Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which of the following is strongest base ?A. `H_(3)C - CH_(2) - NH_(2)`B. `H_(3)C - CH = NH`C. `H_(3)C - C -= N`D. `H_(3)C - CH_(2) - overset(Θ)(NH)`

Answer» Correct Answer - D
Due to negative charge (localised) and `+1` effect of `CH_(3) - CH_(2)`
2.

Major product of this reaction is :A. B. C. D.

Answer» Correct Answer - 3
Anti elimination takes place
3.

Which of the following species is/are isoelectronic to each other ? (I) `overset(Θ)(B)H_(3) - C -= N` (II) `CH_(3) - C -= CH` (III) `N_(2)O`A. I and II onlyB. II and III onlyC. I, II and III onlyD. All four

Answer» Correct Answer - D
Isoelectronic means having same number of electrons in all the options total number of electrons are 22
4.

The species having tetrahedral shape isA. `[PdCl_(4)]^(-2)`B. `[Ni(CN)_(4)]^(-2)`C. `[Pd(CN)_(4)]^(-2)`D. `[NiCl_(4)]^(-2)`

Answer» Correct Answer - 2
Ni has `sp^(3)` hybridisation
5.

The species which is not tetrahedral in shape isA. `ICl_(4)^(-)`B. `BF_(4)^(-)`C. `AlH_(4)^(-)`D. `overset(oplus)(NF_(4))`

Answer» Correct Answer - A
`ICl_(4)^(-)` because it have `(4 b.p. + 2l.p.)` i.e. `sp^(3)d^(2)` hybridisation.
6.

An equimolar mixture of `CO_(2 (g))` and `CF_(4 (g))` was taken in an empty flask at a particular temperature. These gases reacts as: `CO_(2 (g)) + CF_(4 (g)) hArr 2 COF_(2 (g))` After this , mixture attains equilibrium and mole fraction of `COF_(2 (g))` was found to be `0.2`, then Which of the following will increase concentration of `COF_(2 (g))` at equilibriumA. decrease in temperatureB. increase in total pressureC. Addition of inert gas at constant pressureD. A and B both

Answer» Correct Answer - D
For increasing concentration of `COF_(2 (g))` at equilibrium
(A) Reaction is exothermic in forward direction hence, decrease in temperature, increase concentration of `COF_(2 (g))` at equilibrium.
(b) Total pressure increase, volume decreases and hence concentration increases.
7.

In the following compound - Which of the following is correct order of acidic strength ?A. `c gt b gt a gt b`B. `c gt a gt b gt d`C. `a gt c gt b gt d`D. `a gt b gt c gt d`

Answer» Correct Answer - C
Acidic strength
Carboxylic acid group `gt` Phenolic group `gt 1^(@)` Aliphatic alcohol group `gt 2^(@)` alphatic alcohol group
8.

In the following compound - The degree of unsaturation (DBE) in the given compound is :A. 9B. 10C. 11D. 12

Answer» Correct Answer - C
`DBE rarr` no of ring + on of `pi` bonds
9.

Why are halogens coloured?

Answer»

Almost all halogens are coloured. This is because halogens absorb radiations in the visible region. This results in the excitation of valence electrons to a higher energy region. Since the amount of energy required for excitation differs for each halogen, each halogen displays a different colour.

10.

The C-O-H bond angle in alcohol is :(a) slightly greater than 109°28'.(b) slightly less than 109°28'.(c) slightly greater than 120°.(d) slightly less than 120°.

Answer»

Option : (b) slightly less than 109°28'.

Due to presence of lone pairs of electrons on oxygen atom, the C-O-H bond angle decrease from 109°28'. because of lone pair and bond pair repulsions.

11.

When our target is asked to make this ether startint from alkyl halides. First we recall that ethers can be prepared by substitution reactions of alkoxide anion nucleophiles with alkyl halide electrophiles- The William ether synthesis. The two ways to prepare the target ether are as follows Next we examine the two reactions to determine whether both are expected to give a good yield of the target compound. Since route A combines a strongly basic nucleophile a secondary `(2^(@))` alkayl halide we expect the major product to result from elimaination by `E_2` mechanism. Route B on the other hand, employs a primary alkylhalide that can not give elimination (It has no hydrogen on the `beta`-carbon) and that is excellent. Substrate for an `S_N2`substitution because it is benzylic Route B is the obvious choice. Which of the following reagents when heated will give a good yield of an ether.A. Isopropyl bromide and sodium isopropoxideB. Isopropyl bromide and sodium ethoxideC. Bromo benzene and sodium phenoxideD. Sodium tert butoxide and ethyl bromide.

Answer» Correct Answer - D
12.

What inspired N. Barlett for carrying out reaction between Xe and PtF6 ?

Answer»

[Hint : Almost same ionization enthalpy of oxygen and Xe.]

13.

Which is more acidic among HClO4 and HIO4 ? Why ?

Answer»

[Hint : HClO4 is more acidic than HIO4. Because Cl is more electronegative than Br, due to which ClO3 group have more tendency to withdraw electrons of
O – H bond towards itself as compared to BrO3 group.]

14.

When our target is asked to make this ether startint from alkyl halides. First we recall that ethers can be prepared by substitution reactions of alkoxide anion nucleophiles with alkyl halide electrophiles- The William ether synthesis. The two ways to prepare the target ether are as follows Next we examine the two reactions to determine whether both are expected to give a good yield of the target compound. Since route A combines a strongly basic nucleophile a secondary `(2^(@))` alkayl halide we expect the major product to result from elimaination by `E_2` mechanism. Route B on the other hand, employs a primary alkylhalide that can not give elimination (It has no hydrogen on the `beta`-carbon) and that is excellent. Substrate for an `S_N2`substitution because it is benzylic Route B is the obvious choice. Methyl tertiary butyl ether (MTBE) is an important gasoline additive for improving octane number. Select the best method of its synthesis out of the following.A. `CH_3CONa+CH_3Ito`B. `(CH_3)_(2)C=CH_2+CH_3OHoverset(H_2SO_4)to`C. `(CH_3)_(2)CBr+CH_3ONato`D. all give `100%` yield

Answer» Correct Answer - A
15.

Enthalpy of physical adsorption is quite low. Give reason.

Answer»

Because it involves weak van der Waals’ forces.

16.

"Together they have imposed the baggage on the child that he can't put down. Before he is aware, he accepts it as naturally as his father. To do anything else would mean to dare. And daring is not part of his growing up."i. Who has imposed the baggage on the child?ii. What does the child accept as naturally as his father?iii. Why is daring not a part of his growing up?iv. Name the lesson and the author.

Answer» Poverty, stigma of caste and a vicious circle of the sahukars,the middlemen,the police men,the keepers of law, the bureaucrats and the politicians together impose the baggage on the child that he can't put down.
17.

Name the method used for concentration of sulphide ores.

Answer»

Froth Floatation Method or Process.

18.

How is the cyclic movement of rain brought out in the poem. The voice of the rain

Answer» The poet explains the cyclic movement of the rain as the water vapour rises from the land and the bottomless sea to reach the sky. In the sky, it transforms itself into clouds. After wandering, these clouds descend to the earth in the form of rain. Thus it comes back to its origin.

The poet’s description of the cyclic movement of the rain is similar to the cyclical process of rain we learn in Science. We can find terms like evaporation, condensation, etc. The poet has depicted the same scientific phenomenon in an interesting way in the poem.

The cyclic movement of rain is brought out in the poem such that the rain drops in the form of water vapour, rise up to the sky from the land and the oceans to form clouds. It then returns to the earth in the form of rain and provides relief to the drought-ridden areas and infuses life into the unborn and latent seeds. The rain renders the earth with beauty and purity.

the poet explains that the raindrops in the form of water vapor rises up from the land and the sea and then descend again on the earth and dryland in order to wash it down and hence, comes back to its origin. this is the cyclic movement explained by the poet..
19.

Name the above reaction.

Answer»

Gatterman – Koch reaction.

20.

Among Noble gases which one is most abundant in air?

Answer»

Argon is most abundant in air.

21.

Who was called as silky?

Answer»

BOB was Called " Silky " Bob by the police because that was the only name they knew him by. If the wire from Chicago had contained Bob's real last name , then Jimmy would know in advance that his old friend was the wanted criminal.

22.

Name the major organic product formed when 2 – bromopentane is heated with alcoholic potassium hydroxide solution.

Answer»

Pent–2–ene or 2–Pentene

23.

Who was called as a kind of plodder? in the prose after twenty years

Answer»

Jimmy called as a kind of plodder.

24.

Name any one method of redemption of debentures.

Answer»

Payment is lump sum or any ether one.

25.

Profit on forfeited shares is transferred to account.

Answer»

Capital reserve.

26.

Discuss India’s federal structure with reference to Local Self Government?

Answer»

The major relationship between Federal and State Governments and Local Governments are summarized below: In a Federal and State, all the government activities are being coordinated together, yet they are independent of one another. The component states of the federation are created out of a single country. There are powers sharing in the federation. There is the duplication of government departments at the federal, state and local levels. The country’s resources are kept in the national treasury and shared among the 3 levels (tiers) of government every month. Regular council of states meetings bring the Federal and state governments together to discuss national problems and issues of economic development. The federal government represents the entire nation in external affairs. All the levels of government are under the operation of the same constitution to form a united government.

27.

Amount due to deceased partner is settled in the following manner.[a] Immediate full payment [b] Transferred to loan account [c] Partly Paid in cash and balance transferred to loan account [d] All of the above

Answer»

[d] All of the above

28.

Calculate the number of moles of hydrogen gas that can be produced by the reaction of 0.750 moles of hydrochloric acid with calcium.

Answer»

Ca (s) + 2HCl → CaCl2 + H2\(\uparrow\) 

From the above balance chemical equation. we can conclude that.

2 moles of HCl react with one mole of Ca to produce one mole CaCl2 and one mole of hydrogen gas.

\(\therefore\) 0.750 mole HCl on reaction with Ca can produce

 = \(\frac12\times0.750\) mole H2 gas

 = 0.375 mole H2 gas.

29.

Accumulated profits are transferred to all partners’ capital account including new partner [True / False].

Answer»

False: Accumulated profits are transferred to all partners’ capital account including new partner.

30.

Government grant is treated as …………….. receipt.

Answer»

Government grant is treated as Revenue Receipt receipt.

31.

Advantages of going public

Answer»
  • A value for securities can be established. 
  • Increased access to capital-raising opportunities (both public and private financings) and expansion of investor base. 
  • Liquidity for investors is enhanced since securities can be traded through a public market.
32.

What’s the easiest way for finding the oxidation and reduction numbers of an element in a compound in a chemical equation?

Answer»

There are different rules on finding the oxidation number for different compound. These are as follows

1.oxidation number of element is zero i.e. either mono-atomic or di atomic e.g. Na, H2, Cl2 ,Al etc.

2. Oxidation number of ion is charge present on it e.g Al+++ means oxidation number of aluminium is 3.

3. Sum of oxidation number of neutral compound is always zero.

4. Oxidation number of alkali metal is +1 and alkaline earth metal is +2 . In oxygen generally oxidation state is -2 but contain limitation on peroxide and super oxide.

5 Oxidation of halogen is generally -1 but with Chlorine and Bromine contain exception when they formed the compound with Florine.

6. Hydrogen also give the oxidation state of +1 but some exception with metal hydride.

33.

Diethyl ether can be decomposed byA. HIB. NaOHC. WaterD. `KMnO_(4)`

Answer» Correct Answer - A
34.

Highest oxidation state of transition metal is exhibited in its oxide and not in Fluoride . Why ?

Answer»

The highest oxidation state of a metal exhibited in its oxide or fluoride only since fluorine and oxygen are the most electronegative elements. The highest oxidation state shown by any transition element is +8.

35.

what challenges is faced by the jute industries? 

Answer»

Major problems of Indian Jute Industries :

  • High cost of production.
  • Storage of raw Jute.
  • Shortage of Power Supply.
  • Growth of Jute mills in Bangladesh and loss of foreign marke.
  • Emergence of substitute goods against gunny bags and loss of demand for jute goods both at home and abroad.
36.

Explain how. during light reaction of photosynthesis, ATP synthesis as a chemiosmotic phenomenon takes place?

Answer»

Chemiosmosis requires a membrane, a proton pump, a proton gradient and ATPase. Energy is used to pump protons across a membrane, to create a gradient or a high concentration of protons within the thylakoid lumen. ATPase enzyme catalyses the formation of ATP, along with the NADPH produced by.the movement of electrons, the ATP will be used immediately in the biosynthetic ’ reaction taking place in the stroma, responsible for fixing CO2 and synthesis of sugars.

37.

Government grant is treated as __________ receipt.

Answer»

Government grant is treated as Revenue receipt receipt.

38.

When the partners current accounts are prepared in partnership firm?

Answer»

Partners current account is prepared when the partners maintain their capital under Fixed Capital Method.

39.

Give one example for current liability.

Answer»

Current liabilities → Creditors, Bills payable, Short term provisions, Short term borrowings.

40.

When phenolic ehter is heated with `HI`, it yieldsA. alkyl halide +phenolB. alcohol + aryl halideC. alkyl halide + aryl halide + waterD. none of the above.

Answer» Correct Answer - A
41.

Elements A and B form two compounds `B_2​A_3` and `B_2​A`. If 0.05 moles of `B_2​A_3` weigh 9.0 g and 0.10 mole of `B_2​A` weigh 10 g, then atomic weight of A and B are :-A. 20 and 30B. 30 and 40C. 40 and 30D. 30 and 20

Answer» Correct Answer - C
0.05 mol `B_2A_3` = 9 g
1 mol `B_2A_3 = 9/0.05 `= 180 g
`therefore` 2B+3A = 180 ….(i)
0.10 mol `B_2A`=10 g
1 mol `B_2A=10/0.10`=100 g
`therefore` 2B +A = 100 ….(ii)
On solving (i) & (ii)
A = 40, B = 30
42.

In which combinations all the ligands are ambient in nature?A. `NO_(2),overline(S)CN` and `overline(C)N`B. EDTA, `overline(S)CN`C. D. All of these

Answer» Correct Answer - A
Having two possible donating site but donate from one only.
43.

Which of the following is correctly matched ?A. `CH_3-CH_2-NH-CH_2-CH_3` & `CH_3-NH-CH_2CH_2CH_3` Chain isomersB. `CH_3-overset(CH_3)overset|CH-NH_2` & `CH_3-NH_2-CH_3` Functional group isomers

Answer» Correct Answer - B
(1) Metamers
(2) Functional group isomers
(3) Functional group isomers
(4) Functional group isomers
44.

A compound is soluble in conc. `H_2SO_4`. It does not decolourise bromine in carbon tetrachloride but is oxidised by chromic abhydride in aqueous sulphuric acid with in two seconds, turning orange solution to blue, green and then opaque. The original compound isA. a primary alcoholB. a tertiary alcoholC. an alkeneD. an ether.

Answer» Correct Answer - A
Solubility of the compound in conc. `H_2SO_4` indicates that it can be alkene. Alcohol or ether. The inability to discharge bromine colour indicates absence of an alkene. Hence the compound is an alcohol which should be primary alcohol because it readily (with in two seconds) oxidized by `CrO_3` in `H_2SO_4`.
45.

Best method to prepare absolute alcohol from ordinary alcohol is byA. dehydration with anhydrous `CuSO_4`B. dehydration with CaOC. azeotropic distillation after mixing it with benzene.D. none of these.

Answer» Correct Answer - D
Now-a-days all absolute alcohol is made by membrane technology.
46.

Highest percentage of alcohol formed by fermentation isA. `14%`B. `95%`C. `59%`D. `100%`

Answer» Correct Answer - A
During fermentation, the enzyme is deactivated when alcohol content reaches `14%`.
47.

The chemical processes in the production of steel from haematite ore involveA. reduction followed by oxidationB. oxidationC. oxidation followed by reductionD. reduction

Answer» Correct Answer - C
`4FeO+O_(2) to 2F_(2)O_(3), Fe_(2)O_(3) + 3CO to 2Fe +3CO_(2)`
48.

Electrometallurgy is employed for the extraction ofA. CuB. FeC. NaD. Ag

Answer» Correct Answer - C
Sodium is at higher position of activity series haver low SRP.
49.

The underlying of blast furnace is made ofA. Silica bricksB. Fire clay bricksC. Basic bricksD. Graphite

Answer» Correct Answer - B
Fire clay bricks withstand high temperature 2000 K
50.

Give any two differences between lanthanoids and actinoids.

Answer»

Lanthanoids: 

1. 4f–orbital is progressively filled 

2. Magnetic properties are complex 

Actinoids: 

1. 5f–orbital is progressively filled 

2. Magnetic properties are more complex