This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
State the Acidity or Hydroxity of a Base. |
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Answer» It may be defined as the number of OH– ions furnished by a molecule of a base. A base can be, (i) Mono acidic or Monohydroxic like NaOH, NH4OH, AgOH etc. (ii) Diacidic or dihydroxic like Ba(OH)2, Mg(OH)2, Ca(OH)2, Sr(OH)2 etc. (iii) Triacidic or trihydroxic like Fe(OH)3, Al(OH)3 etc. |
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| 2. |
Amongst the various ores of a metal (M) (sulphide, carbonates, oxides, hydrated or hydroxides) two ores [X] and [Y] show the following reactivity. (i)[X] on calcination gives a black solid (S), carbon dioxide and water. (ii)[X] Dissolved in dilute HCl, on reaction with Kl gives a white precipitate (P) and iodine. (iii)[Y] on roasting gives metal (M) and a gas `(G_(1))` which turns acidified `K_2Cr_2O_7` solution green. (iv)[Y] on reaction with dil.HCl gives a white precipitate (Q) and another gas `(G_2)` which turns lead acetate solution black, and also reacts with gas `(G_1)` to precipitate colloidal sulphur in presence of moisture. Reaction involved: (i)`CuCO_3. Cu(OH)_2oversetDeltatoCuOdarr("black")+CO_2+H_2O` `CuCO_3.Cu(OH)_2+4HCl to2CuCl_2+3H_2O+CO_2` (ii)`2Cu^(2+)+4I^(-)toCu_2l^2 darr (P)("white")+l_2uarr` (iii)`2Cu_2S+3O_2to2Cu_2O+2SO_2(G_1)` `Cu_2S+2Cu_2Oto6Cu+SO_2` (iv)`Cu_2S+2HCl to 2CuCldarr(Q)("white")+H_2S(G_2)` `Pb^(2+)+H_2StoPbSdarr("black")+2H^(+)` (v)`SO_2(G_1)+2H_2S(G_2)overset("moisture")to3Sdarr+2H_2O` The white precipitate (P) is of :A. `Cu_2I_2`B. `Cu I_2`C. `K_2[Cu l_4]`D. None |
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Answer» Correct Answer - A `CuCO_3+2HCl to CuCl_2+CO_2 +H_2O , CuCl_2 + 2KltoCu l_2 + 2KCl , 2Cu l_2 to Cu_2l_2 darr (P) +I_2` |
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| 3. |
Amongst the various ores of a metal (M) (sulphide, carbonates, oxides, hydrated or hydroxides) two ores [X] and [Y] show the following reactivity. (i)[X] on calcination gives a black solid (S), carbon dioxide and water. (ii)[X] Dissolved in dilute HCl, on reaction with Kl gives a white precipitate (P) and iodine. (iii)[Y] on roasting gives metal (M) and a gas `(G_(1))` which turns acidified `K_2Cr_2O_7` solution green. (iv)[Y] on reaction with dil.HCl gives a white precipitate (Q) and another gas `(G_2)` which turns lead acetate solution black, and also reacts with gas `(G_1)` to precipitate colloidal sulphur in presence of moisture. Reaction involved: (i)`CuCO_3. Cu(OH)_2oversetDeltatoCuOdarr("black")+CO_2+H_2O` `CuCO_3.Cu(OH)_2+4HCl to2CuCl_2+3H_2O+CO_2` (ii)`2Cu^(2+)+4I^(-)toCu_2l^2 darr (P)("white")+l_2uarr` (iii)`2Cu_2S+3O_2to2Cu_2O+2SO_2(G_1)` `Cu_2S+2Cu_2Oto6Cu+SO_2` (iv)`Cu_2S+2HCl to2CuCldarr(Q)("white")+H_2S(G_2)` `Pb^(2+)+H_2StoPbSdarr("black")+2H^(+)` (v)`SO_2(G_1)+2H_2S(G_2)overset("moisture")to3Sdarr+2H_2O` Which of the following statements is correct about [Y] ?A. [Y] is converted to metal (M) by self reductionB. Carbonate extract of [Y] gives yellow precipitate with suspension of `CdCO_3`C. [Y] is chalcocites or chalcopyritesD. All of these |
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Answer» Correct Answer - D It is sulphide ore (`Cu_2S` or `CuFeS_2`) & is called as chalcopyrites or chalcocities , `S^(2-)` gives yellow precipitate of CdS with `CdCO_3` |
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| 4. |
Amongst the various ores of a metal (M) (sulphide, carbonates, oxides, hydrated or hydroxides) two ores [X] and [Y] show the following reactivity. (i)[X] on calcination gives a black solid (S), carbon dioxide and water. (ii)[X] Dissolved in dilute HCl, on reaction with Kl gives a white precipitate (P) and iodine. (iii)[Y] on roasting gives metal (M) and a gas `(G_(1))` which turns acidified `K_2Cr_2O_7` solution green. (iv)[Y] on reaction with dil.HCl gives a white precipitate (Q) and another gas `(G_2)` which turns lead acetate solution black, and also reacts with gas `(G_1)` to precipitate colloidal sulphur in presence of moisture. Reaction involved: (i)`CuCO_3. Cu(OH)_2oversetDeltatoCuOdarr("black")+CO_2+H_2O` `CuCO_3.Cu(OH)_2+4HCl to2CuCl_2+3H_2O+CO_2` (ii)`2Cu^(2+)+4I^(-)toCu_2l^2 darr (P)("white")+l_2uarr` (iii)`2Cu_2S+3O_2to2Cu_2O+2SO_2(G_1)` `Cu_2S+2Cu_2O to6Cu+SO_2` (iv)`Cu_2S+2HCl to2CuCldarr(Q)("white")+H_2S(G_2)` `Pb^(2+)+H_2StoPbSdarr("black")+2H^(+)` (v)`SO_2(G_1)+2H_2S(G_2)overset("moisture")to3Sdarr+2H_2O` The gas `(G_1)` acts asA. Oxidising agentB. Reducing agentC. Oxidising and reducing agentD. Fluxing agent |
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Answer» Correct Answer - C `G_1=SO_2`, sulphur can increases & decreases its oxidation state. |
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| 5. |
Amongst the various ores of a metal (M) (sulphide, carbonates, oxides, hydrated or hydroxides) two ores [X] and [Y] show the following reactivity. (i)[X] on calcination gives a black solid (S), carbon dioxide and water. (ii)[X] Dissolved in dilute HCl, on reaction with Kl gives a white precipitate (P) and iodine. (iii)[Y] on roasting gives metal (M) and a gas `(G_(1))` which turns acidified `K_2Cr_2O_7` solution green. (iv)[Y] on reaction with dil.HCl gives a white precipitate (Q) and another gas `(G_2)` which turns lead acetate solution black, and also reacts with gas `(G_1)` to precipitate colloidal sulphur in presence of moisture. Reaction involved: (i)`CuCO_3. Cu(OH)_2oversetDeltatoCuOdarr("black")+CO_2+H_2O` `CuCO_3.Cu(OH)_2+4HCl to2CuCl_2+3H_2O+CO_2` (ii)`2Cu^(2+)+4I^(-)toCu_2l^2 darr (P)("white")+l_2uarr` (iii)`2Cu_2S+3O_2to2Cu_2O+2SO_2(G_1)` `Cu_2S+2Cu_2O to 6Cu+SO_2` (iv)`Cu_2S+2HCl to 2CuCldarr(Q)("white")+H_2S(G_2)` `Pb^(2+)+H_2StoPbSdarr("black")+2H^(+)` (v)`SO_2(G_1)+2H_2S(G_2)overset("moisture")to3Sdarr+2H_2O` The metal ores [X] and [Y] are respectively :A. Carbonate and sulphide oresB. Sulphide and carbonate oresC. Carbonate and hydroxide oresD. Carbonate and oxide ores |
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Answer» Correct Answer - A `[X]=CuCO_3 Cu(OH)_2 or 2CuCO_3. Cu(OH)_2 , [Y]=Cu_2S or CuFeS_2` |
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| 6. |
Which is incorrect:-A. `{:("Mixture","Separated by"),((1)Na_(2)S&CuS,H_(2)O):}`B. `{:("Mixture","Separated by"),((2)PbS & ZnS, NaCN):}`C. `{:("Mixture","Separated by"),((3)Fe_(2)O_(3)","Al_(2)O_(3),HCl):}`D. `{:("Mixture","Separated by"),((4)Al_(2)O_(3)","MgO,NaOH):}` |
| Answer» Correct Answer - C | |
| 7. |
______ are the only birds that can fly backwards.1. Common cranes2. Mallards3. Whooper swans4. Hummingbirds |
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Answer» Correct Answer - Option 4 : Hummingbirds The Correct Answer is Hummingbirds.
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| 8. |
______ is a long thick orange vegetable. A) tomato B) cucumber C) onion D) carrot |
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Answer» Correct option is D) carrot |
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| 9. |
An inorganic salt (A) is decomposed at about 523K to give products (B) and (C). Compound (C) is a liquid at room temperature and is neutral to litmus paper while compound (B) is used in dental surgery for anesthesia purpose. Compounds (A),(B),(C) wll be identified as-A. `NH_(4)NO_(3),N_(2)O,H_(2)O`B. `NH_(4)NO_(2),N_(2),H_(2)O`C. `CaCO_(3),CaO,H_(2)O`D. NH_(4)Cl, NH_(3),HCl` |
| Answer» Correct Answer - A | |
| 10. |
4NH3 (g) +5O2(g) =4NO(g)+6H2O(g) |
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Answer» Please refers to the below link http://bit.ly/2GBmCna |
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| 11. |
Sodium hydroxide solution is treated with Acidic acid to form sodium acetate and water |
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Answer» Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water. NaOH + CH3COOH → CH3COONa + H2O |
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| 12. |
4NH3+5O2=4no+6H2O |
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Answer» The reducing agent-- NH3 |
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| 13. |
Aluminum is exteracted from alumine `AI_(2)O_(3)` by electrolysis of a molten mixture of :A. `AI_(2)O_(3) +HF + NaIF_(4)`B. `AI_(2)O_(3) + CaF_(2) + NaAIF_(4)`C. `AI_(2)O_(3) + Na_(3)AIF_(6)+ CaF_(2)`D. `AI_(2)O_(3) +KF + Na_(3)Al_(4)^(2)` |
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Answer» Correct Answer - c Electrolysis of pure alumine faces to difficulties : (i) pure `AI_(2)O_(3))` is a bed conductor of electricity , (ii) fusion temperature of pure alumina is about `2000^(@)C` and at this temperature (when fused mass is electrolyzed) the metal found vaperizes as the boiling point of `AL` is `1800 ^(@)C` .The above difficulties are overcomed (hall- Heroult process) by using a mixture `AI_(2)O_(3))` cryolite`(Na_(3)AIF_(6))` and flursoar `(CaF_(2))` in the ratio of `20 : 40: 20` .The fusion temperature mixture is `900^(@)C` and it is good conductor of electricity . |
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| 14. |
In which case the energy change is minimum :A. `Cl rarr Cl^(-)`B. `P rarrP^(-)`C. `N rarrN^(-)`D. `C rarr C^(-)` |
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Answer» Correct Answer - C `(1)CgtPgtN` `3^(rd)` period `EA gt 2^(nd)` period EA `N rarr 2p^(3)` electronic configration. |
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| 15. |
A drop of a liquid sample was put on the pH paper. It was observed that the colour of the pH paper turned blue. The liquid sample isA. lemon chainB. sodium bicarbonate solutionC. distilled waterD. hydrochloric acid |
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Answer» Correct Answer - B |
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| 16. |
Find the number of moles of electrons present in the biggest unit of charge |
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Answer» We know that the biggest unit of charge is Faraday. 1 Faraday contains only 1 mole of electrons. Hence, no of moles of electrons present in the biggest unit of charge is 1. |
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| 17. |
0.5 mole of `SO_2` gas at `27^@C` is expanded in reversible adiabatic condition to make volume 8 times.Final temperature (in K) and work done by gas (in Cal) respectively are x and y.Report your answer as `y/x`. (Take ideal behaviour of gas, R=2 Cal/K mol and `2^(1.2)=2.3`) |
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Answer» Correct Answer - 3 `T_1V_1^(gamma-1)=T_2V_2^(gamma-1)implies 300xxV^(1//3)=T_2(8V)^(1//3)implies T_2=150 K` `W=nC_v(T_2-T_1)=0.5xx3 R(150-300)=0.5xx3xx2(-150)=-450`cal |
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| 18. |
Give advantages of long form of periodic table. |
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Answer» a. It relates position of periodic table with electronic configuration. b. It reduces study of `114` elements into `18` groups and `7` periods. c. It helps in discovery of new elements. |
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| 19. |
Which one of the following alkaline earth metal sulphates has its hydration enthalpy greater than its lattice enthalpy?A. `CaSO_(4)`B. `BeSO_(4)`C. `BaSO_(4)`D. `SrSO_(4)` |
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Answer» Correct Answer - B `BaBO_(4)` is least soluble. `BeSO_(4)` is most soluble. |
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| 20. |
Give five characteristics of `p`-block elements. |
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Answer» a.They consist of solids, liquids and gases. They consist of metals, non-metals and metalloids. They show variable valency d. They form both ionic and covalent compounds. e. Most of them are good oxidising agents. |
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| 21. |
a. Among `Cu^(o+)`,`Cu^(2+)` and `Cu` which is the largest in size and why? b. Which element in periodic table has the highest `IE` (ionisation energy)? c. Which element, `Mg` or `Al`, is more metallic and why? |
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Answer» a. `Cu` is largest due to less effective nuclear charge. It has `29` electrons , `29` protons, `Cu^(+)` has `28` electrons and `29`protons, `Cu^(2+)` has `27` electrons and `29` protons . b. He has the highest ionisation energy. c. `Mg` is more metallic due to lower ionisation energy. |
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| 22. |
Which of the following orders is correct for the size ? (1)`Mg^(2+)ltNa^(+)ltF^(-)ltAl` (2)`Al^(3+)ltMg^(2+)ltLi^(+)ltK^(+)` (3)`Fe^(4+)ltFe^(3+)ltFe^(2+)ltFe` (4)MggtAlgtSigtPA. (1),(2)&(3)B. (2),(3) & (4)C. (1),(3) & (5)D. (1),(2),(3) & (4) |
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Answer» Correct Answer - D (1)`Mg^(2+),Na^(+) and F^(-)` are isoelectronic and thus follows the order `._12 Mg^(2+) lt ._(11)Na^(+) lt ._9F^(-)` All belongs to third period and has no charge so it is largest. `Na^(+)=102` pm , `Mg^(2+)` =72 pm, Al=143 pm, `F^-`=133 pm. (2)`K^+` has more number of shells than `Mg^(2+)` and `Al^(3+)` .`Al^(3-)` and `Mg^(2+)` are isoelectronic but `Al^(3+)` has higher nuclear charge so `Al^(3+) lt Mg^(2+) . Mg^(2+)` and `Li^(+)` has diagonal relationship.But due to +2 charge to +2 charge in `Mg^(2+)` , the `Mg^(2+)` is smaller than `Li^(+)`.Hence `Al^(3+)` is the smallest one. `K^(+)=1.38Å, Li^(2+)=0.76 Å, Mg^(2+)=0.72 Å, Al^(3+)=0.535 Å` (3)As the number of electrons are lost , the attraction between valence shell electrons and nucleus increases As a consequence of this the electrons are pulled closer to the nucleus leading to the contraction in size of ions. (4)Across the period the nuclear charge increases and thus the size of atoms decreases, Mg=160 pm, Al=143 pm , Si=118 , P=110 pm |
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| 23. |
Match the values of ionization energy and electron gain enthalpy listed in column I with characteristic(s) of elements listed in column II. `{:("Column-I","Column-II"),((A)"2372 5251 +48",(p)"Element which acts as a strong reducing agent"),((B)"419 3051 -48",(q)"Element which exists as a monoatomic molecule"),((C )"1681 3374 -333",(r)"Least reactive non-metal"),((D)"1008 1846 -295",(s)"Element which acts as a strong oxidising agent"),(,(t)"Element which oxides is a stronger basic in nature"):}` |
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Answer» Correct Answer - A`to`q ; B`to`p,t ;C`to`s ; D`to`r (A)Inert gas exist as monoatomic molecule. They have highest `IE_1` and `IE_2` and positive electron gain enthalpies. (B)Alkali metal -`IE_1` is low because of bigger size of atom and `IE_2` is high due to noble gas configuration . As it has low `IE_1` it can lose one electron easily and thus more electropositive .So it acts as strong reducing agents and their oxides are basic in nature.They have low negative value of `DeltaH_(eg)` because of large size. (C )`IE_1 and IE_2` both high and negative value of electron gain enthalpy is very high because of high nuclear charge and small size of atoms, so it has a greater tendency to accept an additional electron.So it (F) act as a strong oxidising agent. (D)As it has less negative value for `DeltaH_(eg)` than (C ) thus it will be least reactive non-metal (I) |
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| 24. |
A narrow beam of white light goes through a slab having parallel faces(a) the light never splits in different colours(b) the emergent beam is white(c) the light inside the slab is split into different colours(d) the light inside the slab is white |
| Answer» (b,c) If faces of prism on which light is incident & from which it emerge are parallel, then angle of prism will be zero & so deviation will also be zero i.e., the prism will act as a transparent prism | |
| 25. |
Identify the wrong sign convention(a) The magnification for virtual image formed by a convex lens is positive(b) The magnification for real image formed by a convex lens is negative(c) The height measured normal to the principal axis upwards is positive(d) The magnification for virtual image formed by a concave lens is negative |
| Answer» (d) The magnification for vertual image formed by concave lens is positive. | |
| 26. |
The speed of light in an isotropic medium depends on(a) the nature of the source(b) its wavelength(c) its direction of propagation(d) its intensity |
| Answer» (b) In an isotropic medium, speed of light depends on its wavelength. | |
| 27. |
Circinate vernation is found inA. Moss/Funaria/RicciaB. Fern/Dryopteris/PterisC. PinusD. Both A and B |
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Answer» Correct Answer - B Circinate vernation is found in fern. |
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| 28. |
The apparent flattening of the sun at sunset and sunrise is due to(a) refraction(b) diffraction(c) total internal reflection(d) interference |
| Answer» (a) The apparent flattening (oval shape) of the sun at sunset and sunrise is due to refraction | |
| 29. |
In ferns, the term frond is used forA. RootB. StemC. LeavesD. Capsule |
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Answer» Correct Answer - C In ferns, the term frond is used for leaves. |
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| 30. |
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side on its principal axis, the intensity of light(a) remains constant(b) continuously increases(c) continuously decreases(d) first increases then decreases |
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Answer» (a) remains constant |
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| 31. |
The rays of different colours fail to converge at a point after going through a converging lens. This defect is called(a) spherical aberration(b) distortion(c) coma(d) chromatic aberration |
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Answer» (d) chromatic aberration. EXPLANATION: Since the refractive index of a medium is different for different colors. Hence the rays of different colors fail to converge at a point. Since this aberration is related to colored rays it is called a chromatic aberration because chrome is a Greek word for color. |
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| 32. |
Sunlight reaches to us in composite form and not in its constituent colours becauseI. vacuum is non–dispersive.II. speed of all colours is same in vacuum.III. light behaves like a particle in vacuum.IV. light travels in a straght line in vacuum.(a) I and II (b) II and III (c) III and IV(d) I and IV |
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Answer» (a) The variation of refractive index with wavelength may be more pronounced in some media than the other. In vacuum, of course, the speed of light is independent of wavelength. Thus, vacuum (or air approximately) is a non dispersive medium in which all colours travel with the same speed. This also follows from the fact that sunlight reaches us in the form of white light and not as its components. On the other hand, glass is a dispersive medium |
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| 33. |
The focal length of a normal eye-lens is about(a) 1 mm (b) 2 cm(c) 25 cm (d) 1 m |
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Answer» The focal length of a normal eye-lens is (b) 2 cm |
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| 34. |
The difference between reflection and total internal reflection is that(a) the laws of reflection hold true for reflection but not for total internal reflection.(b) total internal reflection can take place only when light travels from a rarer medium to a denser medium while reflection can take place vice-versa also.(c) reflection can take place when light travels from a rarer medium to denser medium and vice-versa but total internal reflection can take place only when it travels from an optically denser to an optically rarer medium.(d) reflection is a natural phenomena while total internal reflection is man-made |
| Answer» (c) For total internal reflection light ray must travel from optically denser to an optically rarer medium. | |
| 35. |
Astigmatism is corrected using(a) cylindrical lens (b) plano-convex lens(c) plano-concave lens (d) convex lens |
| Answer» (a) Cylindrical lens is used to rectify eye defect astigmatism | |
| 36. |
Total internal reflection can take place only if(a) light goes from optically rarer medium (smaller refractive index) to optically denser medium(b) light goes from optically denser medium to rarer medium(c) the refractive indices of the two media are close to different(d) the refractive indices of the two media are widely different |
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Answer» (b) According to Snell’s Law, sin i/ sin r =μ 2/μ 1 = where r = 90º for particular incidence angle called critical angle. When the incidence angle is equal to or greater than ic , then total internal reflection occurs. It takes place when ray of light travels from optically denser medium (μ1 > μ2 ) to optically rarer medium. |
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| 37. |
Which light rays undergoes two internal reflection inside a raindrop, which of the rainbow is formed?(a) Primary rainbow (b) Secondary rainbow(c) Both (a) and (b) (d) Can’t say |
| Answer» (b) Secondary rainbow is formed by rays undergoing interanal reflection twice inside the drop | |
| 38. |
Identify the mismatch in the following(a) Myopia - Concave lens(b) For rear view - Concave mirror(c) Hypermetropia - Convex lens(d) Astigmatism - Cylindrical lens |
| Answer» (b) For rear view, Convex mirror is used in vehicle | |
| 39. |
Which of the following statements about laws of reflection is/are correct?I. The incident ray, the reflected ray and the normal all lie in the same plane.II. Angle of incidence is equal to the angle of reflection.III. After reflection, velocity, wavelength and frequency of light remains same but intensity decreases.(a) I only (b) II only(c) I and II (d) I, II and III |
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Answer» statements about laws of reflection are correct (d) I, II and III |
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| 40. |
Which of the following is/are correct relations? |
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Answer» . (a) If n21 is the refractive index of medium 2 with respect to medium 1 and n12 the refractive index of medium 1 with respect to medium 2, then it should be clear that n12=1/n21 It also follows that if n32 is the refractive index of medium 3 with respect to medium 2, then n32 = n31 × n12, where n31 is the refractive index of medium III with respect to medium I. |
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| 41. |
Directions : Each of these questions contains two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion.(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion(c) Assertion is correct, reason is incorrect(d) Assertion is incorrect, reason is correctAssertion : Two convex lenses joined together cannot produce an achromatic combination.Reason : The condition for achromatism is ω1/f1 +ω2/f2 =0 where symbols have their usual meaning |
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Answer» (a) Assertion is correct, reason is correct; reason is a correct explanation for assertion. |
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| 42. |
Directions : Each of these questions contains two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion.(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion(c) Assertion is correct, reason is incorrect(d) Assertion is incorrect, reason is correct.Assertion : Critical angle is minimum for violet colour.Reason : Because critical angle θc=sin-1(1/μ) and μ∝1/λ |
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Answer» (a) Assertion is correct, reason is correct; reason is a correct explanation for assertion. |
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| 43. |
Which of the following is correct for the beam which enters the medium?(a) Travel as a cylindrical beam(b) Diverge(c) Converge(d) Diverge near the axis and converge near the periphery |
| Answer» (c) Since the refractive index is less at beam boundary, the ray at the edges of the beam move faster compared to the axis of beam. Hence the beam converges | |
| 44. |
If D is the deviation of a normally falling light beam on a thin prism of angle A and δ is the dispersive power of the same prism then(a) D is independent of A.(b) D is independent of refractive Index.(c) δ is independent of refractive index.(d) δ is independent of A. |
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Answer» (d) δ is independent of A. |
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| 45. |
The dispersive power of material of a lens of focal length 20 cm is 0.08. What is the longitudinal chromatic aberration of the lens ?(a) 0.08 cm (b) 0.08/20 cm (c) 1.6 cm (d) 0.16 cm |
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Answer» (c) Longitudinal chromatic aberration = ωf = 0.08 × 20 = 1.6 cm |
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| 46. |
Which of the following phenomena is used in optical fibres ?(a) Total internal reflection(b) Scattering(c) Diffraction(d) Refraction |
| Answer» (a) The basic principle of communication in fibre optics is based on the phenomenon of total internal reflection. | |
| 47. |
Which of the following is not due to total internal reflection?(a) Working of optical fibre(b) Difference between apparent and real depth of pond(c) Mirage on hot summer days(d) Brilliance of diamond |
| Answer» (b) Difference between apparent and real depth of a pond is due to the refraction of light, not due to the total internal reflection. Other three phenomena are due to the total internal reflection | |
| 48. |
The dispersive power of a prism depends on its(a) shape(b) size(c) angle of prism(d) refractive index of the monitorial of the prism |
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Answer» (d) refractive index of the monitorial of the prism |
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| 49. |
Assertion: Neopentane forms one mono substitutes compound Reason: Neopentane is an isomer of pentane.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - B Neopentane is isomer of pentane and neopentane forms only one substitution product. Both assertion and reason are true but reason is not the correct explanation of assertion. Neopentane forms monosubstitued product due to presence of four identical methyl groups present on carbon atom. |
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| 50. |
Arrange the following in their nucleophilicity order. (I) `C_(6)H_(5)O^(Theta)` (II) `C_(6)H_(5)S^(Theta)` (III) `C_(6)H_(5) - overset(Theta)CH_(2)` (IV) `CH_(3)-overset(O)overset(||)C-overset(Theta)CH_(2)`A. `II gt III gt IV gt I`B. `I gt IV gt II gt III`C. `II gt IV gt III gt I`D. `III gt IV gt I gt II` |
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Answer» Correct Answer - A Nucleophiclicity of `S^(-)` is more as it is weak base. |
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