InterviewSolution

Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.	For complete HFR to enter the recipient, how much time should the two bacterial cells be in contact?(a) 10 mins(b) 30 mins(c) 60 mins(d) 100 minsThe question was asked in an international level competition.This intriguing question originated from Gene Mapping in Bacteria by Conjugation topic in portion Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» Correct option is (d) 100 mins To EXPLAIN: The TWO participating bacteria taking PART in conjugation should actually stay connected by conjugation tube for 100 MINUTES for the entire chromosome i.e. HFR to get transferred. However, as they are constantly in motion such occurrence is rare.

52.	In an experiment you want to express your gene of interest in a prokaryote through a plasmid. What would be your ideal copy number?(a) 2 or 3(b) 10(c) 80(d) 100The question was asked in quiz.The above asked question is from Plasmids topic in chapter Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» The correct answer is (a) 2 or 3 To elaborate: The GENE of interest by us should always be expressed in low copy number as if it is in higher copy number t will use more of bacterial recourses without helping them at all. So, BACTERIA MIGHT then DISPENSE some of these chromosomes.

53.	The recombination study of phages is done using ____________(a) OD measurement(b) Plaque assay(c) Plating assay(d) Boyden chamber assayThis question was posed to me in class test.Asked question is from Gene Mapping in Bacteria by Transduction topic in section Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» The correct answer is (B) Plaque assay To explain I would say: In Plaque assay BACTERIAL culture is grown in a plate and then it is INFECTED by the viruses. The plaque so FORMED by the viruses is studies to categorize the morphological features and study the recombination.

54.	What is the capacity of viral gene storage termed as?(a) Viral capacity(b) Tight head capacity(c) Head full capacity(d) Virulent capacityThis question was addressed to me during an online exam.Query is from Gene Mapping in Bacteria by Transduction in section Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» Correct option is (c) HEAD full capacity To elaborate: The viral head has a specific capacity to load NUCLEIC acid. This capacity can be satisfied by only viral GENOME, a COMBINATION of viral and bacterial genome or only bacterial genome. This is called head full capacity.

55.	What is the minimum length of DNA fragment in exogenote required for incorporation of the gene in the endogenote?(a) 50bp(b) 250bp(c) 400bp(d) 500bpI had been asked this question in class test.Asked question is from Gene Mapping in Bacteria by Transformation in portion Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» CORRECT choice is (d) 500BP The explanation is: Although very small fragments of DNA are TAKEN up by the cell, a minimum of 500bp is NECESSARY for recombinational machinery to ACT on, thus for incorporation.

56.	Which of the following can transfer the genes in bacterial nucleoid as well?(a) F- plasmid(b) R factor(c) F’ plasmid(d) HFRI have been asked this question in an online quiz.My query is from Gene Mapping in Bacteria by Conjugation in division Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» The CORRECT OPTION is (d) HFR For explanation I would say: While F’ can transfer ONE or TWO of the bacterial gene as well, but only HFR can transfer the gene from the nucleoid of the bacteria as it is the F plasmid incorporated in the central chromosome.

57.	Methylated DNA doesn’t form kink as________________(a) As they don’t fit in the active site(b) The enzyme recognized methylated A as different base than non-methylated A(c) They are less flexible so no kink is formed(d) They don’t interact with the side chains in an active siteThis question was posed to me in my homework.This intriguing question comes from Restriction Endonuclease topic in division Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» The correct option is (d) They don’t INTERACT with the side chains in an ACTIVE site To explain: The KINK in the DNA is FORMED not by just the recognition of the BASE sequence in the restriction site, but also by the interactions of the side chains. Asp 185 is unable to interact with methylated A, so no kink is formed.

58.	Which of the following is not true for type 1 restriction endonuclease?(a) It is a single enzyme with 3 subunits(b) Using it is an energy requiring process(c) Methylation and cleavage occurs in the same sequence(d) The cleavage is up to 1000bp awayThe question was asked in an online interview.The query is from Restriction Endonuclease topic in section Genomics : The Mapping and Sequencing of Genomes of Cytogenetics
Answer» The correct choice is (C) Methylation and cleavage occurs in the same sequence For explanation: Type 1 restriction endonuclease RECOGNIZES and cleaves at DIFFERENT points. While it methylates at the recognition sequence, the cleavage could be as far as 1000bp. ALSO both these processes require ATP.