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Instruments for measuring the intensity of incoming radiation are called1. pyrheliometers2. sunshine recorders3. hygrometer4. psychrometers

Answer» Correct Answer - Option 1 : pyrheliometers

Explanation

Instrument	Measured quantity
1. Pyrheliometer	Solar radiations coming directly from sun
2. Sunshine recorders	Amount of sunlight that a particular location receives throughout a day
3. Hygrometer	used to measure relative humidity
4. Psychrometer	Measures humidity

Discussion

2.	An unconfined aquifer of porosity 35%, permeability 40 m / day, and specific yield of 0.15 has an area of 100 km2. If the water table falls uniformly throughout the aquifer area by 0.2 m during a drought, the volume of water lost from storage is1. 1.5 Mm32. 3.0 Mm33. 7.0 Mm34. 8.0 Mm3
Answer» Correct Answer - Option 2 : 3.0 Mm³ Concept: Specific yield is defined as the volume of water released from storage by an unconfined aquifer per unit surface area of aquifer per unit decline of the water table. When the above statement is expressed in quantitative form, it will be as below- Volume of water lost = Specific yield × Drawdown × Area Calculation: Porosity = 35%, Permeability = 40 m / day, Specific yield = 0.15 Area = 100 km² Drawdown = 0.2 m Volume of water lost = Specific yield × Drawdown × Area ∴ Volume of water lost = 0.15 × 0.2 × 100 × 10⁶ = 3.0 Mm³

An unconfined aquifer of porosity 35%, permeability 40 m / day, and specific yield of 0.15 has an area of 100 km2. If the water table falls uniformly throughout the aquifer area by 0.2 m during a drought, the volume of water lost from storage is1. 1.5 Mm32. 3.0 Mm33. 7.0 Mm34. 8.0 Mm3

Answer» Correct Answer - Option 2 : 3.0 Mm³

Concept:

Specific yield is defined as the volume of water released from storage by an unconfined aquifer per unit

surface area of aquifer per unit decline of the water table.

When the above statement is expressed in quantitative form, it will be as below-

Volume of water lost = Specific yield × Drawdown × Area

Calculation:

Porosity = 35%,

Permeability = 40 m / day,

Specific yield = 0.15

Area = 100 km²

Drawdown = 0.2 m

Volume of water lost = Specific yield × Drawdown × Area

∴ Volume of water lost = 0.15 × 0.2 × 100 × 10⁶ = 3.0 Mm³

Discussion