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Let us assume,

The velocity with which the elevatar ascends be u', the height attained by elevatar at time,T₁ be h .

Thus,

u' = \(\frac{h}{T_1}\)

Equation of motion,

h = -u'T₂ + \(\frac{1}{2}gT_2^2\)

∵ u' = \(\frac{h}{T_1}\)

h + \(\frac{h}{T_1}\)T₂ = \(\frac{1}{2}gT_2^2\)

h(1 + \(\frac{T_2}{T_1}\)) = \(\frac{1}{2}gT_2^2\) 

h = \(\frac{1}{2}\)\(\frac{gT_2^2}{(1+\frac{T_2}{T_1})}\)

Option : (a) 50 V

Option : (c) 60°

Option : (c) 2E

Option : (c) negative to  positive terminal and positive to negative terminal

Option : (c) 25 V

A homeowner replaces a 65 watt incandescent bulb with a 15 watt compact fluorescent lamp. The light is on 2000 hours a year. If electricity cost 10 cents a kilowatt-hour, $10.00 money is saved on the electric bill in one year?  

Correct option is jingle

Correct option is journey

Correct option is Jupiter

Correct option is joke

Correct option is B) bride

Correct option is judge

Correct option is C) flown across

Correct option is C) business

Correct option is A) do with

The practice of rearing honey bees for honey and wax is called apiculture. It is also called Bee keeping. 

There are three castes in honey bee colony. 

1. Queen (fertile female) 

2. Drones (fertile males) 

3. Workers (sterile females) 

Economic importance 

• Honey collected from honey combs is a good nourishing food, it is a sweet syrup contains sugars like levulose (41%), fructose (38%), glucose (31%), maltose, it contains vitamins like ascorbic acid (vitamin c), niacin (B₃), riboflavin (B₂), thiamine (B₁), and minerals (Fe, Cu, mn, mg, Na, k ca p) 
• Honey is a good antiseptic, laxative expectorant, blood purifier and chief source of energy. 
• Honey is used in the preparation of jellies, Jams, cakes, etc. 
• Bees wax secreted from the abdominal wax glands is used in manufacture of polishes, candle, etc. 
• Bee venom is used in the treatment of disease like rheumatoid arthritis 
• Honey bees are best natural pollinators.

We have to find equivalence relations on set A and we know that a relation is said to be equivalence relation if the relation is reflexive, symmetric and transitive on set A.

Condition of reflexive relation on set = {1, 2, 3} is ordered pairs (1, 1), (2, 2) and (3, 3)must belongs to the relation.

We have to find such equivalence relation which containing (1, 2)and (2, 1).

Therefore, smallest equivalence relation which containing (1, 2) and (2, 1) on set {1, 2, 3} is R₁ = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)}.

If we include any one ordered pair outside this relation R₁ like as (1, 3), (2, 3), (3, 1) and (3, 2), then for satisfying equivalence relation conditions gives us the Cartesian product A x A, which is largest relation on set A.

R₂ = R₁ ∪ {(3, 1)} = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (3, 1)}

Since, we want to make a equivalence relation.

Then (1, 3) ∈ R₂. (Condition of symmetric relation )

Therefore, R₂ extended to R₂ = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (3, 1), (1, 3)}.

Since, (3, 1) ∈ R₂ and (1, 2) ∈ R₂. Then, (3, 2) ∈ R₂, therefore (2, 3) ∈ R₂.Given set A = {1, 2, 3}.

(Conditions of symmetric and transitive relations ).

Therefore, R₂ extended to R₂ = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (3, 1), (1, 3), (2, 3), (3, 2)} = A x A which is largest relation defined on A.

Therefore, only possible equivalence relations on set A are R₁ = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)} and R₂ = A x A.

Hence, total number of equivalence relations on the set {1, 2, 3} containing (1, 2)and (2, 1) are 2.

Total number of tickets in the lottery = 8 + 16 = 24. 

Total number of prizes in the lottery = 8. 

Probability of getting a prize = \(\cfrac{Total\, number \, of \, prizes}{Total\,numbers\, of\, tickets}\)

= \(\frac{8}{24} = \frac{1}{3}\).

Hence, the probability of getting a prize is \(\frac{1}{3}\).

Let the length of the broken part of the tree is = x m.

Given that the height of the unbroken part is AC = 15 m

And the broken part of the tree has fallen at 20 m away from the base of tree. i.e., AB = 20 m.

Therefore, the height of the unbroken tree is (x + 15)m.

(i). In right angled triangle ∆ABC,

BC² = AB² + AC² (By Pythagoras theorem in ∆ABC, where angle \(\angle\)BAC is an right angle )

⇒ x² = 20² + 15² = 400 + 225 = 625

(By putting AB = 20 m, AC = 15 m and BC = x m)

⇒ x = \(\sqrt{625}\) = 25.

Hence, the length of the broken part of the tree is 25 m.

Hence, option (c) is correct.

(ii). The height of the unbroken part of the tree is 15 m

And the height of the broken part of the tree is 25 m.

Therefore, the height of full tree is (15 + 25)m = 40 m.

Hence, option (a) is correct.

(iii). The length of the hypotenuse in the formed right angle triangle is BC = x = 25 m.

Hence, option (c) is correct.

(iv). We know that the area of a triangle is A = \(\frac{1}{2}\) × (Base) × (Height) square units.

The height of right angle triangle ∆ABC is AC = 15 m.

And the base of the right angle triangle is AB = 20 m.

Therefore, the area of formed right angle triangle ∆ABC is \(\frac{1}{2}\) × AB × AC = \(\frac{1}{2}\) × 20 × 15 = 150 m².

Hence, option (d) is correct.

(v). We know that the perimeter of a triangle is sum of the length of its sides.

The sides of formed right angle triangle ∆ABC are AB = 20 m, AC = 15 m and BC = 25 m.

Therefore, the perimeter of the formed triangle is AB + AC + BC = (20 + 15 + 25)m = 60 m.

Hence, option (a) is correct.

Correct answer is furniture

Yes. There is only one loop namely for loop that will do this three things. The other loops will do the checking only, initialisation must be do before the loop and updation must be inside the loop. 

The syntax of for loop is given below

 For(initialisation; testing; updation)

{ 

Body of the for loop; 

}

Given:

Average Price of Three Chairs = Rs. 14,014

Ratio of the Prices of three Chairs = 3 : 4 : 7

Formula Used:

Average = Sum of Prices of Articles/ Number of Articles

Concept Used:

Sum of Ratios will be equal to the Sum of Prices of All Chairs

Calculation:

14,014 = Sum of Prices of Chairs/3

⇒ Sum of Prices Of chairs = 14,014 × 3 = 42,042

Sum of Prices of Chairs is also equal to the sum of Ratios given

i.e. 3 + 4 + 7 = 14 Units

⇒ 14 Units = Rs. 42,042

⇒ 1 Unit = 42,042/14 = Rs. 3003

Since, we have to find the Value of Highest Price Chair i.e. 7 Units

⇒ 7 Units = 3003 × 7 = Rs. 21021

∴ The Highest price of Chair is Rs. 21,021

Given:

Total spendings = 11000

The cost price of cupboards = 1000

The cost price of Chair = 300

Calculations:

Let the number of cupboards be 'x'

Let the number of chairs be 'y'

When the maximum possible number of chairs x < y 

1000x + 300y = 11000

Let cupboards = 1

Then 11000 = 1 × 1000 + 300y

Number of chairs not integer. 

Let cupboards = 2 then

11000 = 2 × 1000 + 300y

⇒ Number of chairs (y) = 30.

So, maximum number of chair can be 30

So, 2 : 30 = 1 : 15

∴ The required answer is 1 ∶ 15

Correct option is B) some 

The loop variable inside the while loop must be updated otherwise the loop will not be terminated. The loop will be work infinitely.

Switch tests the value of a variable or an expression against a list of integers or character constants.

(c) 11. This is because of for statement is end with; (semi colon). Here cout<<n; executes only once.

C) What / are 

break statement takes the program control outside a loop even though the test expression is true.

1. break or goto 

2. Only one time because of semicolon(;) in the end of the for(i=0;i<10;i=i+2);

break statement: 

It is used to skip over a part of the code i.e. we can premature exit from a loop such as while, do-while, for or switch. 

Syntax: 

while (expression)

{

if (condition) 

break; 

}

continue statement: 

It bypasses one iteration of the loop. That is it skips one iteration and continue the loop with next iteration value. 

Syntax : 

while (expression) 

{ 

if (condition) 

continue; 

}

1. while or for loop 

2. To store an integer 4 bytes is used in Geany Editor. int A[10] [10]; → It needs 10 × 10 × 4 = 400 bytes

Correct option is A) communication