This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The restaurant had plenty of tables but ________ . A) one only empty B) only one empty C) no one empty D) no ones empty |
|
Answer» Correct option is B) only one empty |
|
| 2. |
There was a lot of post today but ________ you. A) it’s nothing for either of B) it’s nothing for either C) there’s nothing for either of D) there’s nothing for either |
|
Answer» Correct option is C) there’s nothing for either of |
|
| 3. |
Is that the man ________ yesterday? A) you’ve met B) has met you C) you met D) met you |
|
Answer» Correct option is C) you met |
|
| 4. |
He doesn’t ________ English. A) neither speak or write B) neither speak nor write C) speak or write D) speak nor write |
|
Answer» Correct option is C) speak or write |
|
| 5. |
You can travel ______. A) neither by train or by bus B) either by train or by bus C) either by train nor by bus D) or by train nor by bus |
|
Answer» Correct option is B) either by train or by bus |
|
| 6. |
_____ you leave now, or you’ ll miss the bus. A) Neither B) Nor C) Either D) Or |
|
Answer» Correct option is C) Either |
|
| 7. |
I’m reading a book about ________ of Shakespeare. A) the living B) the existence C) the way D) the life E) the road |
|
Answer» Correct option is D) the life |
|
| 8. |
My brother has curly hair but mine is quite ________. A) even B) regular C) uneven D) level E) straight |
|
Answer» Correct option is E) straight |
|
| 9. |
“Hello. Can I speak to Mr. James, please?” “I’m sorry. He is _____ on holiday at the moment. Can I help you?” A) in B) on C) away D) off |
|
Answer» Correct option is C) away |
|
| 10. |
I’m very busy _____ the moment. A) in B) on C) by D) at |
|
Answer» Correct option is D) at |
|
| 11. |
Sally ________ a little money every week for her holiday. A) puts in B) puts off C) puts by D) puts over E) puts upon |
|
Answer» Correct option is C) puts by |
|
| 12. |
They’re staying with us _____ the time being until they find a place of their own. A) during B) in C) since D) for |
|
Answer» Correct option is D) for |
|
| 13. |
I can’t understand the instructions. They’re _____ Chinese. A) by B) at C) in D) for |
|
Answer» Correct option is C) in |
|
| 14. |
“Romeo and Juliet” is a play _____ William Shakespeare. A) for B) by C) with D) on |
|
Answer» Correct option is B) by |
|
| 15. |
Who is whiter than new snow on a raven s back in Romeo and juliet |
|
Answer» According to Juliet, Romeo is whiter than new snow on the back of a raven. Romeo looks whiter than snow on the back of a raven. |
|
| 16. |
How does romeo describe Juliet |
|
Answer» Romeo initially describes Juliet as a source of light, like a star, against the darkness: "she doth teach the torches to burn bright! It seems she hangs upon the cheek of night." As the play progresses, a cloak of interwoven light and dark images is cast around the pair. |
|
| 17. |
Romeo Juliet summary |
|
Answer» Romeo and Juliet fall in love at a party. But they come from families which hate each other. They are sure they will not be allowed to marry. Nevertheless, helped by Friar Laurence, they marry in secret instead. Unfortunately, before their wedding night Romeo kills Juliet's cousin in a duel, and in the morning he is forced to leave her. If he ever returns to the city, he will be put to death. Juliet's parents told her she must marry Paris. Her parents do not know she is already married. She refuses in the beginning, but later agrees because she plans to fake her death and escape to be with Romeo forever; again with the help of Friar Laurence. Frair Laurence designs the plan. He gives Juliet a sleeping potion. She appears to be dead and was put in a tomb. However, Romeo does not know about the plan, visits her grave, thinks she is dead, and kills himself. When Juliet finally wakes up, she discovers that Romeo is dead and then kills herself. |
|
| 18. |
In which years was the office of Divisional Commissioner abolished and revived thereafter ?1. Abolished in 1962 and revived in 19712. Abolished in 1959 and revived in 19873. Abolished in 1966 and revival in 19734. Abolished in 1962 and revived in 1987 |
|
Answer» Correct Answer - Option 4 : Abolished in 1962 and revived in 1987 The correct answer is Abolished in 1962 and revived in 1987.
|
|
| 19. |
Which Nishad king was the father of Ekalvya? |
|
Answer» Hiranyadhanus |
|
| 20. |
Name the conch of Nakula |
|
Answer» Correct answer is Sughosha |
|
| 21. |
Where is 'Guru Ka Lahor' situated?1. Sirmour2. Kullu3. Chamba4. Bilaspur |
|
Answer» Correct Answer - Option 4 : Bilaspur The correct answer is Bilaspur.
|
|
| 22. |
The king of chedis, he was killed by Krishna during Rajsuya-yagna. Name the king |
|
Answer» Correct answer is Sisupala |
|
| 23. |
A Bengali film based on Saratchandra Chatterjee novel Pather Dabi (The demand of the road) was made on him. The film was called Sabysachi-one of the names of Arjuna who could use both his hands equally well in battle. Name the Indian revolutionary |
|
Answer» Rashbehari Bose |
|
| 24. |
Identify the correct statement:A. `0.1 M NaCl` and `0.1 M` glucose solution are isotonicB. `0.1 M NaCl` and `0.3 M` glucose solution are isotonicC. The boiling point of `0.1 m` aqueous urea solution is less the `0.1 m` aqueous KCl solutionD. The freezing point of `0.1 m` glucose solution is less than `0.1 m KCl` solution. |
|
Answer» Correct Answer - C `pi_(NaCl) = i xx CRT " " pi_(glr cos e) = 1 xx 0.1 xx RT` `= 2 xx 0.1RT " " = 0.1 RT` `= 0.2 RT " " pi_(NaCL) != pi_(glu cos e)` `DeltaT_(b(NaCl)) = 2 xx 0.1K_(f) " " DeltaT_(b(urea)) = 0.1 K_(f)` Hence `DeltaT_(b(urea)) lt Delta T_(b(NaCl))` `Delta T_(f(glucos e)) = 0.1 xx K_(f) " " Delta T_(f(KCl)) = 2 xx 0.1 xx K_(f)` `Delta T_(f) = 0.2 K_(f)` `T_(f(glucos e)) gt T_(f(KCl))` |
|
| 25. |
A reaction is carried out at `600 K`. If the same reaction is carried out in the presence of catalyst at the same rate and same frequency factor, the temperature required is `500 K`. What is the activation energy of the reaction, if the catalyst lowers the activation energy barrier by `20 KJ//mol` ?A. 100B. 120C. 80D. None of these |
|
Answer» Correct Answer - B `k = Ae^(- Ea//R xx 600)` `k^(c ) = Ae^((Ea - 20)/(R - 500))` `k = k^(c )` `(Ea)/(R xx 600) = ((Ea - 20))/(R xx 500)` `(Ea)/(6) = (Ea - 20)/(5)` `20 = Ea - (5)/(6)Ea` `Ea = 20 xx 6` `Ea = 120 KJ//mol` |
|
| 26. |
When pressure is applied to equilibrium system: Ice `hArr` Water Which of the following statement is correct ?A. More amount of ice will formB. Melting poin of ice decreasesC. Equilibrium will not disturbD. Both (A) and (B) |
|
Answer» Correct Answer - B Melting point of ice decreases hence more amount of `H_(2)O(l)` will form on increasing pressure. |
|
| 27. |
The ratio of coefficient of `HNO_(3), Fe(N)_(3))_(2)` and `NH_(4)NO_(3)` in the following redox reaction `Fe + HNO_(3) rarr Fe (NO_(3))_(2) + NH_(4)NO_(3) + H_(2)O` are respectivelyA. `10 : 1 : 4`B. `4 : 10 : 1`C. `4 : 1 : 10`D. `10 : 4 : 1` |
|
Answer» Correct Answer - D `4 Fe + 10HNO_(3) rarr 4Fe(NO_(3))_(2) + 3H_(2)O` |
|
| 28. |
The enthalpy of neutralisation of a strong acid by a string base is `-57.32 kJ mol^(-1)`. The enthalpy of formation of water is `-285.84 kJ mol^(-1)`. The enthalpy of formation of hydroxyl ion isA. `+ 228.52 KJ//mol`B. `- 114.26 KJ//mol`C. `- 228.52 KJ//mol`D. `+ 114.2 KJ//mol` |
|
Answer» Correct Answer - C `H^(+) (aq). + OH^(-) (aq) rarr H_(2)O (l)` `Delta_(r )H = Delta_(f)H_(H_(2)O) - (Delta_(f)H_((H^(+)(aq))) + Delta_(f)H_((OH^(-))))` `-57.32 = 285.84 - (0 + Delta_(f)H_((OH^(-)(aq))))` `Delta_(f)H_(OH^(-)(aq)) = -228.52 KJ//mol` |
|
| 29. |
Which acid is stronger ?A. `HA (pK_(a)=4.7)`B. `HB (pK_(a)=3)`C. `HC (pK_(a)=2)`D. `HD (pK_(a)=2.7)` |
| Answer» Correct Answer - C | |
| 30. |
The ionisation constant `(K_(a))` of `0.1 M` weak monobasic acid `(HA)` will be whose degree of ionisation is `50%` ?A. `25xx10^(-3)`B. `25xx10^(-4)`C. `5xx10^(-2)`D. `5xx10^(-5)` |
| Answer» Correct Answer - C | |
| 31. |
Electrode potential is-(a) 1.36 V(b) 1.30 V(c) 1.42 V(d) 1.20 V |
|
Answer» Answer is (c) 1.42 V |
|
| 32. |
What happens when `H_2PO_3` is heated? |
|
Answer» `H_3PO_4overset(Delta)toPH_3+H_2PO_4` on heating `H_3PO_3` undergoes disproportionation to form `PH_3` and `H_3PO_4`. |
|
| 33. |
Which of the following gives yellow or brown precipitate with alkaline Nessler's reagent?(a) CO2(b) NH3(c) NaCl(d) KI |
|
Answer» Answer is (d) KI |
|
| 34. |
Which one of the following complexes is an outer orbital complex? a). [Fe (CN)6]4- b). [Mn(CN)6]4- c). [Co (NH3)6]3+ d). [Ni (NH3)6]2+ [Atomic nos.: Mn = 25, Fe= 26, Co = 27, Ni = 28] |
|
Answer» d). [Ni (NH3)6]2+ |
|
| 35. |
The vapour pressure of a solvent decreased by 10 mm of mercury when a nonvolatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mm of mercury? a). 0.4 b). 0.6 c). 0.8 d). 0.2 |
|
Answer» Answer is (b) 0.6 |
|
| 36. |
A 5% solution of cane sugar (Mol. Wt = 342) is isotonic with 1% solution of substance X. The molecular weight of X. is-(a) 68.4(b) 34.2(c) 171.2(d) 136.2 |
|
Answer» Answer is (b) 34.2 |
|
| 37. |
A 5% solution of cane sugar (mol. wt. = 342) is isotonic with 1% solution of a substance X. The molecular weight of X isa). 68.4 b). 171.2 c). 34.2 d). 136.8 |
|
Answer» The molecular weight of X is 68.4 |
|
| 38. |
While assigning R,S configuration the correct order of priority of groups attached to chiral carbon atom isA. `CONH_(2) gt COCH_(3) gt CH_(2)OH gt CHO`B. `CONH_(2) gt COCH_(3) gt CHO gt CH_(2)OH`C. `COCH_(3) gt CONH_(2) gt CHO gt CH_(2)OH`D. `CHO gt CH_(2)OH gt COCH_(3) gt CONH_(2)` |
|
Answer» Correct Answer - B Priority of groups attached chiral carbon atom is based on atomic number. `overset(O)overset(||)C-NH_(2) gt overset(O)overset(||)C-CH_(3) gt overset(O)overset(||)C -H gt CH_(2)OH` |
|
| 39. |
What are limitation of VB theory |
|
Answer» As we pointed out earlier, nothing is perfect! In a similar way, the Valence Bond theory is also not perfect. It has its own set of limitations. They are:
|
|
| 40. |
How would you account for the following? (a) [Ti (H2O)6]3+ is coloured while [Sc (H2O)6]3+ is colourless. (b) [Fe (CN)6]3- is weakly paramagnetic while Fe (CN)6]4- is diamagnetic. (c) [Ni (CO)4 ] possess tetrahedral geometry while is [Ni (CN)4]2- is square planner. |
|
Answer» (a) In [Ti (H2O)6 ]3+, metal ion has d1 configuration. Because of this unpaired electron, d-d transition is possible and hence, it appears coloured.In [Sc (H2O)6] 3+, no unpaired electron is present in the d-subshell of metal ion hence, d-d transition is not possible, therefore, it would be colourless. (b) In [Fe (CN)6]3- ,Fe is in +3 oxidation state and has 5 unpaired electrons in its d-orbitals. This complex is formed due to d2 Sp3 hybridisation, after the pairing of d- electrons (because of strong ligand field of CNions).These six hybridised orbitals receive six electron pairs from six molecules of CNbut one electron in d-subshell remains unpaired , hence it is weakly paramagnetic. But in [Fe (CN)6]4-, the oxidation state of iron is +2 and has d6 configuration. These six electrons get paired under the influence of ligand molecules and no electron remains unpaired in d-orbitals, therefore, it is diamagnetic. (C) In [Ni (CO)4], Ni is in zero oxidation state and is Sp3 oxidised. As a result, it possess tetrahedral geometry. While in [Ni (CN)4]2- , Ni is in +2 oxidation state and is dsp2 hybridised. As a result, it is square planner |
|
| 41. |
In a semiconductor diode p-side is earthed and N-side is applied a potential of -2V, the diode shallA. conductB. not conductC. conduct partiallyD. break down |
|
Answer» Correct Answer - A Potenial on p-side `V_(p) = 0` Potential on n - side `V_(n) = - 2` As `" "V_(p)gt V_(n)` i.e., diode is in forwards bias, so it will condut . |
|
| 42. |
Assuming that the function diode is ideal, the current in the arrangement shown in figure is . A. zeroB. 2 mAC. 10 mAD. 30 mA |
|
Answer» Correct Answer - A Here,in the circuit the diode is in reverse biase, so current will be zero. |
|
| 43. |
In the given circuit the potential at point B is zero, the potential at points A and D will be A. `V_(A) = 4 V, V_(D) = 9V`B. `V_(A) = 3V,V_(D) = 4V`C. `V_(A) = 9V, V_(D) = 3V`D. `V_(A) = 4V, V_(D) = -3V` |
|
Answer» Correct Answer - D From the given circulit `V_(A) - V_(B) = 2 xx 2 = 4V` According to question `V_(B) =0` Point D is connected to positive terminal of battery of emf 3V. As, `V_(B) -V_(C) = 2xx 3 = 6V` `therefore V_(D) - V_(C) = V_(D) - (-6) = 3V` ` rArr V_(D) = 3 - 6 = - 3V` |
|
| 44. |
An alternating voltage `E=200sqrt(2)sin(100t)` is connected to a `1` microfarad capacitor through an AC ammeter. The reading of the ammeter shall beA. 10 mAB. 22 mAC. 40 mAD. 80 mA |
|
Answer» Correct Answer - B `l_(V) = (E_(V))/(X_(C)) = (E_(V))/(1//omegaC) = E_(V) (omegaC)` ` = 220 xx 100 xx 10^(-6)` `= 22 xx 10^(-3)A = 22mA` |
|
| 45. |
The magnetic flux `phi` (in weber ) in a closed circuit of resistance 10`Omega` varies with time t (in secnod) according to equation `phi=6t^(2)-5t+1`. The magnitude of induced current at `t=0.25` s isA. `0.2A`B. 0.6AC. 1.2AD. 0.8A |
|
Answer» Correct Answer - A We know that `e = - (dphi)/(dt)` ` = -(d)/(dt) (6t^(2) - 5t+1)` ` e=- 12 t + 5` ` e= - 12 xx 0.25 + 5 = 2V` `therefore " " I =(e )/(R) = (2)/(10) = 0.2A` Reading of the ammeter. |
|
| 46. |
In series LCR circuit `R = 18 Omega` and impedence is `33 Omega`. An Vrms voltage `220 V` is applied across the circuit . The true power consumed in AC circuit isA. 220WB. 400WC. 600WD. 800W |
|
Answer» Correct Answer - D `P=e_(rms). i_(rms) cos phi` `=e_(rms.) (e_(rms))/(z). R/z` `=(220 xx 220 xx 18)/(33 xx 33)` `=(20 xx 20 xx 18)/(3 xx 3)` `=20 xx 20 xx 2=800 W`. |
|
| 47. |
The magnetic flux `(phi)` linked with the coil depends on time `t` as `phi=at^(n)`, where `a` and `n` are constants. The emf induced in the coil is `e`A. If `0 lt n lt 1, e ne 0` and |e| decrease with timeB. If `n = 1`, e is constantC. If `n gt1, |e|` increase with timeD. None of these |
|
Answer» Correct Answer - 4 `phi = "at"^(n)` `e = (dphi)/(dt) = "nat"^(4-1)` If `0 lt n lt 1` power of t is - ve hence `tdarreuarr` If n=1 , `phi`= at , `e=(dphi)/(dt) = a` If `n gt 1` So from the expression `e = nat^(n-1)` `edarr as t uarrs` |
|
| 48. |
A wire is bent to form the double loop shown in figure. There is a uniform magnetic field directed into the plane of the loop. If the magnitude of this field is decreasing current will flow from: A. A to B and C to DB. B to A and D to CC. A to B and D to CD. B to A and C to D |
|
Answer» Correct Answer - C As inward B decreases, so CW current in bigger loop & ACWcurrent in smaller loop. |
|
| 49. |
Which type of image is formed by convex mirror?A. Real, inverted and enlargedB. Real, inverted and diminishedC. Virtual, erect and enlargedD. Virtual, erect and diminished |
|
Answer» Correct Answer - D |
|
| 50. |
A plane progessive wave of frequency `25 Hz`, amplitude `2.5 xx 10^-5 m` and initial phase zero propagates along the negative x-direction with a velocity of `300 m//s`. At any instant, the phase difference between the oscillations at two points `6 m` apart the line of propagation is _____ and the corresponding amplitude difference is _____ m. |
|
Answer» `u = 300 m//s` and `n = 25` `:. lamda = (u)/(n) =(300)/(25) = 12 m` For a path difference of `lamda`, the phase difference is `2 pi`. For a path difference of `6 m`, the phase difference is `(2 pi xx 6)/(lamda) = pi rad` The amplitude is same at both points, hence amplitude different is zero. |
|