234 + Interview Questions in GENETIC-BASIS-OF-INHERITANCE IN GENERAL AWARENESS Page 1 InterviewSolution

1.	ABO blood group system is due toA. Multifactor inheritanceB. Incomplete dominanceC. Multiple allelismD. Epistasis
Answer» Correct Answer - C

Discussion

2.	The genes for ABO blood group is located onA. Chromosome 4B. Chromosome 7C. Chromosome 9D. Chromosome 11
Answer» Correct Answer - C

Discussion

3.	The number of phenotypes in ABO blood groups isA. 1B. 4C. 6D. 8
Answer» Correct Answer - B

Discussion

4.	Inheritance of ABO blood groups is an example ofA. Incomplete dominanceB. DominanceC. CodominanceD. Both B and C
Answer» Correct Answer - D

Discussion

5.	Lack of independent assortment between two genes A and B in fruitly Drosophila is due toA. Crossing overB. RepulsionC. RecombinationD. Linkage.
Answer» Correct Answer - D

Discussion

6.	Independent assortment is absent in case ofA. Genes located on the same chromosomeB. Genes located on homologous chromosomesC. Genes located on nonhomologous chromosomesD. All the above
Answer» Correct Answer - A

Discussion

7.	In `F_(2)` generation quantitative inheritance of 1:4:6:4:1 is obtained instead ofA. `9:3:3:1`B. `8:6:4:1`C. `7:4:1:4`D. `6:6:4:7`
Answer» Correct Answer - A

Discussion

8.	What is true of law of independent assortment ?A. Applicable to all the dominant allelesB. Applicable to all genes on the same chromosomeC. Not applicable to gene present on the same chromosomeD. Applicable to all recessive alleles
Answer» Correct Answer - C

Discussion

9.	Which of the following variations are temporary and have nothing to do with the last or next generationA. Heredity variationB. Environmental variationsC. Discontinuous variationsD. Continuous variations
Answer» Correct Answer - B

Discussion

10.	A cross between two heterozygous individuals will yield homozygous individualsA. 2B. 4C. 6D. 8
Answer» Correct Answer - A

Discussion

11.	Variations appear during meiosis due to 1 . Independent assortment 2. Crossing over 3. Linkage 4. Glycolysis Select the correct codeA. 1,2,3 correctB. 1,2 correctC. 2,4 correctD. 1,3 correct
Answer» Correct Answer - B

Discussion

12.	At which stage of meiosis does the genetic constitution of gametes is finally decided?A. Metaphase-IB. Anaphase-IC. Anaphase-IID. Interkinesis
Answer» Correct Answer - C

Discussion

13.	Cross AABb `xx` aaBb yields AaBB:AaBb:Aabb:aabb offspring in the ratio ofA. `0:3:1:1`B. `1:2:1:0`C. `1:1:1:1`D. `1:2:1:1`
Answer» Correct Answer - B

Discussion

14.	In a dihybrid cross AABB `xx` aabb, `"F"_(2)` progeny of AABB, AABb, AaBB and AaBb occurs is the ratio of:A. `1:1:1:1`B. `9:3:3:1`C. `1:2:2:1`D. `1:2:2:4`
Answer» Correct Answer - D

Discussion

15.	In a cross between AABB `xx`aabb, the ratio of `F_(2)` genotype between AABB, AaBB,Aabb and aabb would beA. `9:3:3:1`B. `2:1:1:2`C. `1:2:2:1`D. `7:5:3:1`
Answer» Correct Answer - C

Discussion

16.	Four daughter cells obtained from a single meiosis differ from one another because ofA. Crossing overB. Independent assortmentC. Change in chromosome numberD. Both A and B
Answer» Correct Answer - D

Discussion

17.	G.J. Mendel died inA. 1984B. 1894C. 1884D. 1926
Answer» Correct Answer - C

Discussion

18.	A cross between AaBb and aabb yieldsA. AaBb and aabbB. AaBb, Aabb, aaBb and aabbC. AaBbD. Aabb
Answer» Correct Answer - B

Discussion

19.	Hybrid Pea plant with yellow round seeds (YyRr) is self pollinated. Phenotypic ratio of next generation would beA. `13:3`B. `9:7`C. `1:4:6:4:1`D. `9:3:3:1`
Answer» Correct Answer - D

Discussion

20.	Hybrid Pea plant with yellow round seeds (YyRr) is self pollinated. Phenotypic ratio of next generation would beA. `3:3:1:1`B. `1:1:1:1`C. `9:3:3:1`D. `3:1:3:1`
Answer» Correct Answer - D

Discussion

21.	Polygenes showA. Different phenotypesB. Different genotypeC. Both of the aboveD. None of the above
Answer» Correct Answer - A

Discussion

22.	A blue fowl obtained from mating between black and white fowls, is self-crossed. The `F_(2)` ratio isA. 1 black : 2 white : 1 blueB. 2 black : 1 white : 1 blueC. 1 black : 2 blue : 1 whiteD. None of the above
Answer» Correct Answer - C

Discussion

23.	A couple with curly haired husband and straight haired wife have all their children curly haired becauseA. Both are heterozygousB. Husband is homozygous and wife is heterozygousC. Husband is heterozygous while wife homozygousD. Both are homozygous.
Answer» Correct Answer - D

Discussion

24.	A women with straight hair marries a man with heterozygous curly hair isA. One in fourB. Full chanceC. No chanceD. One in two.
Answer» Correct Answer - D

Discussion

25.	Mendel published his research under the title ofA. Law of heredityB. Experiments in plant hybridisationC. Hybridisation expriments on PeaD. My experiments on particular inheritance
Answer» Correct Answer - B

Discussion

26.	The scientist who proposed particular concept of inheritance wasA. DarwinB. GaltonC. MendelD. Garrod.
Answer» Correct Answer - C

Discussion

27.	Offspring are individuals developed as a result ofA. Vegetative multiplicationB. Asexual reproductionC. Sexual reproductionD. All the above
Answer» Correct Answer - C

Discussion

28.	Siblings areA. Sons and daughter of same parentsB. Individuals formed through asexual meansC. Individual from interspecific crossD. Mutants.
Answer» Correct Answer - A

Discussion

29.	A genetic disorder in African which reduces oxygen uptake isA. HaemophiliaB. Pernicious anaemiaC. AnaemiaD. Sickle cell anaemia
Answer» Correct Answer - D

Discussion

30.	For a given character, a gamete is alwaysA. HomozygousB. PureC. HybridD. Heterozygous
Answer» Correct Answer - B

Discussion

31.	In Lathyrus odoratus, cross between two purple flowered plants give a pink/white progeny. It is dueA. CodominanceB. Incomplete dominanceC. EpistasisD. Segregation
Answer» Correct Answer - D

Discussion

32.	In Pisum sativum there are 14 Chromosomes. How many paris with different chromosomal composition can be preparedA. `2^(14)`B. `2^(7)`C. 7D. 14
Answer» Correct Answer - B

Discussion

33.	Given below are assertion and reason. Point out if both are true with reason being correct explanation (A), both are true but reason is not correct explanation (B), assertion is true but reason is wrong ( C) and both are wrong (D). Assertion. `Hb^(s)Hb^(s)` is homozygous condition of sickle cell anaemia. Reason. It occurs due to substitution of glutamic acid by valine at sixth position in `beta`-chain of haemoglobin.A. AB. BC. CD. D
Answer» Correct Answer - B

Discussion

34.	Given below are assertion and reason. Point our if both are true with reason being correct explanation (A), both are true but reason is not correct explanation (B), assertion is true but reason is wrong ( C) and both are wrong (D). Assertion. A genetist crossed two plants. He got 50% tall and 50% dwarf plants in the progeny Reason. One parent was heterozygous tall while the other was dwarfA. AB. BC. CD. D
Answer» Correct Answer - A

Discussion

35.	Nonallelic gene having similar phenotypic effect, interact to produce a different trait and a ratio of 9:7 in `F_(2)` generation areA. Epistatic geneB. Hypostatic geneC. Supplementary genesD. Complementary genes
Answer» Correct Answer - D

Discussion

36.	`F_(2)` generation has genotypic and phenotypic ratio of 1:2:1. It isA. CodominanceB. Dihybrid crossC. Monohybrid cross with complete dominanceD. Monohybrid cross with incomplete dominance.
Answer» Correct Answer - D

Discussion

37.	Phenotypic and genotypic ratio in `F_(2)` generation in incomplete dominance isA. 1:2:1 and 1:2:1B. 3:1 and 1:2:1C. 9:6 and 3:1D. 9:3:3:1 and 1:2:1:4:1:1:2:1:2:1
Answer» Correct Answer - A

Discussion

38.	In Garden Pea, round shape is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 sedds produced during the cross are subsequently germinated. How many offspring will have parental phenotypeA. 1600B. 800C. 400D. 1200
Answer» Correct Answer - D

Discussion

39.	How many types of gametes are expected from a plant with genotype Pp Qq, provided there occurs independent assortment ?A. 4B. 8C. 2D. 1
Answer» Correct Answer - A

Discussion

40.	Dominant gene for tallness is T and for yellow color is Y. A plant heterozygous for both the traits is selfed, then the ratio of pure homozygous dwarf and green offspring would beA. `1//4`B. `4//16`C. `3//16`D. `1//16`
Answer» Correct Answer - D

Discussion

41.	The Mendelian principle which has always stood true isA. The law of independent assortmentB. The law of segregationC. The law of dominanceD. All the above
Answer» Correct Answer - B

Discussion

42.	How would you test a Pea plant whether it is a pure or hybrid for tallness?A. Cross it with another tall Pea plant of unknown genotypeB. Cross it with a pure tall Pea plantC. Cross with a homozygous dwarf PeaD. Cross it with any Pea plant.
Answer» Correct Answer - C

Discussion

43.	Two plants of Summer Squash both having circular fruits are crossed. `F_(1)` plants had discoid fruits. `F_(2)` generation had 3 types of fruits, dicoid, circular and long in the ratio ofA. 9:3:4`B. `9:6:1`C. `12:3:1`D. `7:6:3`
Answer» Correct Answer - B

Discussion

44.	Which amino acid is substituted in sickle cell anamia ?A. Gutamic acid by valine in `alpha`-chainB. Glutamic acid by valine in `beta`-chainC. Valine by glutamic acid in `beta`-chainD. Valine by glutamic acid in `alpha`-chain
Answer» Correct Answer - B

Discussion

45.	Which is true ?A. Etiolation is genetic while albinism is physiologicalB. Etiolation is not reversibleC. Etiolation is physiological but albinism is geneticD. Etiolation and albinism are synonyms
Answer» Correct Answer - C

Discussion

46.	Which of the following cross will give recessive progeny in `F_(1)` generationA. `T T x ttB. `Tt xx T T`C. tt X ttD. `T T xx T T`
Answer» Correct Answer - C

Discussion

47.	A child of blood group O cannot have parents of blood groupsA. AB and AB/OB. A and BC. B and BD. O and O
Answer» Correct Answer - A

Discussion

48.	A man has blood group O and his mother blood group A. The genotype of mother should beA. `I^(O)I^(O)`B. `I^(A)I^(O)`C. `I^(A)I^(B)`D. `I^(A)I^(A)`
Answer» Correct Answer - B

Discussion

49.	A cross between AA and aa will produce an `F_(1)` progenyA. Genotypically aa, phenotypically AB. Genotypically AA, phenotypically aC. Genotypically Aa, phenotypically AD. Genotypically Aa, phenotypically a
Answer» Correct Answer - C

Discussion

50.	Dihybrid cross is related toA. Principle of dominanceB. Principle of independent assortmentC. Principle of segregationD. Principle of purity of gametes.
Answer» Correct Answer - B

Discussion

Explore topic-wise InterviewSolutions in .

ABO blood group system is due toA. Multifactor inheritanceB. Incomplete dominanceC. Multiple allelismD. Epistasis

The genes for ABO blood group is located onA. Chromosome 4B. Chromosome 7C. Chromosome 9D. Chromosome 11

The number of phenotypes in ABO blood groups isA. 1B. 4C. 6D. 8

Inheritance of ABO blood groups is an example ofA. Incomplete dominanceB. DominanceC. CodominanceD. Both B and C

Lack of independent assortment between two genes A and B in fruitly Drosophila is due toA. Crossing overB. RepulsionC. RecombinationD. Linkage.

Independent assortment is absent in case ofA. Genes located on the same chromosomeB. Genes located on homologous chromosomesC. Genes located on nonhomologous chromosomesD. All the above

In `F_(2)` generation quantitative inheritance of 1:4:6:4:1 is obtained instead ofA. `9:3:3:1`B. `8:6:4:1`C. `7:4:1:4`D. `6:6:4:7`

What is true of law of independent assortment ?A. Applicable to all the dominant allelesB. Applicable to all genes on the same chromosomeC. Not applicable to gene present on the same chromosomeD. Applicable to all recessive alleles

Which of the following variations are temporary and have nothing to do with the last or next generationA. Heredity variationB. Environmental variationsC. Discontinuous variationsD. Continuous variations

A cross between two heterozygous individuals will yield homozygous individualsA. 2B. 4C. 6D. 8

Variations appear during meiosis due to 1 . Independent assortment 2. Crossing over 3. Linkage 4. Glycolysis Select the correct codeA. 1,2,3 correctB. 1,2 correctC. 2,4 correctD. 1,3 correct

At which stage of meiosis does the genetic constitution of gametes is finally decided?A. Metaphase-IB. Anaphase-IC. Anaphase-IID. Interkinesis

Cross AABb `xx` aaBb yields AaBB:AaBb:Aabb:aabb offspring in the ratio ofA. `0:3:1:1`B. `1:2:1:0`C. `1:1:1:1`D. `1:2:1:1`

In a dihybrid cross AABB `xx` aabb, `"F"_(2)` progeny of AABB, AABb, AaBB and AaBb occurs is the ratio of:A. `1:1:1:1`B. `9:3:3:1`C. `1:2:2:1`D. `1:2:2:4`

In a cross between AABB `xx`aabb, the ratio of `F_(2)` genotype between AABB, AaBB,Aabb and aabb would beA. `9:3:3:1`B. `2:1:1:2`C. `1:2:2:1`D. `7:5:3:1`

Four daughter cells obtained from a single meiosis differ from one another because ofA. Crossing overB. Independent assortmentC. Change in chromosome numberD. Both A and B

G.J. Mendel died inA. 1984B. 1894C. 1884D. 1926

A cross between AaBb and aabb yieldsA. AaBb and aabbB. AaBb, Aabb, aaBb and aabbC. AaBbD. Aabb

Hybrid Pea plant with yellow round seeds (YyRr) is self pollinated. Phenotypic ratio of next generation would beA. `13:3`B. `9:7`C. `1:4:6:4:1`D. `9:3:3:1`

Hybrid Pea plant with yellow round seeds (YyRr) is self pollinated. Phenotypic ratio of next generation would beA. `3:3:1:1`B. `1:1:1:1`C. `9:3:3:1`D. `3:1:3:1`

Polygenes showA. Different phenotypesB. Different genotypeC. Both of the aboveD. None of the above

A blue fowl obtained from mating between black and white fowls, is self-crossed. The `F_(2)` ratio isA. 1 black : 2 white : 1 blueB. 2 black : 1 white : 1 blueC. 1 black : 2 blue : 1 whiteD. None of the above

A couple with curly haired husband and straight haired wife have all their children curly haired becauseA. Both are heterozygousB. Husband is homozygous and wife is heterozygousC. Husband is heterozygous while wife homozygousD. Both are homozygous.

A women with straight hair marries a man with heterozygous curly hair isA. One in fourB. Full chanceC. No chanceD. One in two.

Mendel published his research under the title ofA. Law of heredityB. Experiments in plant hybridisationC. Hybridisation expriments on PeaD. My experiments on particular inheritance

The scientist who proposed particular concept of inheritance wasA. DarwinB. GaltonC. MendelD. Garrod.

Offspring are individuals developed as a result ofA. Vegetative multiplicationB. Asexual reproductionC. Sexual reproductionD. All the above

Siblings areA. Sons and daughter of same parentsB. Individuals formed through asexual meansC. Individual from interspecific crossD. Mutants.

A genetic disorder in African which reduces oxygen uptake isA. HaemophiliaB. Pernicious anaemiaC. AnaemiaD. Sickle cell anaemia

For a given character, a gamete is alwaysA. HomozygousB. PureC. HybridD. Heterozygous

In Lathyrus odoratus, cross between two purple flowered plants give a pink/white progeny. It is dueA. CodominanceB. Incomplete dominanceC. EpistasisD. Segregation

In Pisum sativum there are 14 Chromosomes. How many paris with different chromosomal composition can be preparedA. `2^(14)`B. `2^(7)`C. 7D. 14

Nonallelic gene having similar phenotypic effect, interact to produce a different trait and a ratio of 9:7 in `F_(2)` generation areA. Epistatic geneB. Hypostatic geneC. Supplementary genesD. Complementary genes

`F_(2)` generation has genotypic and phenotypic ratio of 1:2:1. It isA. CodominanceB. Dihybrid crossC. Monohybrid cross with complete dominanceD. Monohybrid cross with incomplete dominance.

Phenotypic and genotypic ratio in `F_(2)` generation in incomplete dominance isA. 1:2:1 and 1:2:1B. 3:1 and 1:2:1C. 9:6 and 3:1D. 9:3:3:1 and 1:2:1:4:1:1:2:1:2:1

In Garden Pea, round shape is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 sedds produced during the cross are subsequently germinated. How many offspring will have parental phenotypeA. 1600B. 800C. 400D. 1200

How many types of gametes are expected from a plant with genotype Pp Qq, provided there occurs independent assortment ?A. 4B. 8C. 2D. 1

Dominant gene for tallness is T and for yellow color is Y. A plant heterozygous for both the traits is selfed, then the ratio of pure homozygous dwarf and green offspring would beA. `1//4`B. `4//16`C. `3//16`D. `1//16`

The Mendelian principle which has always stood true isA. The law of independent assortmentB. The law of segregationC. The law of dominanceD. All the above

How would you test a Pea plant whether it is a pure or hybrid for tallness?A. Cross it with another tall Pea plant of unknown genotypeB. Cross it with a pure tall Pea plantC. Cross with a homozygous dwarf PeaD. Cross it with any Pea plant.

Two plants of Summer Squash both having circular fruits are crossed. `F_(1)` plants had discoid fruits. `F_(2)` generation had 3 types of fruits, dicoid, circular and long in the ratio ofA. 9:3:4`B. `9:6:1`C. `12:3:1`D. `7:6:3`

Which amino acid is substituted in sickle cell anamia ?A. Gutamic acid by valine in `alpha`-chainB. Glutamic acid by valine in `beta`-chainC. Valine by glutamic acid in `beta`-chainD. Valine by glutamic acid in `alpha`-chain

Which is true ?A. Etiolation is genetic while albinism is physiologicalB. Etiolation is not reversibleC. Etiolation is physiological but albinism is geneticD. Etiolation and albinism are synonyms

Which of the following cross will give recessive progeny in `F_(1)` generationA. `T T x ttB. `Tt xx T T`C. tt X ttD. `T T xx T T`

A child of blood group O cannot have parents of blood groupsA. AB and AB/OB. A and BC. B and BD. O and O

A man has blood group O and his mother blood group A. The genotype of mother should beA. `I^(O)I^(O)`B. `I^(A)I^(O)`C. `I^(A)I^(B)`D. `I^(A)I^(A)`

A cross between AA and aa will produce an `F_(1)` progenyA. Genotypically aa, phenotypically AB. Genotypically AA, phenotypically aC. Genotypically Aa, phenotypically AD. Genotypically Aa, phenotypically a

Dihybrid cross is related toA. Principle of dominanceB. Principle of independent assortmentC. Principle of segregationD. Principle of purity of gametes.