Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is common between extensive network of blood vessels around walls of alveoli and in glomerulus of nephron? A. Thick walled arteries richly supplied with blood B. Thin walled veins poorly supplied with blood C. Thick walled capillaries poorly supplied with blood. D. Thin walled capillaries richly supplied with blood

Answer»

Correct option is D. Thin walled capillaries richly supplied with blood.

2.

What is Infrastructure?

Answer»

Infrastructure refers to the core elements of economic and social change that serve as support systems to the production activities in the economy. These elements include the following:

1. Roads

2. Railways

3. Telecommunication facilities

4. Educational system including schools and colleges

5. Health system including hospitals

6. Sanitary system including clean drinking water facilities

7. Monetary system including banks, insurance, and other financial institutions

3.

the given statements belong to which plant kingdom?

Answer»
  • It  cant be Angiosperm because it is reduced to few cells. 

  • Where as Bryophytes & Pteridophytes female gametophyte is retained in megasporangia.

  • Therefore, It is clear that Gymnosperms suits the above option.

  • Ans  :   [C] - GYMNOSPERMS 

4.

which of the following is correct about tissue?

Answer»
  • Adipose tissue is another type of loose connective tissue and not dense.
  • Bones have a hard and non-pliable ground substance.
  • Blood is a fluid connective tissue because it contain the above liquid and few gases.
  • Yes, most of the cartilages in vertebrate embryo are replaced by bone in adult.
  • At the age of 25 cartilages are replaced by bones with the help of Ca+ .    
  • In which, the growth is retared.
  • Ans - [C] 

The correct answer is Most of the cartilages in a vertebrate embryo are replaced in adult by bones

  • Cartilage is a specialized type of dense connective tissue designed to give support, bear weight and withstand tension, torsion, and bending.
  • In the vertebrate embryo, the greater part of the skeleton consists of cartilage, which is gradually replaced by bone during development.
  • Early in development, cartilage makes up most of the vertebrate skeleton. As an individual grows older, calcium deposits form around the skeleton, and bone eventually replaces most of the cartilage. This process is called ossification. Ossification begins in humans when the fetus is still in the womb and is not complete until early adulthood
  • Hence Most of the cartilages in the vertebrate embryo are replaced in the adult by bones
5.

Gram-positive cellsA)    have thick, homogeneous cell walls.B)    have large amounts of teichoic acids.C)    do not have an outer membrane.D)    all of the above are true.

Answer»
  • Gram +ve bacteria have well inner layered membrane (i.e plasma membrane & peptidoglycan),but no lipid layer outer membrane.
  • Gram +ve cell have thick,homogeneous cell wall made up of murine & mucopeptide.
  • And, even they a large amount of teichoic acid found in cell wall,and extend to peptidoglycan layer
  • Therefore,the ans is [D] all the above are correct 
6.

How arbitrages earn riskless Profit? Give Example?

Answer»

The cost-of-carry ensures that the futures price stay in tune with the spot price. Whenever the futures price deviates substantially from its fair value, arbitrage opportunities arise.

Say for instance, ABC Ltd. trades at Rs.1000. One-month ABC futures trade at Rs.1025 and seem overpriced. As an arbitrageur, you can make riskless profit by entering into the following set of transactions.

1. On day one, borrow funds, buy the security on the cash/spot market at 1000. 

2. Simultaneously, sell the futures on the security at 1025. 

3. Take delivery of the security purchased and hold the security for a month. 

4. On the futures expiration date, the spot and the futures price converge. Now unwind the position. 

5. Say the security closes at Rs.1015. Sell the security. 

6. Futures position expires with profit of Rs. 10. 

7. The result is a riskless profit of Rs.15 on the spot position and Rs.10 on the futures position. 

8. Return the borrowed funds.

7.

What is the Application of index? Describe index Derivatives.

Answer»

Various products have been designed based on the indices such as the index derivatives, index funds2 and the exchange traded funds. We here restrict our discussion to only index derivatives. 

Index derivatives are derivative contracts which have the index as the underlying. The most popular index derivative contracts the world over are index futures and index options. NSE‘s market index, the Nifty 50 was scientifically designed to enable the launch of index-based products like index derivatives and index funds. Index derivatives offer ease of use for hedging any portfolio irrespective of its composition.

8.

Give Detail of VAR Margin?

Answer»

VAR is a single number, which encapsulates whole information about the risk in a portfolio. It measures potential loss from an unlikely adverse event in a normal market environment. 

The VAR margin will be charged on the net outstanding position (buy value-sell) of the respective clients on the respective securities across all open settlements. There would be no netting off of positions across different settlements. The net position at a client level for a member is arrived at and thereafter, it is grossed across all the clients including proprietary position to arrive at the gross open position.

9.

Explain Market Watch window?

Answer»

Market Watch 

The Market Watch window is the third window from the top of the screen that is always visible to the user. The Market Watch is the focal area for users. The purpose of Market Watch is to setup and view trading details of securities that are of interest to users. For each security in the Market Watch, market information is dynamically updated. 

Following are the key features of Market Watch Screen:

For each security the following information is displayed:

(a) the corporate action indicator ―Ex/Cum‖ 

(b) the total buy order quantity available at best buy price 

(c) best buy price 

(d) best sell price 

(e) total sell order quantity available at best sell price 

(f) the last traded price 

(g) the last trade price change indicator and 

(i) the Percentage change from previous day‘s closing price‘

10.

Mention the Norms in order to become DPG for various categories: a) Unlisted corporate trading member b) foreign entities

Answer»

a. Unlisted corporate trading member: In case of an unlisted corporate trading member, there are three conditions under which the corporate trading member will be eligible to constitute dominant promoter group. These conditions are given below: If a person holds 51% of shares in the trading member corporate on his own or together with 

1) His relatives 

2) The support of strategic investors in such corporate trading member. 

b) Foreign entities : Foreign entities are allowed to take trading membership of the Exchange through their Indian subsidiary under the automatic approval route permitted by the government, subject to compliance with the following guidelines of the RBI in this regard.

11.

What is the number of chromosomes present in human gamates?(a) 21(b) 23(c) 44(d) 46

Answer»

Answer (b) 23

12.

Oviparous are(a) hen(b) snake(c) crocodile(d) all of these

Answer»

Answer (d) all of these

13.

Diploid is(a) ovum(b) pollen(c) both (a) and (b)(d) zygote

Answer»

Answer (d) zygote

14.

Aril is edible in which of the following fruits?(a) Myristica(b) Litchi(c) Annona(d) All of these

Answer»

Answer (b) Litchi

15.

Source of Eco RI enzyme is(a) Bam HI(b) E.coli(c) Both (a) and (b)(d) Hind III

Answer»

Answer (b) E.coli

16.

Indicator of SO2 pollution is(a) algae(b) lichen(c) fungi(d) all of these

Answer»

Answer (b) lichen

17.

Honey is made by(a) male honeybee(b) queen honeybee(c) worker honeybee(d) both (a) and (b)

Answer»

Answer (c) worker honeybee

18.

T-lymphocytes originate from(a) bone marrow(b) stomach(c) thymus(d) liver

Answer»

Answer (a) bone marrow

19.

Zygote meiosis is characterisitic of …………(a) Marchantia (b) Fucus (c) Funaria (d) Chlamydomonas

Answer»

(d) Chlamydomonas

20.

………. refer to the names of variables, functions, arrays, classes etc. created by the programmer. A. Keywords B. Identifiers C. Constraints D. Strings

Answer»

Correct option is: B. Identifiers

21.

The method of CNC programming which enables the programmer to describe part geometry using variables is (a) Computer assisted part programming (b) Computer aided drafting programming (c) Conversational programming (d) Parametric programming

Answer»

(d) Parametric programming

22.

Senescence as an active developmental cellular process in the growth and functioning of a flowering plant, is indicated in(1) Annual plants (2) Floral parts (3) Vessels and tracheid differentiation (4) Leaf abscission

Answer»

(4) Leaf abscission

23.

A block P of mass m is placed on a frictionless horizontal surface. Another block Q of same mass is kept on P and connected to the wall with the help of a spring of spring constant k as shown in the figure. `mu_s` and Q. The blocks move together performing SHM of amplitude A. The maximum value of the friction force between P and Q is :- A. kAB. `(kA)/2`C. ZeroD. `mu_s mg`

Answer» Correct Answer - B
When two blocks performs simple harmonic motion together then at the extreme position (at amplitude =A)
Restoring Force F=KA =2ma `rArr a ="KA"/"2m"`
24.

At t = 0 a 100gm ball is thrown upwards with initial speed `v_(0) = 2` m/s in an open platform elevator which at that time is moving downward with v = 3 m/s and accelerating downward with an acceleration, `a = 3 m//s^(2)`​. A drag force with magnitude `F_"​DRAG"` = 0.8 N acts on the ball. Net force acting on the ball in the frame of the elevator just after it has been thrown is [`g =10 m//^(2)`​] :A. 1.2 NB. 1.5 NC. 1.8 ND. 2.4 N

Answer» Correct Answer - B
Elevator is non inertial frame of reference, therefore we must apply pseudo force.
Elevator is accelerating downwards, therefore pseudo force must act upwards while mg and `F_"DRAG​"` act downwards.
`therefore F_"NET"` [downward] = mg -ma + `F_"DRAG"`
= 0.1 × 10 – 0.1 × 3 + 0.8 = 1.5 N.
25.

A wave is represented by the equetion`y=7 sin(7pi t-0.04pix+(pi)/(3))` x is in metres and t is in seconds. The speed of the wave isA. 175 m/secB. 49 `pi` m/secC. 49/`pi` m/secD. 0.28 `pi` m/sec

Answer» Correct Answer - A
`v="Co-efficient of t"/"Co-efficient of x" = (7pi)/0.04`=175 m/s
26.

clouds are formed when water vapours?a) absorb heatb) release heatc) first absorb then released) none​

Answer»

c) first absorb then release

27.

When p calories of heat is given to a body, it absorbs q calories, then the absorbtion power of body will be :-A. p/qB. q/pC. `p^2//q^2`D. `q^2//p^2`

Answer» Correct Answer - B
Absorption power = `"Heat absorbed"/"Total heat given"`
28.

PQ is a current carrying conductor in the plane of the paper as shown in the figure below.(i) Find the directions of the magnetic fields produced by it at points R and S? (ii) Given r1> r2, where will the strength of the magnetic field be larger? Give reasons. (iii) If the polarity of the battery connected to the wire is reversed, how would the direction of the magnetic field be changed? (iv) Explain the rule that is used to find the direction of the magnetic field for a straight current carrying conductor.

Answer»

(i) The magnetic field lines produced is into the plane of the paper at R and out of it at S. 

(ii) Field at S > Field at P Magnetic field strength for a straight current carrying conductor is inversely proportional to the distance from the wire. 

(iii) The current will be going from top to bottom in the wire shown and the magnetic field lines are now in the clockwise direction on the plane which is perpendicular to the wire carrying current. 

(iv) Right hand thumb rule. The thumb is aligned to the direction of the current and the direction in which the fingers are wrapped around the wire will give the direction of the magnetic field.

29.

enzymes does not affect a)substrate concentration b)product concentration c)both d)None

Answer» Correct answer is d.

enzymes convert substrate into product affecting the concentration of both.
30.

In the given circuit, A, B, C and D are four lamps connected with a battery of 60VAnalyse the circuit to answer the following questions. (i) What kind of combination are the lamps arranged in (series or parallel)? (ii) Explain with reference to your above answer, what are the advantages (any two) of this combination of lamps? (iii) Explain with proper calculations which lamp glows the brightest? (iv) Find out the total resistance of the circuit.

Answer»

The lamps are in parallel. 

Advantages: 

If one lamp is faulty, it will not affect the working of the other lamps. They will also be using the full potential of the battery as they are connected in parallel. 

The lamp with the highest power will glow the brightest. 

P=VI 

In this case, all the bulbs have the same voltage. But lamp C has the highest current. 

Hence, for Lamp C 

P=5 x 60 Watt = 300 W. (the maximum). 

The total current in the circuit = 3+4+5+3 A = 15A 

The Voltage = 60V 

V=IR and hence R =\(\frac{V}{I}\)

\(\frac{60}{15}\) A = 4A

31.

Refractive index of water with respect to air is 1.33 and that of diamond is 2.42. (i) In which medium does the light move faster, water or diamond? (ii) What is the refractive index of diamond with respect to water?

Answer»

Refractive index = \(\frac{speed\,of\,light\,in\,vacuum}{speed\,of\,light\,in\,medium}\)

Since the refractive index of diamond is more, hence the speed of light is lesser in diamond. 

Let speed of light in water vevw and in diamond bevd

Refractive index of diamond w.r.t water is say n = \(\frac{speed\,of\,light\,in\,water}{speed\,of\,light\,in\,diamond}\)

\(n=\frac{V_w}{V_d}\)

Dividing both numerator and denominator by speed of light [c] we get 

n = (\(\frac{V_w}{c}\)) ÷ (\(\frac{V_d}{c}\)) = Inverse Ratio of refractive index of water and diamond. 

n=\(\frac{2.42}{1.33}\) = 1.82 (approx.)

32.

Match the following pH values 1, 7, 10, 13 to the solutions given below: Milk of magnesia Gastric juices Brine Aqueous Sodium hydroxide. Amit and Rita decided to bake a cake and added baking soda to the cake batter.Explain with a balanced reaction, the role of the baking soda. Mention any other use of baking soda.

Answer»
• Milk of magnesia10
• Gastric juices1
• Brine7
Aqueous Sodium hydroxide13

Baking soda undergoes thermal decomposition to form Na2CO3, CO2 and H2O; CO2 makes the cake fluffy & soft

NaHCO3 \(\overset{Heat}{\longrightarrow}\) Na2CO3 + CO2 +H2O

Uses:-

Used in fire extinguishers/ antacid to neutralize excess acid in stomach / to neutralize the effect of acid in insect sting.

33.

(i) Four samples A, B, C and D change the colour of pH paper or solution to Green, Reddish-pink, Blue and Orange. Their pH was recorded as 7, 2, 10.5 & 6 respectively. Which of the samples has the highest amount of Hydrogen ion concentration? Arrange the four samples in the decreasing order of their pH. (ii) Rahul found that the Plaster of Paris, which he stored in a container, has become very hard and lost its binding nature. What is the reason for this? Also, write a chemical equation to represent the reaction taking place. (iii) Give any one use of Plaster of Paris other than for plastering or smoothening of walls.

Answer»

(i) a) B 

b) C,A,D,B 

(ii) Due to moisture in the atmosphere it converted into Gypsum 

CaSO4+\(1\frac{1}{2}\) H2O \(\longrightarrow\) CaSO4.2H2

(iii) Making toys/dolls or statues /fixing broken limbs/making decorative materials.

34.

According to five kingdom system, kingdom protista includes :- (1) Dinoflagellates, Diatoms, Euglenoids, Slime mould, Bacteria (2) Eunglenoids, Fungi, Slime mould, Dinoflagellates, Protozoans (3) Slime mould, Protozoans, Dionflagellates, Diatoms, Euglenoids (4) Protozoans, Moss, Euglenoids, Slime mould, Diatoms

Answer»

Correct option is (3) Slime mould, Protozoans, Dionflagellates, Diatoms, Euglenoids

35.

In \( \triangle ABC \), if \( \angle A = x ^{0}, \angle B =3 x ^{0} \) and \( \angle C = y ^{0} \). If \( 3 y -5 x =30 \), then \( \angle B = \) a) \( 60^{\circ} \) b) \( 45^{\circ} \) c) \( 30^{\circ} \) d) \( 90^{\circ} \).

Answer»

Given: A = x, B = 3x, C = y

∴ Sum of △le = x + 3x + y

180 = 4x + y

⟹180−4x = y

Also,3y − 5x = 30

Subtituting y value,  

∴ 3(180−4x)−5x = 30

∴ x = 30, by solving

∴ y = 180−4×30 = 60

∴ A = 30; B = 90; C = 60

36.

Cell wall of diatoms are embedded with :- (1) Calcium oxylate crystals (2) Silica particles (3) Iron (4) Calcium carbonate crystals

Answer»

Correct option is (2) Silica particles

37.

Abcdef are real numbers

Answer»

Abcdef are alphabets

no they are not

38.

Which of the following is a free – living bacterium? (a) Rhizobium (b) Clostridium (c) Escherichia (d) Cyanobacteria

Answer»

(b) Clostridium

39.

Parenchyma storing calcium carbonate crystals are called …………(a) Leucoplasts(b) Elaioplasts (c) Idioblasts (d) Chromoplasts

Answer»

(c) Idioblasts

40.

Cell cycle was discovered by …………(a) Singer & Nicholson (b) Prevost & Dumans (c) Schleider & Schwann (d) Boveri

Answer»

(b) Prevost & Dumans

41.

Erypsin works on: A. PolypeptideB. Dipeptide C. Peptone D. All

Answer»

Answer : D. All

42.

What do two peaks in action spectrum represent?A. Light absorption B. Consumption of carbon dioxideC. Light emission D. Both A and B

Answer»

Option D is correct



43.

the rigidity of leaves in young part of plant is contributed bya)microtubulesb)Mitochondriac)actind)glyoxysomes

Answer» a) Microtubules is the correct answer.

Eg :- Guard cells in dicot plants.
44.

When the glucose level in blood comes down, glucose is synthesized from ________.A. Fats B. Glycogen C. Amino acids D. DNA

Answer»

Answer : C. Amino acid 

Explain : On average, postprandial blood glucose may rise to 120 to 140 mg/dl, but the body's feedback mechanism returns the glucose to normal within 2 hours. During starvation, the liver provides glucose to the body through gluconeogenesis: synthesizing glucose from lactate and amino acids

45.

List any four properties of a molecule to be able to act as a genetic material.

Answer»

Properties of Genetic Material 

(i) The genetic material should be able to generate its replica so that one can be transmitted to the daughter cell or next generation. 

(ii) It should be chemically and structurally stable. 

(iii) It should be provide scope for slow changes (mutation) that are necessary for evolution. 

(iv) It should be able to express itself in the form of mendelian characters

46.

D all of these

Answer» None
47.

Excretory products of autotrophic plants:A. CO2 B. O2

Answer» None
48.

A patient showed symptoms of sustained high fever, stomach pain and constipation, but no blood clot in stools. Name the disease and its pathogen. Write the diagnostic test for the disease. How does the disease get transmitted?

Answer»

The disease is Typhoid and it is caused by bacteria Salmonella typhi. The test name is Widal test. This disease is transmitted by contaminated food and water.

49.

Write the kind of professional and medical help that is available for prevention and control of alcohol and drug among adolescents

Answer»

Qualified psychologists, psychiatrists, de-addiction, and rehabilitation programmes are helpful for drug abused adolescents.

50.

Name two alcoholic drinks produced in each of the following ways: (i) with distillation and (ii) without distillation.

Answer»

(i) With distillation – Brandy and Whisky 

(ii) Without distillation – Wine and Beer