Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Observe the figurea. Which are the colours formed on the screen?b. Explain the phenomenon that causes the formation of array of coloursc. Which are the colours denoted by ‘A’ and ‘B’?d. Which colour deviates the most?e. Which colour deviates at least?f. Different colours undergo different deviation. Why?

Answer»

a. Violet, Indigo, Blue, Green, Yellow, Orange, Red 

b. Dispersion. The phenomenon of splitting, of a composite light into its constituent colours is known as dispersion of light.

c. A – Violet B – Red 

d. Violet 

e. Red

f. Different colours undergo different deviation due to difference in wavelength

2.

As sunlight passes through the atmosphere, which colour in it undergoes maximum scattering? Which colour undergoes minimum scattering?

Answer»

Colour in it undergoes maximum scattering: Violet Colour in it undergoes minimum scattering: Red

3.

Which are the occasions when sun-light has to travel greater distance through the atmosphere before reaching the eyes of ait observer on the earth?

Answer»

Morning and evening.

4.

What was the final colour observed on the screen?

Answer»

Red colour is seen at the end.

5.

When light reaches the observer after travelling long distances through the atmosphere, which colour reaches the eye? What is the reason?

Answer»

Red, it has highest wavelength and least scattering.

6.

Can you now guess why red colour has been given to the tail lamps of vehicles and signal lights? Discuss and note it down in your science diary.

Answer»

The primary reason why the colour red is used for danger signals is that red light is scattered the least by air molecules. So red light is able to travel the longest distance through fog, rain, and the like.

7.

(a) A person with myopia can see distant objects clearly(b) A person with hypermetropia can see nearby objects clearly(c) A person with myopia can see nearby objects clearly(d) A person with hypermetropia cannot see distant objects clearly

Answer» (c) A person with myopia can see nearby objects clearly
8.

Yellow light from a torch falls on a green paper and then falls on a white screen.a. Which colour is seen on the screen?b. Write the reason in two or three sentences.

Answer»

a. Green colour 

b. When yellow light falls on a green paper it absorbs yellow and reflects green. So . the green colour is seen on the screen.

9.

The western horizon remains reddish for some more time even after sunset. Why?

Answer»

During sunset, the sunlight travels maximum distance through the atmosphere to reach in our eyes. So red also undergoes scattering. So the horizon appears red.

10.

(a) are relaxed and lens becomes thinner(b) contract and lens becomes thicker(c) are relaxed and lens becomes thicker(d) contract and lens becomes thinner

Answer» (a) are relaxed and lens becomes thinner
11.

The beam of white light from a torch is allowed to fall obliquely on the prism.1. Which are the colours formed on the screen?2. Aren’t these colours the same as the component colours obtained from the sunlight?

Answer»

Yes, These colours are the same as the component colours obtained from the sunlight?

12.

The permeability (μ) of a ferromagnetic substance is(a) μ > 1(b) μ = 1(c) μ < 1(d) μ = 1

Answer»

Correct answer is (a) μ > 1

13.

What is embroidery spec sheet?

Answer»

A spec sheet is a technical document that contains the construction details of embroidery, a technical diagram/sketch and measurements of embroidery

14.

The peak voltage of an A.C. is 440 volt. Its virtual voltage is(a) 220 V(b) 440 V(c) 220√2 V(d) 440√2 V

Answer»

Correct answer is (c) 220√2 V

15.

Why one should not deliver damaged embroidered product to clients?

Answer»

it might will be unfair to both the client and the worker or damages the reputation of the organisation or the business handling the project.

16.

The magnifying power of a magnifying glass of power magnifying glass of power 12 diopter is(a) 4(b) 1200(c) 3(d) 25

Answer»

Correct answer is (a) 4

17.

What are the main elements of communication? Explain.

Answer»

Main elements of communication are: 

  1. Sender: Sender means person who conveys his thoughts or ideas to the receiver. 
  2. Message: It is the content of ideas, suggestions, order etc. intended to be communicated. 
  3. Encoding: It is the message into communication symbols such as words, pictures, gestures etc. 
  4. Media: It is the path through which encoded message is transmitted to receiver. 
  5. Decoding: It means translating the message from its sign format into meaning. 
  6. Receiver: The person who receives communication of the sender. 
  7. Feedback: It includes all those actions of receiver indicating that he has received and understood the message of sender. 
  8. Noise: Noise means some obstruction or hindrance to communication.
18.

List down the ways to remove stains from embroidered product.

Answer»

a.drop of dish soap and water. 

b. spray the area with acetone or bleaching agent in case of white fabrics depending upon the type of stains

19.

A current of 10 ampere flows in a wire for 10 sec. If potential difference across the wire is 15 volt, the work done will be(a) 150J (b) 75 J(c) 1500J(d) 750J

Answer»

Correct answer is (c) 1500 J

20.

Give an example of the most suitable fabric used for cross stitch.

Answer»

Matty, gingham, casement, khadi, jute

21.

How big should design be on front of shirt?

Answer»

Adult size- 11 to 14 inches 

Kids- 5.5 to 9 inches 

Also to note size can change depending on what you are making.

22.

What are the things to keep in mind while writing a biodata?

Answer»

Things to keep in mind while writing a bio data: 

1. Check for typos, grammatical errors. 

2. If your career demands a two page resume, then go ahead and do it. 

3. Don’t lie over dates or titles on your resume to hide the fact that you have been unemployed. 

4. If you are seeking a job in a field in which you have no prior experience, don’t use the chronological format for your resume.

23.

Nowadays every person is wandering in search of livelihood, consider yourself an applicant, prepare a biodata for the post of computer operator.

Answer»

Faiyaz Alam

61, Tilak Marg | New Delhi-110001 | 9867543210 

OBJECTIVE :

Seeking challenges role as a Computer operator where my knowledge will be fully consumed to help the organization reach its objective. 

EDUCATION :

Indraprastha University 

Bachelor of Computer Programming, 2010 

EXPERIENCE :

  • Computer Operator – Infosys, India 2011- Present 

SKILLS : 

  •  Expert in installation of various software and other operating programs. 
  •  Skilled in oracle database. 
  •  Good working relationship. 
  •  Ability of work under pressure with consistent excellent results. 

CERTIFICATIONS : 

Certification in Computer Management 

COMPUTER SKILLS : 

Knowledge of Ms. Office Tools: MS Excel, Power Point 

HOBBIES :

Playing Basketball, listening music. 

Signature

24.

what is joule?what is horse power?

Answer»

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.

Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.

25.

The resistance R of a wire is given by the relation `R= (rhol)/( pir^(2))`. Percentage error in the measurement of `rho, l and r` is 1 % , 2% and 3% respectively. Then the percentage error in the measurement of R isA. 6B. 9C. 8D. 10

Answer» Resistance of a wire `R=(pl)/(pir^(2))`
Take log to base e on both sides of equation (i), we get
`lnR=lnp+lnl-lnpi-2lnr`
Differentiate both sides of equation (ii), we get
`(DeltaR)/(R)=(DeltaR)/(p)+2(Deltal)/(l)-2(Deltar)/(r)`.....(iii)
Errors are always added, (for maximum error)
`therefore(DeltaR)/(R)xx100=(DeltaP)/(P)xx100+(Deltal)/(l)xx100+|(-2Deltar)/(r)xx100|`
`=1%+2%+2(3%)=9%`
26.

How many coulombs of positive charge are in 1.30 mol of neutral molecular-hydrogen gas (H2)?

Answer» Hydrogen atom has got 1 proton in its nucleus. 1.3 mole H2 molecules means 2 .6 mole H atoms. So total positive charge is due to 2.6mole proton or 2.6×6.023×10^23  proton.

Each proton contains 1.602×10^-19C positive charge. Hence total positive charge in 1.3 mole H2 molecules will be =2.6×6.023×10^23×1.602×10^-19C
27.

A wire has a mass `(0.3+-0.003)g`, radius `(0.5+-0.005)mm` and length `(6+-0.06)cm`. The maximum percentage error in the measurement of its density isA. 1B. 2C. 3D. 4

Answer» `p=(M)/(V)=(M)/(pir^(2)h)`
`(Deltap)/(p)=(DeltaM)/(M)+(2Deltar)/(r)+(Deltah)/(h)` (for maximum error)
`(DeltaM)/(M)=(0.003)/(0.3)xx100=1%`
`(Deltar)/(r)=(.05)/(0.5)xx100=1%`
`(Deltal)/(kl)=(0.06)/(6)xx100=1%`
`(Deltap)/(p)=4%`
28.

A travelling wave has the frequency `upsilon` and the particle displacement amplitude `A`. For the wave the particle velocity amplitude is ………………… and the particle acceleration amplitude is ……………………..

Answer» If `y = A sin(omegat - kx)`, displacement amplitude `= A`
(Maximum displacement)
Particle velocity,
`v = (dy)/(dt) = A omega cos(omega t - kx)`
Therefore, velocity amplitude `= A omega = A(2 pi v)`
(Maximum velocity)
Particle acceleration,
`A c c = (dv)/(dt) = - A omega^(2) sin(omega tau - kx)`
Therefore, acceleration(maximum acceleration)
amplitude `= A omega^(2) = A(2 pi v)^(2)`.
29.

A particle of mass m is attached to one end of a mass-less spring of force constant k, lying on a frictionless horizontal plane. The other end of the spring is fixed. The particle starts moving horizontally from its equilibrium position at time `t=0` with an initial velocity `u_0`. when the speed of the particle is `0.5u_0`, it collides elastically with a rigid wall. After this collisionA. the speed of the particle when it returns to its equilibrium position is `u_0`.B. the time at which the particle passes through the equilibrium position for the first time is `t = pi sqrt((m)/(k))`C. the time at which the maximum compression of the spring occurs is `t = (4 pi)/(3) sqrt((m)/(k))`D. the time at which the particle passes through the equilibrium position for the second time is `t = (5 pi)/(3) sqrt((m)/(k))`.

Answer» Correct Answer - A::D
`v = u_(0) sin omega t`
(suppose `t_(01)` is the time of collision)
`(u_(0))/(2) = u_(0) cos omega t_(1) rArr t_(1) = (pi)/(3 omega)`
Now the particle returns to equilibrium position at time `t_(2) = 2t_(1)` i.e., `(2 pi)/(3 omega)` with the same mechanical energy i.e., its speed will be `u_(0)`. Let `t` be the time at which the particle passes through the equilibrium position for the second time.
Energy of particle and spring remains conserved.
`t_(2)=(T)/(2)+2t_(1) =(pi)/(omega)+(2pi)/(3 omega)=(5 pi)/(3 omega) =(5pi)/(3) sqrt((m)/(k))`.
30.

A person blows into open- end of a long pipe. As a result,a high pressure pulse of air travel down the pipe. When this pulse reaches the other end of the pipe,A. a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is openB. a low-pressure pulse starts travelling up the pipe, if the other end of the pipe is openC. a low-pressure pulse starts traveling up the pipe, if the other end of the pipe is closed.D. a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is closed.

Answer» Correct Answer - B::D
At open end phase of pressure wave charge by `pi` so compression returns as rarefraction. While at closed end phaseof pressure wave does not charge so compression return as compression.
31.

The IUPAC name for `CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-overset(O)overset(||)(C)-OH` is :A. 1-hydroxypentane-1, 4-dioneB. 1, 4-dioxopentanolC. 1-carboxybutane -3-oneD. 4-oxopentanoic acid

Answer» Correct Answer - D
The given compound is
`overset(5)CH_(3)-overset(O)overset(||)(""^(4)C)-overset(3)CH_(2)-overset(3)CH_(2)-overset(O)overset(||)(""^(1)C)-OH`
IUPAC name of given compound is 4-oxopentanoic acid.
32.

The different members of a homologous series possessA. different molecular weightsB. different general formulaeC. different methods of preparationD. different chemical properties

Answer» Correct Answer - A
The different momebers of a homologus series posses different molecular wieghts.
33.

The systematic name of `PhCH_(2)COOH` isA. 2-phenylethanoic acidB. phenylmethly carboxylic acidC. 2-phenylmethyl carboxylic acidD. benzene acetic acid

Answer» Correct Answer - A
The systematic name of `Ph overset(2)CH_(2)overset(1)C OOH` is 2-phenylethanoic acid.
34.

Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with (a) normal water, (b) acidified water and ( c) alkaline water? Write equations wherever necessary.

Answer» Aluminium chloride, `AlCl_(3)`, is a salt of weak base, `Al(OH)_(3)` and strong acid, `HCl`.
a. In normal water: `AlCl_(3)` undergoes hydrolysis to form `Al(OH)_(3),H^(o+)` and `Cl^(ө)` ions.
`Al(OH)_(3_((s)))+3H_(2)O_(l)to Al(OH)_(3_((s)))+3H_(aq)^(o+)+3Cl_(aq)^(ө)`
In acidified water: `H^(o+)` ions react with `Al(OH)_(3)` to form `Al_(aq)^(3+)` ions and `H_(2)O`. Thus in acidic water, `AlCl_(3)` exists as `Al^(3+)` and `Cl_(aq)^(ө)` ions.
`AlCl_(3(s))overset("Acidfied water")to Al_(aq)^(3+)+3Cl_(aq)^(Θ)`
c. In alkaline water, `Al(OH)_(3)` reacts with `.^(Θ)OH` ion to form soluble tetrahydroxoluminate complex or metaaluminate ion.
`Al(OH)_(3(s))+.^(ө)OHto [Al(OH)_(4)]_(aq)^(ө)` + or `AlO_(2)^(ө)+2H_(2)O`
Potassium chloride, `KCl` is a salt of strong acid `(HCl)` and strong base `(KOH)`.
it does not undergo hydrolysis in normal water. It ionises to give `K_(aq)^(o+)` and `Cl_(aq)^(ө)` ions.
`KCl_(s)overset("water")to K_(aq)^(o+)+Cl_(aq)^(ө)` Since the aqueous solution of `KCl` is neutral, therefore, in acidified water as well as alkaline water, the ions do not react and remains as such.
35.

Which of the following statements is/are correct?A. Inductive effect causes permanent polarity in the molecularB. Free radicals have odd electron in `p-`orbital.C. Inductive effect is a distance dependent.D. Mesomeric effect is distance dependent.

Answer» Correct Answer - A::B::C
Mesomeric effect is not distance depended
36.

Which of the following is the most powerful oxidising agent ?A. `F_2`B. `O_2`C. `Br_2`D. `l_2`

Answer» Correct Answer - A
`F_2` being most electronegative is the most powerful oxidising agent with standard oxidation potential `-2.87`.
37.

The oxidation state of O-atom is `+2` inA. `OF_2`B. `O_2F_2`C. `H_2O`D. `H_2O_2`

Answer» Correct Answer - A
`OF_2` because F being most electronegative have `-1` oxidation state , and oxygen possbes `+2` oxidation state.
38.

Sulphur on boiling with `NaOH` solution givesA. `Na_2S_2O_3+NaHSO_3`B. `Na_2S_2O_3+Na_2S`C. `Na_2SO_3+H_2S`D. `Na_2SO_3+SO_2`

Answer» Correct Answer - B
`3S+4NaOHoverset("Boiling")toNa_2S_2O_3+Na_2S+(1)/(2)[O_2]`
39.

Coordination compounds are the compounds in which the central metal atom is linked to atoms , ions or molecules byA. covalent bondsB. coordinate bondsC. ionic and covalent bondsD. both ionic and coordinate bonds

Answer» Correct Answer - B
Metal is bonded to ligand by coordinate bond.
40.

Define: a. Osmosis b. Freezing point

Answer»

a. Osmosis: The spontaneous and unidirectional flow of solvent molecules through a semipermeable membrane, into the solution or flow of solvent from a solution of lower concentration to the solution of higher concentration through a semipermeable membrane is called osmosis.

b. Freezing point: The freezing point of a substance may be defined as the temperature at which the vapour pressure of solid is equal to the vapour pressure of liquid.

41.

What happens when dilute sulphuric acid is treated with: a. Fe? b. CaF2?

Answer»

a. Dilute H2SO4 reacts with Fe which is below hydrogen in the electrochemical series, with the evolution of H2.

Fe (Iron) + H2SO(Sulphuric acid) → FeSO(Ferrous sulphate) + H(Hydrogen)

b. When H2SO4 is added to calcium fluoride, hydrogen fluoride is obtained. 

CaF2 (Calcium fluoride) + H2SO(Sulphuric acid) → CaSO4 (Calcium sulphate) + 2HF (Hydrogen flurode)

42.

Describe isolation method in determination of rate law and order of reaction.

Answer»

Isolation method: 

a. In the isolation method, the concentrations of all the reactants except one are made to remain constant throughout the course of the reaction by taking them in large excess. The dependence of rate on the concentration of the isolated species is experimentally determined. 

b. The experiment is repeated by isolating one of the reactants each time and determining the rate law with respect to the isolated species. 

c. Consider the reaction

aA + bB → cC + dD

The rate law has the form,

Rate = k[A]x[B]y

d. In one of the experiment, A is isolated by making the initial concentration of B (i.e., [B]0) to remain constant throughout the course of the reaction (by taking it in large excess). 

Hence, the rate law is written as

rate = k[A]x\([B]^y_0\) = k'[A]x  (where, k' = k\([B]^y_0\))

The dependence of rate on [A] that is ‘x’ is found out.

e. In another experiment, B is isolated by keeping initial concentration of A (i.e., [A]0) constant throughout the course of the reaction (i.e., by taking it in large excess). 

The rate law then becomes, Rate =  K\([A]^x_0\) [B]= k'' [B](where, k'' = k\([A]^x_0\))

The dependence of rate on B that is y is found out.

f. Thus, by knowing the values of x and y, the order of the reaction (x + y) and the rate law can be determined.

43.

Write the Nernst equation and explain the terms involved

Answer»

Nernst equation can be given as,

E = E0\(\frac{2.303\,RT}{nF}log_{10}\,\frac{[Products]}{[Reactants]}\)

where,

E0 = Standard potential of electrode or cell, 

n = Number of moles of electrons used in reaction, 

F = Faraday = 96500 C/mol e- , [Products] = Concentration of products, 

[Reactants] = Concentration of reactants, T = temperature in K and 

R = gas constant = 8.314 J K-1 mol-1

44.

To correct the order of stability of group II A metal carbonates isA. `MgCO_3 gtCaCO_3gtSrCO_3gtBaCO_3`B. `BaCO_3 gtSrCO_3gtCaCO_3gtMgCO_3`C. `SrCO_3gtBaCO_3gtCaCO_3gtMgCO_3`D. `CaCO_3gtMgCO_3gtBaCO_3gtSrCO_3`

Answer» Correct Answer - B
`Mg^(2+)` is smallest in size hence , show high polarising power. Thus , `MgCO_3` is most covalent and least stable. Stability increases on moving down the group.
45.

Explain the following methods to protect metals from corrosion: a. Galvanization b. Passivation

Answer»

a. Galvanization:

1. The rusting of iron can be prevented by coating the metal surface with another metal such as zinc,thatis oxidized in preference to iron. This process is called galvanization.

2. If the zinc layer is scratched, even then it protects iron from corrosion as long as Fe and Zn are in contact. If Fe is oxidized to Fe2+, then Zn immediately reduces Fe2+ back to Fe.

b. Passivation: The surface of metal is treated with strong oxidizing acid such as concentrated nitric acid and a thin preventive layer of oxide is formed on the surface of metal. Thus, the surface is made inactive. This is process is called as passivation.

46.

Which of the following test is not carried out of example the presence of `-COOH` group ?A. Litmus testB. Sodium bicarbonate testC. Ester testD. Bromine water test

Answer» Correct Answer - D
`Br_2` water test is carried out to examine unsaturation in compounds and not for the presence of `-COOH` group.
47.

Some amino acids are coded by more than one codon because:A. some aminoacids are needed in large quantitiesB. they are essential aminoacidsC. the genetic code is a triplet code formed out of 4 nitrogenous bases for 20 aminoacids.D. the genetic code is degenerate

Answer»

Correct answer is:- (D) The genetic code is degenerate

48.

Convert (101.101)2 = ( )10 ?

Answer»

101.101 = 1 x 22 + 0 x 21 + 1 x20 + 1 x 2-1 + 0 x 2-2 + 1 x 2-3

= 4 + 0 + 1 + 1/2 + 0 + 1/8

= 5 + 0.5 + 0.125

(101.101)2 = (5.625)10

49.

Convert (101.101)2 = ( )10?

Answer»

101.101 = 1 × 22 + 0 × 21 + 1 × 20 + 1 × 2-1 + 0 × 2-2 + 1 × 2-3 = 4 + 0 + 1 + 1/2 + 0 + 1/8 = 5 + 0.5 + 0.125 

(101.101)2 = (5.625)10

50.

The doctor said that I have to keep ______ alcohol. A) on B) off C) up

Answer»

Correct option is B) off