 units

So remaining (180 - 72) = 108 units is to be done by Rajat and Bishal.

Bishal has left 6 days before completion of the project.

So last 6 days only Rajat will work

Rajat alone will do 6 × 8 = 48 units

So remaining (108 - 48) = 60 units have been completed by Rajat and Bishal in 60/20

⇒ 3 days

Total time taken by all of them is 8 + 3 + 6 = 17 days

∴ In 17 days the project be completed and on Thursday will it be completed.

37.

Assuming that on an average 1% of the output in a factory making certain part of an article are defective and that 200 units are in a package, find the probabilities that: (i) at most 2 defectives, and (ii) at least two defectives, may be found in the package.

Answer»

p = 1% = \(\frac1{100}\)

q = 1 - p = 1 - \(\frac1{100}\) = \(\frac{99}{100}\), n = 200

(i) Probability that almost two defective part in the package = \(P(x\le 2)\)

\(P(0) + P(1) + P(2)\)

\(= \,^{200}C_0 \,p^0\, q^{200} + \,^{200}C_1 \,p\,q^{199}+ \,^{200}C_2 p^2 q^{198}\)

\(= \left(\frac1{100}\right)^0 \left(\frac{99}{100}\right)^{200}+ \,^{200}\left(\frac1{100}\right) \left(\frac{99}{100}\right)^{199} + \frac{200.199}{2}\left(\frac1{100}\right)^2\left(\frac{99}{100}\right)^{198}\)

\(= \left(\frac{99}{100}\right)^{198} \left(\left(\frac{99}{100}\right)^2 + 2\left(\frac{99}{100}\right)+ \frac{199}{100}\right)\)

\(= \left(\frac{99}{100}\right)^{198} \left(\frac{9801 + 19800 + 19900}{10000}\right)\)

\(= \left(\frac{99}{100}\right)^{198} \times \left(\frac1{100}\right)^2 \times 49501\)

(ii) Probability that at least two defective part in the package = \(P(x\ge 2)\)

\(= 1- P(0) - P(1)\)

\(= 1- \,^{200}C_0 \,p^0\,q^{200} -\, ^{200}C_1\,p\,q^{199}\)

\(= 1 - \left(\frac1{100}\right)^0 \left(\frac{99}{100}\right)-\,^{200}\frac1{100}\left(\frac{99}{100}\right)^{99}\)

\(= 1 - \left(\frac{95}{100}\right)^{199} \left(\frac{99}{100}+2\right)\)

\(= 1 - \left(\frac{99}{100}\right)^{199} \left(\frac{299}{100}\right)\)

38.

The police don’t know who made ______ with the money of that big company. A) for B) out c) off

Answer»

Correct option is C) off

39.

Reshma and Ritam are two friends studying in same class 10 of different school Delhi. In order to complete their holidays project work on historical monuments they decide to visit Redfort. For this they decided to tons coin. If heads appear they decide to visit otherwise not. For Redfort they toss coin separately and result of both was head. Redfort remains close on Monday. So none of them visited Redfart. Now to decide day of visit from remaining days of week, each of them throw a die. On the basis of outcome they went to Redfort. (i) What is the probability of visiting Redfort on Monday? (ii) What is the probability of not visiting Redfort on Monday? (iii) What is the probability of visiting Redfort on same day of week? (iv) What is the probability of visiting Redfort on different day of week?

Answer»

(i) Since, Redfort remains close on Monday.

So, none of them visits Redfort on Monday 

∴ Probability of visiting Redfort on Monday = 0.

(ii) Probability of not visiting Redfort on Monday

= 1 - Probability of visiting Redfort on Monday 

= 1 - 0

= 1

(iii) They both decides the visiting day by throwing  a die. If out comes of both dies are same then the visit Redfort on Same day otherwise on different day.

∴ Probability of visiting Redfort on same day = Probability that both die will give same out comes

\(=\frac{6}{36} = \frac16\)

(iv) Probability of visiting Redfort on different day = Probability that both die will give different outcomes

\(= \frac{30}{36} = \frac56\)

40.

I don’t know how many candidates are running ______ President. A) up B) for C) off

Answer»

Correct option is B) for

41.

He ran for the bus but it pulled ______ from the stop just as he got there. A) up B) over C) back D) away

Answer»

Correct option is D) away

42.

They ran ______ against several problems when they tried to build the bridge in that area.A) off B) on C) up

Answer»

Correct option is C) up

43.

Which is the additional official language of Bihar?1. Hindi2. English3. Urdu4. Sanskrit

Answer» Correct Answer - Option 3 : Urdu

The correct answer is option (3) i.e. Urdu.

  • Hindi is the official language of Bihar and Urdu is the additional official language.
  • Bihar was formed in 22nd March 1912. 22nd March is celebrated as Bihar Diwas.
  • Capital of Bihar is Patna and the High Court of the state is also in Patna.
  • Bihar has both Legislative Assembly as well as Legislative Council.
  • The state is divided into nine divisions with thirty-eight districts.
44.

We ran ______ of beer when the party was half over. A) away B) out C) off

Answer»

Correct option is B) out

45.

We have an extra room in our house. We will gladly ____ you ____ for a week or two. A) put / up B) put / off C) put / through D) put / in

Answer»

Correct option is A) put / up

46.

Which is the formation year of Bihar?1. 19122. 19223. 19324. 1942

Answer» Correct Answer - Option 1 : 1912

The correct answer is option (1) i.e. 1912.

  • The Bihar was formed in 22nd March 1912 and got statehood in 26th January 1950.
  • Capital of Bihar is Patna. It is also the largest city of Bihar among all the 38 districts of Bihar.
  • It is third populated state in India after Uttar Pradesh  and Maharashtra. Hindi is its official language.
  • There are presently 40 seats from Lok Sabha and 16 seats from Rajya Sabha is for Bihar.
  • According to the 2011 census sex ratio of the state is 918:1000 and 63.82 % is the literacy rate of Bihar.
47.

How do you find your new neighbors? I’ve heard they are difficult to ____ . A) get up B) get on with C) get down D) get over

Answer»

Correct option is B) get on with

48.

John didn’t notice he had run ______ his neighbor’s little dog. A) over B) on C) off

Answer»

Correct option is A) over

49.

What is the scope and importance of environmental studies

Answer»

The scope of environmental studies is very wide and it deals with many areas like i) Conservation of natural resources, ii) ecological aspects, iii) pollution of the surrounding natural resources, iv) controlling the pollution, v) social issues connected to it, and vi) impacts of human population on the environment.

50.

Our garden is ___ than that of the neighbor’s. A) little B) the least C) most difficult D) the best E) less

Answer»

Correct option is E) less