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101.

Linear Expansion Take a bulb, dry cell, candle, cycle spoke, coin (or broad – headed nail) and two wooden blocks.Place one end of the cycle spoke on a wooden block and connect an electric wire to it. Put a stone over the spoke) to hold it firmly in place on the wooden block, as shown in Figure . The spoke should be parallel to the ground. Place the second wooden block under the free end of the spoke. Wrap some electric wire around the coin (or nail) and place it on the block. You may put a stone over the coin to hold it in place.Connect a bulb and dry cell to the free ends of the wires connected to the coin and the spoke and make the circuit shown in the figure.When the tip of the free end of the spoke touches the coin, the circuit is completed and the bulb lights up. Check to ensure this. If the bulb does not light up, it means the circuit is not complete, so check your connections properly. (Note: We will learn about electric circuit elaborately in electricity lesson.) Now slide a page of your book between the coin and spoke and then slide it out. That way you would get a gap between the coin and spoke equal to the thickness of the sheet of paper,1. Does the bulb light up? If it does not, what could be the reason? ___________________ You saw that the bulb does not light up when the spoke does not touch the coin. Now light the candle and heat the spoke with it. 2. Did the bulb light up after the spoke was heated for some time? 3. If it did, then explain how the spoke touched the coin after it was heated. 4. Why does the bulb go off some time after the candle is taken away from the spoke? 5. What happens to the length of the spoke when it is heated or cooled?

Answer»

1. The bulbs is not light up, because, the coin and the spoke do not touch it. The circuit is not completed. 

2. Yes, the bulb is light up, because the spoke is heated the circuit is completed. 

3. When the spoke is heated, it will be expanded. Here, linear expansion takes place. So it touched the coin. 

4. After removing the candle, the spoke does not get the heat. The spoke is returned to its original state. So it does not touch the coin once again and the bulb goes off. 

5. The length of the spoke is expanded when the spoke is heated.

102.

A sheet of brass is 40 cm long and 8 cm broad at `0^(@)C`. If the area at `100^(@)C` is `320.1m^(2)`, calculate the coefficient of linear expansion of brass.

Answer» Correct Answer - `1.55 xx 10^(-6).^(@)C^(-1)`
103.

How much should the temperature of a brass rod be increased so as to increase its length by `1%`? Given `alpha` for brass is `0.00002 .^(@)C^(-1)`.

Answer» Correct Answer - `500^(@)C`
104.

The length of a brass rod is 1.5 m. Its coefficient of linear expansion is `19xx10^(-6)K^(-1)` Find the increase in length of the rod if it is heated through `20^(@)C`.

Answer» Given length of the rod, l=1.5 m.
Coefficeint of linear expansion, `alpha=19xx10^(-6)K^(-1)`.
Increase in temperature, `Deltatheta=20^(@)C`
`therefore" Increase in length, "Delta l = l xx alpha xx Delta theta`
`=(1.5)xx(19xx10^(-6))xx(20)=5.7xx10^(-4)` m.
105.

Why does the temperature of the surroundings start falling when the ice of frozen lake starts melting?

Answer» Does ice absorb or liberate heat while melting? How does this affect the heat content in the surroundings of the ice ?
106.

A metal wire of length l and area of cross-section A is fixed between rigid supports at negligible tension. If this is cooled, the tension in the wire will be (a) proportional to l (b) inversely proportional to l (c) independent of l (d) independent of A

Answer»

Correct Answer is: (c) independent of l

Let α = coefficient of thermal expansion, Y = Young modulus of the wire. If the wire were free to contract, its decrease in length would be lαt, where t = decrease in temperature. To maintain constant length, lαt becomes the effective elongation. 

∴ strain = lαt/l = αt.

Let T = tension ∴ stress = T/A

Using Y = stress/strain,T = YAαt.

107.

Two metal rods of the same length and area of cross-section are fixed end to end between rigid supports. The materials of the rods have Young mod ulii Y1 and Y2, and coefficients of linear expansion α1 and α2. The junction between the rods does not shift if the rods are cooled. (a) Y1α1 = Y2α2 (b) Y1α2 = Y2α1 (c) Y1α12 = Y2α22 (d) Y12α1 = Y22α2

Answer»

Correct Answer sis: (a) Y1α1 = Y2α2 

Tension must be the same in both the rods for their junction to be in equilibrium. 

Y11t = Y22t. 

108.

Calculate the amount of heat radiated per second by a body of surface area `12 cm^2` kept in thermal equilibrium in a room at temperature `20°C`. The emissivity of the surface `=` `0.80` and `sigma = 6.0 × 10^-8 W m^-2 K^-4`

Answer» The constant temperature at which solid changes to liquid state is called melting point of that solid.
109.

If you drink 200 ml of water at 20° C, what is the heat gained by water from your body? (Body temperature is 37° C)

Answer»

m = 200 g (1 ml of water = 1 gm of water) 

S = 1 cal/gm °C ; 

t1 = 20° C; t2 = 37° C 

Q = mS∆T (∆T = t2 – t1

= 200 × 1 × (37 – 20) 

= 200 × 17 

Q = 3400 calories

110.

An iron ball at `40^(@)C` is dropped in a mug containing oil at `40^(@)C` ThenA. heat flows from iron ball to oilB. heat flows from between oil to iorn ballC. heat does not flow between lil and ironD. temperature of oil increases and temperatue of iron ball decreases

Answer» Correct Answer - c
There is no net heat flow because temperture is same
111.

Net heat lost by the hot bodies = Net heat gained by the cold bodies (if heat is noi lost by any other process). This is known as A) Principle of Pascal B) Principle of Archimedes C) Principle of method of mixtures D) None

Answer»

C) Principle of method of mixtures

112.

Heat flow from one body to another body stops when both bodies attain equal_____.A. temperatureB. heat energyC. massD. volume

Answer» Correct Answer - a
Heat flow form one body to another body stops when both the bodies reach equal temprature
113.

A refrigeratior converts `50` gram of water at `15^(@)C` intoice at `0^(@)C` in one hour. Calculate the quantity of heat removed per minute. Take specific heat of water `=1` cal `g^(-1) .^(@)C^(-1)` and latent heat of ice `=80` cal `g^(-1)`

Answer» Correct Answer - 79.2 cal `min.^(-1)`
114.

Fill in the blanks _________is the SI unit of heat

Answer» Correct Answer - joule
115.

Match the column:Column ‘A’Column ‘B’1. Radiationa. convection current2. Black bodyb. conduction3. Vibrationc. absorbs more heat4. A rotating paper lanternd. no medium

Answer»
Column ‘A’Column ‘B’
1. Radiationd. no medium
2. Black bodyc. absorbs more heat
3. Vibrationb. conduction
4. A rotating paper lanterna. convection current
116.

By heating_______of substance can be changedA. sizeB. temperatureC. stateD. all the above

Answer» Correct Answer - d
On heating substacne will undergo chnge in size temperture and state .
117.

1.50 gram of ice is mixed in 300 gram of water at `50^(@)C`. Determine the resulting temperature. Given heat of fusion of ice = 336 `Jg^(-1)`.

Answer» Correct Answer - `6.67^(@)C`
118.

Fill in the blanks The transfer of heat which takes place due to the vibration of pariticles is _______.

Answer» Correct Answer - more
119.

Kalyan said that the climate was changed by being seen the dark clouds in the sky. Is the word climate correct in his statement?

Answer»

No. climate is different from weather. The changes occur during the period of some hours is called changing in weather. Climate is average weather conditions of a long period. So he had to use weather instead of climate in his statement.

120.

‘Which of the following phenomena are reverse of each other ? A) melting & boiling B) melting & evaporation C) boiling & evaporation D) evaporation & condensation

Answer»

D) evaporation & condensation

D)  Evaporation and Condensation
121.

100 g of ice at `0^(@)C` is mixed with 0.25 kg of water at `0^(@)C` The net transfer of heat is _______

Answer» Correct Answer - zero
When 100 g of ice at `0^(@)C` is mixed with 250 g of water at `0^(@)C` the net transfer of heat energy is zero Because both are at same temperature
122.

The physical state of a substance can be changed byA. decreasing its temperatureB. removing heat energy from the substaneC. giving heat energy to the substacneD. both b and c

Answer» Correct Answer - d
Change of state of substacne is due to the change in het energy
123.

Which of the following condensation restricts visibility in the surrounding air? A) dew B) fog C) both D) none

Answer»

Correct option is  B) fog

124.

Explain the process of condensation with example. (OR) Explain the process of condensation with an activity. (OR) Karan told his friend that he observed that there are some water droplets outside a cold soft drink bottle. Explain the phenomenon involved in the formation of these droplets.

Answer»

Procedure :

Place a glass tumbler on the table. Pour cold water up to half of its height. 

Observation : 

There are droplets formed outside of the glass. 

Explanation : 

  • The reason is that the surrounding air contains water molecules in the form of water vapour. When the water molecules strike the surface of the glass tumbler which is cool, they lose their kinetic energy. 
  • This energy lowers the temperature of vapour and it turns into droplets. 
  • The energy lost by water molecules in air is gained by the molecules of the glass tumbler. 
  • Hence the average kinetic energy of glass molecules increases. In turn the energy is transferred to water molecules in die glass. 

Conclusion : 

  • So the average kinetic energy and temperature of water in glass increases. 
  • This is called condensation. Condensation is the phase change from gas to liquid.
125.

What is cause of heat stroke or sunstroke ?

Answer»

High temperatures, along with humidity sometimes may cause heat stroke or sunstroke.

126.

Which instrument is used to measure the air pressure?

Answer»

Mercury Barometer and aneroid barometers are used to measure air pressure.

127.

Which instrument is used to measure temperature ?

Answer»

Thermometer is used to measure temperature.

128.

What is meant by condensation?

Answer»

The phase change from gas to liquid at the surface of the liquid is called condensation.

129.

Which instrument is used to measure the humidity in air?

Answer»

Hygrometer is used to measure humidity in air.

130.

Define humidity?

Answer»

The amount of water vapor present in the air is called humidity.

131.

A system S receives heat continuously from an electrical heater of power 10 W. The temperature of S becomes constant at 50°C when the surrounding temperature is 20°C. After the heater is switched off, S cools from 35.1°C to 34.9°C in 1 minute. The heat capacity of S is (a) 100 J/°C (b) 300 J/°C (c) 750 J/°C (d) 1500 J/°C

Answer»

Correct Answer is: (d) 1500 J/°C

Rate of loss of heat ∝ difference in temperature with the surroundings.

At 50°C, dQ/dt = k(50 - 20) = 10, where k = constant

 k = 1/3

At an average temperature of 35°C, dQ/dt = 1/3 (35 - 20) J/s = 5 J/s.

 Heat lost in 1 minute = dQ/dt x 60 J = 5 x 60 J = 300 J = Q.

Fall in temperature = 0.2°C Δθ.

Q = cΔθ.

Heat capacity = c Q/Δθ = 300 J/0.2°C.

132.

When the temperature of a body increases from t to t + Δt, its moment of inertia increases from I to I + ΔI. The coefficient of linear expansion of the body is α. The ratio 2ΔI/I is equal to(a) Δt/t (b) 2Δt/t (c) α Δt (d) 2α Δt 

Answer»

Correct Answer is: (d) 2α Δt 

I = ∑mr2

I + ΔI = ∑m[r(1 + α Δt)]2

or I + ΔI = ∑[mr2 (1 + 2α Δt)] = I(1 + 2 Δt)

or ΔI/I = 2α Δt.

133.

Before use, the clinical thermometer is jerked.

Answer»

Before use, the clinical thermometer is jerked so that the mercury flows back into the bulb.

134.

A few sharp jerks are given to clinical thermometer before using it. Why is it done so?

Answer»

The jerk to the thermometer will allow the mercury in or above the kink to flow into the bulb so that the mercury level is below normal temperature.

135.

The ratio Cp/Cv = γ for a gas. Its molecular weight is M. Its specific heat capacity at constant pressure is(a) R/γ - 1(b) γR/γ - 1(c) γR/M(γ - 1)(d) γRM/(γ - 1)

Answer»

Correct Answer is: (c) γR/M(γ - 1)

Specific heat capacity = molar heat capacity/molecular weight.

136.

The molar heat capacity for an ideal gas (a) is zero for an adiabatic process (b) is infinite for an isothermal process (c) depends only on the nature of the gas for a process in which either volume or pressure is constant (d) is equal to the product of the molecular weight and specific heat capacity for any process

Answer»

Correct Answer is: (a, b, c, & d)

 The molar heat capacity has the general definition

C = 1/n . ΔQ/ΔT ,

where n = number of moles, ΔQ = heat absorbed by the gas and ΔT = rise in temperature of gas.

It is possible to obtain almost any set of values for ΔQ and ΔT by proper selection of a process.

137.

A system undergoes a cyclic process in which it absorbs Q1 heat and gives out Q2 heat. The efficiency of the process is η and the work done is W.(a) W = Q1 - Q2(b) η = W/Q1(c) η = Q2/Q1(d) η = 1 - Q2/Q1

Answer»

Correct Answer is:(a, b, & d)

138.

cp is always greater than cV for a gas. Which of the following statements provide, party or wholly, the reason for this? (a) No work is done by a gas at constant volume. (b) When a gas absorbs heat at constant pressure, its volume must change. (c) For the same change in temperature, the internal energy of a gas changes by a smaller amount at constant volume than at constant pressure. (d) The internal energy of an ideal gas is a function only of its temperature.

Answer»

Correct Answer is: (a,b)

139.

Water in lakes and ponds in cold countries does not freeze all at once. Give reason.

Answer»

1. The latent heat of fusion of ice is sufficiently high. 

2. So to freeze water, a large quantity of heat has to be withdrawn, hence it freezes slowly and thus keeps the surroundings moderate.

140.

Give scientific reasons:If crushed ice is pressed and then the pressure is released, a lump of ice is formed.

Answer»

1. When crushed ice is pressed, its melting point is lowered and some ice melts to form water.

2. When pressure is released, the melting point becomes normal and the water freezes to form ice forming a lump.

141.

Give scientific reasons:Water droplets are seen on’ the outer surface of a cold drink bottle.

Answer»

1. The temperature of the outer surface of a cold drink bottle is less than that of the atmosphere.

2. Therefore, the excess of water vapour from the air condenses to form droplets on the outer surface of the cold drink bottle.

142.

Give scientific reasons:In cold countries, in winter, even when the water of lakes freezes, aquatic animals and plants can survive.

Answer»

1. In cold countries, in winter, a layer of ice is formed on the surface of lakes when the atmospheric temperature falls below 0 °C. However, below this layer, there is water at 4 °C.

2. Ice, being a bad conductor of heat, does not allow transfer of heat from this water to the atmosphere.

Hence, aquatic animals and plants can survive in this water.

143.

Which is essential for our healthy living? (OR) Why should we protect environment?

Answer»

A clean environment is essential for heathy living. So, we want a concrete plan to protect environment.

144.

Where the thermometers are used?

Answer»

People use thermometers in homes, hospitals, automobiles, industries and restaurants etc., to measure temperatures of different objects and substances.

145.

What is the use of clinical thermometer?

Answer»

Clinical thermometer is used in hospitals to measure the temperature of the human body.

146.

The principle used in the construction of air (gas) thermometer isA. variation of volume with temperature at constant pressure.B. variation of volume with temperature at constant heat energy.C. variation of pressure with temperature at constant volumeD. variation of pressure with temperature at constant heat energy

Answer» Correct Answer - A
The pressure exerted on the air thermometer is 1 atm and the volume of the air changes with temperature.
147.

Based on which principle a Thermometer does work?

Answer»

Thermometer works on the expansion of liquids (mercury).

148.

For each of the equation four choices have been provided .select the correct alternative SI unit of specific heat capacity is ______.A. `j kg^([email protected])C^(-1)`B. `cal g^([email protected])C^(-1)`C. `J kg^(-1)k^(-1)`D. all the above

Answer» Correct Answer - c
Amount of heat energy required to raise temperature of unit mass of a substacne through `1^(@)C` is called specific heat capacity
`therefore` Its SI units is j `kg^(-1) k^(1)`
149.

For each of the equation four choices have been provided .select the correct alternative Temperature is measured in________.A. degree celsiusB. kelvinC. degree fahrenheitD. All the above

Answer» Correct Answer - d
150.

A thermometer workd on the principle ofA. linear expansion of solidB. cubical expansion of solidC. uniform expansion of volume of liquid or gas with temperatureD. both a and c

Answer» Thermometer worked on the priniciple of cubical expansion of liquid or gas And this expansions should be uniform thourghout the material