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1.

avg velocity of a particle moving in a straight line , with constant acceleration a and initial velocity u in first t seconds

Answer» Total displacement S= ut + 1/2 at2

Time = t

Average velocity = S/t

Av velocity = u+ 1/2at
Discussion
2.

integration of a=3t2-4t and a is acceleration. find distance in time 2 second

Answer»

Use derivative formula for Acceleration and distance to solve this question.

dv/dt = a   and

d2x/dt2 = a
Discussion
3.

Two balls are projected simultaneously in the same vertical plane from the same point with velocities V1 and V2 with angles θ1 and θ2 respectively with the horizontal. If V1 cosθ1 = V2 cosθ2 the path of one ball as seen from the position of other ball is1) Parabola 2) Horizontal straight line 3) Vertical straight line 4) Straight line making 45° with the vertical 

Answer»

Correct :-(3)

Explanation :-

It is given that V1 cos θ1 = V2 cos θ2 . Hence the relative velocity between them is zero. The path of one ball as seen from the position of the other ball is vertical straight line. 
Discussion