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The length of a brass rod is 1.5 m. Its coefficient of linear expansion is `19xx10^(-6)K^(-1)` Find the increase in length of the rod if it is heated through `20^(@)C`.

Answer» Given length of the rod, l=1.5 m.
Coefficeint of linear expansion, `alpha=19xx10^(-6)K^(-1)`.
Increase in temperature, `Deltatheta=20^(@)C`
`therefore" Increase in length, "Delta l = l xx alpha xx Delta theta`
`=(1.5)xx(19xx10^(-6))xx(20)=5.7xx10^(-4)` m.


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