1.

A vessel contains ice and is in thermal equilibrium at `-10^(@)C` and is supplied heat energy at the rate of 20 cal `s^(-1)` for 450 seconds. If the mass of ice is 0.1 kg and due to supply of heat energy, the whole ice just melts find the water equivalent of the vessel. (Take specific heat of ice `=0.5 cal g^(-1)""^(@)C^(-1)` and specific heat of the vessel is `=0.1 cal g^(-1)""^(@)C^(-1)`. Latent heat of fussion = `80 cal g^(-1)` and assume that no heat is transferred to the surroundings)

Answer» (i) The amount of heat absorbed by the ice at `-10^(@)C` to just melt = Q.
`rArr" "Q_(1)=m_(i)S_(i)Delta t+m_(i)L_(F)" (1)"`
The actual amount of heat energy supplied
`=Q = Rxx t" (2)"`
`Q=20xx450` cal
Then find the amount of heat absorved by vessel
`Q_(2)=Q-Q_(1)" (3)"`
`Q_(2)=m_(V)S_(V)(Delta T)" (4)"`
Find the value `m_(V)` from (4).
Now water equivalent `=M=m_(V)S_(V)`
(ii) 50 g


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