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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In plants stomata opens during day time and close during night time. How is decreasing water potential of guard cell affect the opening and closing of stomata? |
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Answer» If decreasing the water potential of guard cell, water enters into guard cell from the subsidiary and it becomes turgid, stomata open. |
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| 2. |
“Water is transient in plants. Less than 1% of water reaching the leaves is used in photosynthesis and plant growth’’. What is the fate of remaining percentage of water? Specify the phenomenon? Give its significance in plants? |
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Answer» 99% of water absorbed is lost through transpiration. 1. It provides cooling effect to leaves and other organs. 2. It promotes mineral absorption. 3. It helps to maintain the shape and structure of plants by keeping up its turgidity. |
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| 3. |
Gravitational |
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Answer» Gravitation or just gravity is the force of attraction between any two bodies. All the objects in the universe attract each other with a certain amount of force, but in most of the cases, the force is too weak to be observed due to the very large distance of separation. Besides, gravity’s range is infinite but the effect becomes weaker as objects move away. This force of attraction was first observed by Sir Isaac Newton and was presented as Newton’s law of gravitation in the year 1680. However, gravitation can generally exist in two main instances. |
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| 4. |
The chemical reaction between copper and oxygen can be categorized as: A. Displacement reaction B. Decomposition reaction C. Combination reaction D. Double displacement reaction |
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Answer» Correct answer is C. Combination reaction When copper combines with oxygen, the process is known as corrosion or oxidation. When copper reacts with oxygen, then it produces copper oxide, a black color compound. 4Cu + O2 \(\longrightarrow\) 2Cu2 O (Combination reaction) Correct option is C. Combination reaction |
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| 5. |
In the reaction of iron with copper sulphate solution: CuSO4 + Fe\(\longrightarrow\) Cu + FeSO4 Which option in the given table correctly represents the substance oxidised and the reducing agent ?OPTIONSubstance OxidizedReducing AgentAFeFeBFeCuSO4CCuFeDCuSO4Fe |
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Answer» Correct answer is A. Fe and Fe respectively. Substance which is oxidized, reduces the other substance. Hence, substance oxidized is itself a reducing agent Correct option is A. Fe and Fe respectively. |
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| 6. |
The graph given below depicts a neutralization reaction (acid + alkali → salt + water). The pH of a solution changes as we add excess of acid to an alkali.Which letter denotes the area of the graph where both acid and salt are present? A. A B. B C. C D. D |
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Answer» Correct answer is (D) D As we add acid to an alkali, solution will become acidic in nature where PH ranges below 7. So D is the correct option. Correct option is D. D |
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| 7. |
Which of the following correctly represents a balanced chemical equation? A. Fe(s) + 4H2O(g) → Fe3O4 (s) + 4H2(g) B. 3Fe(s) + 4H2O(g) → Fe3O4 (s) + 4H2(g) C. 3Fe(s) + H2O(g) → Fe3O4 (s) + H2(g) D. 3Fe(s) + 4H2O(g) → Fe3O4 (s) + H2(g) |
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Answer» Correct option is B. 3Fe(s) + 4H2O(g) → Fe3O4 (s) + 4H2(g) |
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| 8. |
Which of the following two combinations are correct?MetalGas Evolved(i)CopperYes(ii)IronYes(iii)MagnesiumYes(iv)ZincYesA. i and iii B. i and iv C. ii and iii D. ii and iv |
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Answer» Correct option is D. ii and iv |
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| 9. |
It is a balance between dry and oily skin 1. Dry skin 2. Oily skin 3. Normal skin |
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Answer» Correct option: 3. Normal skin |
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| 10. |
Match the items given in column A and B:Column AColumn BCatalytic converterParticulate matterElectrostatic precipitatorCarbon monoxide and nitrogen oxidesEarmuffsHigh noise levelLandfillsSolid wastes |
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| 11. |
Discuss the causes and effects of global warming. What measures need to be taken to control global warming? |
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Answer» Global warming is defined as an increase in the average temperature of the Earth’s surface.
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| 12. |
Mention any one skeletal difference between ape and man. |
| Answer» In apes, lumber curve is absent and pelvic girdle is narrow and elongated. In man, lumbar curve is well developed and pelvic girdle is broad and basin-like. | |
| 13. |
Mention the symptoms of Down’s syndrome. |
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Answer» Severe mental retardation, defective development of the central nervous system, increased separation between the eyes, flattened nose, ears are malformed, mouth is constantly open and the tongue protrudes. |
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| 14. |
Write short notes on Darwin’s finches. |
Answer»
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| 15. |
Name the chemical substance which is called by the name (a) Kornberg Enzyme (b) Ochoa’s enzyme |
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Answer» DNA polymerase I is also known as Kornberg enzyme. Polynucleotide phosphorylase is also known as Ochoa’s enzyme. |
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| 16. |
Why should we conserve biodiversity? |
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Answer» There are three types of benefits of biodiversity, they are 1. Economic benefits. 2. Ecological benefits. 3. Ethical benefits. 1. Narrow utilitarian reasons for direct or economic benefits Man derives maximum economic benefits from nature in the form of food (cereals, pulses fruits), fire wood, construction material, industrial products (tannin, resins, gums, latex, perfumes, dyes) and products of medicinal importance (quinine, reserpine, morphine, nimbin, vincristine), more than 25% of the drugs sold in market are derived from plants, more than 85% of the food materials are obtained from just 20 traditional crop species like cereals, millets, pulses etc. Scientists are busy in exploring molecular genetics and species level diversity for products of economic importance this is called biprospecting. 2. Broadly utilitarian reasons for ecological benefits or services Biodiversity is necessary for maintenance and sustainable utilization of useful products and services from various ecosystems, such as cycling and recycling of nutrients through producers, consumers and decomposers, helps in maintaining climate conditions, soil fertility , pollination of plants, decomposition of waste and services such as purification of air, water mitigating floods and droughts and other environmental disasters. 3. Ethical reasons or benefits Biodiversity has an ethical role. Every species have an intrinsic right to exist and share the wealth of the planet, therefore, it is our moral duty to ensure the well being of all other organisms and leave the biological legacy to future generations. |
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| 17. |
What are homologous organs? What is homology? What do the homologous organs explain as an evidence of organic evolution? |
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Answer» Organs which are similar in origin but perform varied functions are called homologous organs. Example: mouth parts of insects. Homology is phenomenon of having similar origin and basic structures in different species due to their common ancestry for the same phenotype. Homologous organs indicate divergent evolution. |
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| 18. |
How do homologous organs provide evidence in support of evolution? |
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Answer» The presence of homologous organs indicates that all vertebrates have a common ancestry. Similarly all organs and system of the vertebrates show the fundamental similarities Which point towards common ancestry. |
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| 19. |
Antixenosis is a ------------word means against or expelling guest a. Greek b. Japanese c. Italian d. French |
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Answer» Antixenosis is a Greek word means against or expelling guest. |
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| 20. |
What Is Inventory? |
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Answer» Inventory is the accounting of items, component parts and raw materials a company uses in production, or sells. As a business leader, you practice inventory management in order to ensure that you have enough stock on-hand and to identify when there’s a shortage. |
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| 21. |
Illustrate various audio visual aids that are available / needed for e - communication. |
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Answer» Audio Aids examples are Radio, Tape-recorder, Gramophone, Linguaphone, Audio cassette player, Language laboratory. Visual Aids examples are Chart, Black and while board, Maps, Pictures, Models, Text-books, Slide projector, Transparency, Flash-cards, Print materials etc. |
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| 22. |
The eutrophication of water body results in: (A) loss of Biodiversity (B) breakdown of organic matter(C) increase in biodiversity(D) decrease in BOD |
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Answer» Correct option is (A) loss of Biodiversity Eutrophication of water body results in loss of Biodiversity. |
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| 23. |
Which one of the following are analogous structuresA. Flippers of Dolphin and Legs of HorseB. Wings of Bat and Wings of PigeonC. Gills of Prawn and Lungs of Man.D. Thorns of Bougainvillea& Tendrils of Cucurbita |
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Answer» Both (b) and ( c) are corerct wings of insects ,birds and bats are belived to have developed indepedently and are analogous since they perform same fuction .(Evolution by PK Gupta and Evolution by Ridley ) As for Gills of Preawn and Lungs of Man , they are structurally different and fuctionally serve the same function thus are analogous |
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| 24. |
When the margins of sepals or petals over- lap one another without any particular direction, the condition is termed asA. ValvateB. VexillaryC. lmbricateD. Twisted |
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Answer» In vaivate aestivtion - margins of adjacent paetals touch each other without overlapping In Vexillary aestivation-marigins of adjacent touch petal the other margin being overlapped by margin of another adjacent petal. |
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| 25. |
An example of edible underground stem isA. PotatoB. CarrotC. GroundnutD. Sweet potato |
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Answer» Potato-edible underground steam Carrot - edible underground stem Groundut -edible underground root Sweet potato -edible part is seed. Sweet potato -edible part is seed. Sweet potato - edible part is seed . |
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| 26. |
Placenta and pericarp are both edible por- tions inA. PotatoB. AppleC. BananaD. Tomato |
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Answer» Potato- modified stem apple -Thalamus is edible Banana - Mesocarp and Endocarp is edible Tomato - Pericarp and Placenta is stem |
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| 27. |
Select the option which is not correct with respect to enzyme actionA. Malonate is a competitive inhibitor of succinic dehydrogenaseB. Substrate binds with enzyme at its ac- tive siteC. Addition of lot of succinate does not re- verse the inhibition of succinic dehydro- genase by malonateD. A non-competitive inhibitor binds the enzyme at a site distinct from that which binds the substrate |
| Answer» Inhibition of succinate dehydrogenase by malonate is an example of competitive inhibition , where malonate occupies the active site fo the enzyme and blocks it .Howere , this kind of inhibition is reversible and increase in substrate concentration will reverse the inhibition .In non-competitive inhibition the inhibitor binds to the enzyme at a site different form its substrate (i,e the active site ). | |
| 28. |
Which one of the following is wrongly matchedA. Operon - Structural genes, operator and promoterB. Transcription - Writing information from DNA tot-RNAC. Translation - Using information in m- RNA to make proteinD. Repressor protein - Binds to operator to stop enzyme synthesis |
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Answer» Transcription is the general term for synthesis of any kind of RNA on a DNA template. (Biology by Campbell & Reece) NCERT Class XII itself on pg 109, 110 and 111 mentions There is a single DNA-dependent RN A polymerase that catalyses transcription of all types of RNA in bacteria. The RNA polymerase ltranscribes rRNAs and the RNA polymerase Ill is responsible for transcription of tRNA, 5 srRNA and sn RNA Thus, none of the given options is wrongly matched. |
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| 29. |
Select the correct option describing gona- dotropin activity in a normal pregnant femaleA. High level of hCG stimulates the thick- ening of endometriumB. High level of FSH and LH stimulates the thickening of endometriumC. High level of FSH and LH facilitate im- plantation of the embryoD. High level of hCG stimulates the syn- thesis of estrogen and progesterone |
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Answer» In a normal pregnancy hCG from the placenta maintains the corpus luteum and the secretion of estrogen and progesterone by it The FSH and LH levels are suppressed during pregnancy thus both option (b) and (c) are incorrect |
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| 30. |
Which one of the following statements is not correct ?A. Rhodopsin is the purplish red protein present in rods onlyB. Retinal is the light absorbing portion of visual photo pigmentsC. In retina the rods have the photo pig- ment rhodopsin while cones have three different photopigmentsD. Retinal is a derivative of Vitamin C |
| Answer» Retinal is a derivative of Vit. A | |
| 31. |
Choose the correctly matched pairA. Inner surface of bronchioles - squa- mous epitheliumB. Inner lining of salivary ducts - Ciliated epitheliumC. Moist surface of buccal cavity - Glandu- lar epitheliumD. Tubular parts of nephrons - Cuboidal epithelium |
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Answer» (a) Inner surface of bronchioles has ciliated columnar epithelium. (b) Inner lining of salivary ducts has cuboidal epithelium (c) Moist surface of buccal cavity has Non-keratinised stratified squamous epithelium |
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| 32. |
Consider the set the of hyperbola `xy = k, k in R`. Let `e_(1)` be the eccentricity when `k = 4` and `e_(2)` be the eccentricity when `k = 9` then `e_(1) - e_(2) =`A. `-1`B. `0`C. `2`D. `3` |
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Answer» Correct Answer - B `e_(1) = sqrt(2) , e_(2) = sqrt(2)` `e_(1) = e_(2) = sqrt(2) - sqrt(2) = 0` |
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| 33. |
Assisted reproductive to technology. IVF involves transfer ofA. Embryo with 16 blastomeres into the fallopian tubeB. Ovum into the fallopian tubeC. Zygote into the fallopian tubeD. Zygote into the uterus |
| Answer» In IVF and embryo transfer, the zygote or early embryo (upto 8 blastomeres) could be transferred into fallopian tube (ZIFT) and embryos with more than 8 blastomeres into the uterus ( HJT). | |
| 34. |
Identify the hormone with its correct matching of source and functionA. Atrial natriuretic factor - ventricular wall increases the blood pressureB. Oxytocin - posterior pituitary, growth and maintenance of mammary glandsC. Melatonin - pineal gland, regulates the normal rhythm of sleepwake cycle.D. Progesterone - corpus luteum, stimu- lation of growth and activities of female secondary sex organs |
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Answer» (a) Incorrect, as ANF is secreted by the atrial wall and it leads to a decrease in blood pressure. (b) Incorrect, as oxytocin is released by posterior pituitary but is not responsible for growth and maintenance of mammary glands ( d) Incorrect, Progesterone is not responsible for secondary sexual characters and growth of secondary sex organs, it is estrogen which causes these effects |
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| 35. |
Which one of the following is not a correct statementA. A museum has collection of photo- graphs of plants and animalsB. Key is a taxonomic aid for identifica- tion of specimensC. Herbarium houses dried, pressed and preserved plant specimensD. Botanical gardens have collection of living plants for reference |
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Answer» Correct Answer - 1 A museum has a collectio:1 of preserved plant and animal specimens for study and reference. |
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| 36. |
When `MnO_(2)` fused with `KOH`, a coloured compound is formed . The product and its colour is:A. `K_(2)MnO_(4).` greenB. `Mn_(2)O_(3)`, brownC. `Mn_(2)O_(4)`, blackD. `KMnO_(4)`, purple |
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Answer» Correct Answer - 1 Pyrolusite on fusion with KOH in air gives green coloured manganate. `2MnO_(2)+4KOH+O_(2)rarr2K_(2)MnO_(2)("green")+2H_(2)O` |
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| 37. |
Someone _____ my bag! A) was stolen B) has been stolen C) has stolen D) is stolen |
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Answer» Correct option is C) has stolen |
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| 38. |
Which of the following sets of complexes is`//` are correct with respect to the properties indicated against each ?A. `[V(CO)_(6)],K_(4)[Mn(CN)_(6)],Cs_(2)[CuF_(6)]-` Low spin octahedral complex with one unparied electron.B. `K_(2)[NiCl_(4)],[NiCl(PPh_(3))_(3)],[NiCl_(2)(PPh_(3))_(2)]`- Tetrahedral geometry containing two unparied electrons.C. `Cs[CuF_(4)],[Cu(NH_(3))_(4)](NO_(3))_(2),K_(3)[Cu(CN)_(4)]-` Square planar geometry and diamagnetic.D. `K_(4)[Fe(CN)_(6)],[Fe(H_(2)O)_(5)NO]SO_(4),Na_(4)[Fe(CN)_(5)NO]-` Diamagnetic having `+2` oxidation state of central metal atom. |
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Answer» Correct Answer - 1 `(1)` `[V(CO)_(6)]-d^(2)sp^(3)` containing one electron `(d^(5))`. `K_(4)[Mn(CN)_(6)],-d^(2)sp^(3)` containing one unpaired electron `(d^(5))`. `[CuF_(6)]^(2-)-` It is a low spin octahedral complex with one unpaired electron `(d^(7))` `(2)` `[NiCl_(4)]^(2-)` and `[NiCl_(2)(PPh_(3))_(2)]-sp^(3)` containing two unpaired electron `(d^(8))` . `[NiCl(PPh_(3))_(2)-sp^(3)` containing one unpaired electron `(d^(9))`. `(3)` `[CuF_(4)]^(-)-` diamagnetic planar complex with `d^(8)` configuration. `[Cu(NH_(3))_(4)]^(2+)-` paramagnetic planar complex with `d^(9)` configuration. `[Cu(CN)_(4)]^(3-)-` diamagnetic tetrahedral complex with `d^(10)` configuration. `(4)` `[Fe(CN)_(5)]^(4-)-` diamagnetic with `+2` oxidation state of ion. `[Fe(H_(2)O)_(5)NO^(+)]-` paramagnetic with `+1` oxidation state of ion. `[Fe(CN)_(5)NO^(+)]^(2-)-` diamagnetic with `+2` oxidation state of ion. |
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| 39. |
I was given this watch _____ my aunt. A) to B) from C) isD) by |
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Answer» Correct option is D) by |
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| 40. |
Which of the following sets of complexes is/are correct with respect to the properties indicated against each ?A. `[V(CO)_6],K_4[Mn(CN)_6], Cs_2[CuF_6]`-Low spin octahedral complex with one unpaired electronB. `K_2 [NiCl_4], [NiCl(PPh_3)_3], [NiCl_2(PPh_3)_2]`- Tetrahedral geometry containing two unpaired electronsC. `Cs[CuF_4], [Cu(NH_3)_4] (NO_3)_2, K_3[Cu(CN)_4]`-Square planar geometry and diamagneticD. `K_4[Fe(CN)_6], [Fe(H_2O)_5NO]SO_4, Na_4[Fe(CN)_5NO]` - Diamagnetic having +2 oxidation state of central metal atom |
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Answer» Correct Answer - A (A)`[V(CO)_6]-d^2sp^3` containing one unpaired electron `(d^5)` `K_4[Mn(CN)_6]-d^2sp^3` containing one unpaired electron `(d^5)` `[CuF_6]^(2-)`-It is a low spin octahedral complex with one unpaired electron `(d^7)` (B)`[NiCl_4]^(2-) and [NiCl_2(PPh_3)_2]-sp^3` containing two unpaired electrons `(d^8)` `[NiCl(PPh_3)_3]-sp^3` containing one unpaired electron `(d^9)` (C )`[CuF_4]^(-)`-diamagnetic planar complex with `d^9` configuration . `[Cu(CN)_4]^(3-)`-diamagnetic tetrahedral complex with `d^10` configuration. (D)`[Fe(CN)_6]^(4-)`-diamagnetic with +2 oxidation state of iron. `[Fe(H_2O)_5NO^(+)]` -paramagnetic with +1 oxidation state of iron. `[Fe(CN)_5NO^(+)]^(2-)`-diamagnetic with +2 oxidation state of iron. |
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| 41. |
Where _____ these shoes made? A) was B) were C) did D) is |
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Answer» Correct option is B) were |
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| 42. |
Which of the following statements is/are correct ?A. `[Cr(NH_3)_6]^(3+) gt [Mn(CN)_6]^(3-) gt [V(CO)_6]^(3-) gt [Mn(CN)_6]`, with respect to magnetic moment (spin values in B.M.)B. `[Co(CN)_6]^(3-)gt[Co(NH_3)_6]^(3+) gt [Co(H_2O)_6]^(3+)` , With respect to `Delta_0` valuesC. `[Ni(CO)_4] gt [Co(CO)_4]^(-) gt [Fe(CO)_4]^(2-)`, With respect to strength of M-C, `pi`-bond (M=Ni, Co or Fe)D. `[NiCl_4]^(2-) lt [CuCl_4]^(2-) lt [ZnCl_4]^(2-)` ,With respect to stability. |
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Answer» Correct Answer - A,B,D (A)`Cr^(3+)-3d^3` configuration `(t_(2g)^(1,1,1).e_(g)^(0,0)),Mn^(3+)-3d^(4)` configuration `(t_(2g)^(1,1,1).e_(g)^(0,0)),V-3s^5` configuration `(t_(2g)^(1,1,1).e_(g)^(0,0))` (B)`Delta_0prop` strength of ligand for same oxidation state of central metal. (C )In carbonylate anion, the metal has a greater electron density to be dispersed , with the result that M-C,`pi` bonding is enhanced in strength. hence the correct order is `[Ni(CO)_4]lt[Co(CO)_4]^(-)lt [Fe(CO)_4]^(2-)` for strength of M-C , `pi` bond (D)Chelate effect. |
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| 43. |
Concorde, the world’s fastest passenger plane, __(1)__ by France and Britain together. In the 1950s, both countries dreamed of having a supersonic plane, and the project __(2)__ in 1962. £1.5 billion __(3)__ on developing the Concorde, and it __(4)__ for over 5.000 hours, which makes it the most tested plane in history. The first passenger plane __(5)__ by British Airways and Air France in 1976. The Concorde holds many world records, including the fastest crossing of the Atlantic Ocean from New York to London, which __(6)__ in 2 hours 45 seconds! Flying at twice the speed of sound means that flying time __(7)__ by half, which is why the Concorde flight between London and New York __(8)__ a lot by business people and film stars - you can leave Britain at 10.30 and arrive in New York an hour earlier! Twenty planes __(9)__ up to the present day. But there are no plans to build any more. Each plane __(10)__ at a cost of £55 million, which makes them very expensive! 1. A) developed B) have been developed C) was developed D) develops 2. A) was started B) starts C) have been started D) started 3. A) spend B) was spent C) have been spent D) spent 4. A) has tested B) tested C) have been tested D) was tested 5. A) introduce B) has been introduced C) introduces D) was introduced 6. A) have been achieved B) was achieved C) will achieve D) achieved 7. A) was reduced B) has reduced C) is reduced D) will be reduced 8. A) had been used B) uses C) used D) is used 9. A) were built B) are built C) have been built D) build 10. A) is being produced B) is produced C) was produced D) has been produced |
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Answer» 1 C) was developed 2 A) was started 3 C) have been spent 4 D) was tested 5 D) was introduced 6 B) was achieved 7 A) was reduced 8 D) is used 9 C) have been built 10 B) is produced |
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| 44. |
The question consist of two statements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses: Assertion: Co-ordination number of cobalt in the complex `[Co(en)_3]^(3+)` is six. Reason: Ethylenediamine acts as a bidentate ligand.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - A In`H_2oversetuarrddotN-H_2C-CH_2-oversetuarrddotNH_2` two ammine nitrogen atoms act as donor atoms. So, it acts as a bidentate ligand.Hence, there are six `sigma`-bonds between metal and ligands, there by given coordination number six. |
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| 45. |
The only correct combination which product produces intense blue colour with starch paper will be .A. (I)(i)(Q)B. (II)(i)(R)C. Both (A) and (B)D. (IV),(i),(S) |
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Answer» Correct Answer - C `K_2Cr_2O_7+6KI+14H^(+)to8K_((aq))^+ +2Cr_((aq))^(+3)+7H_2O+3I_2` `2KMnO_4+10KI+16H^(+)to12K_((aq))^(+)+2Mn_((aq))^(+2)+5I_2+8H_2O` |
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| 46. |
Select the appropriate combination which gives glycol `[undersetunderset(OH)(|)CH_2-undersetunderset(OH)(|)CH_2]` as a product.A. (IV)(ii)(S)B. (II)(ii)(P)C. (III)(ii)(S)D. (I)(ii)(Q) |
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Answer» Correct Answer - B `2KMnO_4+3CH_2=CH_2+4HOHto2KOH+2MnO_2+[undersetunderset(OH)(|)(3CH_2)-undersetunderset(OH)(|)(CH_2)]` |
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| 47. |
Concentrated sulphuric acid is added followed by heating of each of the following test tubes labelled (i) to Which of the following statement is incorrect about these observations ?A. Evolution of reddish brown gas take place in (ii) test tube and black substance is formed in (i) test tubeB. Evolution of reddish brown gas take place in (iii) test tube and blue solution is formedC. Evolution of neutral colourless gas take place in (iv) test tube and gas burns with blue flameD. Evolution of yellowish green gas take place in (v) test tube and colourless solution is formed |
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Answer» Correct Answer - D (i)`C_12H_22O_11underset("Dehydration")overset(Conc. H_2SO_4)12C (black)+11H_2O` (ii)`2NaBr+2H_2SO_4 to Na_2SO_4 + SO_2+Br_2 uarr` (reddish brown) +`2H_2O` (iii)`2Cu(NO_3)_2+2H_2SO_4to2CuSO_4` (blue solution) +`4NO_2 uarr` (reddish brown) +`O_2+2H_2O` (iv)`K_4[fe(CN)_6]+6H_2SO_4+6H_2Oto2K_2SO_4+FeSO_4+3(NH_4)_2SO_4+6COuarr`(neutral and colourless ) Co burns with blue flame. (v)`KCl+H_2SO_4 to KHSO_4 + HCl uarr` (colourless) |
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| 48. |
Which one of the following statement is correct ?A. From a mixed precipitate of AgCl of Agl, ammonia solution dissolves only AgCl completelyB. `I^-` ions gives red precipitate with `Hg_2^(2+)` ion solutionC. On boiling a solution having `Ca^(2+), K^(+) and HCO_3` ions we get white precipitateD. (A) and (C ) both |
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Answer» Correct Answer - D AgCl is soluble while Agl is partially soluble in concentrated ammonia solution. |
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| 49. |
Which one of the following reagents can be used for differentiating the nitrates of `Cu^(2+)` and `Bl^(3+)`?A. Excess of waterB. `NH_4OH` (excess)C. Excess of KID. All of these |
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Answer» Correct Answer - D (A)`Cu^(2+)+H_2O`(excess) `to` no change `Bi^(3+)+NO_3^(-)+H_2O`(excess)`to BiO(NO_3)darr`(white)+`2H^+` (B)`Cu^(2+)+4NH_4OHto[Cu(NH_3)_4]^(+2)`(deep blue)+`4H_2O` `Bi^(3+)+3NH_4OHtoBi(OH)_3darr`(white)+`3NH_4^(+)` ( C)`Cu^(2+)+4I^(-)toCu_2I_2darr`(white)+`I_2` `Bi^(3+)+4I^(-)to[BiI_4]^(-)`(orange colour solution) |
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| 50. |
The ion that cannot be precipitated by both HCl and `H_2 S` isA. `Pb^(2+)`B. `Cu^+`C. `Ag^+`D. `Sn^(2+)` |
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Answer» Correct Answer - D (A)(B)(C )can be precipitated by HCl as well as `H_2S` as their insoluble chlorides and sulphides respectively. (D)`Sn^(2+)+2HCl toSnCl_2`(soluble)+`2H^+` . It can be precipitated only by `H_2S` as its insoluble sulphide (brown). |
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