This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Complete the following dialogue between a Bus commuter and Conductor. Prasad : Sir, May I know when is the next bus to Kanyakumari? Conductor : (i) ……… Prasad: (ii) ……… Conductor : Yes it is Point to point bus and it should reach the destination by 9 a.m. sir. Prasad : Does it stop anywhere midway for refreshment? Conductor : Yes. It halts twice midway for refreshing. |
|
Answer» (i) The next bus is at 11 p.m., sir. (ii) Is it a point to point bus and when is it expected to reach the destination? |
|
| 2. |
Complete the following dialogue between two classmates meeting after a decade. Suresh : Hello, aren’t you Chandrasekar by any chance? Chandrasekar : Er.. yes I am but (i) ………… Suresh : Yes, I surely look different (ii) ………… Chandrasekar : Oh Suresh, I recall now. You surely look robust! How have you been? Suresh : I’m good thank you. So glad to meet you after such a long time. Chandrasekar : Yes. Me too. (iii) …………… |
|
Answer» (i) I am afraid, I cannot recognize you. (ii) I am Suresh, your classmate from Agarwal School. (iii) I recently got transferred here. |
|
| 3. |
Complete the following dialogue between two classmates discussing after exam. Apoorva : Hello Chaitanya! (i) ………… Chaitanya : It was a good and 1 hope to get centum. How about you? Apoorva : (ii) ………… Chaitanya : Forget it and just don’t bother about the past. I am sure you will get centum too. Apoorva : Thanks. But I don’t think I will make it this time. Chaitanya : Be positive. Keep your fingers crossed |
|
Answer» (i) How did you do the paper? (ii) I think, I have made a mess in one five mark answer. |
|
| 4. |
Put the verbs in brackets into the correct Past Tense:(i) I (meet) him on Monday.(ii) Reena and Sohan (go) to work by car.(iii)The children were frightened because it (get) dark.(iv)While they (watch) TV somebody entered the house from the back.(v) My wife and I (talk) about you the other day. |
|
Answer» (i) met (ii) went (iii)was getting (iv) were watching (v) were talking. |
|
| 5. |
Complete the following dialogue between a Patient and a Clinic Receptionist.Patient : Is Dr. Mohanty available this evening? I have a review meet on Monday. Receptionist: I am sony madam, (i) ……………Patient : (ii) ………… Receptionist: Yes madam. You may please confirm the appointment for Wednesday at 8 p.m. Patient : Thank you. Receptionist: No mention. Please be here half an hour before time |
|
Answer» (i) he is out of station and is expected to see patients from Wednesday. (ii) Can I fix an appointment for Wednesday, please? |
|
| 6. |
A small ball is moving on the flat surface (without rotation) such that its position is given by:where ex and ey are two unit vectors along the axis x and y. How can ı find the angle between velocity v(t) and the acceleration a(t) as t = 1? |
|
Answer» Given that the position vector of the moing ball at t th instant is given by r(t)= t.ex- sin(t).ey Differentiating wrt t we get velocity vector v(t)= r'(t)= 1.ex-cos(t).ey Hence the angle of velocity vector with the positive direction of x axis at t=1 is in 4th quadrant and the angle of inclination is tan^-1cos(1) Now the accleration at t th instant is a(t)=v'(t)=sin(t).ey Hence acceleration vector is directed towards +ve direction of y axis . So angle beween accleration and velocity vector at t=1 is given by π/2+tan^-1cos(1) |
|
| 7. |
Combine the following sets of simple sentences into one simple sentences:(i) Mrs. Naidu was standing by his side. Mrs. Naidu cried, ‘Hail, Deliverer.’(ii) Gandhi returned to the beach. Gandhi picked up some salt.(iii) They walked at a fast pace. They covered two hundred miles in twenty four days.(iv) The crowd shouted slogans. The crowd marched to the collector’s office.(v) The President took his seat on the platform. The meeting began.(vi) The students had left for their homes. The campus looked deserted.(vii) He raised his hand. He asked the people to be quiet |
|
Answer» (i) Standing by his side, Mrs. Naidu cried, ‘Hail, Deliverer. (ii) Returning to the beach, Gandhi picked up some salt. (iii) Walking at a fast pace, they covered two hundred miles in twenty four days. (iv) Shouting slogans, the crowd marched to the collector’s office. (v) Taking his seat on the platform, the President began the meeting. (vi) The students having left for their homes, the campus looked deserted. (vii) Raising his hand, he asked the people to be quiet. |
|
| 8. |
I enjoyed that book so much that I read it from ________ to end in one day. A) opening B) beginning C) start D) commencement E) introduction |
|
Answer» Correct option is B) beginning |
|
| 9. |
Area A) source B) farm C) beach D) region |
|
Answer» Correct option is D) region |
|
| 10. |
Gift A) present B) punishment C) penalty D) fine |
|
Answer» Correct option is A) present |
|
| 11. |
The _______ of ice-cream sold increases sharply in the summer months. A) account B) amount C) count D) number E) size |
|
Answer» Correct option is B) amount |
|
| 12. |
The kidnappers demanded a ________ of £509.000. A) forfeit B) ransom C) penalty D) fine E) reward |
|
Answer» Correct option is B) ransom |
|
| 13. |
If there is an earthquake, you should make ______ the park. A) out B) up C) for |
|
Answer» Correct option is C) for |
|
| 14. |
It was so foggy that she couldn’t make ______ the road ahead. A) out B) over C) up |
|
Answer» Correct option is A) out |
|
| 15. |
It took 20 years for them to make ______ after their fight. A) up B) over C) out |
|
Answer» Correct option is A) up |
|
| 16. |
The man made ______ with all her money. A) for B) off C) up |
|
Answer» Correct option is B) off |
|
| 17. |
He ______ silly questions until my patience finally ran out. A) has kept asking B) kept asking C) had been kept asking D) was kept asking |
|
Answer» Correct option is B) kept asking |
|
| 18. |
I wish they wouldn't just rush in, eat really quickly, and then leave. A) snippet B) stop it up C) scarf it down |
|
Answer» Correct option is C) scarf it down |
|
| 19. |
I wish she wouldn’t make ______ stories like that. A) for B) up C) over |
|
Answer» Correct option is B) up |
|
| 20. |
I wish you wouldn’t keep _______ my time asking such silly questions. A) losing B) spending C) wasting D) engagingE) occupying |
|
Answer» Correct option is C) wasting |
|
| 21. |
Her husband felt it would be silly to ________ the color of the curtains before they had painted the room. A) change B) find C) chooseD) lose E) charge |
|
Answer» Correct option is C) choose |
|
| 22. |
Figure shows two unequal point charges, q and Q, of opposite sign. Charge Q has greater magnitude than charge q. In which of the regions X, Y, Z will there be a point at which the net electric field due to these two charges is zero?A) only region X B) only regions X and Z C) only region Y D) only region Z E) all three regions |
|
Answer» Correct option is A) only region X |
|
| 23. |
Energy required per unit mass of substance to raise temperature of that substance by 1 K is called A. enthalpy B. internal energy C. specific heat capacity D. temperature |
|
Answer» C. specific heat capacity |
|
| 24. |
Which of the following statements distinguishes excitatory chemical synapses in the brain from the neuromuscular junction? |
|
Answer» Answer: Temporal summation and spatial summation onto the postsynaptic cell increase the likelihood that a postsynaptic. action potential will be evoked. In contrast to other neuronal synapses, the individual EPSPs (or |
|
| 25. |
In a certain experiments to measure the ratio of charge to mass of elementry particles, a surprising result was obtained in which two particle, a surprising result was obtained in which two particles moved in such a way that the distance between them always remained constant. It was also noticed that this two-particle system was isolated from all other particles and no force was acting on this system except the force between these two mases. After careful observation followed bu intensive calculation, it was deduced that velocity of these two particles was always opposite in direction and magnitude of velocity was `10^(3) ms^(-1) and 2 xx 10^(3) ms^(-1)` for first and second particle, respectively, and mass of these particles were `2 xx 10^(-30) kg and 10^(-30)kg`, respectively. Distance between them were 12Å(1Å = 10^(-`10)m).` if the first particle is stopped for a moment and then released, the velocity of center of mass of the system just after the release will beA. `1/3 xx 10^(-30)ms^(-1)`B. `1/3 xx 10^(3) ms^(-1)`C. `2/3 xx 10^(3) ms^(-1)`D. none of these |
|
Answer» Correct Answer - C Just after release, `V_(CM)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))` `=((2xx10^(-30))(0)+(10^(-30))(2xx10^(3)))/(3xx10^(-30))=(2)/(3)xx10^(3)ms^(-1)` |
|
| 26. |
In a certain experiments to measure the ratio of charge to mass of elementry particles, a surprising result was obtained in which two particle, a surprising result was obtained in which two particles moved in such a way that the distance between them always remained constant. It was also noticed that this two-particle system was isolated from all other particles and no force was acting on this system except the force between these two mases. After careful observation followed bu intensive calculation, it was deduced that velocity of these two particles was always opposite in direction and magnitude of velocity was `10^(3) ms^(-1) and 2 xx 10^(3) ms^(-1)` for first and second particle, respectively, and mass of these particles were `2 xx 10^(-30) kg and 10^(-30)kg`, respectively. Distance between them were 12Å(1Å = 10^(-`10)m).` Acceleration of the second particle wasA. `5 xx 10^(15) ms^(-2)`B. `4 xx 10^(16)ms^(-2)`C. `2 xx 10^(16)ms^(-2)`D. zero |
|
Answer» Correct Answer - A Acceleration of second particle is `(v_(2)^(2))/(r_(2))=((2xx10^(3))^(2))/((8xx10^(-12)))=5xx10^(15)ms^(-2)` |
|
| 27. |
In a certain experiments to measure the ratio of charge to mass of elementry particles, a surprising result was obtained in which two particle, a surprising result was obtained in which two particles moved in such a way that the distance between them always remained constant. It was also noticed that this two-particle system was isolated from all other particles and no force was acting on this system except the force between these two mases. After careful observation followed bu intensive calculation, it was deduced that velocity of these two particles was always opposite in direction and magnitude of velocity was `10^(3) ms^(-1) and 2 xx 10^(3) ms^(-1)` for first and second particle, respectively, and mass of these particles were `2 xx 10^(-30) kg and 10^(-30)kg`, respectively. Distance between them were 12Å(1Å = 10^(-`10)m).` Acceleration of the first particle wasA. zeroB. `4 xx 10^(16)ms^(-2)`C. `2 xx 10^(16)ms^(-2)`D. `2.5 xx 10^(15)ms^(-2)` |
|
Answer» Correct Answer - D The two particles move in different circles. The mutual interaction force provides the required centripetal force to the particle, as magnitude of the intersection force is same we get `F_(12)=(m_(1)v_(1)^(2))/(r_(1))` and `F_(21)=(m_(2)v_(2)^(2))/(r_(2))` `|vecF_(1)|=|vecF_(2)|` or `(m_(1)v_(1)^(2))/(r_(1))=(m_(2)v_(2)^(2))/(r_(2))` putting values we get `r_(2)=2r_(1)` Also, `r_(1)+r_(2)=12xx10^(-12)m` (given) `r_(1)=4xx10^(-12)m,r_(2)=8xx10^(-12)m` Acceleration of first particle `=(v_(1)^(2))/(r_(1))=((10^(3))^(2))/((4xx10^(-12)))` `=2.5xx10^(15)ms^(-2)` |
|
| 28. |
What is the force that a conductor \(\vec{dl}\) carrying a current I experiences, when placed in a magnetic field\(\vec B\), when its length is making an angle of 30˚ with the direction of field? |
|
Answer» \(|\vec {dF}|=I|\vec{dl}\times \vec B|\) = I.dl.B sin30˚ = \(\frac{I\,dl.B}{2}\) |
|
| 29. |
Acceleration - velocity graph of a particle moving in a straight line is as shown in figure. Then slope of velocity displacement graph : A. increases linearlyB. decreases linearlyC. in constantD. increases parabolically |
|
Answer» Correct Answer - C a = kv (from graph) `(vdv)/(dx) = kv` `(dv)/(dx) = k =` const. |
|
| 30. |
A slit of width ‘d’ is illuminated by light of wavelength 5000 Å. For what value of ‘d’ will the first maximum fall at an angle of diffraction of 30˚. |
|
Answer» Here, λ = 5000Å = 5× 10−7m d = ?; n = 1 ; θ = 30˚ For maxima of diffraction, d sin θ = (2n + 1)\(\frac{λ}{2}\) or, d = \(\frac{(2n+1)\lambda}{2sin\theta}\) = \(\frac{3\times 5\times 10^{-7}}{2sin\,30°}\) = 1.5× 10−6 m. |
|
| 31. |
For what distance is ray optics a good approximation when the aperture is 3mm wide and wavelength is 500 nm? |
|
Answer» Here, a = 3mm = 3 × 10−3m λ = 500 nm = 5× 10−7m Fresnel distance, ZF = ? ZF = \(\frac{a^2}{\lambda}\) = \(\frac{(3\times 10^{-3})^2}{5\times 10^{-7}}\) = 18m |
|
| 32. |
We know that electric field (E ) at any point in space can be calculated using the relation `vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk` if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as `V = 2x^2`, where x is in meter. Its variation is as shown in figure Will the particle perform a simple harmonic motion? Also, find the time period of its oscillations.A. Yes, time period `= 2pis`.B. No, time period `= 2pis`C. Yes, time period `= 4pis`.D. The particle will perform SHM, but time period cannot be found from the given data. |
|
Answer» Correct Answer - A `F=-10^(-5)x` `ma=-10^(-5)x` or `10xx10^(-6)a=-10^(-5)x` or `a=-x` `omega^(2)=1,omega=1rad. T=(2pi)/(omega)=(2pi)/(1)=2pis` |
|
| 33. |
We know that electric field (E ) at any point in space can be calculated using the relation `vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk` if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as `V = 2x^2`, where x is in meter. Its variation is as shown in figure A charge particle of mass 10 mg and charge `2.5 muC` is released from rest at `x = 2 m`. Find its velocity when it crosses origin.A. `0.5ms^(-1)`B. `1 ms^(-1)`C. `2ms^(-1)`D. `4 ms^(-1)` |
|
Answer» Correct Answer - C `E=-(dV)/(dx)=-4x` `F=qE=2.5xx10^(-6)(-4x)=-10^(-5)x` `W=underset(2)overset(0)int Fdx=-10^(-5)underset(2)overset(0)intxdx` `(1)/(2)mv^(2)=10^(-5)[(x^(2))/(2)]_(0)^(2)` or `V=2ms^(-1)` |
|
| 34. |
We know that electric field (E ) at any point in space can be calculated using the relation `vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk` if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as `V = 2x^2`, where x is in meter. Its variation is as shown in figure Draw the variation of electric field (E ) along the x-axis.B. C. D. |
|
Answer» Correct Answer - C `E=-(dV)/(dx)=-4x` `F=qE=2.5xx10^(-6)(-4x)=-10^(-5)x` `W=underset(2)overset(0)int Fdx=-10^(-5)underset(2)overset(0)intxdx` `(1)/(2)mv^(2)=10^(-5)[(x^(2))/(2)]_(0)^(2)` or `V=2ms^(-1)` |
|
| 35. |
An polaroid long cylindrical object with radius R has a charge distribution that depends upon distance r from the axis like this : `rho = ar + br^(2)(r le R`, a and b are non zero constant, `rho` is volume charge density). If electric field outside the cylinder is zero than value of `(a)/(b)` is :A. `3R//4`B. `-3R//4`C. `-4R//3`D. `4 R//3` |
|
Answer» Correct Answer - B By Gauss Theoren Net charge inside cylinder =0 `rArr int (2 pi r dr)h rho=0 rArr underset(O)overset(R)(int) (ar+br^(2))rdr =0` `rArr (aR^(3))/(3)+(bR^(4))/(4) =0rArr (a)/(b) =-(3R)/(4)` |
|
| 36. |
A man of mass 50 kg is pulling on a plank of mass 100 kg kept on a smooth floor as shown with force of 100 N. If both man & plank move together, the force of friction acting on man is `(100)/(x)`N. What is x ? |
|
Answer» Correct Answer - 3 N If the blocks are not sliding w.r.t each other than they can be considered one system `F - f = 3a` maximum value of a = 0 `F - 0.1 xx 3kg xx10ms^(-2)=0` F = 3N |
|
| 37. |
A polaroid is placed at `45^@` to an incoming light of intensity `I_0`. Now the intensity of light passing through polaroid after polarisation would beA. `I_(0)`B. `I_(0)//2`C. `I_(0)//4`D. zero |
|
Answer» Correct Answer - B `I=I_(0) cos^(2)theta = I_(0)cos^(2)45 = (I_(0))/(2)` |
|
| 38. |
In the figure, what should be mass m so that block A slide up with a constant velocity? |
|
Answer» Correct Answer - 1 sec `a_("rel")=2((4-1)/(4+1))hat(j)=12ms^(-2)` `l= 6m` `l=(1)/(2)a_("rel")t^(2)` `6=(1)/(2)xx12xxt^(2)` `t = 1s` |
|
| 39. |
In figure shown, pulley are ideal `m_(1) gt 2m_(2)`. Initially the system is in equilibrium and string connecting `m_(2)` to rigid support below is cut. Find the initial acceleration of `m_(2)` If `m_(1)= 6 kg , m_(2) = 2.5 kg " and "g =10ms^(-2)` |
|
Answer» Correct Answer - 3 Contact force between the block and the belt is 10.5 N |
|
| 40. |
Which of the following are isoelectronic species, i.e., those having the same number of electrons: `Na^(o+), K^(o+), Mg^(2+), Ca^(2+), S^(2-), Ar` |
|
Answer» `(Na^(o+), Mg^(2+))," "Na^(o+)=11-1=10` `Mg^(2+)=12-2=10` `Ca^(2+), Ar," " Ca^(2+)=20-2=18` `Ar=18` `S^(2-)," " K^(o+), S^(2-)=16+2=18` `K^(o+)=19-1=18` |
|
| 41. |
`A` and `B` are two hydrogen like atoms such that `m_(B)=2m_(A)`. Also, the number of protons and neutrons in the two nuclei are equal. Given that difference of photon energy corresponding to the first Balmer lines emitted by `A` and `B` is `2.667eV`. Let `Z_(A)` and `Z_(B)` be the atomic numbers of `A` and `B` respectively.A. `Z_(A)=4`B. `Z_(A)=1`C. `Z_(B)=2`D. `Z_(B)=8` |
|
Answer» Correct Answer - B::C `m_(B)=2m_(A)impliesZ_(B)=2Z_(A)`. Let `Z_(A)=Z, Z_(B)=2Z` So, `E_(B)-E_(A)=(13.6xx5)/36xx3Z^(2)=5.667` `implies Z=1` |
|
| 42. |
If radiation corresponding to first line "Balmer series" of `He^(+)` ion is subjected to a sample of `Li^(+2)` ion (containing atoms in different energy states) and it causes ejection of photo electron with non-zero kinetic energy then calculate least shell number in which the electron must be present in `Li^(+2)`. |
|
Answer» Correct Answer - 5 `13.6xx2^(2) (1/(2^(2))-1/(3^(2))) gt 13.6 xx(3^(2))/(n^(2))` `n gt 4.1 " " , " " n=5` |
|
| 43. |
A hydrogen like atom in ground state absorbs `n` photon having the same energy and its emits exacity `n`` photon when electrons transition takes placed .Then the energy of the absorbed photon may beA. `91.8 eV`B. `40.8 eV`C. `48.4 eV`D. None of these |
|
Answer» Correct Answer - A::B No. of drank lines (in absorption) i.e. ecitation `=` No. of bright lines (in emission) i.e. de-excitation [is possible only when the `e^(-) s` is excited to `n = 2` from ground state] Cleraly, `DeltaE = underset((Li^(2+)))(91.8 eV)` and `underset((He^(+)))(40.8eV)` are possible |
|
| 44. |
Write any two observations which support the fact that atoms are divisible. |
|
Answer» Hint— Discovery of electrons and protons |
|
| 45. |
The value derived from the use of money over time as a result of investment and re-investment is known as ___________ . A. Cash flow model B. Time Value of Money C. Fund flow modelD. Depreciation |
|
Answer» B. Time Value of Money |
|
| 46. |
Name the branches of accounting. |
|
Answer» 1. Financial Accounting 2. Cost Accounting 3. Management Accounting |
|
| 47. |
Billing accuracy is most important factor for: a) Customer satisfaction b) Reseller satisfaction c) Purchase satisfaction d) None of the above |
|
Answer» a) Customer satisfaction Billing accuracy is most important factor for Customer satisfaction. |
|
| 48. |
The preference for money now, as compared to future money is known as ___________. A. Time Preference of Money B. Risk Analysis C. Profitability D. Investment Management |
|
Answer» A. Time Preference of Money |
|
| 49. |
The important branches of accounting are: a) Financial Accounting b) Cost Accounting c) Management Accounting d) All of the above |
|
Answer» d) All of the above The important branches of accounting are: a) Financial Accounting b) Cost Accounting c) Management Accounting |
|
| 50. |
Conventions are the customs or traditions guiding the preparation of accounting statements.(State True/ False) |
|
Answer» True Conventions are the customs or traditions guiding the preparation of accounting statements is True. |
|