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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
A pea with white flowers was crossed to another pea which is also white flower plant. When selfed the `F_(2)` generation produced purple and white in the ration 9:7. The reason for the results is thatA. It is typical monohybrid Mendalian ratioB. Purple flower colour is dominant over the whiteC. It is a complementary factorD. None of the above |
| Answer» Correct Answer - C | |
| 152. |
Ratio 1:1:1:1 is obtained from a cross ofA. RRYY `xx` rryyB. RRYy `xx` rrYyC. RrYY `xx` RryyD. `RrYy `xx`rryy |
| Answer» Correct Answer - D | |
| 153. |
Tallness (T-) is dominant over dwarfness (tt) while red flower colour (R-) is dominant over white colour (rr). A plant with genotype TtRr is crossed with plant of genotype ttrr. Percentage of progeny having tall plants with red flower isA. 0.25B. 0.5C. 0.75D. 1 |
| Answer» Correct Answer - A | |
| 154. |
A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the `F_(1)` plant were selfed the resulting genotypeswere in the ratio ofA. 3:1-dwarf: tallB. 1:2:1- tall homozygous : tall heterozygous : dwarfC. 1:2:1- heterozygous : tall homozygous : dwarfD. 3:1-tall : dwarf |
| Answer» Correct Answer - B | |
| 155. |
Match the columns and choose the correct combination A. a-r,b-t,c-s,d-qB. a-t,b-r,c-q,d-sC. a-r,b-t,c-p,d-qD. a-r,b-p,c-t,d-q |
| Answer» Correct Answer - C | |
| 156. |
`(1)/(4)TT, (1)/(2)Tt,(1)/(4)tt` is binomial expansion ofA. `((1)/(2)T+(1)/(2)t)^(2)`B. `((1)/(4)T+(1)/(4)t)^(2)`C. `((1)/(4)T+(1)/(2)t)^(2)`D. `((1)/(2)T+(1)/(4)t)^(2)` |
| Answer» Correct Answer - A | |
| 157. |
A cross between two tall Garden Pea Plants produced all tall plants. The possible genotype of the parents are (I)TT,TT(II)TT,Tt(III)Tt,tt(IV) Tt,Tt Correct answer isA. III,IVB. I,IVC. I,IID. II,III |
| Answer» Correct Answer - C | |
| 158. |
TT Pea plant is crossed to tt plant. `F_(2)` generation will haveA. All tall plantsB. Tall and dwarf in the ratio of 3:1C. Tall and dwarf in the ratio of 1:2D. Tall and dwarf in the ratio of 1:1 |
| Answer» Correct Answer - B | |
| 159. |
Pleiotropic effect is found inA. Human skin colourB. Night blindnessC. HaemophiliaD. Sickle cell anaemia |
| Answer» Correct Answer - D | |
| 160. |
Tt `xx` tt isA. Test crossB. Back crossC. HybridisationD. Reciprocal cross |
| Answer» Correct Answer - A | |
| 161. |
Which of the following cross determines heterozygosity or homozogosity ?A. Monohybrid crossB. Dihybrid crossC. Test crossD. Back cross |
| Answer» Correct Answer - C | |
| 162. |
Total number of progeny of a dihybrid cross is 1280 in `F_(2)` generation. How many are recombinants ?A. 240B. 360C. 480D. 720 |
|
Answer» Correct Answer - C Recombinants 6 out of 16 (9:3:3:1), `6//16xx1280` |
|
| 163. |
A gene showing codominance hasA. One alleles dominant over otherB. Alleles tightly linked on the same chromosomeC. Alleles that are recessiv to each otherD. Both the alleles independently expressed in heterozygote. |
| Answer» Correct Answer - D | |
| 164. |
Blue eye colour is recessive to brown eye colour. A brown eyed man whose mother was blue eyed marries a blue eyed women. The children shall beA. Both blue eyed and brown eyed 1:1B. All brown eyedC. All blue eyedD. Blue eyed and brown eyed 3:1 |
| Answer» Correct Answer - A | |
| 165. |
Source of mendelian recombination isA. LinkageB. Independent assortmentC. MutationsD. Dominat traits |
| Answer» Correct Answer - B | |
| 166. |
The contrasting pairs of factors in Mendelian crosses are calledA. Multiple allelesB. Allelomorphs/AllelesC. AllolociD. Paramorphs |
| Answer» Correct Answer - B | |
| 167. |
First geneticist/father of genetics wasA. De VriesB. MendelC. DarwinD. Morgan |
| Answer» Correct Answer - B | |
| 168. |
Word genetics comes fromA. GeneB. GenesisC. GenomeD. Genomics |
| Answer» Correct Answer - B | |
| 169. |
Which law of Mendelian genetics can be considered universalA. DominanceB. CodominanceC. Independent assortmentD. Segregation |
| Answer» Correct Answer - D | |
| 170. |
Match the genetics phenomena with their respective ratios A. a-5,b-4,c-3,d-2,e-1B. a-4,b-5, c-1,d-2,e-3C. a-1,b-2,c-4,d-3,e-5D. a-2,b-2,c-4,d-5,e-3 |
| Answer» Correct Answer - B | |
| 171. |
Most favourite and ideal material for researches in genetics isA. HouseflyB. MosquitoC. FrogD. Fruitfly. |
| Answer» Correct Answer - D | |
| 172. |
Genetics deal withA. Heredity and variationsB. HeredityC. MutationsD. Nuclear and cytoplasmic inheritance. |
| Answer» Correct Answer - A | |
| 173. |
A pure breeding plant with red dot on leaves was crossed with pure breeding white dotted plants. The heterozygotes have both red and white dots. On self pollination of `F_(1)`, what fraction of plants show both red and white dots on leavesA. `(2)/(4)`B. `1/4`C. `2/3`D. `3/4` |
| Answer» Correct Answer - A | |
| 174. |
Three alleles namely `I^(A),I^(B)` and `i` control the blood grouping in human beings. How many genotypes are likely to be present in human populationA. 2B. 4C. 5D. 6 |
| Answer» Correct Answer - D | |
| 175. |
Blood grouping in human beings is controlled byA. 4 alleles in which A is dominantB. 3 alleles in which A and B are codominant and `i` is recessvieC. 3 alleles in which one is dominantD. 3 alleles in which A is dominat |
| Answer» Correct Answer - B | |
| 176. |
In multiple allele system a gamete possessesA. Two allelesB. Three allelesC. One alleleD. Several alleles |
| Answer» Correct Answer - C | |
| 177. |
ABO blood grouping is determined by three alleles. Possble genotypes and phenotypes areA. 3,1B. 6,4C. 4,6D. 9,7 |
| Answer» Correct Answer - B | |
| 178. |
How many types of gametes are expected from the organism with genotype AABBCC :-A. oneB. TwoC. FourD. Eight |
| Answer» Correct Answer - A | |
| 179. |
The offspring of AA bb `xx` aa BB is crossed with , aabb. The genotypic ratio of progeny will beA. `9:3:3:1`B. `1:2:1`C. `1:1:1:1`D. `4:1` |
| Answer» Correct Answer - C | |
| 180. |
What are the expected phenotypes in `F_(2)` generation of cross RRYY `xx` rryyA. Only wrinkled seeds with green cotylendonsB. Only wrinkled seeds with yellow cotyldonsC. Only round seeds with green cotyledonsD. Four, round seeds with yellow cotyledons, round seeds with green cotyledons, wrinkled seeds with yellow cotyledons and wrinkled seeds with green cotyledons |
| Answer» Correct Answer - B | |
| 181. |
The number of genotypes produced by gametes Y and y would beA. 1B. 12C. 3D. 4 |
| Answer» Correct Answer - C | |
| 182. |
Same gene loci on two homologous chromosomes produce different phenotypes. They bearA. Homozygous allelesB. Heterozygous allelesC. Two different genesD. Pleiotropic genes. |
| Answer» Correct Answer - D | |
| 183. |
In a dihybrid cross, the proportion of individuals showing recessive phenotypes would beA. `1//16`B. `7//16`C. `1//4`D. `3//4` |
| Answer» Correct Answer - D | |
| 184. |
Ratio between completely homozygous dominant and homozygous recessive individuals of a dihybrid cross isA. `1:1`B. `2:2`C. `6:10`D. `10:6` |
| Answer» Correct Answer - A | |
| 185. |
Double homozygous individuals in `F_(2)` generation of a dihybrid cross would beA. `1//16`B. `2//16`C. `6//16`D. `9//16` |
| Answer» Correct Answer - B | |
| 186. |
How many types of gametes are required for `F_(2)` generation of a monohybrid cross ?A. 2B. 4C. 16D. 8 |
| Answer» Correct Answer - B | |
| 187. |
Percentage of pure breeding `F_(2)` individual of a monohybrid cross would beA. 0.75B. 0.5C. 0.25D. 0.125 |
| Answer» Correct Answer - B | |
| 188. |
In a monohybrid cross the ratio of `F_(2)` true breeding dominant and true breeding recessive would beA. `50:50`B. `25:25`C. `75:25`D. `25:75` |
| Answer» Correct Answer - B | |
| 189. |
An individual having similar unit factors of a character isA. HeterozygoteB. HomozygoteC. DominantD. Recessive. |
| Answer» Correct Answer - B | |
| 190. |
A yellow seeded true breeding Pea plant is crossed with green seeded true breeding plant. `F_(1)` plants were yellow seeded showing that allele for yellow colour isA. HeterozygousB. DominantC. LethalD. Epistatic |
| Answer» Correct Answer - B | |
| 191. |
Punnet square is used to knowA. Outcome of a crossB. Probable result of a crossC. Types of gametes.D. Result of meiosis. |
| Answer» Correct Answer - B | |
| 192. |
Allele isA. Segment of geneB. Form of a geneC. Special kind of geneD. A muton. |
| Answer» Correct Answer - B | |
| 193. |
Repeated selfing producesA. HeterozygosityB. HomozygosityC. Homozygosity in some and heterozygosity in other traits.D. Pure hybrids. |
| Answer» Correct Answer - B | |
| 194. |
Complete dominance does not occur inA. Mirabilis jalapaB. Oenothera lamarckianaC. Pisum sativumD. Lathyrus odoratus. |
| Answer» Correct Answer - A | |
| 195. |
Emasculation is related toA. Pure lineB. Mass selectionC. Clonal selectionD. Hybridisation |
| Answer» Correct Answer - D | |
| 196. |
Emasculation ensures cross pollination inA. Staminate flowerB. Bisexual flowerC. Neuter flowerD. Pistillate flower |
| Answer» Correct Answer - B | |
| 197. |
All are dominant traits studied by MendelA. Axial flower, green pod, green seedB. Green pod, inflated pod, axial flowerC. Yellow seed, violet flower, yellow podD. Round seed, constricted pod, axial flower. |
| Answer» Correct Answer - B | |
| 198. |
A recessive trait in Garden Pea isA. Wrinkled seedsB. Tall stemC. Round seedsD. Coloured seed coat |
| Answer» Correct Answer - A | |
| 199. |
Human skin colour is polygenic trait with each dominant determing a part of melanin deposition while the recessive are coding for no melanin. If a very dark skinned person marries a very light skinned women, the chances of a very dark skinned offspring areA. OB. `1//4`C. `5//8`D. `9//64` |
| Answer» Correct Answer - A | |
| 200. |
Two genetic loci produce identical phenotypes in cis as well as trans position. They areA. PseudoallelesB. Multiple allelesC. Different genesD. Part of same gene |
| Answer» Correct Answer - A | |