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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
Mendel chose contrasting traits in PeaA. ThreeB. TwoC. OneD. Seven |
| Answer» Correct Answer - D | |
| 202. |
Which blood group can safely be transfused in emergency when there is no time to analyse the blood group of recipient ?A. O and `Rh^(-)`B. O and `Rh^(+)`C. B and `Rh^(-)`D. AB and `Rh^(+)` |
| Answer» Correct Answer - A | |
| 203. |
In a hybrid cross, the maximum number of phenotypes would beA. 8B. 4C. 2D. 16 |
| Answer» Correct Answer - B | |
| 204. |
A person with blood group A possessesA. Antigen A and antibody BB. Antigen B and antibody aC. Antigen A and antibody bD. No antigen and no antibody. |
| Answer» Correct Answer - C | |
| 205. |
If a genotype consists of different types of alleles, it is calledA. HomozygousB. HeterozygousC. MonoallelicD. Uniallelic |
| Answer» Correct Answer - B | |
| 206. |
Blood group A person canA. Be parent of a child with B blood groupB. Possess only B-antigenC. Safely receive blood from a donor of B-groupD. Possess both antigens A and B |
| Answer» Correct Answer - A | |
| 207. |
With respect to phenyl ketouria indentify which statement is not correctA. It is an error in metabolismB. Caused due to autosomal recessive traitC. It is an example of pleiotropyD. It is a case of aneuploidy |
| Answer» Correct Answer - D | |
| 208. |
A donor having blood AB can safely donate red blood cells to recipient having blood group typeA. A and ABB. B and ABC. AB onlyD. O only |
| Answer» Correct Answer - C | |
| 209. |
B blood group person can donate blood to and receive blood fromA. B, O nad B,OB. B, AB and B,ABC. B, AB and B,OD. A,B and A,B |
| Answer» Correct Answer - C | |
| 210. |
Universal donor blood group isA. ABB. OC. AD. B |
| Answer» Correct Answer - B | |
| 211. |
Test cross involvesA. Crossing between two genotypes with dominant traitB. Crossing between two genotypes with recessive traitC. Crossing the `F_(1)` hybrid with double recessive genotypeD. Crossing between two `F_(1)` hybrids. |
| Answer» Correct Answer - C | |
| 212. |
In Drosophila gene for white eye colour is also responsible for depigmentation of body parts. It is an example ofA. OncogeneB. Epistatice geneC. Hypostatic geneD. Pleiotropic gene |
| Answer» Correct Answer - D | |
| 213. |
A human male produces diallelic sperms in equal proportion AB, Ab, aB and ab. The genotype of the person would beA. Aa BbB. Aa BBC. AABbD. AA BB |
| Answer» Correct Answer - A | |
| 214. |
Phenotype of an organism is result ofA. Mutations and linkageB. Cytoplasmic effects and nutritionC. Environmental changes and sexual dimorphismD. Genotype and environment interactions |
| Answer» Correct Answer - B | |
| 215. |
Phenotype of an organism is result ofA. Mutations and linkageB. Genotype and environment interactionsC. Cytoplasmic effects and nutritionD. Environmental changes and sexual dimorphism. |
| Answer» Correct Answer - B | |
| 216. |
Change in the number of body parts is calledA. Meristic variationB. Substantive variationC. Continuous variationD. Discontinuous variation |
| Answer» Correct Answer - A | |
| 217. |
In pea, yellow seed colour is dominant over green colour. Heterozygous Yellow seeded plant is crossed with green seeded plant. The ratio of yellow to green seeded offspring will beA. `9:1`B. `1:3`C. `3:1`D. `50: 50` |
| Answer» Correct Answer - D | |
| 218. |
Multiple phenotype is seen inA. Dominance relationshipB. Particulate inheritanceC. Monogenic inheritanceD. Polygenic inheritance |
| Answer» Correct Answer - D | |
| 219. |
Red seed colour shows an `F_(2)` ratio of 1:4:6:4:1. It is due toA. Two polygeneB. Different number of dominant genesC. Different number of recessive genesD. Supplementary genes. |
| Answer» Correct Answer - A | |
| 220. |
A dihybrid ratio of 1:4:6:4:1 is obtained instead of 9:3:3:1. This is an example ofA. Complementary genesB. Supplementary genesC. Polygenic inheritanceD. Pleiotropic genes. |
| Answer» Correct Answer - C | |
| 221. |
Epistatic gene differs from dominant gene inA. Epistatic gene is nonallelicB. Epistatic gene never expressed itself independentlyC. Epistatic and hypostatic genes are present at different lociD. All the above |
| Answer» Correct Answer - D | |
| 222. |
Gene with multiple effects isA. CodominantB. PleiotropicC. EpistaticD. Supplementary |
| Answer» Correct Answer - B | |
| 223. |
In a dihybrid cross, `F_(2)` phenotypic ratio is 13:3. It is case ofA. Complementary genesB. Epistatic genesC. Multigentic inheritanceD. Incomplete dominance |
| Answer» Correct Answer - B | |
| 224. |
Mendel is popular for postulatingA. Origin of speciesB. Cell theoryC. Linkage theoryD. Laws of inheritance. |
| Answer» Correct Answer - D | |
| 225. |
Two allelic genes are located onA. Two homologous chromosomesB. Two nonhomologous chromosomesC. Any two chromosomesD. The same chromosome |
| Answer» Correct Answer - A | |
| 226. |
Genes showing multiple effects areA. Complementary geneB. PseudogenesC. Pleiotropic genesD. Cistrons |
| Answer» Correct Answer - C | |
| 227. |
In complementary genes, the dihybrid ratio of 9:3:3:1 is modified toA. `9:1`B. `12:3:1`C. `15:1`D. `13:3` |
| Answer» Correct Answer - A | |
| 228. |
Genes do not occur in pairs inA. ZygoteB. Somatic cellC. Endosperm cellsD. Gametes |
| Answer» Correct Answer - D | |
| 229. |
Percentage of heterozygous individuals obtained from selfing Rr individuals is:A. 100B. 75C. 50D. 25 |
| Answer» Correct Answer - C | |
| 230. |
A modified dihybrid mendelian ratio of 9:3:4 indicatesA. Supplementary genesB. Complementary genesC. Lethal genesD. Epistatic genes |
| Answer» Correct Answer - A | |
| 231. |
Segeration of genes take place duringA. MetaphaseB. AnaphaseC. ProphaseD. Embryo formation |
| Answer» Correct Answer - B | |
| 232. |
The law of segeration of characters is also called the law of purity of gametes becauseA. Gametes have only one of the two alleles for each characterB. Gametes cannot be contaminatedC. Gametes are very different type of cellsD. It was just another name adopted accidently |
| Answer» Correct Answer - A | |
| 233. |
A dwarf pea plant was treated with GA. The plant became tall. The treated plant was then crossed with a homozygous tall pea. The resutl in `F_(2)` are expected to beA. All tallB. Tall and dwarf in 3:1 ratioC. 50% tallD. All dwarf |
| Answer» Correct Answer - B | |
| 234. |
Which of the following genotype does not produce any sugar polymer on the surface of RBCsA. `I^(A)I^(A)`B. `I^(B)i`C. `I^(A)I^(B)`D. `ii` |
| Answer» Correct Answer - D | |