Explore topic-wise InterviewSolutions in Current Affairs.

Calculation:

4

⇒ 4 × 2 + 1 = 9

⇒ 9 × 2 + 1 = 19

⇒ 19 × 2 + 1 = 39

⇒ 39 × 2 + 1 = 79

∴ 79 will be next number in this series.

The correct option is 2 i.e. 79.

Calculation:

25 × 2 × 10 = 500

100 × 5 × 2 = 1000

7 × 1 × 13 = 13 × 7 = 91

12 × 0 × 5 = 13 × 0 = 0

178 × 2 = 89 × 4 = 356

∴ In option 1 product of RHS and LHS is not equal.

The correct option is 1  i.e. 25 × 2 × 10 = 100 × 5 × 2

Given:

Five-digit number 235xy is divisible by 3, 7 and 11

Concept used:

Divisibility rule of 3- The sum of its digit is divisible by 3.

Divisibility rule of 7-  To make a pair of 3 from unit digit than subtract left over pair,

The result is divisible by 7.

Divisibility rule of 11- The difference of the sum of odd place and even place is zero or multiples of 11.

The result is divisible by 11.

Calculation:

235xy

For 3, x + y = 2, 5, 8, 11

For 11, (7 + y) - (3 + x) = 0 or 11

y = 2 then x = 6, x + y = 8

For 7, 562 - 023 = 539

it is also divisible by 7

number = 23562 and x = 6, y = 2

now,

3x - 4y = 18 - 8 = 10

∴ The value of 3x - 4y is 10.

Given-   

Given numbers = 56, 216, 28

Concept Used-

The greatest number which divides a given set of numbers is the HCF of that given set of numbers.

Calculation- 

56 = 7 × 2³

216 = 2³ × 3³

28 = 2² × 7

∴ HCF of 56, 216, 28 = 2² = 4.

Calculation:

Let assume that number is x

According to the question

216 × x = P        ----(1)

P – 12 = 6,900       ----(2)

⇒ P = 6,900 + 12

⇒ P = 6,912

Placing value of P in Equation (1)

⇒ 216 × x = 6,912

⇒ x = 6,912 ÷ 216

⇒ x = 32

∴ That number is 32.

The correct option is 4 i.e. 32.

Correct answer is (A) \(-\frac{f_O}{f_e}\)

B. not in equilibrium

A. 0.189 cm s^-1

C. angular displacement 

3 ladies out of 8 can be selected in ⁸C₃ ​ ways and 4 gentlemen out of 7 in ⁷C₄ ​ ways. 

Now each way of selecting 3 ladies is associated with each way of selecting 4 gentlemen. 

Hence, the required number of ways = ⁸C₃ ​ × ⁷C₄ ​ =56×35=1960. 

We now find the number of committee of 3 ladies and 4 gentlemen in which both Mrs A and Mr B are member. 

In this case we can select 2 other ladies from the remaining 7 in ⁷C₂ ​ ways and 3 other gentlemen from the remaining 6 in ⁶C₃ ​ ways. 

∴ The number of ways in which both Mrs A and Mr B are always included = ⁷C₂ ​ × ⁸C₃ ​ =21×20=420 

Hence the required number of committee in which Mrs A and Mr B do not serve together =1960=420=1540.

Correct option is D) were discussing/were talking

(D² + 4D + 1)y = sin x

It's auxiliary equation is

m² + 4m + 1 = 0

= m² + 4m + 4 - 4 + 1 = 0

= (m + 2)² = 3

= m + 2 = ± √3

= m = -2 ± √3

C.F = C₁e^{-(2 + √3)x} + C₂e^{-(2 - √3)x}

P.I = \(\cfrac1{D^2+4D+1}\) sin x

= \(\cfrac1{-1^2+4D+1}\)sin x

= \(\cfrac1{4D}\) sin x

= \(\cfrac1{4}\) \(\int\) sin x (\(\because\) \(\cfrac1{D}\) f(x) = \(\int\) f(x) )

= - \(\cfrac1{4}\) cos x

\(\therefore\) complete solution of given differential equation is

y = C.F + P.I

= C₁e^{-(2 + √3)x} + C₂e^{-(2 - √3)x}

^{\(\cfrac{-cos\,x}4\)}

Given differential equation is \(\frac {d^4y}{dx^4} + \frac {d^3y}{dx^3} + \frac {d^2y}{dx^2}\)

It's auxiliary equation is m⁴ + m³ + m² = 0

= m² (m²+m+1) = 0

= m = 0, 0, \(\frac {-1\pm \sqrt{1-4}}{2}\) 

= m = 0, 0, \(\frac {-1}{2}\pm\frac {\sqrt3}{2}\)

∴ C.F. = (C₁ + C₂x)e^0x + e^-x/2 \((C_3\,cos\frac {\sqrt3}{2}x + C_4sin \frac {\sqrt3}{2}x)\)

= C₁ + C₂ x + e^-x/2 (\((C_3\, cos (\frac {\sqrt3}{2}x) + C_4\, sin (\frac {\sqrt3}{2}x)\)

\(\frac {dy}{dx} \) = 1-xy+y-x

= 1-x + y (1-x)

= (1-x) (1+y)

∴  \(\frac {dy}{1+y} \) = (1-x) dx

= ln [1+y] = \(x-\frac {x^2}{2} + C\) ( By integrating both sides)

which is solution of given differential equation.

Given that

P_d = 10 - x - x²----(1)

and P_s = x + 2---(2)

On equilibrium, we have

P_d = P_s

⇒ 10 - x - x² = x + 2

⇒ x² + 2x - 8 = 0

⇒ (x + 4) (x - 2) = 0

⇒ (x + 4) (x - 2) = 0

⇒ x = 2, -4

\(\therefore\) x = 2 (\(\because\) x never be negative)

Put x = 2 in equation (1) we get

(P_d)₂ = 10- 2 - 2²

 = 10 - 2 - 4

 = 10 - 6 = 4

Now consumer's surplus = \(\int\limits_0^2(10-x-x^2)dx-2\times4\)

 = \([10x-\frac{x^2}2-\frac{x^3}3]_0^2-8\) 

 = 20 - 2 - 8/3 - 8

 = 10 - 8/3

 = \(\frac{30-8}3=\frac{22}3\)

Given t = 5 years

V_begin = 20000 & CAGR = 11.84%

\(\because\) CAGR = \([(\frac{V_{final}}{V_{begin}})^{1/t}-1]\times100\)

⇒ 11.84  = \([(\frac{V_{final}}{20000})^{1/5}-1]\times100\) 

⇒ 1 + 0.1184 = \((\frac{V_{final}}{20000})^{1/5}\)

⇒ \(\frac{V_{final}}{20000}\) = (1.1184)⁵ = 1.7498

⇒ V_final = 34996

The end balance will be 34996.

(-3/5)-4 * (-2/5)2

(-3^-4/5)^-4 * (-2^2/5^2)

625/81 * 4/25

25/81 * 4/1

100/81

Let the investment in each case = Rs. 120 In the first case,

Dividend on Rs. 120 = Rs. 6

In second case, Dividend on Rs. 10

= 8 × 10/100 = 0.8

Now dividend on Rs. 15 = 0.8

then dividend on Rs. 120 = (0.8 × 120)/15 = Rs. 6.4

It is clear that, second investment i.e. 8%

Rs.10 shares at 15 is more profitable.

Total annual expenditure of the family = Rs. (4 x 2570 + 3 x 2490 + 5 x 3030)

= Rs. (10280 + 7470 + 15150) 

= Rs. 32900

Total income = Rs. (32900 + 5320) = Rs. 38220

∴  Required average monthly income = \(\frac{3880}{12}\) = Rs. 3185

\(C.I. = S.I\)

⇒ \(P\left( 1 + \frac R{100}\right)^T - P = \frac{PRT}{100}\)

⇒ \(P \left(\left(1 + \frac R {100}\right)^T - 1 \right) = \frac{PRT}{100}\)

⇒ \(\frac {RT}{100} = \left( 1 + \frac R{100}\right)^T - 1\)

⇒ \(\frac {RT}{100} + 1 = \left(\frac{100 + R}{100}\right) ^T\)

⇒ \(\frac{RT + 100}{100} = \left(\frac {R + 100}{100}\right)^T\)

For T = 1,

L.H.S = \(\frac{R + 100}{100}\)

R.H.S. = \(\frac{R + 100}{100}\) 

Hence, for after 1 year compound interest will be equal to simple interest.

LCM of what? Please Specify the question

उत्पादन के पाँच साधनों के नाम हैं

1. भूमि
2. श्रम
3. पूँजी
4. प्रबन्ध (संगठन) तथा
5. साहस।

Animals and birds do control and balance our environment. They have a great importance in our lives.  Animals are important in our daily life as well as for other purposes. Such that we use animals for providing us food, clothing, help in our works. In India animals are worshiped like snake, bull, oxen,cow,etc. All the fauna in the world is important. Even the small of the smallest of living creature is the part of the whole ecosystem.if any of the species would exhaust the whole ecosystem would be in danger. Animals and birds also can inspire us such that weaver birds inspired us to weave,dogs inspire us to be loyal and ants and the bees inspire us to work hard. Camel is the sheep of the desert who fulfills all the needs of the locals. It is only the one animal to survive in the desert without water for so many days.the next is cow it gives milk and some people do eat the meat of cow.horse, bullocks,elephant, etc. Are used for hazardous works still we are killing elephants for their tusks.if there would not have been birds then wright brothers would not have got the ideas about aeroplane. If there would not have been fishes the no ships were formed.So animals also contribute to the development of technologies.so if you want further development in technologies then stop killing animals and hurting them ruthlessly and teens should create an awareness among adults to not to kill animals.

A) It is generally agreed that Mr. Carr will manage the company much better than Mr. Burton did

Correct option is B) broken down

Correct option is C) as tall as

B) Though brothers, Paul and Mark are very different in appearance and in interests.

Given:

Speed of train = 25 m/s

Time taken to cross the platform = 20 second

Length of platform = Length of train/3

Formula used:

Distance = Speed × Time

Solution:

Let the length of train be 3x m

Length of platform = (1/3) × 3x

Length of platform = x m

Total distance covered by train = 3x + x = 4x m

Distance = Speed × Time

⇒ 4x = 25 × 20

⇒ 4x = 500

⇒ x = 125

Length of train = 3x = 3 × 125

∴ Length of train is 375 m

Correct option is B) as tall as

Given: 

The ratio of time taken to cover the distance from A to B by both boats is 4 : 5

The speed of boat Q is 34 km/h

Concept: 

When distance is constant 

The ratio of speed is equal to inverse the ratio of time.

Hence, if the ratio of the speed of A : B is 4 : 5, the ratio of time taken by A and B would be 5 : 4. 

Calculation: 

Let the speed of boat P be x km/h.

According to the question 

The speed of boat P downstream is (x + 6) km/h

The speed of boat Q in downstream is (34 + 6) = 40 km/h 

Now, 

The ratio of the speed of boat P and Q is 

⇒ (x + 6) : 40 = 5 : 4

⇒ x + 6 = 50

⇒ x = 44 km/h

So, 

The speed of boat P, when It travels from B to A (upstream)

⇒ 44 - 6 

⇒ 38 km/h

∴ 38 km/h

Correct option is E) opened

Correct option is C) go there

Correct option is C) many boats

Correct option is D) without a hat

Correct option is C) was opened

Correct option is C) was opened

Correct option is A) Don’t go in

Correct option is C) as Brian

Correct option is C) opened

Correct answer is bank

Correct answer is travel agency

Correct option is A) can I buy

Correct option is B) was

Correct option is D) has been

Correct option is C) made

Correct answer is post office

Correct option is D) has been