

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
Proteins are synthesized on :(A) Cytoskeleton (B) Mitochondria (C) Ribosomes (D) Golgi apparatus |
Answer» Proteins are synthesized on Ribosomes. |
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202. |
What is the advantage of storing glucose as glycogen in animals instead of as monomeric glucose ?(A) Energy obtained from glycogen is more than that from the corresponding glucose monomers(B) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in loss of water from the cells.(C) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in excess water within the cells.(D) Glycogen gives more rigidity to the cells. |
Answer» Correct option (C) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in excess water within the cells. Explanation: Glucose is a monosaccharide and osmotically active molecule which increase osmotic pressure in cell so water enters in cell while glycogen is osmotically inert molecule does not change the osmotic pressure. |
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203. |
What is the advantage of storing glucose as glycogen in animals instead of a monomeric glucose?(a) Energy obtained from glycogen is more than that from the corresponding glucose monomers(b) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in loss of water from the cells(c) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in excess water within the cells(d) Glycogen gives more rigidity to the cells |
Answer» Answer is : (c) Glucose present as monomers within the cell exerts more osmotic pressure than a single glycogen molecule, resulting in excess water within the cells Glucose is a monosaccharide and an osmotically active molecule which increases osmotic pressure in cell. So, water enters in cell while glycogen is osmotically inert molecule does not change the osmotic pressure. This is the reason why glucose is not stored in the cell instead glycogen is stored in the animal body. |
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204. |
The correct order of the lattice energies of the following ionic compounds is(a) NaCl > MgBr2 > CaO > Al2O3(b) NaCl > CaO > MgBr2 > Al2O3(c) Al2O3 > MgBr2 > CaO > NaCl(d) Al2O3 > CaO > MgBr2 > NaCl |
Answer» Answer is : (d) Al2O3 > CaO > MgBr2 > NaCl Lattice energy is defined as the amount of energy required to completely seperate one mole of a solid ionic compound into gaseous constituent ions. It is directly proportional to the charge of the ions. Thus, greater the ionic charge, larger is the lattice energy. Hence, correct order is Al2O3 > CaO > MgBr2 > NaCl |
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205. |
A new life form discovered on a distant planet has a genetic code consisting of five unique nucleotides and only one stop codon. If each codon has four bases, what is the maximum number of unique amino acids this life form can use ?(A) 624(B) 20(C) 124(D) 3124 |
Answer» Correct option (A) 624 Explanation: No. of unique nucleotide = 5 No. of bases in codon = 4 so, total combinations ⇒ 54 ⇒ 625 No. of stop codons = 1 so, unique amino acids (maximum) = 625 – 1 ⇒ 624 |
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206. |
Which of the following organisms produces sperm without involving meiosis?(a) Sandfly and fruitfly(b) Housefly and grasshopper(c) Honeybee and ant(d) Zebra fish and frog |
Answer» Answer is : (c) Honeybee and ant All haploid sexually reproducing organisms would produce sperms/male gametes without the process of meiosis, e.g. Honeybee (Apis) and Ant (Formica). Haploid parents produce gametes by mitotic division. This happens because meiosis is reductional division in which the daughter cells contain half the number of chromosomes as the parent cell. Therefore, haploid organisms do not show meiosis to further disturb their ploidy. |
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207. |
Among the following molecules, the one with the largest bond angle at the central atom is(a) ClF3(b) POCl3(c) BCl3(d) SO3 |
Answer» Answer is : (a) ClF3 The bond angle depends upon the electronegativity of the central atom. More is the electronegativity of the central, larger is the bond angle. Thus, among the given central atom Cl has the highest electronegativity. Therefore, ClF3 has the largest bond angle at the central atom. |
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208. |
A ball is thrown horizontally from a height with a certain initial velocity at time t = 0. The ball bounces repeatedly from the ground with the coefficient of restitution less than 1 as shownNeglect air resistance and taking the upward direction as positive, which figure qualitatively depicts the vertical component of the ballís velocity (Vy) as a function of time (t)? |
Answer» Correct option(b) Explanation: as Vy=Uy-gt |
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209. |
A man inside a freely falling box throws a heavy ball towards a side wall. The ball keeps on bouncing between the opposite walls of the box. We neglect air resistance and friciton. Which of the following figures depicts the motion of the centre of mass of the entire system (man, the ball and the box)? |
Answer» Correct option(a) Explanation: CM will go downwards |
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210. |
We are able to squeeze snow and make balls out of it because of(a) anomalous behaviour of water(b) large latent heat of ice(c) large specific heat of water(d) low melting point of ice |
Answer» (No option is matching) When we squeeze the snow due to increased pressure, melting point of ice (snow) is lowered and it melts. As pressure is removed, water formed is again frozen because melting point is again raised. This process is called regelation of ice. None of the option given is correct. |
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211. |
Removal of the pancreas impairs the breakdown of(a) lipids and carbohydrates only(b) lipids and proteins only(c) lipids, proteins and carbohydrates(d) proteins and carbohydrates only |
Answer» Answer is : (c) lipids, proteins and carbohydrates Removal of pancreas impairs the breakdown of lipids, proteins and carbohydrates because pancreas produces insulin and other important enzyme like trypsin, chymotrypsin, amylase and lipase which helps in breakdown of macromolecules. |
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212. |
Which one of the following genetic phenomena is represented by the blood group AB(a) Codominance(b) Dominance(c) Overdominance(d) Semidominance |
Answer» Answer is : (a) Codominance Blood group AB represents codominance. In codominance a heterozygous individual expresses both alleles simultaneously with blending. No single allele is dominant over the other. Expression of both A and B alleles at same time results in AB type blood. |
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213. |
Consider the set A = {1, 2, 3, ....., 30}. The number of ways in which one can choose three distinct number from A so that the product of the chosen numbers is divisible by 9 is(a) 1590(b) 1505(c) 1110(d) 1025 |
Answer» Answer is : (a) 1590 Given, A = {1, 2, 3, …, 30} Case I All three number are multiple of 3 then product of three number are divisible by 9. ∴ 10C3 = 120 Case II Two number are multiple of 3 and other are not multiple of 9. i.e. 10C2 x 20C1 = 900 Case III One are multiple of 9 and other two are not multiple of 3. 3C1 x 20C2 = 570 ∴Total number of ways = 120+900+570 = 1590 |
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214. |
Let S be the set of all ordered pairs (x, y) of positive integers satisfying the condition x2 - y2 = 12345678. Then,(a) S is an infinite set(b) S is the empty set(c) S has exactly one element(d) S is a finite set and has at least two elements. |
Answer» Answer is : (b) S is the empty set x and y are positive integer x2 - y2 = 12345678 RHS 12345678 is and even number and last digit is 8. ∴ The last digit of x be 3, 7 and the last digit of y be 1, 9 ∴x and y must be odd and square of difference is multiple of 8 but RHS is not multiple of 8. ∴ S is the empty set. |
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215. |
Consider four triangles having sides (5, 12, 9), (5, 12, 11), (5, 12, 13) and (5, 12, 15). Among these, the triangle having maximum area has sides.(a) (5,12, 9)(b) (5, 12, 11)(c) (5, 12, 13)(d) (5, 12, 15) |
Answer» Answer is : (c) (5, 12, 13) We have, Four triangle having sides are (5, 12, 9), (5, 12, 11), (5, 12, 13), (5, 12, 15) A right triangle has maximum area. ∴ Among these the triangle whose sides (5, 12, 13) form a right angled triangle. ∴ It has maximum area. |
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216. |
In warmer, weather, curds from milk forms faster because :(A) bacteria diffuse better in warmer milk (B) the rate of bacterial multiplication increases(C) lactogen is better dissolved (D) it is easier to separate protein from water |
Answer» In warmer, weather, curds from milk forms faster because the rate of bacterial multiplication increases. |
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217. |
Seedlings grown in dark are(a) similar to those grown in light(b) taller than those grown in light(c) shorter than those grown in light(d) they do not grow at all |
Answer» Answer is : (b) taller than those grown in light Seedlings grown in dark are taller than those grown in light as they develop long hypocotyls (embryonic shoot) and their cotyledons remain closed around the epicotyl in an apical hook. This process is referred to as etiolation. |
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218. |
Rotation of crops is carried out to :(A) increase variation in the mineral content of the soil(B) increase diversity of plant habitats(C) increase in nitrogen content of the soil(D) increase convenience for the farmer |
Answer» Rotation of crops is carried out to increase in nitrogen content of the soil. |
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219. |
‘On the origin of species , by means of Natural selection’ was written by.(A) Hugo de vires (B) Charles Darwin (C) Charles dickons (D)Alfred Russell wallace |
Answer» ‘On the origin of species , by means of Natural selection’ was written by Charles Darwin. |
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220. |
Saturated dietary fats increase the risk of heart disease by(a) widening arteries by thinning their walls(b) narrowing veins by carbohydrate deposition(c) narrowing arteries by fat deposition(d) narrowing arteries by carbohydrate deposition |
Answer» Answer is : (c) narrowing arteries by fat deposition Saturated dietary fats increase the risk of heart disease by narrowing arteries by fat deposition. Saturated fat raises the level of cholesterol in your blood. High levels of Low Density Lipid (LDL) cholesterol in blood are responsible for their deposition in blood vessel, thus narrowing the lumens and increasing the risk of heart diseases and stroke. |
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221. |
Dietary fibres are composed of(a) cellulose(b) proteins(c) amylase(d) unsaturated fats |
Answer» Answer is : (a) cellulose Dietary fibres are composed of non-starch polysaccharides such as cellulose, dextrins, inulin, lignin, chitins, pectins, beta-glucans, waxes and oligosaccharides. Dietary fibres, also known as roughage is the portion of plant derived food that cannot be completely broken down by digestive enzymes. Rest others, i.e. amylase, proteins and unsaturated fats are although basic components of diet but are not considered as dietary fibres. |
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222. |
Saturated dietary fats increase the risk of heart disease by :(A) widening arteries by thinning their walls (B) narrowing veins by carbohydrate deposition(C) narrowing arteries by fat deposition (D) narrowing arteries by carbohydrate deposition |
Answer» Saturated dietary fats increase the risk of heart disease by narrowing arteries by fat deposition. |
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223. |
Dietary fibers are composed of :(A) Cellulose (B) Amylase (C) Proteins (D) Unsaturated fats |
Answer» Dietary fibers are composed of Cellulose. |
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224. |
What is the number of chromosomes in an individual with Turner’s syndrome?(a) 44(b) 45(c) 46(d) 47 |
Answer» Answer is : (b) 45 The people with Turner’s syndrome have 44 + XO chromosomes, so there are a total of 45 chromosomes only in each cell. Such persons are sterile females who have rudimentary ovaries, undeveloped breasts, small uterus, short stature and abnormal intelligence. |
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225. |
During urine formation, the filtration of blood at the glomerulus is(a) an active process(b) an osmotic process(c) a pressure dependent physical process(d) a non-energy-mediated transport process |
Answer» Answer is : (c) a pressure dependent physical process The filtration of blood at the glomerulus is a pressure dependent physical process known as renal ultrafiltration. The force of hydrostatic pressure in the glomerulus (the force of pressure exerted from the pressure of the blood vessel itself) is the driving force that pushes filtrate out of the capillaries and into the slits in the nephron. |
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226. |
Grave’s disease is associated with(a) insufficiency of thyroid hormones(b) excess of thyroid hormones(c) insufficiency of corticosteroids(d) excess of growth hormones |
Answer» Answer is : (b) excess of thyroid hormones Grave’s disease is an immune system disorder that results in the overproduction of thyroid hormones (hyperthyroidism). Its symptoms include anxiety, irritability, tremor, heat sensitivity, enlargement of thyroid gland, change in menstrual cycle, etc. |
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227. |
‘Imperfect fungi’ is a group represented by fungal species which have(a) simple mycelia(b) no known mechanism of sexual reproduction(c) unknown phylogenetic relationship(d) lost its survival mechanism against harsh environment |
Answer» Answer is : (b) no known mechanism of sexual reproduction The ‘imperfect fungi’ belongs to class Deuteromycetes. They are called as imperfect because sexual reproduction is absent in these forms. They reproduce only by asexual spores called conidia. |
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228. |
Which of the following is not a characteristic of phylum Chordata?(a) Pharyngeal slits(b) Amniotic egg(c) Post-anal tail(d) Notochord |
Answer» Answer is : (b) Amniotic egg Presence of amniotic egg is not a characteristic of phylum Chordata. The four features shared by all chordates are presence of a single notochord, a dorsal hollow nerve cord, pharyngeal slits and a post-anal tail. Amniotic eggs are present in reptiles, birds and mammals only. |
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229. |
The energy rich fuel molecules produced in the TCA cycle are(a) 2 GTP, 2 NADH and 1 FADH2(b) 1 GTP, 2 NADH and 2 FADH2(c) 1 GTP, 3 NADH and 1 FADH2(d) 2 GTP and 3 NADH |
Answer» Answer is : (c) 1 GTP, 3 NADH and 1 FADH2 TCA cycle or Citric acid cycle is a series of reactions that produces one GTP or ATP as well as three NADH molecules and one FADH2 molecule in each turn, which will be used in further steps of cellular respiration to produce ATP for the cell. |
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230. |
Hydrogen bonds occur between which of the following constituents of DNA?(a) Sugar and base(b) Phosphate and base(c) Complementary bases(d) Phosphate and sugar |
Answer» Answer is : (c) Complementary bases Hydrogen bonding in DNA occurs between complementary bases in order to keep the two strands of DNA helix together. These bonds occur as 2 hydrogen bonds between adenine and thymine and 3 hydrogen bonds between cytosine and guanine. |
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231. |
A mixture of NH4CI and NaCI can be separated by -(A) filtration (B) Distillation (C) Sublimation (D) Decantation |
Answer» Correct option: (C) Sublimation Explanation: NH4Cl undergoes sublimation while NaCl does not. |
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232. |
The element X which forms a stable product of the type XCI4 is (A) AI (B) Na (C) Ca (D) Si |
Answer» Correct option: (D) Si Explanation: Silicon is tetravalent, so it forms SiCl4. |
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233. |
Among Mg, Cu, Fe, Zn, the metal that does not produce hydrogen gas in reaction with hydrochloric acid is (A) Cu(B) Zn(C) Mg(D) Fe |
Answer» Correct option (A) Cu Explanation: Cu is present below H2 in electrochemical series so it can not produce H2 gas in reaction with HCl |
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234. |
The metal with the highest oxidation state present in K2CrO4, NbCl5 and MnO2 is -(A) Nb(B) Mn(C) K(D) Cr |
Answer» Correct option (D) Cr Explanation: K2CrO4 ⇒ Cr+6 (highest oxidation state) NbCl5 ⇒ Nb+5 MnO2 ⇒ Mn+4 |
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235. |
Let a, b be non-zero real numbers. Which of the following statements about the quadratic equation ax2 + (a + b)x + b = 0 is neccesarily true ?(I) It has at least one negative root (II) It has at least one positive root. (III) Both its roots are real. (A) (I) and (II) only (B) (I) and (III) only (C) (II) and (III) only (D) All of them |
Answer» Correct option(b) Explanation: ax2 + (a + b)x + b = 0 (x + 1) (ax + b) = 0 roots are -1, -b/a |
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236. |
In given nuclear reaction, \(^9_4Be\) + α → \(^{12}_6C\) + X, particle X is(a) \(^4_2He\)(b) \(^0_{-1}e\)(c) \(^1_1H\)(d) \(^1_0n\) |
Answer» Answer is : (d) \(^1_0n\) Following conservation of mass number and atomic number, we have \(^9_4Be\) + \(^4_2He\) → \(^{12}_6C\) + \(^1_0n\) So, particle \(^1_0n\) is a neutron. |
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237. |
Three cellular processes are listed below. Choose the correct combination of processes that involve proton gradient across the membrane.I. PhotosynthesisII. Aerobic respirationIII. Anaerobic respiration(a) II and III(b) I and II(c) I, II and III(d) I and III |
Answer» Answer is : (b) I and II In photosynthesis, photophosphorylation and in aerobic respiration, oxidative phosphorylation occurs that requires proton gradient. The sunlight-driven production of ATP from ADP and inorganic phosphate is called photophosphorylation. It occurs in the chloroplast. Oxidative phosphorylation is the process in which ATP is formed by the transfer of electrons from NADH or FADH2 to O2 by a series of electron carriers. It occurs inside the mitochondria. |
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238. |
Consider arrangements A and B for making a torch:Now, consider the following statements. I. Torch A is brighter. II. Torch B is brighter. III. Torch A lasts longer. IV. Torch B lasts longer. Which of the above statements are correct? (a) Statements I and III are correct (b) Statements II and IV are correct (c) Statements I and IV are correct (d) Statements II and III are correct |
Answer» Correct option is (c) Statements I and IV are correct In case A, voltage across bulb is higher, so lamb will burn brighter. In case B, voltage is same as either of battery but each battery supplies only half of current, hence the batteries will lasts twice as long. |
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239. |
Correct variation of velocity of a table-tennis ball dropped from top of a 14-story building is |
Answer» Answer is : (d) Velocity increases with time and then reaches terminal velocity. Velocity remains constant after reaching terminal speed. |
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240. |
If a low pressure centre is developed in atmosphere (very common in India in summer), the wind will flow radially towards centre. The whirlpool of wind formed will rotate in India as(a) clockwise only(b) anti-clockwise only(c) clockwise or anti-clockwise(d) whirlpools are not formed in India |
Answer» Answer is : (b) anti-clockwise only India is in northern hemisphere and due to rotation of earth, radially rushing wind will tend to rotate in anti-clockwise sense. |
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241. |
In Rutherford’s scattering experiment, choose the correct statements are given below.I. Only α-particles are scattered backwards but not protons.II. α-particles cannot be effectively scattered by electrons because α-particles are positively charged.III. Radius nucleus of target is between 9.6 x 10-15 m to 4.8 x 10-15 m.IV. α-particles with energy greater than a certain critical value are not scattered back.(a) Only statement II is correct(b) Only statement III is correct(c) Statements I, III and IV are correct(d) All statements are correct |
Answer» Answer is : (c) Statements I, III and IV are correct Electrons are not effective in scattering α-particles because they are about 7000 times lighter than α-particles. |
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242. |
A concentrated solution of lead nitrate in water can be stored in -(A) an iron vessel (B) a copper vessel(C) a zinc vessel (D) a magnesium vessel |
Answer» Correct option: (B) a copper vessel Explanation: Copper cannot displace lead from its solution as it is less reactive than lead. |
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243. |
Given the solubility curves of KNO3 and KCl, which of the following statements is not true?(A) At room temperature the solubility of KNO3 and KCI are not equal.(B) The solubilities of both KNO3 and KCI increase with temperature.(C) The solubility of KCI decreases with temperature.(D) The solubility of KNO3 increases much more as compared to that of KCl with increase in temperature. |
Answer» (C) The solubility of KCI decreases with temperature. |
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244. |
The solubility curve of KNO3 in water is shown below.The amount of KNO3 that dissolves in 50 g of water at 40°C is closest to(a) 100 g(b) 150 g(c) 200 g(d) 50 g |
Answer» Answer is : (a) 100 g From the graph it can be seen that solubility of KNO3 in water at 40°C is approximately 200 g per 100 of water. ∴ Amount of KNO3 that dissolve (or solubility) in 50 g of water will = 200/100 x 50 = 100 g |
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245. |
The role of haemoglobin is to(a) store oxygen in muscles(b) transport oxygen to different parts of the body(c) convert CO to CO2(d) convert CO2 into carbonic acid |
Answer» Answer is : (b) transport oxygen to different parts of the body The role of haemoglobin is to transport oxygen from lungs or gills to different parts of the body. There it releases the oxygen to permit aerobic respirisation to provide energy to power the functions of the organism in the process called metabolism. |
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246. |
Which of the following plots represents schematically the dependence of the time period of a pendulum if measured and plotted as a function of its oscillations? (Note : amplitude need not be small) |
Answer» Correct option (A) Explanation: Time period will increase as the amplitude is increases. |
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247. |
Consider a bowl filled with water on which some black pepper powder have been sprinkled uniformly. Now a drop of liquid soap is added at the centre of the surface of water. The picture of the surface immediately after this will look like |
Answer» Correct option (C) Explanation: due to soap bubble surface tension is reduced therefore in that area. Black paper powder will sink. |
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248. |
A block of mass m is sliding down an inclined plane with constant speed. At a certain instant t0, its height above the ground is h. The coefficient of kinetic friction between the block and the plane is µ. If the block reaches the ground at a later instant tg, then the energy dissipated by friction in the time interval (tg - t0) is(a) µmgh(b) µmgh/sinθ(c) mgh(d) µmgh/cosθ |
Answer» Answer is : (c) mgh As block is sliding with a constant speed, so change in kinetic energy of block when it reaches bottom is zero. Now, by work-energy theorem, Total work done = Change in kinetic energy ⇒ Wfriction + Wgravitation = ∆KE ⇒ Wfriction = - Wgravitation or Wfriction = - mgh = So, energy dissipated due to friction = mgh. |
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249. |
The primary and the secondary coils of a transformer contain 10 and 100 turns, respectively. The primary coil is connected to a battery that supplies a constant voltage of 1.5 V. The voltage across the secondary coil is(a) 1.5 V(b) 0.15 V(c) 0.0 V(d) 15 V |
Answer» Answer is : (c) 0.0 V As primary voltage is constant, there is no change of magnetic flux of secondary coil. So, there is no induction and hence voltage across secondary is zero. |
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250. |
Which of the following features is not present in the phylum Arthropoda? (a) Metameric segmentation (b) Parapodia (c) Jointed appendages (d) Chitinous exoskeleton |
Answer» Correct option is (b) Parapodia Parapodia are present in aquatic animals, i.e. annelids like Nereis which help them in swimming. Other three features, i.e. metameric segmentation, jointed appendages and chitinous exoskeleton are present in phylum Arthropoda. Out of these, metameric segmentation is visible as tagmetisation. |
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